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Paper II: Refinement Towers, Weighted Transfer, and Integral Separation of Operator Packets

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674 symbol spellings in 2177 mathematical passages across 36 selected source files. Subscripts and superscripts have their own entries alongside their base symbols.

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+Notation table · 127 passages

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ANotation table · 114 passages

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CNotation table · 55 passages

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cNotation table · 50 passages

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C_{\ell,\ell+1}Notation table · 1 passage

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\cANotation table · 2 passages

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\cA_\ellNotation table · 1 passage

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\cSNotation table · 2 passages

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\cS_\ellNotation table · 1 passage

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ENotation table · 111 passages

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  • Notation table · Read passage · 06_models.tex, line 190

    s_π,Λ(E) · separation weight of a rational projector on the chosen lattice, when a clearing exponent exists

    Exact mathematical passage
    s_{\pi,\Lambda}(E)
eNotation table · 55 passages

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fNotation table · 77 passages

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INotation table · 86 passages

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I_\ellNotation table · 3 passages

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JNotation table · 18 passages

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jNotation table · 59 passages

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J_{\ell+1,\ell}Notation table · 1 passage

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NNotation table · 140 passages

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PNotation table · 92 passages

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P_{N,j}Notation table · 16 passages

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P_{\ell,\alpha}Notation table · 2 passages

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P_{\ell,\beta}Notation table · 1 passage

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\pmodNotation table · 31 passages

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sNotation table · 118 passages

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s_{\pi,\Lambda}Notation table · 3 passages

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  • Notation table · Read passage · 06_models.tex, line 190

    s_π,Λ(E) · separation weight of a rational projector on the chosen lattice, when a clearing exponent exists

    Exact mathematical passage
    s_{\pi,\Lambda}(E)
\succNotation table · 2 passages

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TNotation table · 99 passages

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tNotation table · 55 passages

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T^{(\ell)}_{\beta\alpha}Notation table · 1 passage

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T_cNotation table · 29 passages

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T_fNotation table · 30 passages

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WNotation table · 21 passages

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wNotation table · 27 passages

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ZNotation table · 24 passages

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Z_{s,t}Notation table · 4 passages

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\alphaNotation table · 95 passages

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\betaNotation table · 62 passages

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\gammaNotation table · 34 passages

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\DeltaNotation table · 28 passages

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\LambdaNotation table · 103 passages

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  • Notation table · Read passage · 06_models.tex, line 190

    s_π,Λ(E) · separation weight of a rational projector on the chosen lattice, when a clearing exponent exists

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    s_{\pi,\Lambda}(E)
\piNotation table · 80 passages

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  • Notation table · Read passage · 06_models.tex, line 190

    s_π,Λ(E) · separation weight of a rational projector on the chosen lattice, when a clearing exponent exists

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    s_{\pi,\Lambda}(E)
\ellNotation table · 32 passages

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=Definition passage · 505 passages

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  • Definition passage: Packet system · Read passage · 02_coordinates.tex, line 7

    [Packet system] Let X be a module over a unital ring. A finite packet system on X is a family P=(P_α)_α∈ I ⊆End(X) of nonzero idempotents such that P_α P_β=0 when α≠β, ∑_α∈ IP_α=I_X. Write X_α=P_α X, X^ P=⊕_α∈ IX_α. The analysis and synthesis maps are A_ Px=(P_α x)_α, S_ P(x_α)_α=∑_α x_α. They are inverse isomorphisms.

    Exact mathematical passage
    
    \Pcal=(P_\alpha)_{\alpha\in I}
    \subseteq\End(X)
    
aDefinition passage · 87 passages

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  • Definition passage: Residue selector · Read passage · 02_coordinates.tex, line 370

    [Residue selector] Let R be a commutative ring and let F(z)=∑_n≥0a_nz^n∈ R[[z]]. For N≥1 and 0≤ j<N, define (P_N,jF)(z) = ∑_n≡ jpmod Na_nz^n.

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    F(z)=\sum_{n\geq0}a_nz^n\in R[[z]].
    
a_nDefinition passage · 18 passages

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  • Definition passage: Residue selector · Read passage · 02_coordinates.tex, line 370

    [Residue selector] Let R be a commutative ring and let F(z)=∑_n≥0a_nz^n∈ R[[z]]. For N≥1 and 0≤ j<N, define (P_N,jF)(z) = ∑_n≡ jpmod Na_nz^n.

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    F(z)=\sum_{n\geq0}a_nz^n\in R[[z]].
    
\AcalDefinition passage · 7 passages

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  • Definition passage: Packet system · Read passage · 02_coordinates.tex, line 25

    ket_system Let X be a module over a unital ring. A finite packet system on X is a family P=(P_α)_α∈ I ⊆End(X) of nonzero idempotents such that P_α P_β=0 when α≠β, ∑_α∈ IP_α=I_X. Write X_α=P_α X, X^ P=⊕_α∈ IX_α. The analysis and synthesis maps are A_ Px=(P_α x)_α, S_ P(x_α)_α=∑_α x_α. They are inverse isomorphisms.

    Exact mathematical passage
    
    \Acal_{\Pcal}x=(P_\alpha x)_\alpha,
    \qquad
    \Scal_{\Pcal}(x_\alpha)_\alpha=\sum_\alpha x_\alpha.
    
\Acal_{\Pcal}Definition passage · 4 passages

Search aliases: Acal_Pcal A_ P Acal Pcal mathcal mathcal

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  • Definition passage: Packet system · Read passage · 02_coordinates.tex, line 25

    ket_system Let X be a module over a unital ring. A finite packet system on X is a family P=(P_α)_α∈ I ⊆End(X) of nonzero idempotents such that P_α P_β=0 when α≠β, ∑_α∈ IP_α=I_X. Write X_α=P_α X, X^ P=⊕_α∈ IX_α. The analysis and synthesis maps are A_ Px=(P_α x)_α, S_ P(x_α)_α=∑_α x_α. They are inverse isomorphisms.

    Exact mathematical passage
    
    \Acal_{\Pcal}x=(P_\alpha x)_\alpha,
    \qquad
    \Scal_{\Pcal}(x_\alpha)_\alpha=\sum_\alpha x_\alpha.
    
\Acal_{\Qcal}Definition passage · 4 passages

Search aliases: Acal_Qcal A_ Q Acal Qcal mathcal mathcal

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  • Definition passage: Coordinate change across levels · Read passage · 02_coordinates.tex, line 84

    [Coordinate change across levels] For two packet systems P and Q on X, define J_ Q← P = A_ Q S_ P:X^ P⟶ X^ Q and C_ P← Q = A_ P S_ Q:X^ Q⟶ X^ P. When Q refines P, the first map resolves each coarse coordinate into its children and the second adds the children back to their parent.

    Exact mathematical passage
    
    J_{\Qcal\leftarrow\Pcal}
    =
    \Acal_{\Qcal}\Scal_{\Pcal}:X^{\Pcal}\longrightarrow X^{\Qcal}
    
\bbkDefinition passage · 7 passages

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  • Definition passage: Weighted transfer series · Read passage · 03_weighted.tex, line 373

    [Weighted transfer series] Let G be a finite directed multigraph. Give every edge e a positive integer weight w(e) and a scalar multiplicity m(e) in a field bbk. Define the polynomial adjacency matrix A(t)_ij = ∑_e:i→ jm(e)t^w(e). For column vectors u and v, define Z_u,v(t) = ∑_n≥0a_nt^n, where a_n=∑_i,j ∑_substackγ:ileadsto j

    Exact mathematical passage
    \bbk
\BcalDefinition passage · 34 passages

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  • Definition passage: Complete multiplicative filtration · Read passage · 03_weighted.tex, line 6

    [Complete multiplicative filtration] A complete filtered algebra is a unital algebra B with a decreasing sequence of two-sided ideals B=F^0 B⊇ F^1 B⊇ F^2 B⊇⋯ such that F^r B F^s B⊆ F^r+s B, ⋂_L≥0F^L B=0, and the natural map B⟶varprojlim_L B/F^L B is an isomorphism. A transfer term N_e has a declared positive integer weight w(e)∈ Z_>0 when N_e∈ F^w(e) B.

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    \Bcal
C_{\Pcal\leftarrow\Qcal}Definition passage · 6 passages

Search aliases: C_Pcal←Qcal C_ P← Q Pcal leftarrow Qcal mathcal leftarrow mathcal

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  • Definition passage: Coordinate change across levels · Read passage · 02_coordinates.tex, line 90

    [Coordinate change across levels] For two packet systems P and Q on X, define J_ Q← P = A_ Q S_ P:X^ P⟶ X^ Q and C_ P← Q = A_ P S_ Q:X^ Q⟶ X^ P. When Q refines P, the first map resolves each coarse coordinate into its children and the second adds the children back to their parent.

    Exact mathematical passage
    
    C_{\Pcal\leftarrow\Qcal}
    =
    \Acal_{\Pcal}\Scal_{\Qcal}:X^{\Qcal}\longrightarrow X^{\Pcal}.
    
e_1Definition passage · 13 passages

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  • Definition passage: Weighted transfer series · Read passage · 03_weighted.tex, line 390

    W(γ)=n u_i v_j∏_ν=1^|γ|m(e_ν). Here γ=(e_1,…,e_|γ|) is a directed walk. Vertices and edges may repeat, and the empty walk has weight zero and multiplicity one. Thus the endpoint vectors weight the start and end of each walk, rather than only selecting subsets of vertices.

    Exact mathematical passage
    \gamma=(e_1,\ldots,e_{|\gamma|})
e_{|\gamma|}Definition passage · 1 passage

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  • Definition passage: Weighted transfer series · Read passage · 03_weighted.tex, line 390

    W(γ)=n u_i v_j∏_ν=1^|γ|m(e_ν). Here γ=(e_1,…,e_|γ|) is a directed walk. Vertices and edges may repeat, and the empty walk has weight zero and multiplicity one. Thus the endpoint vectors weight the start and end of each walk, rather than only selecting subsets of vertices.

    Exact mathematical passage
    \gamma=(e_1,\ldots,e_{|\gamma|})
E_\alphaDefinition passage · 13 passages

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  • Definition passage: Lattice packet data · Read passage · 04_arithmetic.tex, line 239

    [Lattice packet data] Let V=⊕_α∈ IV_α be a finite direct sum over K, with packet projectors E_α. Let Λ⊆ V be an O lattice. Put Λ_α=Λ∩ V_α, Λ_split=⊕_αΛ_α, and define the gluing module G_Λ, P = Λ/Λ_split. The separation weight of E_α is s_Λ(E_α) = min{s≥0:π^sE_αΛ⊆Λ}. The global separation weight is s_Λ( P)=max({0}∪{s_Λ(E_α):α∈ I}). For a finitely generated torsion O module G, write exp_π(G) for the least s such that π^sG=0.

    Exact mathematical passage
    E_\alpha
e_\nuDefinition passage · 1 passage

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  • Definition passage: Weighted transfer series · Read passage · 03_weighted.tex, line 386

    [Weighted transfer series] Let G be a finite directed multigraph. Give every edge e a positive integer weight w(e) and a scalar multiplicity m(e) in a field bbk. Define the polynomial adjacency matrix A(t)_ij = ∑_e:i→ jm(e)t^w(e). For column vectors u and v, define Z_u,v(t) = ∑_n≥0a_nt^n, where a_n=∑_i,j ∑_substackγ:ileadsto j W(γ)=n u_i v_j∏_ν=1^|γ|m(e_ν). Here γ=(e_1,…,e_|γ|) is a directed walk. Vertices and edges may repeat, and the empty walk has weight zero and multiplicity one. Thus the en…

    Exact mathematical passage
    
    a_n=\sum_{i,j}\ \sum_{\substack{\gamma:i\leadsto j\\W(\gamma)=n}}
     u_i v_j\prod_{\nu=1}^{|\gamma|}m(e_\nu).
    
\EndDefinition passage · 10 passages

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  • Definition passage: Packet system · Read passage · 02_coordinates.tex, line 7

    [Packet system] Let X be a module over a unital ring. A finite packet system on X is a family P=(P_α)_α∈ I ⊆End(X) of nonzero idempotents such that P_α P_β=0 when α≠β, ∑_α∈ IP_α=I_X. Write X_α=P_α X, X^ P=⊕_α∈ IX_α. The analysis and synthesis maps are A_ Px=(P_α x)_α, S_ P(x_α)_α=∑_α x_α. They are inverse isomorphisms.

    Exact mathematical passage
    
    \Pcal=(P_\alpha)_{\alpha\in I}
    \subseteq\End(X)
    
\expnDefinition passage · 4 passages

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  • Definition passage: Lattice packet data · Read passage · 04_arithmetic.tex, line 261

    mbda_α, and define the gluing module G_Λ, P = Λ/Λ_split. The separation weight of E_α is s_Λ(E_α) = min{s≥0:π^sE_αΛ⊆Λ}. The global separation weight is s_Λ( P)=max({0}∪{s_Λ(E_α):α∈ I}). For a finitely generated torsion O module G, write exp_π(G) for the least s such that π^sG=0.

    Exact mathematical passage
    \expn_\pi(G)
\expn_\piDefinition passage · 4 passages

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  • Definition passage: Lattice packet data · Read passage · 04_arithmetic.tex, line 261

    mbda_α, and define the gluing module G_Λ, P = Λ/Λ_split. The separation weight of E_α is s_Λ(E_α) = min{s≥0:π^sE_αΛ⊆Λ}. The global separation weight is s_Λ( P)=max({0}∪{s_Λ(E_α):α∈ I}). For a finitely generated torsion O module G, write exp_π(G) for the least s such that π^sG=0.

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    \expn_\pi(G)
FDefinition passage · 57 passages

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  • Definition passage: Residue selector · Read passage · 02_coordinates.tex, line 370

    [Residue selector] Let R be a commutative ring and let F(z)=∑_n≥0a_nz^n∈ R[[z]]. For N≥1 and 0≤ j<N, define (P_N,jF)(z) = ∑_n≡ jpmod Na_nz^n.

    Exact mathematical passage
    
    F(z)=\sum_{n\geq0}a_nz^n\in R[[z]].
    
F^0Definition passage · 5 passages

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  • Definition passage: Complete multiplicative filtration · Read passage · 03_weighted.tex, line 7

    [Complete multiplicative filtration] A complete filtered algebra is a unital algebra B with a decreasing sequence of two-sided ideals B=F^0 B⊇ F^1 B⊇ F^2 B⊇⋯ such that F^r B F^s B⊆ F^r+s B, ⋂_L≥0F^L B=0, and the natural map B⟶varprojlim_L B/F^L B is an isomorphism. A transfer term N_e has a declared positive integer weight w(e)∈ Z_>0 when N_e∈ F^w(e) B.

    Exact mathematical passage
    
    \Bcal=F^0\Bcal\supseteq F^1\Bcal\supseteq F^2\Bcal\supseteq\cdots
    
F^1Definition passage · 2 passages

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  • Definition passage: Complete multiplicative filtration · Read passage · 03_weighted.tex, line 7

    [Complete multiplicative filtration] A complete filtered algebra is a unital algebra B with a decreasing sequence of two-sided ideals B=F^0 B⊇ F^1 B⊇ F^2 B⊇⋯ such that F^r B F^s B⊆ F^r+s B, ⋂_L≥0F^L B=0, and the natural map B⟶varprojlim_L B/F^L B is an isomorphism. A transfer term N_e has a declared positive integer weight w(e)∈ Z_>0 when N_e∈ F^w(e) B.

    Exact mathematical passage
    
    \Bcal=F^0\Bcal\supseteq F^1\Bcal\supseteq F^2\Bcal\supseteq\cdots
    
F^2Definition passage · 1 passage

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  • Definition passage: Complete multiplicative filtration · Read passage · 03_weighted.tex, line 7

    [Complete multiplicative filtration] A complete filtered algebra is a unital algebra B with a decreasing sequence of two-sided ideals B=F^0 B⊇ F^1 B⊇ F^2 B⊇⋯ such that F^r B F^s B⊆ F^r+s B, ⋂_L≥0F^L B=0, and the natural map B⟶varprojlim_L B/F^L B is an isomorphism. A transfer term N_e has a declared positive integer weight w(e)∈ Z_>0 when N_e∈ F^w(e) B.

