Quantum and CircuitsReading edition

A continuous phase family with a fixed initial histogram

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1.14 A continuous phase family with a fixed initial histogram

The two endpoint states are especially simple, but the mechanism is continuous. Define the nonnegative vectors \(v_+\) and \(v_-\) by placing \(|c(n)|/\sqrt{48}\) respectively on the positive and negative entries of \(c\), with zero elsewhere. Thus

\[ \chi=v_++v_-, \qquad \psi=v_+-v_-. \]

Their supports are disjoint, and each has squared norm \(1/2\). For real \(\theta\), define

\[ \chi_\theta=v_++e^{i\theta}v_-. \]

It is a normalized state with the same original-basis probabilities for every \(\theta\). The endpoints are \(\chi_0=\chi\) and \(\chi_\pi=\psi\).

Theorem QA19: Relative-phase response

For this family,

\[ \boxed{\Pr_{F^\dagger\chi_\theta}(k\in U_{12}) =\|P\chi_\theta\|^2=\sin^2(\theta/2).} \]

Proof

Disjoint support gives \(\|\chi_\theta\|^2=\|v_+\|^2+\|v_-\|^2=1\) and unchanged entrywise squared magnitudes. Solving for \(v_+\) and \(v_-\) in terms of \(\chi\) and \(\psi\) gives

\[ \chi_\theta =\frac{1+e^{i\theta}}2\chi +\frac{1-e^{i\theta}}2\psi. \]

Since \(P\chi=0\) and \(P\psi=\psi\),

\[ P\chi_\theta=\frac{1-e^{i\theta}}2\psi. \]

Its squared norm is

\[ \frac{|1-e^{i\theta}|^2}{4} =\frac{1-\cos\theta}{2} =\sin^2(\theta/2). \]

Finally, \(P=FDF^\dagger\) and unitarity imply \(\|P\chi_\theta\|^2=\|DF^\dagger\chi_\theta\|^2\), exactly the sum of the selected Fourier-basis probabilities. \(\square\)

This is a proved prose extension for the visual guide. It is not presented as an inherited Lean theorem. It shows that a probability histogram can stay fixed while an interference-based observation varies from zero to one.

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