Paper V visual guide · Visual 17 of 40 · MASK GEOMETRY / TRANSLATION BY ONE SIXTEENTH

Small location errors, different norms

Traditional monograph: Theorem 7.1 (p. 13).

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In Lebesgue measure on the line, let

\[ \Omega=[\tfrac14,\tfrac34],\qquad \widehat\Omega=[\tfrac5{16},\tfrac{13}{16}],\qquad a=\widehat a=3. \]

The two intervals have the same length. Their disagreement consists of one missed strip and one extra strip, each of width \(1/16\).

Shifted intervals and their symmetric difference
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Three aligned rows show the true interval, its translated estimate and the two strips in their symmetric difference. The labels retain the distinct norm errors.

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  • \(\Omega\)
  • \(\widehat\Omega\)
  • \(\Omega\triangle\widehat\Omega\)
  • \(0\)

\(\frac{1}{4}\)

\(\frac{5}{16}\)

\(\frac{3}{4}\)

\(\frac{13}{16}\)

  • \(1\)
\[\delta=1/16,\qquad\mu(\Omega\triangle\widehat\Omega)=2\delta=1/8\]
\[\|j-\widehat j\|_1=3/8,\qquad\|j-\widehat j\|_2^2=9/8,\qquad\|j-\widehat j\|_\infty=3\]

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\[ |\Omega\mathbin{\triangle}\widehat\Omega|=\tfrac18, \qquad j-\widehat j=3(\mathbf1_\Omega-\mathbf1_{\widehat\Omega}). \]
Exact error norms for the translated interval
error measure\(L^1\) normsquared \(L^2\) norm\(L^\infty\) norm
exact value\(3/8\)\(9/8\)\(3\)

Area shrinks while the missed jump keeps its height

For a translation by \(\delta\) with \(0<|\delta|<1/2\), the symmetric difference has measure \(2|\delta|\). At finite \(p\),

\[ \|j-\widehat j\|_p=3(2|\delta|)^{1/p}. \]

It tends to zero as the displacement tends to zero. The essential supremum stays \(3\) for every nonzero displacement, because the error reaches height \(3\) on a set of positive measure. At exactly zero displacement all norms vanish. A nonempty disagreement set of measure zero would be different: it can affect the pointwise supremum while leaving the essential norm unchanged. This is why the paper distinguishes the two statements.

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A shrinking boundary strip can give small integrated error and still contain a full-height jump error.

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