    Exact mathematical passage
    
    \Bcal=F^0\Bcal\supseteq F^1\Bcal\supseteq F^2\Bcal\supseteq\cdots
    
F^LDefinition passage · 16 passages

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  • Definition passage: Complete multiplicative filtration · Read passage · 03_weighted.tex, line 11

    [Complete multiplicative filtration] A complete filtered algebra is a unital algebra B with a decreasing sequence of two-sided ideals B=F^0 B⊇ F^1 B⊇ F^2 B⊇⋯ such that F^r B F^s B⊆ F^r+s B, ⋂_L≥0F^L B=0, and the natural map B⟶varprojlim_L B/F^L B is an isomorphism. A transfer term N_e has a declared positive integer weight w(e)∈ Z_>0 when N_e∈ F^w(e) B.

    Exact mathematical passage
    
    F^r\Bcal\,F^s\Bcal\subseteq F^{r+s}\Bcal,
    \qquad
    \bigcap_{L\geq0}F^L\Bcal=0,
    
F^rDefinition passage · 3 passages

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  • Definition passage: Complete multiplicative filtration · Read passage · 03_weighted.tex, line 11

    [Complete multiplicative filtration] A complete filtered algebra is a unital algebra B with a decreasing sequence of two-sided ideals B=F^0 B⊇ F^1 B⊇ F^2 B⊇⋯ such that F^r B F^s B⊆ F^r+s B, ⋂_L≥0F^L B=0, and the natural map B⟶varprojlim_L B/F^L B is an isomorphism. A transfer term N_e has a declared positive integer weight w(e)∈ Z_>0 when N_e∈ F^w(e) B.

    Exact mathematical passage
    
    F^r\Bcal\,F^s\Bcal\subseteq F^{r+s}\Bcal,
    \qquad
    \bigcap_{L\geq0}F^L\Bcal=0,
    
F^{r+s}Definition passage · 1 passage

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  • Definition passage: Complete multiplicative filtration · Read passage · 03_weighted.tex, line 11

    [Complete multiplicative filtration] A complete filtered algebra is a unital algebra B with a decreasing sequence of two-sided ideals B=F^0 B⊇ F^1 B⊇ F^2 B⊇⋯ such that F^r B F^s B⊆ F^r+s B, ⋂_L≥0F^L B=0, and the natural map B⟶varprojlim_L B/F^L B is an isomorphism. A transfer term N_e has a declared positive integer weight w(e)∈ Z_>0 when N_e∈ F^w(e) B.

    Exact mathematical passage
    
    F^r\Bcal\,F^s\Bcal\subseteq F^{r+s}\Bcal,
    \qquad
    \bigcap_{L\geq0}F^L\Bcal=0,
    
F^sDefinition passage · 1 passage

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  • Definition passage: Complete multiplicative filtration · Read passage · 03_weighted.tex, line 11

    [Complete multiplicative filtration] A complete filtered algebra is a unital algebra B with a decreasing sequence of two-sided ideals B=F^0 B⊇ F^1 B⊇ F^2 B⊇⋯ such that F^r B F^s B⊆ F^r+s B, ⋂_L≥0F^L B=0, and the natural map B⟶varprojlim_L B/F^L B is an isomorphism. A transfer term N_e has a declared positive integer weight w(e)∈ Z_>0 when N_e∈ F^w(e) B.

    Exact mathematical passage
    
    F^r\Bcal\,F^s\Bcal\subseteq F^{r+s}\Bcal,
    \qquad
    \bigcap_{L\geq0}F^L\Bcal=0,
    
F^{w(e)}Definition passage · 5 passages

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  • Definition passage: Complete multiplicative filtration · Read passage · 03_weighted.tex, line 21

    with a decreasing sequence of two-sided ideals B=F^0 B⊇ F^1 B⊇ F^2 B⊇⋯ such that F^r B F^s B⊆ F^r+s B, ⋂_L≥0F^L B=0, and the natural map B⟶varprojlim_L B/F^L B is an isomorphism. A transfer term N_e has a declared positive integer weight w(e)∈ Z_>0 when N_e∈ F^w(e) B.

    Exact mathematical passage
    
    N_e\in F^{w(e)}\Bcal.
    
GDefinition passage · 38 passages

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  • Definition passage: Weighted transfer series · Read passage · 03_weighted.tex, line 373

    [Weighted transfer series] Let G be a finite directed multigraph. Give every edge e a positive integer weight w(e) and a scalar multiplicity m(e) in a field bbk. Define the polynomial adjacency matrix A(t)_ij = ∑_e:i→ jm(e)t^w(e). For column vectors u and v, define Z_u,v(t) = ∑_n≥0a_nt^n, where a_n=∑_i,j ∑_substackγ:ileadsto j

    Exact mathematical passage
    G
gDefinition passage · 25 passages

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  • Definition passage: Separation weight · Read passage · 04_arithmetic.tex, line 186

    [Separation weight] For a rational projector E and a specified O lattice Λ, provided at least one clearing exponent exists, define s_π,Λ(E) = min{s≥0:π^sE(Λ)⊆Λ}. If the evaluated certificate arises from integral v,g and r=uπ^s with u^-1 preserving the lattice, then [source reference] gives the upper bound s_π,Λ(E)≤ s=val_π(r). Indeed, π^sE=u^-1VG preserves Λ. The minimal Lean theorem needs only the lattice action of u^-1. The bundled wrapper for lattice units records both u and u^-1. A nonzero s…

    Exact mathematical passage
    v,g
G_{\Lambda,\Pcal}Definition passage · 12 passages

Search aliases: G_Λ,Pcal G_Λ, P Lambda Pcal Lambda mathcal

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  • Definition passage: Lattice packet data · Read passage · 04_arithmetic.tex, line 246

    [Lattice packet data] Let V=⊕_α∈ IV_α be a finite direct sum over K, with packet projectors E_α. Let Λ⊆ V be an O lattice. Put Λ_α=Λ∩ V_α, Λ_split=⊕_αΛ_α, and define the gluing module G_Λ, P = Λ/Λ_split. The separation weight of E_α is s_Λ(E_α) = min{s≥0:π^sE_αΛ⊆Λ}. The global separation weight is s_Λ( P)=max({0}∪{s_Λ(E_α):α∈ I}). For a finitely generated torsion O module G, write exp_π(G) for the least s such that π^sG=0.

    Exact mathematical passage
    
    G_{\Lambda,\Pcal}
    =
    \Lambda/\Lambda_{\mathrm{split}}.
    
iDefinition passage · 46 passages

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  • Definition passage: Weighted transfer series · Read passage · 03_weighted.tex, line 374

    [Weighted transfer series] Let G be a finite directed multigraph. Give every edge e a positive integer weight w(e) and a scalar multiplicity m(e) in a field bbk. Define the polynomial adjacency matrix A(t)_ij = ∑_e:i→ jm(e)t^w(e). For column vectors u and v, define Z_u,v(t) = ∑_n≥0a_nt^n, where a_n=∑_i,j ∑_substackγ:ileadsto j

    Exact mathematical passage
    
    A(t)_{ij}
    =
    \sum_{e:i\to j}m(e)t^{w(e)}.
    
I_XDefinition passage · 6 passages

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  • Definition passage: Packet system · Read passage · 02_coordinates.tex, line 12

    [Packet system] Let X be a module over a unital ring. A finite packet system on X is a family P=(P_α)_α∈ I ⊆End(X) of nonzero idempotents such that P_α P_β=0 when α≠β, ∑_α∈ IP_α=I_X. Write X_α=P_α X, X^ P=⊕_α∈ IX_α. The analysis and synthesis maps are A_ Px=(P_α x)_α, S_ P(x_α)_α=∑_α x_α. They are inverse isomorphisms.

    Exact mathematical passage
    
    P_\alpha P_\beta=0
    \quad\text{when }\alpha\ne\beta,
    \qquad
    \sum_{\alpha\in I}P_\alpha=I_X.
    
J_{\Qcal\leftarrow\Pcal}Definition passage · 6 passages

Search aliases: J_Qcal←Pcal J_ Q← P Qcal leftarrow Pcal mathcal leftarrow mathcal

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  • Definition passage: Coordinate change across levels · Read passage · 02_coordinates.tex, line 84

    [Coordinate change across levels] For two packet systems P and Q on X, define J_ Q← P = A_ Q S_ P:X^ P⟶ X^ Q and C_ P← Q = A_ P S_ Q:X^ Q⟶ X^ P. When Q refines P, the first map resolves each coarse coordinate into its children and the second adds the children back to their parent.

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    J_{\Qcal\leftarrow\Pcal}
    =
    \Acal_{\Qcal}\Scal_{\Pcal}:X^{\Pcal}\longrightarrow X^{\Qcal}
    
KDefinition passage · 23 passages

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  • Definition passage: Lattice packet data · Read passage · 04_arithmetic.tex, line 239

    [Lattice packet data] Let V=⊕_α∈ IV_α be a finite direct sum over K, with packet projectors E_α. Let Λ⊆ V be an O lattice. Put Λ_α=Λ∩ V_α, Λ_split=⊕_αΛ_α, and define the gluing module G_Λ, P = Λ/Λ_split. The separation weight of E_α is s_Λ(E_α) = min{s≥0:π^sE_αΛ⊆Λ}. The global separation weight is s_Λ( P)=max({0}∪{s_Λ(E_α):α∈ I}). For a finitely generated torsion O module G, write exp_π(G) for the least s such that π^sG=0.

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    K
LDefinition passage · 111 passages

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  • Definition passage: Complete multiplicative filtration · Read passage · 03_weighted.tex, line 11

    [Complete multiplicative filtration] A complete filtered algebra is a unital algebra B with a decreasing sequence of two-sided ideals B=F^0 B⊇ F^1 B⊇ F^2 B⊇⋯ such that F^r B F^s B⊆ F^r+s B, ⋂_L≥0F^L B=0, and the natural map B⟶varprojlim_L B/F^L B is an isomorphism. A transfer term N_e has a declared positive integer weight w(e)∈ Z_>0 when N_e∈ F^w(e) B.

    Exact mathematical passage
    
    F^r\Bcal\,F^s\Bcal\subseteq F^{r+s}\Bcal,
    \qquad
    \bigcap_{L\geq0}F^L\Bcal=0,
    
\leadstoDefinition passage · 2 passages

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  • Definition passage: Weighted transfer series · Read passage · 03_weighted.tex, line 386

    [Weighted transfer series] Let G be a finite directed multigraph. Give every edge e a positive integer weight w(e) and a scalar multiplicity m(e) in a field bbk. Define the polynomial adjacency matrix A(t)_ij = ∑_e:i→ jm(e)t^w(e). For column vectors u and v, define Z_u,v(t) = ∑_n≥0a_nt^n, where a_n=∑_i,j ∑_substackγ:ileadsto j W(γ)=n u_i v_j∏_ν=1^|γ|m(e_ν). Here γ=(e_1,…,e_|γ|) is a directed walk. Vertices and edges may repeat, and the empty walk has weight zero and multiplicity one. Thus the en…

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    a_n=\sum_{i,j}\ \sum_{\substack{\gamma:i\leadsto j\\W(\gamma)=n}}
     u_i v_j\prod_{\nu=1}^{|\gamma|}m(e_\nu).
    
mDefinition passage · 59 passages

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  • Definition passage: Weighted transfer series · Read passage · 03_weighted.tex, line 373

    [Weighted transfer series] Let G be a finite directed multigraph. Give every edge e a positive integer weight w(e) and a scalar multiplicity m(e) in a field bbk. Define the polynomial adjacency matrix A(t)_ij = ∑_e:i→ jm(e)t^w(e). For column vectors u and v, define Z_u,v(t) = ∑_n≥0a_nt^n, where a_n=∑_i,j ∑_substackγ:ileadsto j

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    m(e)
\maxDefinition passage · 4 passages

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  • Definition passage: Lattice packet data · Read passage · 04_arithmetic.tex, line 258

    et Λ⊆ V be an O lattice. Put Λ_α=Λ∩ V_α, Λ_split=⊕_αΛ_α, and define the gluing module G_Λ, P = Λ/Λ_split. The separation weight of E_α is s_Λ(E_α) = min{s≥0:π^sE_αΛ⊆Λ}. The global separation weight is s_Λ( P)=max({0}∪{s_Λ(E_α):α∈ I}). For a finitely generated torsion O module G, write exp_π(G) for the least s such that π^sG=0.

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    s_\Lambda(\Pcal)=\max\bigl(\{0\}\cup\{s_\Lambda(E_\alpha):\alpha\in I\}\bigr).
    
\minDefinition passage · 14 passages

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  • Definition passage: Separation weight · Read passage · 04_arithmetic.tex, line 181

    [Separation weight] For a rational projector E and a specified O lattice Λ, provided at least one clearing exponent exists, define s_π,Λ(E) = min{s≥0:π^sE(Λ)⊆Λ}. If the evaluated certificate arises from integral v,g and r=uπ^s with u^-1 preserving the lattice, then [source reference] gives the upper bound s_π,Λ(E)≤ s=val_π(r). Indeed, π^sE=u^-1VG preserves Λ. The minimal Lean theorem needs only the lattice action of u^-1. The bundled wrapper for lattice units records both u and u^-1. A nonzero s…

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    s_{\pi,\Lambda}(E)
    =
    \min\{s\ge0:\pi^sE(\Lambda)\subseteq\Lambda\}.
    
nDefinition passage · 80 passages

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  • Definition passage: Residue selector · Read passage · 02_coordinates.tex, line 370

    [Residue selector] Let R be a commutative ring and let F(z)=∑_n≥0a_nz^n∈ R[[z]]. For N≥1 and 0≤ j<N, define (P_N,jF)(z) = ∑_n≡ jpmod Na_nz^n.

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    F(z)=\sum_{n\geq0}a_nz^n\in R[[z]].
    
N_eDefinition passage · 7 passages

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  • Definition passage: Complete multiplicative filtration · Read passage · 03_weighted.tex, line 20

    ef:filtered_algebra A complete filtered algebra is a unital algebra B with a decreasing sequence of two-sided ideals B=F^0 B⊇ F^1 B⊇ F^2 B⊇⋯ such that F^r B F^s B⊆ F^r+s B, ⋂_L≥0F^L B=0, and the natural map B⟶varprojlim_L B/F^L B is an isomorphism. A transfer term N_e has a declared positive integer weight w(e)∈ Z_>0 when N_e∈ F^w(e) B.

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    N_e
\OODefinition passage · 55 passages

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  • Definition passage: Separation weight · Read passage · 04_arithmetic.tex, line 179

    [Separation weight] For a rational projector E and a specified O lattice Λ, provided at least one clearing exponent exists, define s_π,Λ(E) = min{s≥0:π^sE(Λ)⊆Λ}. If the evaluated certificate arises from integral v,g and r=uπ^s with u^-1 preserving the lattice, then [source reference] gives the upper bound s_π,Λ(E)≤ s=val_π(r). Indeed, π^sE=u^-1VG preserves Λ. The minimal Lean theorem needs only the lattice action of u^-1. The bundled wrapper for lattice units records both u and u^-1. A nonzero s…

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    \OO
P_\alphaDefinition passage · 37 passages

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  • Definition passage: Packet system · Read passage · 02_coordinates.tex, line 7

    [Packet system] Let X be a module over a unital ring. A finite packet system on X is a family P=(P_α)_α∈ I ⊆End(X) of nonzero idempotents such that P_α P_β=0 when α≠β, ∑_α∈ IP_α=I_X. Write X_α=P_α X, X^ P=⊕_α∈ IX_α. The analysis and synthesis maps are A_ Px=(P_α x)_α, S_ P(x_α)_α=∑_α x_α. They are inverse isomorphisms.

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    \Pcal=(P_\alpha)_{\alpha\in I}
    \subseteq\End(X)
    
P_\betaDefinition passage · 9 passages

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  • Definition passage: Packet system · Read passage · 02_coordinates.tex, line 12

    [Packet system] Let X be a module over a unital ring. A finite packet system on X is a family P=(P_α)_α∈ I ⊆End(X) of nonzero idempotents such that P_α P_β=0 when α≠β, ∑_α∈ IP_α=I_X. Write X_α=P_α X, X^ P=⊕_α∈ IX_α. The analysis and synthesis maps are A_ Px=(P_α x)_α, S_ P(x_α)_α=∑_α x_α. They are inverse isomorphisms.

