Quantum and CircuitsReading edition

Exact cut comparison and safe discrepancies

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Exact cut comparison and safe discrepancies

CLAIM C01

Theorem 14.1: Cut-comparison identity and complete coverage

Let a restored oracle be written \(\mathcal C=Q\circ P\), and put \(R=Q^{-1}\). Suppress zero ancillas in boundary arguments and define

\[ A(x)=P(x,0),\qquad B(x)=R(x,0),\qquad D(x)=P(x,1)+P(x,0). \]

These are vectors indexed by all registers. Then

\[ A(x)+B(x)=f(x)D(x),\qquad D(x)\ne0. \]
(14.1)

Consequently, the coordinate discrepancies \(H_i=A_i+B_i\) satisfy

\[ H_i\le f\quad\hbox{for every }i,\qquad \bigvee_iH_i=f. \]
(14.2)

Proof

For a boundary state with target \(z\), correctness of the full circuit gives

\[ R(x,z)=P(x,z+f(x)). \]

When \(f(x)=0\), this says \(B(x)=A(x)\). When \(f(x)=1\), it says \(B(x)=P(x,1)\), and the discrepancy is \(D(x)\). Both cases are summarized by (14.1).

The prefix \(P\) is a permutation. Its images of the two distinct boundary states \((x,0)\) and \((x,1)\) are different, so \(D(x)\) is a nonzero vector.

If \(f(x)=0\), every discrepancy is zero. If \(f(x)=1\), at least one discrepancy is one. These are precisely the safety and complete-coverage assertions in (14.2).

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