Paper VII visual guide · Visual 16 of 40 · THE ANSWER DEPENDS ON ITS EFFECTS

Which coherence can a measurement see?

Traditional edition: Theorem II.7.2, Theorem II.7.4, Corollary II.7.5.

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For the Bell density matrix \(\rho={\left|\Phi^+\right\rangle}{\left\langle\Phi^+\right|}\), parity dephasing does nothing: both nonzero amplitudes already lie in the even subspace. Dephasing in the computational basis removes the entries between addresses \(00\) and \(11\).

Two density matrices share a diagonal but retain different coherence.
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Reading the drawing

The left matrix retains the Bell coherence under parity dephasing. The right matrix removes it under computational dephasing. The middle and bottom notes compare their diagonals and the Bell-projector outcome.

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  • \(2\rho\), also \(2D_{\rm parity}(\rho)\)
Drawing grid 1 · rows top to bottom, columns left to right
Row / columnColumn 1Column 2Column 3Column 4
00\(1\)\(0\)\(0\)\(1\)
01\(0\)\(0\)\(0\)\(0\)
10\(0\)\(0\)\(0\)\(0\)
11\(1\)\(0\)\(0\)\(1\)
  • \(2D_{\rm computational}(\rho)\)
Drawing grid 2 · rows top to bottom, columns left to right
Row / columnColumn 1Column 2Column 3Column 4
00\(1\)\(0\)\(0\)\(0\)
01\(0\)\(0\)\(0\)\(0\)
10\(0\)\(0\)\(0\)\(0\)
11\(0\)\(0\)\(0\)\(1\)

same diagonal
different coherence

Bell-projector outcome: \(1\) on the left, \(1/2\) on the right.

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Every effect in the computational basis \(E_a={\left|a\right\rangle}{\left\langle a\right|}\) has the same expectation on both matrices, namely \(1/2\) at \(00\) and \(11\) and zero elsewhere. These measurements read only the diagonal. They cannot distinguish the pure Bell state from this incoherent mixture.

A measurement that resolves the difference

Use the valid two-outcome measurement with effects \(E=\rho\) and \(I-E\). Then

\[ {\operatorname{Tr}}(E\rho)=1,\qquad {\operatorname{Tr}}\!\left(E D_{\rm computational}(\rho)\right)=\frac12. \]

The effect itself is not diagonal in the fine computational packets. It compares their coherent combination, so it falls outside the paper's invariance result for block-diagonal effects.

This example contains three operations that should not be conflated: representing a state by all of its packet matrix blocks, applying a dephasing channel, and reading one specified measurement. Only the second discards the off-diagonal blocks. The third may or may not notice that loss, depending on its effects.

The exact checks construct all four fine projectors, both parity projectors, both dephased states, and the outcome traces. They reject the stronger statement that every measurement is invariant under dephasing.

Read this as

A measurement's inability to see a coherence does not make that coherence absent. It states a restriction on the observable, not an equality of the underlying states.

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