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    P_\alpha P_\beta=0
    \quad\text{when }\alpha\ne\beta,
    \qquad
    \sum_{\alpha\in I}P_\alpha=I_X.
    
\PcalDefinition passage · 56 passages

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  • Definition passage: Packet system · Read passage · 02_coordinates.tex, line 7

    [Packet system] Let X be a module over a unital ring. A finite packet system on X is a family P=(P_α)_α∈ I ⊆End(X) of nonzero idempotents such that P_α P_β=0 when α≠β, ∑_α∈ IP_α=I_X. Write X_α=P_α X, X^ P=⊕_α∈ IX_α. The analysis and synthesis maps are A_ Px=(P_α x)_α, S_ P(x_α)_α=∑_α x_α. They are inverse isomorphisms.

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    \Pcal=(P_\alpha)_{\alpha\in I}
    \subseteq\End(X)
    
QDefinition passage · 55 passages

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  • Definition passage: Refinement · Read passage · 02_coordinates.tex, line 34

    [Refinement] Let P=(P_α)_α∈ I and Q=(Q_β)_β∈ J be packet systems on the same module. We say that Q refines P when there is a surjection ρ:J⟶ I such that P_α=∑_ρ(β)=αQ_β for every α∈ I. The index β is then called a child of ρ(β).

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    \Qcal=(Q_\beta)_{\beta\in J}
Q_\betaDefinition passage · 27 passages

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  • Definition passage: Refinement · Read passage · 02_coordinates.tex, line 34

    [Refinement] Let P=(P_α)_α∈ I and Q=(Q_β)_β∈ J be packet systems on the same module. We say that Q refines P when there is a surjection ρ:J⟶ I such that P_α=∑_ρ(β)=αQ_β for every α∈ I. The index β is then called a child of ρ(β).

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    \Qcal=(Q_\beta)_{\beta\in J}
\QcalDefinition passage · 32 passages

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  • Definition passage: Refinement · Read passage · 02_coordinates.tex, line 34

    [Refinement] Let P=(P_α)_α∈ I and Q=(Q_β)_β∈ J be packet systems on the same module. We say that Q refines P when there is a surjection ρ:J⟶ I such that P_α=∑_ρ(β)=αQ_β for every α∈ I. The index β is then called a child of ρ(β).

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    \Qcal=(Q_\beta)_{\beta\in J}
RDefinition passage · 42 passages

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  • Definition passage: Residue selector · Read passage · 02_coordinates.tex, line 369

    [Residue selector] Let R be a commutative ring and let F(z)=∑_n≥0a_nz^n∈ R[[z]]. For N≥1 and 0≤ j<N, define (P_N,jF)(z) = ∑_n≡ jpmod Na_nz^n.

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rDefinition passage · 98 passages

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  • Definition passage: Complete multiplicative filtration · Read passage · 03_weighted.tex, line 11

    [Complete multiplicative filtration] A complete filtered algebra is a unital algebra B with a decreasing sequence of two-sided ideals B=F^0 B⊇ F^1 B⊇ F^2 B⊇⋯ such that F^r B F^s B⊆ F^r+s B, ⋂_L≥0F^L B=0, and the natural map B⟶varprojlim_L B/F^L B is an isomorphism. A transfer term N_e has a declared positive integer weight w(e)∈ Z_>0 when N_e∈ F^w(e) B.

    Exact mathematical passage
    
    F^r\Bcal\,F^s\Bcal\subseteq F^{r+s}\Bcal,
    \qquad
    \bigcap_{L\geq0}F^L\Bcal=0,
    
s_\LambdaDefinition passage · 11 passages

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  • Definition passage: Lattice packet data · Read passage · 04_arithmetic.tex, line 252

    et V=⊕_α∈ IV_α be a finite direct sum over K, with packet projectors E_α. Let Λ⊆ V be an O lattice. Put Λ_α=Λ∩ V_α, Λ_split=⊕_αΛ_α, and define the gluing module G_Λ, P = Λ/Λ_split. The separation weight of E_α is s_Λ(E_α) = min{s≥0:π^sE_αΛ⊆Λ}. The global separation weight is s_Λ( P)=max({0}∪{s_Λ(E_α):α∈ I}). For a finitely generated torsion O module G, write exp_π(G) for the least s such that π^sG=0.

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    s_\Lambda(E_\alpha)
    =
    \min\{s\geq0:\pi^sE_\alpha\Lambda\subseteq\Lambda\}.
    
\ScalDefinition passage · 7 passages

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  • Definition passage: Packet system · Read passage · 02_coordinates.tex, line 25

    ket_system Let X be a module over a unital ring. A finite packet system on X is a family P=(P_α)_α∈ I ⊆End(X) of nonzero idempotents such that P_α P_β=0 when α≠β, ∑_α∈ IP_α=I_X. Write X_α=P_α X, X^ P=⊕_α∈ IX_α. The analysis and synthesis maps are A_ Px=(P_α x)_α, S_ P(x_α)_α=∑_α x_α. They are inverse isomorphisms.

    Exact mathematical passage
    
    \Acal_{\Pcal}x=(P_\alpha x)_\alpha,
    \qquad
    \Scal_{\Pcal}(x_\alpha)_\alpha=\sum_\alpha x_\alpha.
    
\Scal_{\Pcal}Definition passage · 4 passages

Search aliases: Scal_Pcal S_ P Scal Pcal mathcal mathcal

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  • Definition passage: Packet system · Read passage · 02_coordinates.tex, line 25

    ket_system Let X be a module over a unital ring. A finite packet system on X is a family P=(P_α)_α∈ I ⊆End(X) of nonzero idempotents such that P_α P_β=0 when α≠β, ∑_α∈ IP_α=I_X. Write X_α=P_α X, X^ P=⊕_α∈ IX_α. The analysis and synthesis maps are A_ Px=(P_α x)_α, S_ P(x_α)_α=∑_α x_α. They are inverse isomorphisms.

    Exact mathematical passage
    
    \Acal_{\Pcal}x=(P_\alpha x)_\alpha,
    \qquad
    \Scal_{\Pcal}(x_\alpha)_\alpha=\sum_\alpha x_\alpha.
    
\Scal_{\Qcal}Definition passage · 4 passages

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  • Definition passage: Coordinate change across levels · Read passage · 02_coordinates.tex, line 90

    [Coordinate change across levels] For two packet systems P and Q on X, define J_ Q← P = A_ Q S_ P:X^ P⟶ X^ Q and C_ P← Q = A_ P S_ Q:X^ Q⟶ X^ P. When Q refines P, the first map resolves each coarse coordinate into its children and the second adds the children back to their parent.

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    C_{\Pcal\leftarrow\Qcal}
    =
    \Acal_{\Pcal}\Scal_{\Qcal}:X^{\Qcal}\longrightarrow X^{\Pcal}.
    
\mathrm{split}Definition passage · 7 passages

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  • Definition passage: Lattice packet data · Read passage · 04_arithmetic.tex, line 240

    [Lattice packet data] Let V=⊕_α∈ IV_α be a finite direct sum over K, with packet projectors E_α. Let Λ⊆ V be an O lattice. Put Λ_α=Λ∩ V_α, Λ_split=⊕_αΛ_α, and define the gluing module G_Λ, P = Λ/Λ_split. The separation weight of E_α is s_Λ(E_α) = min{s≥0:π^sE_αΛ⊆Λ}. The global separation weight is s_Λ( P)=max({0}∪{s_Λ(E_α):α∈ I}). For a finitely generated torsion O module G, write exp_π(G) for the least s such that π^sG=0.

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    \Lambda_\alpha=\Lambda\cap V_\alpha,
    \qquad
    \Lambda_{\mathrm{split}}=\bigoplus_\alpha\Lambda_\alpha,
    
t^nDefinition passage · 3 passages

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  • Definition passage: Weighted transfer series · Read passage · 03_weighted.tex, line 380

    [Weighted transfer series] Let G be a finite directed multigraph. Give every edge e a positive integer weight w(e) and a scalar multiplicity m(e) in a field bbk. Define the polynomial adjacency matrix A(t)_ij = ∑_e:i→ jm(e)t^w(e). For column vectors u and v, define Z_u,v(t) = ∑_n≥0a_nt^n, where a_n=∑_i,j ∑_substackγ:ileadsto j

    Exact mathematical passage
    
    Z_{u,v}(t)
    =
    \sum_{n\geq0}a_nt^n,
    
t^{w(e)}Definition passage · 3 passages

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  • Definition passage: Weighted transfer series · Read passage · 03_weighted.tex, line 374

    [Weighted transfer series] Let G be a finite directed multigraph. Give every edge e a positive integer weight w(e) and a scalar multiplicity m(e) in a field bbk. Define the polynomial adjacency matrix A(t)_ij = ∑_e:i→ jm(e)t^w(e). For column vectors u and v, define Z_u,v(t) = ∑_n≥0a_nt^n, where a_n=∑_i,j ∑_substackγ:ileadsto j

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    A(t)_{ij}
    =
    \sum_{e:i\to j}m(e)t^{w(e)}.
    
uDefinition passage · 20 passages

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  • Definition passage: Weighted transfer series · Read passage · 03_weighted.tex, line 379

    [Weighted transfer series] Let G be a finite directed multigraph. Give every edge e a positive integer weight w(e) and a scalar multiplicity m(e) in a field bbk. Define the polynomial adjacency matrix A(t)_ij = ∑_e:i→ jm(e)t^w(e). For column vectors u and v, define Z_u,v(t) = ∑_n≥0a_nt^n, where a_n=∑_i,j ∑_substackγ:ileadsto j

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    u
u^{-1}Definition passage · 4 passages

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  • Definition passage: Separation weight · Read passage · 04_arithmetic.tex, line 187

    [Separation weight] For a rational projector E and a specified O lattice Λ, provided at least one clearing exponent exists, define s_π,Λ(E) = min{s≥0:π^sE(Λ)⊆Λ}. If the evaluated certificate arises from integral v,g and r=uπ^s with u^-1 preserving the lattice, then [source reference] gives the upper bound s_π,Λ(E)≤ s=val_π(r). Indeed, π^sE=u^-1VG preserves Λ. The minimal Lean theorem needs only the lattice action of u^-1. The bundled wrapper for lattice units records both u and u^-1. A nonzero s…

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    u^{-1}
u_iDefinition passage · 2 passages

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  • Definition passage: Weighted transfer series · Read passage · 03_weighted.tex, line 386

    [Weighted transfer series] Let G be a finite directed multigraph. Give every edge e a positive integer weight w(e) and a scalar multiplicity m(e) in a field bbk. Define the polynomial adjacency matrix A(t)_ij = ∑_e:i→ jm(e)t^w(e). For column vectors u and v, define Z_u,v(t) = ∑_n≥0a_nt^n, where a_n=∑_i,j ∑_substackγ:ileadsto j W(γ)=n u_i v_j∏_ν=1^|γ|m(e_ν). Here γ=(e_1,…,e_|γ|) is a directed walk. Vertices and edges may repeat, and the empty walk has weight zero and multiplicity one. Thus the en…

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    a_n=\sum_{i,j}\ \sum_{\substack{\gamma:i\leadsto j\\W(\gamma)=n}}
     u_i v_j\prod_{\nu=1}^{|\gamma|}m(e_\nu).
    
VDefinition passage · 45 passages

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  • Definition passage: Separation weight · Read passage · 04_arithmetic.tex, line 193

    rojector E and a specified O lattice Λ, provided at least one clearing exponent exists, define s_π,Λ(E) = min{s≥0:π^sE(Λ)⊆Λ}. If the evaluated certificate arises from integral v,g and r=uπ^s with u^-1 preserving the lattice, then [source reference] gives the upper bound s_π,Λ(E)≤ s=val_π(r). Indeed, π^sE=u^-1VG preserves Λ. The minimal Lean theorem needs only the lattice action of u^-1. The bundled wrapper for lattice units records both u and u^-1. A nonzero scalar in the fraction field need not…

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    \boxed{\pi^sE=u^{-1}VG}
    
vDefinition passage · 25 passages

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  • Definition passage: Weighted transfer series · Read passage · 03_weighted.tex, line 379

    [Weighted transfer series] Let G be a finite directed multigraph. Give every edge e a positive integer weight w(e) and a scalar multiplicity m(e) in a field bbk. Define the polynomial adjacency matrix A(t)_ij = ∑_e:i→ jm(e)t^w(e). For column vectors u and v, define Z_u,v(t) = ∑_n≥0a_nt^n, where a_n=∑_i,j ∑_substackγ:ileadsto j

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    v
v_jDefinition passage · 1 passage

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  • Definition passage: Weighted transfer series · Read passage · 03_weighted.tex, line 386

    [Weighted transfer series] Let G be a finite directed multigraph. Give every edge e a positive integer weight w(e) and a scalar multiplicity m(e) in a field bbk. Define the polynomial adjacency matrix A(t)_ij = ∑_e:i→ jm(e)t^w(e). For column vectors u and v, define Z_u,v(t) = ∑_n≥0a_nt^n, where a_n=∑_i,j ∑_substackγ:ileadsto j W(γ)=n u_i v_j∏_ν=1^|γ|m(e_ν). Here γ=(e_1,…,e_|γ|) is a directed walk. Vertices and edges may repeat, and the empty walk has weight zero and multiplicity one. Thus the en…

    Exact mathematical passage
    
    a_n=\sum_{i,j}\ \sum_{\substack{\gamma:i\leadsto j\\W(\gamma)=n}}
     u_i v_j\prod_{\nu=1}^{|\gamma|}m(e_\nu).
    
V_\alphaDefinition passage · 7 passages

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  • Definition passage: Lattice packet data · Read passage · 04_arithmetic.tex, line 236

    [Lattice packet data] Let V=⊕_α∈ IV_α be a finite direct sum over K, with packet projectors E_α. Let Λ⊆ V be an O lattice. Put Λ_α=Λ∩ V_α, Λ_split=⊕_αΛ_α, and define the gluing module G_Λ, P = Λ/Λ_split. The separation weight of E_α is s_Λ(E_α) = min{s≥0:π^sE_αΛ⊆Λ}. The global separation weight is s_Λ( P)=max({0}∪{s_Λ(E_α):α∈ I}). For a finitely generated torsion O module G, write exp_π(G) for the least s such that π^sG=0.

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    V=\bigoplus_{\alpha\in I}V_\alpha
    
\valDefinition passage · 2 passages

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  • Definition passage: Separation weight · Read passage · 04_arithmetic.tex, line 189

    ight] For a rational projector E and a specified O lattice Λ, provided at least one clearing exponent exists, define s_π,Λ(E) = min{s≥0:π^sE(Λ)⊆Λ}. If the evaluated certificate arises from integral v,g and r=uπ^s with u^-1 preserving the lattice, then [source reference] gives the upper bound s_π,Λ(E)≤ s=val_π(r). Indeed, π^sE=u^-1VG preserves Λ. The minimal Lean theorem needs only the lattice action of u^-1. The bundled wrapper for lattice units records both u and u^-1. A nonzero scalar in the f…

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    s_{\pi,\Lambda}(E)\le s=\val_\pi(r).
    
\val_\piDefinition passage · 2 passages

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  • Definition passage: Separation weight · Read passage · 04_arithmetic.tex, line 189

    ight] For a rational projector E and a specified O lattice Λ, provided at least one clearing exponent exists, define s_π,Λ(E) = min{s≥0:π^sE(Λ)⊆Λ}. If the evaluated certificate arises from integral v,g and r=uπ^s with u^-1 preserving the lattice, then [source reference] gives the upper bound s_π,Λ(E)≤ s=val_π(r). Indeed, π^sE=u^-1VG preserves Λ. The minimal Lean theorem needs only the lattice action of u^-1. The bundled wrapper for lattice units records both u and u^-1. A nonzero scalar in the f…

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    s_{\pi,\Lambda}(E)\le s=\val_\pi(r).
    
