Paper XI visual guide · Visual 19 of 47 · PART II / FINITE WILD COMPARISON

Two dyadic refinements can have opposite signs

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Original source locator: Original Section 13

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Two quadratic refinements of the same symplectic plane
Original figure from the retained vector PDF.

Reading the figure

Two four-point diagrams share the underlying alternating plane but assign different quadratic values. The retained point table records the two refinements and distinguishes their signs.

Mathematical labels

\(q_0(x,y)=xy\)

\(q_1(x,y)=xy+x+y\)

Recorded quadratic values
Point (x, y)q0q1
(0, 0)00
(1, 0)01
(0, 1)01
(1, 1)11
Selectable labels from the original PDF

Native PDF text retains the figure’s extraction order. Equations and data tables above provide the reading order.

0 1
x
0
1
y
0 0
0 1
q0(x, y) = xy
0 1
x
0
1
y
0 1
1 1
q1(x, y) = xy + x + y

Original vector figure PDF · Full-size image

Original figure caption

The entries are exact values in \({\mathbb F}_2\); both polar forms are \(xy'+x'y\).

A quadratic refinement satisfies \(q(x+y)+q(x)+q(y)=b(x,y)\). On a plane,

\[ q_0(x,y)=xy,\qquad q_1(x,y)=xy+x+y. \]

For \(q_0\) there are three zeros and one one, so its Gauss sum is \(2\). For \(q_1\) there is one zero and three ones, so its sum is \(-2\). The alternating forms agree but the Arf invariants differ.

\[ \sum_{x\in V}(-1)^{q(x)}=(-1)^{{\operatorname{Arf}}(q)}2^r, \qquad \dim V=2r. \]

Reading the diagram

Keeping the alternating form alone loses dyadic phase information. The refinement and the marked central extension must travel with the packet.

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This edition preserves all 47 lessons, the opening orientation and both route sections. Figures are rendered from retained vector PDFs. Descriptions and recorded-data tables are reading aids. No mathematical generator, TeX build, proof audit or Lean replay was run for this conversion.

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