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K. Whole finite extensions and dyadic marking criteria

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K Whole finite extensions and dyadic marking criteria

Evidence: direct reading of the original dyadic contract and ordinary finite group proofs. This note does not prove a dyadic arithmetic field construction, its simple-character existence, nontrivial stabilizer attachment, H5, or a Lean closure. It identifies exactly what a supplied actual host and sector must preserve, and proves the marked finite attachment step for C={1}.

K.1 1. The original datum includes more than the alternating form

The original text closure_attempt162/inputs/original_reading.txt states in Definition11.1, starting line4911, that at p=2 a restricted bridge additionally supplies compatible quadratic refinements and an isomorphism of the resulting Heisenberg central extensions lifting the given symplectic isometry. Sections13.1–13.9 define the refinements and their Arf/Gauss signs.

The retained visual appendix is particularly explicit, at lines6892–6947: with center {I,-I} fixed, squares of lifts carry the quadratic bit. Multiplying a lift by i changes the particular finite central-extension realization. The appendix says that allowing complex scalar rescaling without recording this distinction erases data that the bridge is required to retain.

The finite record must therefore retain at least:

  • the labelled symplectic quotient and its pairing;

  • the supplied quadratic refinement q;

  • the specified finite central extension, its central embedding/character, and any marked lifts or specified extension isomorphism;

  • the resulting normalized Gauss sign, and all declared phase operators;

  • the complete original character values retained by the scalar pushout.

The last item alone does not retain the preceding finite-subgroup/lift marking unless that marking is explicitly carried along. The raw text does not require literal embeddings of the old arithmetic matrix groups into a new type. Nor does it define a unique quadratic refinement extracted automatically from an unmarked C× scalar extension of every arithmetic type.

K.2 2. General finite central-extension criterion

Let V be an elementary abelian 2-group with ordered basis v_1,…,v_m. Let E_s and E_t be central extensions of V by the same abelian group Z. Fix the identity on Z and a quotient isomorphism f. Choose lifts a_i of v_i in E_s and b_i of f(v_i) in E_t. Write

a_i²=s_i,  b_i²=t_i,  [a_i,a_j]=c_ij, [b_i,b_j]=d_ij.

Every element has a unique normal form

z a_1^(epsilon_1) ... a_m^(epsilon_m), epsilon_i in {0,1},

and analogously on the target. The multiplication is completely determined by the displayed squares and commutators.

Criterion. A center-fixing isomorphism lifting f exists precisely when

c_ij=d_ij for every i,j,
s_i/t_i belongs to Z² for every i.                     (1)

Indeed, every such isomorphism must take a_i to lambda_i b_i for some lambda_i in Z, forcing lambda_i²=s_i/t_i. Conversely these equations make the assignment a_i -> lambda_i b_i preserve all relations, and the normal forms prove it is bijective.

If the particular lifts a_i and b_i must correspond exactly, the condition is s_i=t_i, with lambda_i=1. If a full chosen section is marked, rather than only generating lifts, its multiplication coefficients must also correspond:

a(v)a(w)=c_s(v,w)a(v+w),
b(fv)b(fw)=c_t(fv,fw)b(f(v+w)),

and exact section preservation requires c_s(v,w)=c_t(fv,fw) for every pair. Transporting the complete section under an existing group isomorphism retains these identities automatically. Preserving just its squares need not retain an additional independently specified section.

K.2.1 2.1. Fixed two-element center

For Z={+1,-1}, Z²={1}. The lift square is independent of the lift within its fiber and defines

a(v)²=(-1)^(q_s(v)).

The identity (ab)²=a²b²[b,a] gives the quadratic refinement law. Criterion(1) becomes the exact requirement

q_t(f(v))=q_s(v) for every v.                          (2)

For an unspecified symplectic isomorphism between equal-dimensional nondegenerate spaces, such an f exists exactly when their Arf invariants agree. For a preassigned f, equality of Arf invariants alone is insufficient: (2) must hold for that f.

K.2.2 2.2. Four-element and complex centers

For Z=mu_4, multiplication of a lift by i changes its square by -1. The unmarked extension criterion preserves square classes modulo Z²=mu_2. In particular, squares +1 and -1 do not distinguish unmarked mu_4 extensions. A separately marked finite mu_2-central extension subgroup (such as the full D8 or Q8), or prescribed lifts, still distinguishes them.