\varprojlimDefinition passage · 1 passage

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  • Definition passage: Complete multiplicative filtration · Read passage · 03_weighted.tex, line 17

    [Complete multiplicative filtration] A complete filtered algebra is a unital algebra B with a decreasing sequence of two-sided ideals B=F^0 B⊇ F^1 B⊇ F^2 B⊇⋯ such that F^r B F^s B⊆ F^r+s B, ⋂_L≥0F^L B=0, and the natural map B⟶varprojlim_L B/F^L B is an isomorphism. A transfer term N_e has a declared positive integer weight w(e)∈ Z_>0 when N_e∈ F^w(e) B.

    Exact mathematical passage
    
    \Bcal\longrightarrow\varprojlim_L\Bcal/F^L\Bcal
    
\varprojlim_LDefinition passage · 1 passage

Search aliases: varprojlim_L varprojlim

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  • Definition passage: Complete multiplicative filtration · Read passage · 03_weighted.tex, line 17

    [Complete multiplicative filtration] A complete filtered algebra is a unital algebra B with a decreasing sequence of two-sided ideals B=F^0 B⊇ F^1 B⊇ F^2 B⊇⋯ such that F^r B F^s B⊆ F^r+s B, ⋂_L≥0F^L B=0, and the natural map B⟶varprojlim_L B/F^L B is an isomorphism. A transfer term N_e has a declared positive integer weight w(e)∈ Z_>0 when N_e∈ F^w(e) B.

    Exact mathematical passage
    
    \Bcal\longrightarrow\varprojlim_L\Bcal/F^L\Bcal
    
XDefinition passage · 50 passages

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  • Definition passage: Packet system · Read passage · 02_coordinates.tex, line 6

    [Packet system] Let X be a module over a unital ring. A finite packet system on X is a family P=(P_α)_α∈ I ⊆End(X) of nonzero idempotents such that P_α P_β=0 when α≠β, ∑_α∈ IP_α=I_X. Write X_α=P_α X, X^ P=⊕_α∈ IX_α. The analysis and synthesis maps are A_ Px=(P_α x)_α, S_ P(x_α)_α=∑_α x_α. They are inverse isomorphisms.

    Exact mathematical passage
    X
xDefinition passage · 120 passages

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  • Definition passage: Packet system · Read passage · 02_coordinates.tex, line 25

    ket_system Let X be a module over a unital ring. A finite packet system on X is a family P=(P_α)_α∈ I ⊆End(X) of nonzero idempotents such that P_α P_β=0 when α≠β, ∑_α∈ IP_α=I_X. Write X_α=P_α X, X^ P=⊕_α∈ IX_α. The analysis and synthesis maps are A_ Px=(P_α x)_α, S_ P(x_α)_α=∑_α x_α. They are inverse isomorphisms.

    Exact mathematical passage
    
    \Acal_{\Pcal}x=(P_\alpha x)_\alpha,
    \qquad
    \Scal_{\Pcal}(x_\alpha)_\alpha=\sum_\alpha x_\alpha.
    
X^{\Pcal}Definition passage · 4 passages

Search aliases: X^Pcal X^ P Pcal mathcal

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  • Definition passage: Packet system · Read passage · 02_coordinates.tex, line 19

    [Packet system] Let X be a module over a unital ring. A finite packet system on X is a family P=(P_α)_α∈ I ⊆End(X) of nonzero idempotents such that P_α P_β=0 when α≠β, ∑_α∈ IP_α=I_X. Write X_α=P_α X, X^ P=⊕_α∈ IX_α. The analysis and synthesis maps are A_ Px=(P_α x)_α, S_ P(x_α)_α=∑_α x_α. They are inverse isomorphisms.

    Exact mathematical passage
    
    X_\alpha=P_\alpha X,
    \qquad
    X^{\Pcal}=\bigoplus_{\alpha\in I}X_\alpha.
    
X^{\Qcal}Definition passage · 3 passages

Search aliases: X^Qcal X^ Q Qcal mathcal

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  • Definition passage: Coordinate change across levels · Read passage · 02_coordinates.tex, line 84

    [Coordinate change across levels] For two packet systems P and Q on X, define J_ Q← P = A_ Q S_ P:X^ P⟶ X^ Q and C_ P← Q = A_ P S_ Q:X^ Q⟶ X^ P. When Q refines P, the first map resolves each coarse coordinate into its children and the second adds the children back to their parent.

    Exact mathematical passage
    
    J_{\Qcal\leftarrow\Pcal}
    =
    \Acal_{\Qcal}\Scal_{\Pcal}:X^{\Pcal}\longrightarrow X^{\Qcal}
    
X_\alphaDefinition passage · 1 passage

Search aliases: X_α alpha

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  • Definition passage: Packet system · Read passage · 02_coordinates.tex, line 19

    [Packet system] Let X be a module over a unital ring. A finite packet system on X is a family P=(P_α)_α∈ I ⊆End(X) of nonzero idempotents such that P_α P_β=0 when α≠β, ∑_α∈ IP_α=I_X. Write X_α=P_α X, X^ P=⊕_α∈ IX_α. The analysis and synthesis maps are A_ Px=(P_α x)_α, S_ P(x_α)_α=∑_α x_α. They are inverse isomorphisms.

    Exact mathematical passage
    
    X_\alpha=P_\alpha X,
    \qquad
    X^{\Pcal}=\bigoplus_{\alpha\in I}X_\alpha.
    
x_\alphaDefinition passage · 5 passages

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  • Definition passage: Packet system · Read passage · 02_coordinates.tex, line 25

    ket_system Let X be a module over a unital ring. A finite packet system on X is a family P=(P_α)_α∈ I ⊆End(X) of nonzero idempotents such that P_α P_β=0 when α≠β, ∑_α∈ IP_α=I_X. Write X_α=P_α X, X^ P=⊕_α∈ IX_α. The analysis and synthesis maps are A_ Px=(P_α x)_α, S_ P(x_α)_α=∑_α x_α. They are inverse isomorphisms.

    Exact mathematical passage
    
    \Acal_{\Pcal}x=(P_\alpha x)_\alpha,
    \qquad
    \Scal_{\Pcal}(x_\alpha)_\alpha=\sum_\alpha x_\alpha.
    
\mathbb ZDefinition passage · 10 passages

Search aliases: Z mathbb

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  • Definition passage: Complete multiplicative filtration · Read passage · 03_weighted.tex, line 20

    bra is a unital algebra B with a decreasing sequence of two-sided ideals B=F^0 B⊇ F^1 B⊇ F^2 B⊇⋯ such that F^r B F^s B⊆ F^r+s B, ⋂_L≥0F^L B=0, and the natural map B⟶varprojlim_L B/F^L B is an isomorphism. A transfer term N_e has a declared positive integer weight w(e)∈ Z_>0 when N_e∈ F^w(e) B.

    Exact mathematical passage
    w(e)\in\mathbb Z_{>0}
zDefinition passage · 53 passages

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  • Definition passage: Residue selector · Read passage · 02_coordinates.tex, line 370

    [Residue selector] Let R be a commutative ring and let F(z)=∑_n≥0a_nz^n∈ R[[z]]. For N≥1 and 0≤ j<N, define (P_N,jF)(z) = ∑_n≡ jpmod Na_nz^n.

    Exact mathematical passage
    
    F(z)=\sum_{n\geq0}a_nz^n\in R[[z]].
    
z^nDefinition passage · 6 passages

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  • Definition passage: Residue selector · Read passage · 02_coordinates.tex, line 370

    [Residue selector] Let R be a commutative ring and let F(z)=∑_n≥0a_nz^n∈ R[[z]]. For N≥1 and 0≤ j<N, define (P_N,jF)(z) = ∑_n≡ jpmod Na_nz^n.

    Exact mathematical passage
    
    F(z)=\sum_{n\geq0}a_nz^n\in R[[z]].
    
\mathbb Z_{>0}Definition passage · 1 passage

Search aliases: Z_>0 mathbb

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  • Definition passage: Complete multiplicative filtration · Read passage · 03_weighted.tex, line 20

    bra is a unital algebra B with a decreasing sequence of two-sided ideals B=F^0 B⊇ F^1 B⊇ F^2 B⊇⋯ such that F^r B F^s B⊆ F^r+s B, ⋂_L≥0F^L B=0, and the natural map B⟶varprojlim_L B/F^L B is an isomorphism. A transfer term N_e has a declared positive integer weight w(e)∈ Z_>0 when N_e∈ F^w(e) B.

    Exact mathematical passage
    w(e)\in\mathbb Z_{>0}
Z_{u,v}Definition passage · 5 passages

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  • Definition passage: Weighted transfer series · Read passage · 03_weighted.tex, line 380

    [Weighted transfer series] Let G be a finite directed multigraph. Give every edge e a positive integer weight w(e) and a scalar multiplicity m(e) in a field bbk. Define the polynomial adjacency matrix A(t)_ij = ∑_e:i→ jm(e)t^w(e). For column vectors u and v, define Z_u,v(t) = ∑_n≥0a_nt^n, where a_n=∑_i,j ∑_substackγ:ileadsto j

    Exact mathematical passage
    
    Z_{u,v}(t)
    =
    \sum_{n\geq0}a_nt^n,
    
|Definition passage · 14 passages

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  • Definition passage: Weighted transfer series · Read passage · 03_weighted.tex, line 386

    [Weighted transfer series] Let G be a finite directed multigraph. Give every edge e a positive integer weight w(e) and a scalar multiplicity m(e) in a field bbk. Define the polynomial adjacency matrix A(t)_ij = ∑_e:i→ jm(e)t^w(e). For column vectors u and v, define Z_u,v(t) = ∑_n≥0a_nt^n, where a_n=∑_i,j ∑_substackγ:ileadsto j W(γ)=n u_i v_j∏_ν=1^|γ|m(e_ν). Here γ=(e_1,…,e_|γ|) is a directed walk. Vertices and edges may repeat, and the empty walk has weight zero and multiplicity one. Thus the en…

    Exact mathematical passage
    
    a_n=\sum_{i,j}\ \sum_{\substack{\gamma:i\leadsto j\\W(\gamma)=n}}
     u_i v_j\prod_{\nu=1}^{|\gamma|}m(e_\nu).
    
\Lambda_{\mathrm{split}}Definition passage · 7 passages

Search aliases: Λ_split Lambda mathrm

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  • Definition passage: Lattice packet data · Read passage · 04_arithmetic.tex, line 240

    [Lattice packet data] Let V=⊕_α∈ IV_α be a finite direct sum over K, with packet projectors E_α. Let Λ⊆ V be an O lattice. Put Λ_α=Λ∩ V_α, Λ_split=⊕_αΛ_α, and define the gluing module G_Λ, P = Λ/Λ_split. The separation weight of E_α is s_Λ(E_α) = min{s≥0:π^sE_αΛ⊆Λ}. The global separation weight is s_Λ( P)=max({0}∪{s_Λ(E_α):α∈ I}). For a finitely generated torsion O module G, write exp_π(G) for the least s such that π^sG=0.

    Exact mathematical passage
    
    \Lambda_\alpha=\Lambda\cap V_\alpha,
    \qquad
    \Lambda_{\mathrm{split}}=\bigoplus_\alpha\Lambda_\alpha,
    
\Lambda_\alphaDefinition passage · 7 passages

Search aliases: Λ_α Lambda alpha

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  • Definition passage: Lattice packet data · Read passage · 04_arithmetic.tex, line 240

    [Lattice packet data] Let V=⊕_α∈ IV_α be a finite direct sum over K, with packet projectors E_α. Let Λ⊆ V be an O lattice. Put Λ_α=Λ∩ V_α, Λ_split=⊕_αΛ_α, and define the gluing module G_Λ, P = Λ/Λ_split. The separation weight of E_α is s_Λ(E_α) = min{s≥0:π^sE_αΛ⊆Λ}. The global separation weight is s_Λ( P)=max({0}∪{s_Λ(E_α):α∈ I}). For a finitely generated torsion O module G, write exp_π(G) for the least s such that π^sG=0.

    Exact mathematical passage
    
    \Lambda_\alpha=\Lambda\cap V_\alpha,
    \qquad
    \Lambda_{\mathrm{split}}=\bigoplus_\alpha\Lambda_\alpha,
    
\nuDefinition passage · 1 passage

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  • Definition passage: Weighted transfer series · Read passage · 03_weighted.tex, line 386

    [Weighted transfer series] Let G be a finite directed multigraph. Give every edge e a positive integer weight w(e) and a scalar multiplicity m(e) in a field bbk. Define the polynomial adjacency matrix A(t)_ij = ∑_e:i→ jm(e)t^w(e). For column vectors u and v, define Z_u,v(t) = ∑_n≥0a_nt^n, where a_n=∑_i,j ∑_substackγ:ileadsto j W(γ)=n u_i v_j∏_ν=1^|γ|m(e_ν). Here γ=(e_1,…,e_|γ|) is a directed walk. Vertices and edges may repeat, and the empty walk has weight zero and multiplicity one. Thus the en…

    Exact mathematical passage
    
    a_n=\sum_{i,j}\ \sum_{\substack{\gamma:i\leadsto j\\W(\gamma)=n}}
     u_i v_j\prod_{\nu=1}^{|\gamma|}m(e_\nu).
    
\pi^sDefinition passage · 24 passages

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  • Definition passage: Separation weight · Read passage · 04_arithmetic.tex, line 181

    [Separation weight] For a rational projector E and a specified O lattice Λ, provided at least one clearing exponent exists, define s_π,Λ(E) = min{s≥0:π^sE(Λ)⊆Λ}. If the evaluated certificate arises from integral v,g and r=uπ^s with u^-1 preserving the lattice, then [source reference] gives the upper bound s_π,Λ(E)≤ s=val_π(r). Indeed, π^sE=u^-1VG preserves Λ. The minimal Lean theorem needs only the lattice action of u^-1. The bundled wrapper for lattice units records both u and u^-1. A nonzero s…

    Exact mathematical passage
    
    s_{\pi,\Lambda}(E)
    =
    \min\{s\ge0:\pi^sE(\Lambda)\subseteq\Lambda\}.
    
\rhoDefinition passage · 20 passages

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  • Definition passage: Refinement · Read passage · 02_coordinates.tex, line 35

    [Refinement] Let P=(P_α)_α∈ I and Q=(Q_β)_β∈ J be packet systems on the same module. We say that Q refines P when there is a surjection ρ:J⟶ I such that P_α=∑_ρ(β)=αQ_β for every α∈ I. The index β is then called a child of ρ(β).

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    \rho:J\longrightarrow I
    
\ldotsDefinition passage · 17 passages

Search aliases: … ldots

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  • Definition passage: Weighted transfer series · Read passage · 03_weighted.tex, line 390

    W(γ)=n u_i v_j∏_ν=1^|γ|m(e_ν). Here γ=(e_1,…,e_|γ|) is a directed walk. Vertices and edges may repeat, and the empty walk has weight zero and multiplicity one. Thus the endpoint vectors weight the start and end of each walk, rather than only selecting subsets of vertices.

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    \gamma=(e_1,\ldots,e_{|\gamma|})
\leftarrowDefinition passage · 8 passages

Search aliases: ← leftarrow

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  • Definition passage: Coordinate change across levels · Read passage · 02_coordinates.tex, line 84

    [Coordinate change across levels] For two packet systems P and Q on X, define J_ Q← P = A_ Q S_ P:X^ P⟶ X^ Q and C_ P← Q = A_ P S_ Q:X^ Q⟶ X^ P. When Q refines P, the first map resolves each coarse coordinate into its children and the second adds the children back to their parent.

    Exact mathematical passage
    
    J_{\Qcal\leftarrow\Pcal}
    =
    \Acal_{\Qcal}\Scal_{\Pcal}:X^{\Pcal}\longrightarrow X^{\Qcal}
    
\toDefinition passage · 19 passages

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  • Definition passage: Weighted transfer series · Read passage · 03_weighted.tex, line 374

    [Weighted transfer series] Let G be a finite directed multigraph. Give every edge e a positive integer weight w(e) and a scalar multiplicity m(e) in a field bbk. Define the polynomial adjacency matrix A(t)_ij = ∑_e:i→ jm(e)t^w(e). For column vectors u and v, define Z_u,v(t) = ∑_n≥0a_nt^n, where a_n=∑_i,j ∑_substackγ:ileadsto j

    Exact mathematical passage
    
    A(t)_{ij}
    =
    \sum_{e:i\to j}m(e)t^{w(e)}.
    
