Paper V visual guide · Visual 28 of 40 · LATTICE COORDINATES / A RECTANGULAR EXAMPLE

Six image phases are six exact address classes

Traditional monograph: Theorem E3.2 (p. 43), Theorem E3.5 (p. 44), Remark E2.2 (p. 43).

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Original plate in the visual guide PDF · Original atlas source

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Take \(L=2{\mathbb Z}\times3{\mathbb Z}\) inside \({\mathbb Z}^2\), with representatives

\[ R=\{0,1\}\times\{0,1,2\}. \]

Every address has a unique expression \((i,j)=(r_1,r_2)+(2q_1,3q_2)\). The six channels are \(x_r(2q_1,3q_2)=x(r_1+2q_1,r_2+3q_2)\).

Six phases of a rectangular image lattice
Original drawing. Read the description below; expand the labels and data for selectable text.

Reading the drawing

The colored lattice cells identify six address classes for a two-by-three sublattice. Labels retain the original horizontal and vertical index conventions.

Drawing labels and data 40 labels

Read the original labels as selectable text. Tables preserve grid relationships; other short labels are grouped compactly.

Drawing grid 1 · rows top to bottom, columns left to right
Row / columnColumn 1Column 2Column 3Column 4Column 5Column 6
Row 1\((0,2)\)\((1,2)\)\((0,2)\)\((1,2)\)\((0,2)\)\((1,2)\)
Row 2\((0,1)\)\((1,1)\)\((0,1)\)\((1,1)\)\((0,1)\)\((1,1)\)
Row 3\((0,0)\)\((1,0)\)\((0,0)\)\((1,0)\)\((0,0)\)\((1,0)\)
Row 4\((0,2)\)\((1,2)\)\((0,2)\)\((1,2)\)\((0,2)\)\((1,2)\)
Row 5\((0,1)\)\((1,1)\)\((0,1)\)\((1,1)\)\((0,1)\)\((1,1)\)
Row 6\((0,0)\)\((1,0)\)\((0,0)\)\((1,0)\)\((0,0)\)\((1,0)\)
  • \(i\)
  • \(j\)
  • \(i=2q_1+r_1\)
  • \(j=3q_2+r_2\)

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Evidence note from the source edition

Each cell shows its residue label. Colors identify six disjoint classes; they do not average neighboring image pixels.

A negative address is still unique

The point \((-1,7)\) has representative \((1,1)\) and lattice displacement \((-2,6)\), hence channel index \((-1,2)\). Floor division gives the correct answer in both coordinates. For finite \(p\), the channel norm uses the sum of the \(p\)th powers. At \(p=\infty\), it uses their maximum. Both equal the norm on the original lattice because the cosets partition all addresses. In \(\ell^\infty\), this coordinate identity does not imply that translates of an impulse are dense: their closure is only \(c_0\).

Refinement partitions a class again

For \(L'=4{\mathbb Z}\times6{\mathbb Z}\subset L\), the coarse representative \((1,2)\) has fine representatives

\[ (1,2),\ (3,2),\ (1,5),\ (3,5). \]

Their original-lattice masks sum to the coarse mask. As on V4, decimated arrays are interleaved, not added entrywise.

Read this as

Dimension changes the address tuple. Unique coset decomposition still supplies exact synthesis and the correct norm identity.

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