For Z=C× every square ratio has a square root. Thus matching commutators is sufficient for an unmarked center-fixing extension isomorphism. This fact does not delete a marked finite subgroup from the objects being compared.

K.3 3. Exact D8/Q8 check

In dimension two over C put

X=[[0,1],[1,0]],       Z=[[1,0],[0,-1]].

Then X²=Z²=I, XZ=-ZX, and [X,Z]=-I. The group generated by X and Z has order8 and is D8. Its refinement on V=F2² is

q_D(x,y)=xy,       Arf(q_D)=0,

with square table (+1,+1,+1,-1) at (0,e,f,e+f), and Gauss sum +2.

The generators iX,iZ also anticommute, but each squares to -I and their product also squares to -I. They generate Q8, with

q_Q(x,y)=xy+x+y,   Arf(q_Q)=1,

square table (+1,-1,-1,-1), and Gauss sum -2.

Both C× pushouts identify with the same ambient matrix group

P={z X^a Z^b : z in C×, a,b in {0,1}}.

Nevertheless the marked subgroups

H_D=<X,Z>,          H_Q=<iX,iZ>

are different. No isomorphism fixing the two-element center can map H_D onto H_Q: it would preserve q and hence the Arf invariant, which differs. There is also no center-fixing automorphism of P carrying the marked H_D onto H_Q. Their unmarked pushouts are isomorphic, but the marked objects (P,H_D) and (P,H_Q) are not.

Conversely a Q8 source embeds perfectly into the same P by sending its generators to iX and iZ. This preserves every source square and its negative Gauss sign. It does not identify those generators with the independently marked D8 lifts X,Z. This is the distinction needed for the arithmetic sector.

K.4 4. Marked scalar-pushout attachment with C={1}

Assume an actual type, its full character theta, and its Heisenberg quotient W have already been constructed. Let P_W be its actual C× scalar pushout, acting on its actual Heisenberg representation eta_W. Let V_src be a finite nondegenerate symplectic F2-space of dimension2s, with its complete supplied dyadic marked extension data. For several breaks use their labelled orthogonal sum, balanced central product, and supplied product refinement.

Assume the following precise finite contract:

  1. The source full-character pushout P_src has quotient V_src and the same represented scalar center as P_W.

  2. The supplied finite central extensions and their marked lifts are retained as subgroups/elements of P_src, or as already specified maps into P_src. Any central character kernel already factored out must be recorded; a scalar pushout cannot recover invisible elements of that kernel.

  3. The host has enough symplectic capacity, dim W>=2s, and the new attachment into this host has no independently fixed conflicting quadratic marking.

  4. The declared stabilizer is C={1}; the graph has one vertex.

Then a complete marked attachment exists in the same actual candidate.

Proof. Choose a symplectic embedding f:V_src -> W and let V be its image. The restriction P_V of P_W and P_src have the same commutator. Criterion(1) with center C× produces an isomorphism

F:P_src -> P_V

fixing every scalar and lifting f. Carry every supplied finite subgroup H_src to the actual subgroup F(H_src) of P_V, and every marked lift a to F(a). This operation does not erase square data:

F(a)²=F(a²),        [F(a),F(b)]=F([a,b]).              (3)

Since F fixes the scalar center, a²=(-1)^q(v) implies F(a)²=(-1)^q(v). The transported refinement is therefore exactly q, not a new choice with the same polar form. All marked section products, specified extension maps, and finite group relations are preserved by the same F. Consequently the Arf invariant and normalized Gauss sign are unchanged.

Every original h in a full character domain still maps to theta_i(h), because F fixes the entire scalar center. Thus the dyadic marking is retained together with the full original character values.

Write W=V perpendicular-sum U. Finite Stone–von Neumann gives

eta_W isomorphic to eta_src tensor eta_U.

Choose a line in eta_U and its projector e. It lies in the actual Heisenberg image algebra, and the marked source subgroup acts on e eta_W by precisely its supplied irreducible Heisenberg representation. Its lift squares remain the operators in (3). The existing sector recovery theorem then recovers the unchanged inducing representation Lambda, and the same arithmetic candidate. There is no C-equivariance equation to solve because C={1}. QED.