\inDefinition passage · 81 passages

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  • Definition passage: Packet system · Read passage · 02_coordinates.tex, line 7

    [Packet system] Let X be a module over a unital ring. A finite packet system on X is a family P=(P_α)_α∈ I ⊆End(X) of nonzero idempotents such that P_α P_β=0 when α≠β, ∑_α∈ IP_α=I_X. Write X_α=P_α X, X^ P=⊕_α∈ IX_α. The analysis and synthesis maps are A_ Px=(P_α x)_α, S_ P(x_α)_α=∑_α x_α. They are inverse isomorphisms.

    Exact mathematical passage
    
    \Pcal=(P_\alpha)_{\alpha\in I}
    \subseteq\End(X)
    
\prodDefinition passage · 3 passages

Search aliases: ∏ prod

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  • Definition passage: Weighted transfer series · Read passage · 03_weighted.tex, line 386

    [Weighted transfer series] Let G be a finite directed multigraph. Give every edge e a positive integer weight w(e) and a scalar multiplicity m(e) in a field bbk. Define the polynomial adjacency matrix A(t)_ij = ∑_e:i→ jm(e)t^w(e). For column vectors u and v, define Z_u,v(t) = ∑_n≥0a_nt^n, where a_n=∑_i,j ∑_substackγ:ileadsto j W(γ)=n u_i v_j∏_ν=1^|γ|m(e_ν). Here γ=(e_1,…,e_|γ|) is a directed walk. Vertices and edges may repeat, and the empty walk has weight zero and multiplicity one. Thus the en…

    Exact mathematical passage
    
    a_n=\sum_{i,j}\ \sum_{\substack{\gamma:i\leadsto j\\W(\gamma)=n}}
     u_i v_j\prod_{\nu=1}^{|\gamma|}m(e_\nu).
    
\prod_{\nu=1}^{|\gamma|}Definition passage · 1 passage

Search aliases: ∏_ν=1^|γ| prod nu gamma

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  • Definition passage: Weighted transfer series · Read passage · 03_weighted.tex, line 386

    [Weighted transfer series] Let G be a finite directed multigraph. Give every edge e a positive integer weight w(e) and a scalar multiplicity m(e) in a field bbk. Define the polynomial adjacency matrix A(t)_ij = ∑_e:i→ jm(e)t^w(e). For column vectors u and v, define Z_u,v(t) = ∑_n≥0a_nt^n, where a_n=∑_i,j ∑_substackγ:ileadsto j W(γ)=n u_i v_j∏_ν=1^|γ|m(e_ν). Here γ=(e_1,…,e_|γ|) is a directed walk. Vertices and edges may repeat, and the empty walk has weight zero and multiplicity one. Thus the en…

    Exact mathematical passage
    
    a_n=\sum_{i,j}\ \sum_{\substack{\gamma:i\leadsto j\\W(\gamma)=n}}
     u_i v_j\prod_{\nu=1}^{|\gamma|}m(e_\nu).
    
\sumDefinition passage · 78 passages

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  • Definition passage: Packet system · Read passage · 02_coordinates.tex, line 12

    [Packet system] Let X be a module over a unital ring. A finite packet system on X is a family P=(P_α)_α∈ I ⊆End(X) of nonzero idempotents such that P_α P_β=0 when α≠β, ∑_α∈ IP_α=I_X. Write X_α=P_α X, X^ P=⊕_α∈ IX_α. The analysis and synthesis maps are A_ Px=(P_α x)_α, S_ P(x_α)_α=∑_α x_α. They are inverse isomorphisms.

    Exact mathematical passage
    
    P_\alpha P_\beta=0
    \quad\text{when }\alpha\ne\beta,
    \qquad
    \sum_{\alpha\in I}P_\alpha=I_X.
    
\sum_{e:i\to j}Definition passage · 2 passages

Search aliases: ∑_e:i→ j sum to

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  • Definition passage: Weighted transfer series · Read passage · 03_weighted.tex, line 374

    [Weighted transfer series] Let G be a finite directed multigraph. Give every edge e a positive integer weight w(e) and a scalar multiplicity m(e) in a field bbk. Define the polynomial adjacency matrix A(t)_ij = ∑_e:i→ jm(e)t^w(e). For column vectors u and v, define Z_u,v(t) = ∑_n≥0a_nt^n, where a_n=∑_i,j ∑_substackγ:ileadsto j

    Exact mathematical passage
    
    A(t)_{ij}
    =
    \sum_{e:i\to j}m(e)t^{w(e)}.
    
\sum_{i,j}Definition passage · 1 passage

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  • Definition passage: Weighted transfer series · Read passage · 03_weighted.tex, line 386

    [Weighted transfer series] Let G be a finite directed multigraph. Give every edge e a positive integer weight w(e) and a scalar multiplicity m(e) in a field bbk. Define the polynomial adjacency matrix A(t)_ij = ∑_e:i→ jm(e)t^w(e). For column vectors u and v, define Z_u,v(t) = ∑_n≥0a_nt^n, where a_n=∑_i,j ∑_substackγ:ileadsto j W(γ)=n u_i v_j∏_ν=1^|γ|m(e_ν). Here γ=(e_1,…,e_|γ|) is a directed walk. Vertices and edges may repeat, and the empty walk has weight zero and multiplicity one. Thus the en…

    Exact mathematical passage
    
    a_n=\sum_{i,j}\ \sum_{\substack{\gamma:i\leadsto j\\W(\gamma)=n}}
     u_i v_j\prod_{\nu=1}^{|\gamma|}m(e_\nu).
    
\sum_{n\equiv j\pmod N}Definition passage · 1 passage

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  • Definition passage: Residue selector · Read passage · 02_coordinates.tex, line 374

    [Residue selector] Let R be a commutative ring and let F(z)=∑_n≥0a_nz^n∈ R[[z]]. For N≥1 and 0≤ j<N, define (P_N,jF)(z) = ∑_n≡ jpmod Na_nz^n.

    Exact mathematical passage
    
    (P_{N,j}F)(z)
    =
    \sum_{n\equiv j\pmod N}a_nz^n.
    
\sum_{n\geq0}Definition passage · 2 passages

Search aliases: ∑_n≥0 sum geq

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  • Definition passage: Residue selector · Read passage · 02_coordinates.tex, line 370

    [Residue selector] Let R be a commutative ring and let F(z)=∑_n≥0a_nz^n∈ R[[z]]. For N≥1 and 0≤ j<N, define (P_N,jF)(z) = ∑_n≡ jpmod Na_nz^n.

    Exact mathematical passage
    
    F(z)=\sum_{n\geq0}a_nz^n\in R[[z]].
    
\sum_{\substack{\gamma:i\leadsto j\\W(\gamma)=n}}Definition passage · 1 passage

Search aliases: ∑_substackγ:ileadsto j W(γ)=n sum substack gamma leadsto W gamma

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  • Definition passage: Weighted transfer series · Read passage · 03_weighted.tex, line 386

    [Weighted transfer series] Let G be a finite directed multigraph. Give every edge e a positive integer weight w(e) and a scalar multiplicity m(e) in a field bbk. Define the polynomial adjacency matrix A(t)_ij = ∑_e:i→ jm(e)t^w(e). For column vectors u and v, define Z_u,v(t) = ∑_n≥0a_nt^n, where a_n=∑_i,j ∑_substackγ:ileadsto j W(γ)=n u_i v_j∏_ν=1^|γ|m(e_ν). Here γ=(e_1,…,e_|γ|) is a directed walk. Vertices and edges may repeat, and the empty walk has weight zero and multiplicity one. Thus the en…

    Exact mathematical passage
    
    a_n=\sum_{i,j}\ \sum_{\substack{\gamma:i\leadsto j\\W(\gamma)=n}}
     u_i v_j\prod_{\nu=1}^{|\gamma|}m(e_\nu).
    
\sum_\alphaDefinition passage · 11 passages

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  • Definition passage: Packet system · Read passage · 02_coordinates.tex, line 25

    ket_system Let X be a module over a unital ring. A finite packet system on X is a family P=(P_α)_α∈ I ⊆End(X) of nonzero idempotents such that P_α P_β=0 when α≠β, ∑_α∈ IP_α=I_X. Write X_α=P_α X, X^ P=⊕_α∈ IX_α. The analysis and synthesis maps are A_ Px=(P_α x)_α, S_ P(x_α)_α=∑_α x_α. They are inverse isomorphisms.

    Exact mathematical passage
    
    \Acal_{\Pcal}x=(P_\alpha x)_\alpha,
    \qquad
    \Scal_{\Pcal}(x_\alpha)_\alpha=\sum_\alpha x_\alpha.
    
\sum_{\alpha\in I}Definition passage · 1 passage

Search aliases: ∑_α∈ I sum alpha in

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  • Definition passage: Packet system · Read passage · 02_coordinates.tex, line 12

    [Packet system] Let X be a module over a unital ring. A finite packet system on X is a family P=(P_α)_α∈ I ⊆End(X) of nonzero idempotents such that P_α P_β=0 when α≠β, ∑_α∈ IP_α=I_X. Write X_α=P_α X, X^ P=⊕_α∈ IX_α. The analysis and synthesis maps are A_ Px=(P_α x)_α, S_ P(x_α)_α=∑_α x_α. They are inverse isomorphisms.

    Exact mathematical passage
    
    P_\alpha P_\beta=0
    \quad\text{when }\alpha\ne\beta,
    \qquad
    \sum_{\alpha\in I}P_\alpha=I_X.
    
\sum_{\rho(\beta)=\alpha}Definition passage · 2 passages

Search aliases: ∑_ρ(β)=α sum rho beta alpha

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  • Definition passage: Refinement · Read passage · 02_coordinates.tex, line 39

    [Refinement] Let P=(P_α)_α∈ I and Q=(Q_β)_β∈ J be packet systems on the same module. We say that Q refines P when there is a surjection ρ:J⟶ I such that P_α=∑_ρ(β)=αQ_β for every α∈ I. The index β is then called a child of ρ(β).

    Exact mathematical passage
    
    P_\alpha=\sum_{\rho(\beta)=\alpha}Q_\beta
    
\capDefinition passage · 7 passages

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  • Definition passage: Lattice packet data · Read passage · 04_arithmetic.tex, line 240

    [Lattice packet data] Let V=⊕_α∈ IV_α be a finite direct sum over K, with packet projectors E_α. Let Λ⊆ V be an O lattice. Put Λ_α=Λ∩ V_α, Λ_split=⊕_αΛ_α, and define the gluing module G_Λ, P = Λ/Λ_split. The separation weight of E_α is s_Λ(E_α) = min{s≥0:π^sE_αΛ⊆Λ}. The global separation weight is s_Λ( P)=max({0}∪{s_Λ(E_α):α∈ I}). For a finitely generated torsion O module G, write exp_π(G) for the least s such that π^sG=0.

    Exact mathematical passage
    
    \Lambda_\alpha=\Lambda\cap V_\alpha,
    \qquad
    \Lambda_{\mathrm{split}}=\bigoplus_\alpha\Lambda_\alpha,
    
\cupDefinition passage · 4 passages

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  • Definition passage: Lattice packet data · Read passage · 04_arithmetic.tex, line 258

    et Λ⊆ V be an O lattice. Put Λ_α=Λ∩ V_α, Λ_split=⊕_αΛ_α, and define the gluing module G_Λ, P = Λ/Λ_split. The separation weight of E_α is s_Λ(E_α) = min{s≥0:π^sE_αΛ⊆Λ}. The global separation weight is s_Λ( P)=max({0}∪{s_Λ(E_α):α∈ I}). For a finitely generated torsion O module G, write exp_π(G) for the least s such that π^sG=0.

    Exact mathematical passage
    
    s_\Lambda(\Pcal)=\max\bigl(\{0\}\cup\{s_\Lambda(E_\alpha):\alpha\in I\}\bigr).
    
\neDefinition passage · 23 passages

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  • Definition passage: Packet system · Read passage · 02_coordinates.tex, line 12

    [Packet system] Let X be a module over a unital ring. A finite packet system on X is a family P=(P_α)_α∈ I ⊆End(X) of nonzero idempotents such that P_α P_β=0 when α≠β, ∑_α∈ IP_α=I_X. Write X_α=P_α X, X^ P=⊕_α∈ IX_α. The analysis and synthesis maps are A_ Px=(P_α x)_α, S_ P(x_α)_α=∑_α x_α. They are inverse isomorphisms.

    Exact mathematical passage
    
    P_\alpha P_\beta=0
    \quad\text{when }\alpha\ne\beta,
    \qquad
    \sum_{\alpha\in I}P_\alpha=I_X.
    
\equivDefinition passage · 23 passages

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  • Definition passage: Residue selector · Read passage · 02_coordinates.tex, line 374

    [Residue selector] Let R be a commutative ring and let F(z)=∑_n≥0a_nz^n∈ R[[z]]. For N≥1 and 0≤ j<N, define (P_N,jF)(z) = ∑_n≡ jpmod Na_nz^n.

    Exact mathematical passage
    
    (P_{N,j}F)(z)
    =
    \sum_{n\equiv j\pmod N}a_nz^n.
    
\leDefinition passage · 17 passages

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  • Definition passage: Separation weight · Read passage · 04_arithmetic.tex, line 189

    ight] For a rational projector E and a specified O lattice Λ, provided at least one clearing exponent exists, define s_π,Λ(E) = min{s≥0:π^sE(Λ)⊆Λ}. If the evaluated certificate arises from integral v,g and r=uπ^s with u^-1 preserving the lattice, then [source reference] gives the upper bound s_π,Λ(E)≤ s=val_π(r). Indeed, π^sE=u^-1VG preserves Λ. The minimal Lean theorem needs only the lattice action of u^-1. The bundled wrapper for lattice units records both u and u^-1. A nonzero scalar in the f…

    Exact mathematical passage
    
    s_{\pi,\Lambda}(E)\le s=\val_\pi(r).
    
\leqDefinition passage · 23 passages

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  • Definition passage: Residue selector · Read passage · 02_coordinates.tex, line 373

    [Residue selector] Let R be a commutative ring and let F(z)=∑_n≥0a_nz^n∈ R[[z]]. For N≥1 and 0≤ j<N, define (P_N,jF)(z) = ∑_n≡ jpmod Na_nz^n.

    Exact mathematical passage
    0\leq j<N
\geDefinition passage · 10 passages

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  • Definition passage: Separation weight · Read passage · 04_arithmetic.tex, line 181

    [Separation weight] For a rational projector E and a specified O lattice Λ, provided at least one clearing exponent exists, define s_π,Λ(E) = min{s≥0:π^sE(Λ)⊆Λ}. If the evaluated certificate arises from integral v,g and r=uπ^s with u^-1 preserving the lattice, then [source reference] gives the upper bound s_π,Λ(E)≤ s=val_π(r). Indeed, π^sE=u^-1VG preserves Λ. The minimal Lean theorem needs only the lattice action of u^-1. The bundled wrapper for lattice units records both u and u^-1. A nonzero s…

    Exact mathematical passage
    
    s_{\pi,\Lambda}(E)
    =
    \min\{s\ge0:\pi^sE(\Lambda)\subseteq\Lambda\}.
    
\geqDefinition passage · 21 passages

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  • Definition passage: Residue selector · Read passage · 02_coordinates.tex, line 370

    [Residue selector] Let R be a commutative ring and let F(z)=∑_n≥0a_nz^n∈ R[[z]]. For N≥1 and 0≤ j<N, define (P_N,jF)(z) = ∑_n≡ jpmod Na_nz^n.

    Exact mathematical passage
    
    F(z)=\sum_{n\geq0}a_nz^n\in R[[z]].
    
\subseteqDefinition passage · 12 passages

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  • Definition passage: Packet system · Read passage · 02_coordinates.tex, line 7

    [Packet system] Let X be a module over a unital ring. A finite packet system on X is a family P=(P_α)_α∈ I ⊆End(X) of nonzero idempotents such that P_α P_β=0 when α≠β, ∑_α∈ IP_α=I_X. Write X_α=P_α X, X^ P=⊕_α∈ IX_α. The analysis and synthesis maps are A_ Px=(P_α x)_α, S_ P(x_α)_α=∑_α x_α. They are inverse isomorphisms.

