Paper VI visual guide · Visual 6 of 42 · DEFECTS / A GUARANTEE WITHOUT A FIT

A broken lump and its error budget

Traditional Part I: Theorems 3.1, 3.3, and 5.2. Continuous and discrete defect identities.

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Original plate in the visual guide PDF · Original atlas source

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Modify only column zero of \(K\): move \(1/16\) of its mass from target state zero to target state two. The perturbed matrix \(K_\varepsilon\) remains stochastic, but its aggregate column now differs from column one. Relative to the unchanged coarse kernel,

\[ \Delta=CK_\varepsilon-\bar KC =\begin{pmatrix}-1/16&0&0&0\\1/16&0&0&0\end{pmatrix}, \qquad \|\Delta\|_1=1/8. \]
A solid finite-horizon defect curve lies below a dashed linear certificate.
Original drawing. Read the description below; expand the labels and data for selectable text.

Reading the drawing

The horizontal axis counts steps and the vertical axis uses the induced one-norm. The solid values come from the exact finite model. The dashed line is the bound based on the one-step defect; it is a guarantee and need not be sharp. The axis ticks and all original legend labels follow.

Drawing labels and data 15 labels

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Horizontal axis and ticks

number of steps \(n\), 0, 2, 4, 6, 8

Vertical axis and ticks

induced \(\ell^1\) operator norm, 0, 0.25, 0.5, 0.75, 1

One-step defect and legend

  • \(\|\Delta\|_1=1/8\)

solid: exact defect
dashed: \(n/8\)

The bound is a guarantee,
not a fitted trend.

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Evidence note from the source edition

The solid values are computed with rational matrix powers. The dashed certificate uses only stochasticity and the exact one-step defect. It need not be sharp.

Telescoping tells us where every error originates

For \(n\ge0\),

\[ CK_\varepsilon^n-\bar K^nC =\sum_{j=0}^{n-1}\bar K^{n-1-j}\Delta K_\varepsilon^j. \]

Each summand propagates one defect between an earlier fine evolution and a later coarse evolution. Column-stochastic matrices have induced \(\ell^1\) norm one, so the norm is at most \(n/8\). The empty sum at \(n=0\) is zero.

The continuous counterpart is equally explicit. With fine generator \(-1\), coarse generator \(-2\), and \(C=1\), the generator defect is \(1\) and

\[ e^{-t}-e^{-2t}=\int_0^t e^{-2(t-r)}e^{-r}\,dr. \]

Its resolvent version is \(1/(z+1)-1/(z+2)=1/((z+1)(z+2))\) for \(z>0\).

Read this as

A small defect does not disappear. The identity specifies how it accumulates, and the norm assumptions turn that identity into a finite-horizon certificate.

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