This realizes an actual finite marked subgroup in the scalar extension of the actual type, with actual represented operators that are complex scalars times type operators. It does not assert that every marked source element is the image of an unscaled element of the old or new arithmetic matrix group. That stronger literal-embedding requirement is absent from the present contract.

It also does not assert that the newly marked subgroup equals a separately specified canonical native subgroup of the host. The marked subgroup is part of the result and must be retained in the artifact. Omitting it and recording only the unmarked P_W would reproduce the loss displayed by D8/Q8.

K.5 5. If the host refinement is independently fixed

Suppose instead that the actual host arrives with a particular nonsingular quadratic refinement q_W and its actual finite mu_2 central extension H_W. An attachment into that marked extension requires a quadratic isometric embedding, not merely a symplectic embedding. There is a sharp capacity test.

Theorem. Let dim V_src=2s and dim W=2R. With embeddings otherwise free, a quadratic isometric embedding

(V_src,q_src) -> (W,q_W)

exists if and only if R>=s and, in the equal-capacity case R=s,

Arf(q_src)=Arf(q_W).                                  (4)

If R> s, either source Arf type embeds.

Proof. Necessity of dimension is immediate. An equal-dimensional embedding is an isometry, forcing (4). If R> s, choose a nondegenerate quadratic space U of dimension2(R-s) with

Arf(q_U)=Arf(q_W)+Arf(q_src).

Both Arf types exist in every positive even dimension, by original Proposition13.7. The orthogonal sum V_src perpendicular-sum U then has the same dimension and Arf invariant as W. Original Standard Fact13.4 gives an isometry to W; restriction to V_src gives the desired embedding. QED.

After this embedding is chosen, the preimage of its image in H_W has exactly q_src. The fixed-two-element-center criterion of Section2 gives the extension isomorphism. Generating lifts with the specified squares can be matched. Additional fully prescribed section elements still require their exact product relations, as described in Section2.

Thus one spare symplectic plane absorbs the Arf mismatch, without changing the host's own refinement. This conclusion remains conditional on the host's actual marked refinement/finite extension being supplied or constructed. It does not manufacture a canonical arithmetic quadratic datum from its dimension.

For a preassigned embedding f, the missing equation is instead

q_W(f(v))=q_src(v) for all v.                          (5)

Its discrepancy q_W composed with f minus q_src is a linear functional. Strict capacity allows a different quadratic embedding when it is free; it does not authorize replacing a fixed original map, fixed depth placement, or fixed transport marking.

K.6 6. Exact outcome for the dyadic construction

Under the retained one-vertex, C={1}, full scalar-pushout realization contract, an actual host with sufficient symplectic capacity does support every supplied finite dyadic marking, provided the transported finite subgroup, lifts, refinement, and phase are explicitly kept. The proof is Section4, rather than an assertion that commutators determine the dyadic sign.

If a particular host-native quadratic extension is fixed in advance, use Section5. Strict capacity suffices for its quadratic embedding; equal capacity requires the Arf equation, and a preassigned embedding requires (5). If only the type quotient is known and a specifically canonical host quadratic datum is requested, constructing and comparing that datum remains an arithmetic obligation. The scalar-pushout proof must not silently claim to have done it.

No part of this note handles nontrivial prescribed C actions. In that case quadratic embedding, full extension action, lift markings, and chosen honest phase operators must all be equivariant; dimension and Arf equality alone do not settle those equations.

K.7 Evidence and author self-review

Read directly: original Definition11.1, Sections13 and15, and visual appendix pagesV–22/V–23 in the retained raw file; final Block166 PROOF166.md, Section2, and LEADING_LAYER_CAPACITY166.md, Sections2.1 and4. The extension criterion and D8/Q8 calculation are complete finite proofs. The quadratic embedding theorem uses the Arf classification already explicitly supplied by the original paper. The sector conclusion reuses the retained exact recovery theorem and does not assert new arithmetic existence.

Self-review checked that complex lift rescaling is never treated as an automorphism changing squares within a fixed marked extension, that the marked subgroup remains in the output, that preassigned maps differ from freely chosen embeddings, and that fixed native refinements require their own actual input. No independent review of this note or new Lean execution is claimed here.

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