    Exact mathematical passage
    
    \Pcal=(P_\alpha)_{\alpha\in I}
    \subseteq\End(X)
    
\supseteqDefinition passage · 1 passage

Search aliases: ⊇ supseteq

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  • Definition passage: Complete multiplicative filtration · Read passage · 03_weighted.tex, line 7

    [Complete multiplicative filtration] A complete filtered algebra is a unital algebra B with a decreasing sequence of two-sided ideals B=F^0 B⊇ F^1 B⊇ F^2 B⊇⋯ such that F^r B F^s B⊆ F^r+s B, ⋂_L≥0F^L B=0, and the natural map B⟶varprojlim_L B/F^L B is an isomorphism. A transfer term N_e has a declared positive integer weight w(e)∈ Z_>0 when N_e∈ F^w(e) B.

    Exact mathematical passage
    
    \Bcal=F^0\Bcal\supseteq F^1\Bcal\supseteq F^2\Bcal\supseteq\cdots
    
\bigoplusDefinition passage · 12 passages

Search aliases: ⊕ bigoplus

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  • Definition passage: Packet system · Read passage · 02_coordinates.tex, line 19

    [Packet system] Let X be a module over a unital ring. A finite packet system on X is a family P=(P_α)_α∈ I ⊆End(X) of nonzero idempotents such that P_α P_β=0 when α≠β, ∑_α∈ IP_α=I_X. Write X_α=P_α X, X^ P=⊕_α∈ IX_α. The analysis and synthesis maps are A_ Px=(P_α x)_α, S_ P(x_α)_α=∑_α x_α. They are inverse isomorphisms.

    Exact mathematical passage
    
    X_\alpha=P_\alpha X,
    \qquad
    X^{\Pcal}=\bigoplus_{\alpha\in I}X_\alpha.
    
\bigoplus_\alphaDefinition passage · 4 passages

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  • Definition passage: Lattice packet data · Read passage · 04_arithmetic.tex, line 240

    [Lattice packet data] Let V=⊕_α∈ IV_α be a finite direct sum over K, with packet projectors E_α. Let Λ⊆ V be an O lattice. Put Λ_α=Λ∩ V_α, Λ_split=⊕_αΛ_α, and define the gluing module G_Λ, P = Λ/Λ_split. The separation weight of E_α is s_Λ(E_α) = min{s≥0:π^sE_αΛ⊆Λ}. The global separation weight is s_Λ( P)=max({0}∪{s_Λ(E_α):α∈ I}). For a finitely generated torsion O module G, write exp_π(G) for the least s such that π^sG=0.

    Exact mathematical passage
    
    \Lambda_\alpha=\Lambda\cap V_\alpha,
    \qquad
    \Lambda_{\mathrm{split}}=\bigoplus_\alpha\Lambda_\alpha,
    
\bigoplus_{\alpha\in I}Definition passage · 3 passages

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  • Definition passage: Packet system · Read passage · 02_coordinates.tex, line 19

    [Packet system] Let X be a module over a unital ring. A finite packet system on X is a family P=(P_α)_α∈ I ⊆End(X) of nonzero idempotents such that P_α P_β=0 when α≠β, ∑_α∈ IP_α=I_X. Write X_α=P_α X, X^ P=⊕_α∈ IX_α. The analysis and synthesis maps are A_ Px=(P_α x)_α, S_ P(x_α)_α=∑_α x_α. They are inverse isomorphisms.

    Exact mathematical passage
    
    X_\alpha=P_\alpha X,
    \qquad
    X^{\Pcal}=\bigoplus_{\alpha\in I}X_\alpha.
    
\bigcapDefinition passage · 2 passages

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  • Definition passage: Complete multiplicative filtration · Read passage · 03_weighted.tex, line 11

    [Complete multiplicative filtration] A complete filtered algebra is a unital algebra B with a decreasing sequence of two-sided ideals B=F^0 B⊇ F^1 B⊇ F^2 B⊇⋯ such that F^r B F^s B⊆ F^r+s B, ⋂_L≥0F^L B=0, and the natural map B⟶varprojlim_L B/F^L B is an isomorphism. A transfer term N_e has a declared positive integer weight w(e)∈ Z_>0 when N_e∈ F^w(e) B.

    Exact mathematical passage
    
    F^r\Bcal\,F^s\Bcal\subseteq F^{r+s}\Bcal,
    \qquad
    \bigcap_{L\geq0}F^L\Bcal=0,
    
\bigcap_{L\geq0}Definition passage · 2 passages

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  • Definition passage: Complete multiplicative filtration · Read passage · 03_weighted.tex, line 11

    [Complete multiplicative filtration] A complete filtered algebra is a unital algebra B with a decreasing sequence of two-sided ideals B=F^0 B⊇ F^1 B⊇ F^2 B⊇⋯ such that F^r B F^s B⊆ F^r+s B, ⋂_L≥0F^L B=0, and the natural map B⟶varprojlim_L B/F^L B is an isomorphism. A transfer term N_e has a declared positive integer weight w(e)∈ Z_>0 when N_e∈ F^w(e) B.

    Exact mathematical passage
    
    F^r\Bcal\,F^s\Bcal\subseteq F^{r+s}\Bcal,
    \qquad
    \bigcap_{L\geq0}F^L\Bcal=0,
    
\cdotsDefinition passage · 14 passages

Search aliases: ⋯ cdots

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  • Definition passage: Complete multiplicative filtration · Read passage · 03_weighted.tex, line 7

    [Complete multiplicative filtration] A complete filtered algebra is a unital algebra B with a decreasing sequence of two-sided ideals B=F^0 B⊇ F^1 B⊇ F^2 B⊇⋯ such that F^r B F^s B⊆ F^r+s B, ⋂_L≥0F^L B=0, and the natural map B⟶varprojlim_L B/F^L B is an isomorphism. A transfer term N_e has a declared positive integer weight w(e)∈ Z_>0 when N_e∈ F^w(e) B.

    Exact mathematical passage
    
    \Bcal=F^0\Bcal\supseteq F^1\Bcal\supseteq F^2\Bcal\supseteq\cdots
    
\longrightarrowDefinition passage · 13 passages

Search aliases: ⟶ longrightarrow

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  • Definition passage: Refinement · Read passage · 02_coordinates.tex, line 35

    [Refinement] Let P=(P_α)_α∈ I and Q=(Q_β)_β∈ J be packet systems on the same module. We say that Q refines P when there is a surjection ρ:J⟶ I such that P_α=∑_ρ(β)=αQ_β for every α∈ I. The index β is then called a child of ρ(β).

    Exact mathematical passage
    
    \rho:J\longrightarrow I
    
\bmodIntroduction passage · 8 passages

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  • Introduction passage · visual_atlas.tex, line 103

    vpage5The operator changes coordinates tooMODEL A / COHERENCE AND NATURALITYTraditional paper: Theorem 3.5 (p. 4), Theorem 3.8 (p. 6) Use a finite periodic carrier X=QQ^8 for this example. Let Se_j=e_j+1bmod8 and let T=I+2S+S^2. This is a concrete cyclic model, not an unannounced boundary convention for the finitely supported signal on V20. Write R_N for the permutation that groups coordinates in increasing residue order modulo N.

    Exact mathematical passage
    Se_j=e_{j+1\bmod8}
dIntroduction passage · 30 passages

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  • Introduction passage · visual_atlas.tex, line 487

    If w denotes one delay on a phase sequence, the filter becomes y_rm even y_rm odd = underbrace1+w · 2w 2 · 1+w_H_rm phase(w) e o. The cross-phase delay is not optional. A unit shift sends an odd sample to the next even position, while it sends an even sample to the odd position in the same phase block.

    Exact mathematical passage
    
    \begin{pmatrix}y_{\rm even}\\y_{\rm odd}\end{pmatrix}
    =
    \underbrace{\begin{pmatrix}1+w&2w\\2&1+w\end{pmatrix}}_{H_{\rm phase}(w)}
    \begin{pmatrix}e\\o\end{pmatrix}.
    
e_jIntroduction passage · 3 passages

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  • Introduction passage · visual_atlas.tex, line 103

    vpage5The operator changes coordinates tooMODEL A / COHERENCE AND NATURALITYTraditional paper: Theorem 3.5 (p. 4), Theorem 3.8 (p. 6) Use a finite periodic carrier X=QQ^8 for this example. Let Se_j=e_j+1bmod8 and let T=I+2S+S^2. This is a concrete cyclic model, not an unannounced boundary convention for the finitely supported signal on V20. Write R_N for the permutation that groups coordinates in increasing residue order modulo N.

    Exact mathematical passage
    Se_j=e_{j+1\bmod8}
e_{j+1\bmod8}Introduction passage · 1 passage

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  • Introduction passage · visual_atlas.tex, line 103

    vpage5The operator changes coordinates tooMODEL A / COHERENCE AND NATURALITYTraditional paper: Theorem 3.5 (p. 4), Theorem 3.8 (p. 6) Use a finite periodic carrier X=QQ^8 for this example. Let Se_j=e_j+1bmod8 and let T=I+2S+S^2. This is a concrete cyclic model, not an unannounced boundary convention for the finitely supported signal on V20. Write R_N for the permutation that groups coordinates in increasing residue order modulo N.

    Exact mathematical passage
    Se_j=e_{j+1\bmod8}
HIntroduction passage · 20 passages

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  • Introduction passage · visual_atlas.tex, line 487

    If w denotes one delay on a phase sequence, the filter becomes y_rm even y_rm odd = underbrace1+w · 2w 2 · 1+w_H_rm phase(w) e o. The cross-phase delay is not optional. A unit shift sends an odd sample to the next even position, while it sends an even sample to the odd position in the same phase block.

    Exact mathematical passage
    
    \begin{pmatrix}y_{\rm even}\\y_{\rm odd}\end{pmatrix}
    =
    \underbrace{\begin{pmatrix}1+w&2w\\2&1+w\end{pmatrix}}_{H_{\rm phase}(w)}
    \begin{pmatrix}e\\o\end{pmatrix}.
    
hIntroduction passage · 9 passages

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  • Introduction passage · visual_atlas.tex, line 487

    If w denotes one delay on a phase sequence, the filter becomes y_rm even y_rm odd = underbrace1+w · 2w 2 · 1+w_H_rm phase(w) e o. The cross-phase delay is not optional. A unit shift sends an odd sample to the next even position, while it sends an even sample to the odd position in the same phase block.

    Exact mathematical passage
    
    \begin{pmatrix}y_{\rm even}\\y_{\rm odd}\end{pmatrix}
    =
    \underbrace{\begin{pmatrix}1+w&2w\\2&1+w\end{pmatrix}}_{H_{\rm phase}(w)}
    \begin{pmatrix}e\\o\end{pmatrix}.
    
H_{\rm phase}Introduction passage · 1 passage

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  • Introduction passage · visual_atlas.tex, line 487

    If w denotes one delay on a phase sequence, the filter becomes y_rm even y_rm odd = underbrace1+w · 2w 2 · 1+w_H_rm phase(w) e o. The cross-phase delay is not optional. A unit shift sends an odd sample to the next even position, while it sends an even sample to the odd position in the same phase block.

    Exact mathematical passage
    
    \begin{pmatrix}y_{\rm even}\\y_{\rm odd}\end{pmatrix}
    =
    \underbrace{\begin{pmatrix}1+w&2w\\2&1+w\end{pmatrix}}_{H_{\rm phase}(w)}
    \begin{pmatrix}e\\o\end{pmatrix}.
    
oIntroduction passage · 5 passages

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  • Introduction passage · visual_atlas.tex, line 487

    If w denotes one delay on a phase sequence, the filter becomes y_rm even y_rm odd = underbrace1+w · 2w 2 · 1+w_H_rm phase(w) e o. The cross-phase delay is not optional. A unit shift sends an odd sample to the next even position, while it sends an even sample to the odd position in the same phase block.

    Exact mathematical passage
    
    \begin{pmatrix}y_{\rm even}\\y_{\rm odd}\end{pmatrix}
    =
    \underbrace{\begin{pmatrix}1+w&2w\\2&1+w\end{pmatrix}}_{H_{\rm phase}(w)}
    \begin{pmatrix}e\\o\end{pmatrix}.
    
pIntroduction passage · 48 passages

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  • Introduction passage · visual_atlas.tex, line 487

    If w denotes one delay on a phase sequence, the filter becomes y_rm even y_rm odd = underbrace1+w · 2w 2 · 1+w_H_rm phase(w) e o. The cross-phase delay is not optional. A unit shift sends an odd sample to the next even position, while it sends an even sample to the odd position in the same phase block.

    Exact mathematical passage
    
    \begin{pmatrix}y_{\rm even}\\y_{\rm odd}\end{pmatrix}
    =
    \underbrace{\begin{pmatrix}1+w&2w\\2&1+w\end{pmatrix}}_{H_{\rm phase}(w)}
    \begin{pmatrix}e\\o\end{pmatrix}.
    
\QQIntroduction passage · 2 passages

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  • Introduction passage · visual_atlas.tex, line 103

    vpage5The operator changes coordinates tooMODEL A / COHERENCE AND NATURALITYTraditional paper: Theorem 3.5 (p. 4), Theorem 3.8 (p. 6) Use a finite periodic carrier X=QQ^8 for this example. Let Se_j=e_j+1bmod8 and let T=I+2S+S^2. This is a concrete cyclic model, not an unannounced boundary convention for the finitely supported signal on V20. Write R_N for the permutation that groups coordinates in increasing residue order modulo N.

    Exact mathematical passage
    X=\QQ^8
\QQ^8Introduction passage · 1 passage

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  • Introduction passage · visual_atlas.tex, line 103

    vpage5The operator changes coordinates tooMODEL A / COHERENCE AND NATURALITYTraditional paper: Theorem 3.5 (p. 4), Theorem 3.8 (p. 6) Use a finite periodic carrier X=QQ^8 for this example. Let Se_j=e_j+1bmod8 and let T=I+2S+S^2. This is a concrete cyclic model, not an unannounced boundary convention for the finitely supported signal on V20. Write R_N for the permutation that groups coordinates in increasing residue order modulo N.

    Exact mathematical passage
    X=\QQ^8
R_NIntroduction passage · 2 passages

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  • Introduction passage · visual_atlas.tex, line 107

    vpage5The operator changes coordinates tooMODEL A / COHERENCE AND NATURALITYTraditional paper: Theorem 3.5 (p. 4), Theorem 3.8 (p. 6) Use a finite periodic carrier X=QQ^8 for this example. Let Se_j=e_j+1bmod8 and let T=I+2S+S^2. This is a concrete cyclic model, not an unannounced boundary convention for the finitely supported signal on V20. Write R_N for the permutation that groups coordinates in increasing residue order modulo N.

    Exact mathematical passage
    R_N
\rmIntroduction passage · 6 passages

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  • Introduction passage · visual_atlas.tex, line 487

    If w denotes one delay on a phase sequence, the filter becomes y_rm even y_rm odd = underbrace1+w · 2w 2 · 1+w_H_rm phase(w) e o. The cross-phase delay is not optional. A unit shift sends an odd sample to the next even position, while it sends an even sample to the odd position in the same phase block.

    Exact mathematical passage
    
    \begin{pmatrix}y_{\rm even}\\y_{\rm odd}\end{pmatrix}
    =
    \underbrace{\begin{pmatrix}1+w&2w\\2&1+w\end{pmatrix}}_{H_{\rm phase}(w)}
    \begin{pmatrix}e\\o\end{pmatrix}.
    
SIntroduction passage · 14 passages

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  • Introduction passage · visual_atlas.tex, line 103

    vpage5The operator changes coordinates tooMODEL A / COHERENCE AND NATURALITYTraditional paper: Theorem 3.5 (p. 4), Theorem 3.8 (p. 6) Use a finite periodic carrier X=QQ^8 for this example. Let Se_j=e_j+1bmod8 and let T=I+2S+S^2. This is a concrete cyclic model, not an unannounced boundary convention for the finitely supported signal on V20. Write R_N for the permutation that groups coordinates in increasing residue order modulo N.

    Exact mathematical passage
    Se_j=e_{j+1\bmod8}
S^2Introduction passage · 1 passage

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  • Introduction passage · visual_atlas.tex, line 104

    vpage5The operator changes coordinates tooMODEL A / COHERENCE AND NATURALITYTraditional paper: Theorem 3.5 (p. 4), Theorem 3.8 (p. 6) Use a finite periodic carrier X=QQ^8 for this example. Let Se_j=e_j+1bmod8 and let T=I+2S+S^2. This is a concrete cyclic model, not an unannounced boundary convention for the finitely supported signal on V20. Write R_N for the permutation that groups coordinates in increasing residue order modulo N.

    Exact mathematical passage
    
    T=I+2S+S^2.
    
yIntroduction passage · 36 passages

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  • Introduction passage · visual_atlas.tex, line 487

    If w denotes one delay on a phase sequence, the filter becomes y_rm even y_rm odd = underbrace1+w · 2w 2 · 1+w_H_rm phase(w) e o. The cross-phase delay is not optional. A unit shift sends an odd sample to the next even position, while it sends an even sample to the odd position in the same phase block.

    Exact mathematical passage
    
    \begin{pmatrix}y_{\rm even}\\y_{\rm odd}\end{pmatrix}
    =
    \underbrace{\begin{pmatrix}1+w&2w\\2&1+w\end{pmatrix}}_{H_{\rm phase}(w)}
    \begin{pmatrix}e\\o\end{pmatrix}.
    
y_{\rm even}Introduction passage · 3 passages

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  • Introduction passage · visual_atlas.tex, line 487

    If w denotes one delay on a phase sequence, the filter becomes y_rm even y_rm odd = underbrace1+w · 2w 2 · 1+w_H_rm phase(w) e o. The cross-phase delay is not optional. A unit shift sends an odd sample to the next even position, while it sends an even sample to the odd position in the same phase block.

    Exact mathematical passage
    
    \begin{pmatrix}y_{\rm even}\\y_{\rm odd}\end{pmatrix}
    =
    \underbrace{\begin{pmatrix}1+w&2w\\2&1+w\end{pmatrix}}_{H_{\rm phase}(w)}
    \begin{pmatrix}e\\o\end{pmatrix}.
    
y_{\rm odd}Introduction passage · 3 passages

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  • Introduction passage · visual_atlas.tex, line 487

    If w denotes one delay on a phase sequence, the filter becomes y_rm even y_rm odd = underbrace1+w · 2w 2 · 1+w_H_rm phase(w) e o. The cross-phase delay is not optional. A unit shift sends an odd sample to the next even position, while it sends an even sample to the odd position in the same phase block.

    Exact mathematical passage
    
    \begin{pmatrix}y_{\rm even}\\y_{\rm odd}\end{pmatrix}
    =
    \underbrace{\begin{pmatrix}1+w&2w\\2&1+w\end{pmatrix}}_{H_{\rm phase}(w)}
    \begin{pmatrix}e\\o\end{pmatrix}.
    
*Use in source · 1 passage

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  • Use in source · finite_polyphase_filter.tex, line 15

    5000,3.60000) rectangle ++(0.85000,0.62000); node[] at (2.97500,3.91000) 4; draw[fill=black!10,draw=black!45,line width=.35pt,] (3.40000,3.60000) rectangle ++(0.85000,0.62000); node[] at (3.82500,3.91000) 5; draw[fill=black!25,draw=black!45,line width=.35pt,] (4.25000,3.60000) rectangle ++(0.85000,0.62000); node[] at (4.67500,3.91000) 6; node[anchor=east] at (-0.15000,2.97000) h*x; draw[fill=black!25,draw=black!45,line width=.35pt,] (0.00000,2.67000) rectangle ++(0.85000,0.62000); node[] at (0.4…

    Exact mathematical passage
    h*x
\mathbf1Use in source · 2 passages

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  • Use in source · Read passage · 03_weighted.tex, line 499

    [Automatic finite-graph transfer-zeta rationality] Assume the vertex and edge sets are finite and every edge has positive integer weight. For every n, exact enumeration of edge tuples of lengths at most n, followed by endpoint and total-weight filtering, returns a_n(s,t). These coefficients obey the recurrence obtained by removing the first edge a_n(s,t) = 1_s=t, n=0 +∑_substacke: source(e)=s w(e)≤ n a_n-w(e)(target(e),t). Let T(t)=I-A(t), Q(t)=det T(t), P_s,t(t)=adj(T(t))_s,t. Then Q(0)=1, henc…

    Exact mathematical passage
    
    a_n(s,t)
    =
    \mathbf 1_{s=t,\,n=0}
    +\sum_{\substack{e:\,\operatorname{source}(e)=s\\w(e)\le n}}
    a_{n-w(e)}(\operatorname{target}(e),t).
    
\mathbf1_{s=t,\,n=0}Use in source · 2 passages

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  • Use in source · Read passage · 03_weighted.tex, line 499

    [Automatic finite-graph transfer-zeta rationality] Assume the vertex and edge sets are finite and every edge has positive integer weight. For every n, exact enumeration of edge tuples of lengths at most n, followed by endpoint and total-weight filtering, returns a_n(s,t). These coefficients obey the recurrence obtained by removing the first edge a_n(s,t) = 1_s=t, n=0 +∑_substacke: source(e)=s w(e)≤ n a_n-w(e)(target(e),t). Let T(t)=I-A(t), Q(t)=det T(t), P_s,t(t)=adj(T(t))_s,t. Then Q(0)=1, henc…

    Exact mathematical passage
    
    a_n(s,t)
    =
    \mathbf 1_{s=t,\,n=0}
    +\sum_{\substack{e:\,\operatorname{source}(e)=s\\w(e)\le n}}
    a_{n-w(e)}(\operatorname{target}(e),t).
    
\mathcal AUse in source · 3 passages

Search aliases: A mathcal

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  • Use in source · visual_atlas.tex, line 27

    A_N, S_N · Split into range-restricted packet vectors, then sum them. · A permutation/interleaving of eight coordinates.

    Exact mathematical passage
    \mathcal A_N,\mathcal S_N
A^2Use in source · 4 passages

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  • Use in source · Read passage · 04_arithmetic.tex, line 610

    Consider the integral involution A= 1 · 1 0 · -1 , A^2=I. Over a field of characteristic different from two, its sign projectors are E_+=fracI+A2 = 1 · 1/2

    Exact mathematical passage
    
    A=
    \begin{pmatrix}
    1&1\\
    0&-1
    \end{pmatrix},
    \qquad
    A^2=I.
    
a^2Use in source · 1 passage

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  • Use in source · visual_atlas.tex, line 207

    vfig[.97]weighted_word_cutoff platecaptionAll nonzero retained terms of the signed inverse sum, followed by the first discarded nonzero word. The empty word contributes I. Other words of weight below five can still be zero because a^2=b^2=0.

    Exact mathematical passage
    a^2=b^2=0
A^{2k}Use in source · 1 passage

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  • Use in source · visual_atlas.tex, line 260

    In this particular model, A^2=8I. Therefore v_2(A^2k)=3k, v_2(A^2k+1)=3k+1, where the matrix valuation means the minimum entry valuation. Three geometric terms leave a residual of valuation four and do not suffice modulo 32. Four terms leave valuation six and do suffice.

    Exact mathematical passage
    
    v_2(A^{2k})=3k,\qquad v_2(A^{2k+1})=3k+1,
    
A^{2k+1}Use in source · 1 passage

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  • Use in source · visual_atlas.tex, line 260

    In this particular model, A^2=8I. Therefore v_2(A^2k)=3k, v_2(A^2k+1)=3k+1, where the matrix valuation means the minimum entry valuation. Three geometric terms leave a residual of valuation four and do not suffice modulo 32. Four terms leave valuation six and do suffice.

    Exact mathematical passage
    
    v_2(A^{2k})=3k,\qquad v_2(A^{2k+1})=3k+1,
    
A^NUse in source · 2 passages

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  • Use in source · Read passage · 03_weighted.tex, line 328

    W(γ)<LA_γ. Lean proves directly that q_L(S^pr_L,N) equals the mapped geometric inverse whenever q_L(A^N)=0, and hence is a two-sided inverse of q_L(I+A), where A=∑_eA_e=D^-1H. With the supplied two-sided inverse D^-1 of D, this gives the explicit two-sided inverse q_L (S^pr_L,ND^-1) of q_L(D+H). If every edge weight is at least m and L≤ mN, then the nilpotence condition follows from the filtration data because m|γ|≤ W(γ). For m>0, the executable choice N=lceil L/mrceil satisfies L≤ mN. This elem…

    Exact mathematical passage
    q_L(A^N)=0
A^rUse in source · 1 passage

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  • Use in source · Read passage · 03_weighted.tex, line 277

    [Certified weighted inverse] Let R be a possibly noncommutative ring, let D^-1 be a supplied two-sided inverse of D, and put A=D^-1H. [label=(alph*)] item If A^r=0, then D+H has the two-sided inverse (D+H)^-1=(∑_k=0^r-1(-A)^k)D^-1. item If R is a complete normed ring and lVert ArVert<1, then ∑_k≥0(-A)^k converges and (D+H)^-1=(∑_k≥0(-A)^k)D^-1.

    Exact mathematical passage
    A^r=0
a_0Use in source · 1 passage

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  • Use in source · visual_atlas.tex, line 311

    From QZ_0,1=2t^2 one obtains a_0=a_1=0, a_2=2, a_n=a_n-1+2a_n-3 (n≥3). The numerator is responsible for the initial exception. Omitting it would incorrectly force the entire series to vanish.

    Exact mathematical passage
    
    a_0=a_1=0,\quad a_2=2,\qquad a_n=a_{n-1}+2a_{n-3}\quad(n\ge3).
    
a_1Use in source · 3 passages

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  • Use in source · Read passage · 04_arithmetic.tex, line 289

    _packet, the map Φ:G_Λ, P ⟶ ⊕_α∈ IE_αΛ/Λ_α, [x]⟼(E_α x+Λ_α)_α is injective, and every coordinate projection of its image is surjective. We also have exp_π(G_Λ, P) = s_Λ( P). If G_Λ, P ≅ ⊕_j=1^r O/π^a_j O with a_1≤⋯≤ a_r, then s_Λ( P)=max({0}∪{a_j:1≤ j≤ r}).

    Exact mathematical passage
    a_1\leq\cdots\leq a_r
\mathcal A_2Use in source · 1 passage

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  • Use in source · visual_atlas.tex, line 87

    Define X_N^rm pkt=⊕_j P_N,jX, A_Nx=(P_N,jx)_j, S_N(x_j)_j=∑_jx_j. Completeness and mutual annihilation give both inverse laws. Consequently, J= A_4 S_2, C= A_2 S_4, CJ=I, JC=I. The apparently larger list of fine packets simply has smaller individual packet spaces.

    Exact mathematical passage
    
    J=\mathcal A_4\mathcal S_2,\qquad C=\mathcal A_2\mathcal S_4,
    \qquad CJ=I,\quad JC=I.
    
a_2Use in source · 1 passage

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  • Use in source · visual_atlas.tex, line 311

    From QZ_0,1=2t^2 one obtains a_0=a_1=0, a_2=2, a_n=a_n-1+2a_n-3 (n≥3). The numerator is responsible for the initial exception. Omitting it would incorrectly force the entire series to vanish.

    Exact mathematical passage
    
    a_0=a_1=0,\quad a_2=2,\qquad a_n=a_{n-1}+2a_{n-3}\quad(n\ge3).
    
\mathcal A_4Use in source · 1 passage

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  • Use in source · visual_atlas.tex, line 87

    Define X_N^rm pkt=⊕_j P_N,jX, A_Nx=(P_N,jx)_j, S_N(x_j)_j=∑_jx_j. Completeness and mutual annihilation give both inverse laws. Consequently, J= A_4 S_2, C= A_2 S_4, CJ=I, JC=I. The apparently larger list of fine packets simply has smaller individual packet spaces.

    Exact mathematical passage
    
    J=\mathcal A_4\mathcal S_2,\qquad C=\mathcal A_2\mathcal S_4,
    \qquad CJ=I,\quad JC=I.
    
a_5Use in source · 1 passage

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  • Use in source · zeta_recurrence.tex, line 57

    e ++(0.87000,0.65000); node[] at (10.87500,2.07500) 12; draw[fill=black!20,draw=black!45,line width=.35pt,] (10.44000,1.00000) rectangle ++(0.87000,0.65000); node[] at (10.87500,1.32500) 218; node[anchor=east] at (-0.15000,2.07500) n; node[anchor=east] at (-0.15000,1.32500) a_n; node[] at (5.65000,3.10000) Z_0,1(t)=dfrac2t^21-t-2t^3; node[] at (5.65000,0.00000) a_8=a_7+2a_5=14+2·6=26;

    Exact mathematical passage
    a_8=a_7+2a_5=14+2\cdot6=26
a_7Use in source · 1 passage

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  • Use in source · zeta_recurrence.tex, line 57

    e ++(0.87000,0.65000); node[] at (10.87500,2.07500) 12; draw[fill=black!20,draw=black!45,line width=.35pt,] (10.44000,1.00000) rectangle ++(0.87000,0.65000); node[] at (10.87500,1.32500) 218; node[anchor=east] at (-0.15000,2.07500) n; node[anchor=east] at (-0.15000,1.32500) a_n; node[] at (5.65000,3.10000) Z_0,1(t)=dfrac2t^21-t-2t^3; node[] at (5.65000,0.00000) a_8=a_7+2a_5=14+2·6=26;

    Exact mathematical passage
    a_8=a_7+2a_5=14+2\cdot6=26
a_8Use in source · 1 passage

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  • Use in source · zeta_recurrence.tex, line 57

    e ++(0.87000,0.65000); node[] at (10.87500,2.07500) 12; draw[fill=black!20,draw=black!45,line width=.35pt,] (10.44000,1.00000) rectangle ++(0.87000,0.65000); node[] at (10.87500,1.32500) 218; node[anchor=east] at (-0.15000,2.07500) n; node[anchor=east] at (-0.15000,1.32500) a_n; node[] at (5.65000,3.10000) Z_0,1(t)=dfrac2t^21-t-2t^3; node[] at (5.65000,0.00000) a_8=a_7+2a_5=14+2·6=26;

    Exact mathematical passage
    a_8=a_7+2a_5=14+2\cdot6=26
A_eUse in source · 5 passages

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  • Use in source · Read passage · 03_weighted.tex, line 48

    [Weighted inverse] Let B be a complete filtered algebra. Let D∈ B be invertible with D,D^-1∈ F^0 B. Let E be a finite set and suppose T=D+∑_e∈ EN_e, N_e∈ F^w(e) B, w(e)≥1. Set A_e=D^-1N_e. For a word γ=(e_1,…,e_r), write A_γ=A_e_r⋯ A_e_1, W(γ)=∑_j=1^rw(e_j). The empty word has weight zero and contributes the identity. Then T is invertible and T^-1 = ∑_γ(-1)^|γ|A_γ D^-1. The series converges in the filtration, and the term indexed by γ belongs to F^W(γ) B.

    Exact mathematical passage
    
    A_e=D^{-1}N_e.
    
A_{e_1}Use in source · 2 passages

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  • Use in source · Read passage · 03_weighted.tex, line 52

    [Weighted inverse] Let B be a complete filtered algebra. Let D∈ B be invertible with D,D^-1∈ F^0 B. Let E be a finite set and suppose T=D+∑_e∈ EN_e, N_e∈ F^w(e) B, w(e)≥1. Set A_e=D^-1N_e. For a word γ=(e_1,…,e_r), write A_γ=A_e_r⋯ A_e_1, W(γ)=∑_j=1^rw(e_j). The empty word has weight zero and contributes the identity. Then T is invertible and T^-1 = ∑_γ(-1)^|γ|A_γ D^-1. The series converges in the filtration, and the term indexed by γ belongs to F^W(γ) B.

    Exact mathematical passage
    
    A_\gamma=A_{e_r}\cdots A_{e_1},
    \qquad
    W(\gamma)=\sum_{j=1}^rw(e_j).
    
A_{e_r}Use in source · 2 passages

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  • Use in source · Read passage · 03_weighted.tex, line 52

    [Weighted inverse] Let B be a complete filtered algebra. Let D∈ B be invertible with D,D^-1∈ F^0 B. Let E be a finite set and suppose T=D+∑_e∈ EN_e, N_e∈ F^w(e) B, w(e)≥1. Set A_e=D^-1N_e. For a word γ=(e_1,…,e_r), write A_γ=A_e_r⋯ A_e_1, W(γ)=∑_j=1^rw(e_j). The empty word has weight zero and contributes the identity. Then T is invertible and T^-1 = ∑_γ(-1)^|γ|A_γ D^-1. The series converges in the filtration, and the term indexed by γ belongs to F^W(γ) B.

    Exact mathematical passage
    
    A_\gamma=A_{e_r}\cdots A_{e_1},
    \qquad
    W(\gamma)=\sum_{j=1}^rw(e_j).
    
a_jUse in source · 5 passages

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  • Use in source · Read passage · 04_arithmetic.tex, line 284

    ght] With the notation of [source reference], the map Φ:G_Λ, P ⟶ ⊕_α∈ IE_αΛ/Λ_α, [x]⟼(E_α x+Λ_α)_α is injective, and every coordinate projection of its image is surjective. We also have exp_π(G_Λ, P) = s_Λ( P). If G_Λ, P ≅ ⊕_j=1^r O/π^a_j O with a_1≤⋯≤ a_r, then s_Λ( P)=max({0}∪{a_j:1≤ j≤ r}).

    Exact mathematical passage
    
    G_{\Lambda,\Pcal}
    \cong
    \bigoplus_{j=1}^r\OO/\pi^{a_j}\OO
    
a_kUse in source · 1 passage

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  • Use in source · Read passage · 03_weighted.tex, line 441

    In the recurrence, set a_k=0 when k<0. This is the coefficient convention for the formal power series Z_u,v(t) and makes the first recurrence equations meaningful even when n<d.

    Exact mathematical passage
    a_k=0
\mathcal A_NUse in source · 2 passages

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  • Use in source · visual_atlas.tex, line 27

    A_N, S_N · Split into range-restricted packet vectors, then sum them. · A permutation/interleaving of eight coordinates.

    Exact mathematical passage
    \mathcal A_N,\mathcal S_N
a_{n-1}Use in source · 2 passages

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  • Use in source · Read passage · 03_weighted.tex, line 428

    [Recurrence for path counts] Write Z_u,v(t)=fracP(t)Q(t), Q(t)=1+q_1t+⋯+q_dt^d. Use the convention deg 0=-∞. Then, for every nonnegative integer n>deg P, a_n+q_1a_n-1+⋯+q_da_n-d=0.

    Exact mathematical passage
    
    a_n+q_1a_{n-1}+\cdots+q_da_{n-d}=0.
    
a_{n-3}Use in source · 1 passage

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  • Use in source · visual_atlas.tex, line 311

    From QZ_0,1=2t^2 one obtains a_0=a_1=0, a_2=2, a_n=a_n-1+2a_n-3 (n≥3). The numerator is responsible for the initial exception. Omitting it would incorrectly force the entire series to vanish.

    Exact mathematical passage
    
    a_0=a_1=0,\quad a_2=2,\qquad a_n=a_{n-1}+2a_{n-3}\quad(n\ge3).
    
a_{n-d}Use in source · 1 passage

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  • Use in source · Read passage · 03_weighted.tex, line 428

    [Recurrence for path counts] Write Z_u,v(t)=fracP(t)Q(t), Q(t)=1+q_1t+⋯+q_dt^d. Use the convention deg 0=-∞. Then, for every nonnegative integer n>deg P, a_n+q_1a_n-1+⋯+q_da_n-d=0.

    Exact mathematical passage
    
    a_n+q_1a_{n-1}+\cdots+q_da_{n-d}=0.
    
a_{n-k}Use in source · 1 passage

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  • Use in source · Read passage · 03_weighted.tex, line 564

    [Linear recurrence] With the canonical polynomials from [source reference], write Q(t)=∑_kq_kt^k, Z_s,t(t)=∑_n≥0a_n(s,t)t^n. Then the walk counts satisfy the recurrence with constant coefficients determined by Q after the finite initial range contributed by P_s,t, with deg 0=-∞: ∑_k=0^nq_k a_n-k(s,t)=0 (n>deg P_s,t).

    Exact mathematical passage
    
    \boxed{
    \sum_{k=0}^{n}q_k a_{n-k}(s,t)=0
    \qquad\bigl(n>\deg P_{s,t}\bigr).
    }
    
a_{n-w(e)}Use in source · 2 passages

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  • Use in source · Read passage · 03_weighted.tex, line 499

    [Automatic finite-graph transfer-zeta rationality] Assume the vertex and edge sets are finite and every edge has positive integer weight. For every n, exact enumeration of edge tuples of lengths at most n, followed by endpoint and total-weight filtering, returns a_n(s,t). These coefficients obey the recurrence obtained by removing the first edge a_n(s,t) = 1_s=t, n=0 +∑_substacke: source(e)=s w(e)≤ n a_n-w(e)(target(e),t). Let T(t)=I-A(t), Q(t)=det T(t), P_s,t(t)=adj(T(t))_s,t. Then Q(0)=1, henc…

    Exact mathematical passage
    
    a_n(s,t)
    =
    \mathbf 1_{s=t,\,n=0}
    +\sum_{\substack{e:\,\operatorname{source}(e)=s\\w(e)\le n}}
    a_{n-w(e)}(\operatorname{target}(e),t).
    
a_rUse in source · 1 passage

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  • Use in source · Read passage · 04_arithmetic.tex, line 289

    _packet, the map Φ:G_Λ, P ⟶ ⊕_α∈ IE_αΛ/Λ_α, [x]⟼(E_α x+Λ_α)_α is injective, and every coordinate projection of its image is surjective. We also have exp_π(G_Λ, P) = s_Λ( P). If G_Λ, P ≅ ⊕_j=1^r O/π^a_j O with a_1≤⋯≤ a_r, then s_Λ( P)=max({0}∪{a_j:1≤ j≤ r}).

    Exact mathematical passage
    a_1\leq\cdots\leq a_r
A_\gammaUse in source · 9 passages

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  • Use in source · Read passage · 03_weighted.tex, line 52

    [Weighted inverse] Let B be a complete filtered algebra. Let D∈ B be invertible with D,D^-1∈ F^0 B. Let E be a finite set and suppose T=D+∑_e∈ EN_e, N_e∈ F^w(e) B, w(e)≥1. Set A_e=D^-1N_e. For a word γ=(e_1,…,e_r), write A_γ=A_e_r⋯ A_e_1, W(γ)=∑_j=1^rw(e_j). The empty word has weight zero and contributes the identity. Then T is invertible and T^-1 = ∑_γ(-1)^|γ|A_γ D^-1. The series converges in the filtration, and the term indexed by γ belongs to F^W(γ) B.

    Exact mathematical passage
    
    A_\gamma=A_{e_r}\cdots A_{e_1},
    \qquad
    W(\gamma)=\sum_{j=1}^rw(e_j).
    
\operatorname{adj}Use in source · 5 passages

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  • Use in source · Read passage · 03_weighted.tex, line 412

    ce every entry of A(t) has zero constant term, the inverse exists in the formal power series ring and (I-A(t))^-1=∑_r≥0A(t)^r. The (i,j) entry of A(t)^r is the sum of the monomials attached to all paths of length r from i to j. Summing over r records paths of every length. Multiplication by the endpoint vectors gives the stated series. The adjugate formula gives (I-A(t))^-1 = fracadj(I-A(t))det(I-A(t)), so every entry is rational.

    Exact mathematical passage
    
    (I-A(t))^{-1}
    =
    \frac{\operatorname{adj}(I-A(t))}{\det(I-A(t))},
    
\operatorname{analyze}Use in source · 1 passage

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  • Use in source · Read passage · 06_models.tex, line 214

    The verified contract is synthesize(analyze(x,N))=x. The Lean counterpart uses packet coordinates restricted to projector ranges and proves both inverse laws. The finite Python routine checks the concrete array realization.

    Exact mathematical passage
    \operatorname{synthesize}(\operatorname{analyze}(x,N))=x
BUse in source · 17 passages

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  • Use in source · Read passage · 02_coordinates.tex, line 499

    [Coprime factorization] Let A and B be coprime positive integers. For each j modulo AB, write j_A=jpmod A, j_B=jpmod B. Then P_AB,j=P_A,j_AP_B,j_B. Every pair (j_A,j_B) occurs for one residue j modulo AB.

    Exact mathematical passage
    B
bUse in source · 59 passages

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  • Use in source · Read passage · 02_coordinates.tex, line 176

    Typed coordinate naturality. These coordinate changes are coherent through every finite tower. If three complete packet systems are denoted by a,b,c, then J_c,bJ_b,a=J_c,a, J_a,a=I, J_b,a^-1=J_a,b. These laws hold for arbitrary exact packet systems representing the same ambient module. The parent maps supply the component formulas linking children to their parents. Coordinate coherence itself does not require them.

    Exact mathematical passage
    a,b,c
B^{-1}Use in source · 3 passages

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  • Use in source · visual_atlas.tex, line 356

    Write B=1 · -1 0 · 2, AB=Bdiag(1,-1), E_+=Bdiag(1,0)B^-1. The index-two eigenlattice explains the denominator in B^-1 and in the projector. Over the localized lattice Λ_p=ZZ_(p)^2, the number 2 is a unit for every odd prime p. Hence the local denominator weight is zero there and one at p=2.

    Exact mathematical passage
    
    B=\begin{pmatrix}1&-1\\0&2\end{pmatrix},\qquad
    AB=B\diag(1,-1),\qquad
    E_+=B\diag(1,0)B^{-1}.
    
b^2Use in source · 1 passage

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  • Use in source · visual_atlas.tex, line 207

    vfig[.97]weighted_word_cutoff platecaptionAll nonzero retained terms of the signed inverse sum, followed by the first discarded nonzero word. The empty word contributes I. Other words of weight below five can still be zero because a^2=b^2=0.

    Exact mathematical passage
    a^2=b^2=0
b_iUse in source · 2 passages

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  • Use in source · Read passage · 04_arithmetic.tex, line 838

    [Concrete Smith-weighted congruence solve] Let p>1 and consider the diagonal system over ( Z/(p^L) Z)^d diag(p^s_1,…,p^s_d)x=b pmodp^L. The system is solvable if and only if p^min(s_i,L)mid (b_i)_val for every i, where (b_i)_val is the canonical natural representative. Conditional on this admissibility condition, the number of solutions is p^∑_i=1^dmin(s_i,L). If any coordinate is inadmissible, the solution set is empty and its cardinality is zero.

    Exact mathematical passage
    
    p^{\min(s_i,L)}\mid (b_i)_{\mathrm{val}}
    
b_{\mathrm{val}}Use in source · 2 passages

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  • Use in source · Read passage · 04_arithmetic.tex, line 856

    Lean proves the one-coordinate arithmetic directly over Z/p^L Z for every p>1: (∃ x∈ Z/p^L Z: p^s x=bpmodp^L) Longleftrightarrow p^min(s,L)mid b_val, where b_val is the canonical natural representative, and every admissible fibre has exactly p^min(s,L) elements. The coordinates are independent, so the product equivalence gives the displayed global count. If one coordinate fibre is empty, the global fibre is empty. Lean proves both the global solvability equivalence and the conditional count, inc…

    Exact mathematical passage
    
    \bigl(\exists x\in\mathbb Z/p^L\mathbb Z:\quad p^s x=b\pmod{p^L}\bigr)
    \quad\Longleftrightarrow\quad
    p^{\min(s,L)}\mid b_{\mathrm{val}},
    
\bbk^2Use in source · 1 passage

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  • Use in source · Read passage · 05_defects.tex, line 262

    [A visible one step defect] Let X_f=bbk^2, let X_c=bbk, and let C(x_1,x_2)=x_1. Take T_f= a · b

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    X_f=\bbk^2
\bulletUse in source · 1 passage

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  • Use in source · Read passage · 03_weighted.tex, line 310

    [Finite precision] Let F^bullet R be a multiplicative decreasing filtration and let q_L:R→ R_L be a ring homomorphism that kills F^L R. Suppose H=∑_e∈ EH_e, D^-1H_e∈ F^w(e)R, w(e)≥1, with E finite. Then q_L(D^-1H)^L=0, the finite sum in [source reference](a) is a two-sided inverse after applying q_L, and its word expansion may discard every word of weight at least L. More explicitly, for a length cutoff N, define S^pr_L,N = ∑_n=0^N-1(-1)^n ∑_substackγ∈ E^n

    Exact mathematical passage
    F^\bullet R
C^{-1}Use in source · 1 passage

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  • Use in source · visual_atlas.tex, line 547

    Had we chosen the transported operator T_c'=CT_fC^-1, the defect would be zero and every polynomial action would intertwine exactly. That is a different choice of coarse operator, not a stronger conclusion from the faulty one.

    Exact mathematical passage
    T_c'=CT_fC^{-1}
C_{0,L}Use in source · 3 passages

Search aliases: C_0,L

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  • Use in source · Read passage · 05_defects.tex, line 228

    [Multilevel defect decomposition] The total defect from level L to level zero is C_0,LT_L-T_0C_0,L = ∑_ℓ=0^L-1 C_0,ℓΔ_ℓ C_ℓ+1,L. For bounded maps, C_0,LT_L-T_0C_0,L ≤ ∑_ℓ=0^L-1 C_0,ℓ Δ_ℓ C_ℓ+1,L .

    Exact mathematical passage
    
    C_{0,L}T_L-T_0C_{0,L}
    =
    \sum_{\ell=0}^{L-1}
    C_{0,\ell}\Delta_\ell C_{\ell+1,L}.
    
C_{0,\ell}Use in source · 4 passages

Search aliases: C_0,ℓ ell

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  • Use in source · Read passage · 05_defects.tex, line 228

    [Multilevel defect decomposition] The total defect from level L to level zero is C_0,LT_L-T_0C_0,L = ∑_ℓ=0^L-1 C_0,ℓΔ_ℓ C_ℓ+1,L. For bounded maps, C_0,LT_L-T_0C_0,L ≤ ∑_ℓ=0^L-1 C_0,ℓ Δ_ℓ C_ℓ+1,L .

    Exact mathematical passage
    
    C_{0,L}T_L-T_0C_{0,L}
    =
    \sum_{\ell=0}^{L-1}
    C_{0,\ell}\Delta_\ell C_{\ell+1,L}.
    
c_{00}Use in source · 1 passage

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  • Use in source · Read passage · 06_models.tex, line 5

    Let x=(x_n)_n∈ Z∈ c_00( Z;R) and let the seed be δ_0 under the bilateral shifts (S^rδ_0)_n=δ_n,r. This makes the algebraic span and every displayed sum finite. The N packets are x_j[m]=x[Nm+j]. Synthesis interleaves these sequences. A linear filter with a finite impulse response that is invariant under shifts becomes an N× N matrix of transfer blocks. Refining from N to M with Nmid M splits each coarse phase into its descendants without changing the reconstructed signal. The same formulas extend…

    Exact mathematical passage
    x=(x_n)_{n\in\Z}\in c_{00}(\Z;R)
C_aUse in source · 1 passage

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  • Use in source · Read passage · 05_defects.tex, line 221

    Let C_ℓ:X_ℓ+1⟶ X_ℓ be linear maps for 0≤ℓ<L, and let T_ℓ∈End(X_ℓ). Put Δ_ℓ=C_ℓ T_ℓ+1-T_ℓ C_ℓ. For a<b, write C_a,b=C_aC_a+1⋯ C_b-1, with C_a,a=I.

    Exact mathematical passage
    
    C_{a,b}=C_aC_{a+1}\cdots C_{b-1},
    
C_{a+1}Use in source · 1 passage

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  • Use in source · Read passage · 05_defects.tex, line 221

    Let C_ℓ:X_ℓ+1⟶ X_ℓ be linear maps for 0≤ℓ<L, and let T_ℓ∈End(X_ℓ). Put Δ_ℓ=C_ℓ T_ℓ+1-T_ℓ C_ℓ. For a<b, write C_a,b=C_aC_a+1⋯ C_b-1, with C_a,a=I.

    Exact mathematical passage
    
    C_{a,b}=C_aC_{a+1}\cdots C_{b-1},
    
C_{a,a}Use in source · 1 passage

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  • Use in source · Read passage · 05_defects.tex, line 224

    Let C_ℓ:X_ℓ+1⟶ X_ℓ be linear maps for 0≤ℓ<L, and let T_ℓ∈End(X_ℓ). Put Δ_ℓ=C_ℓ T_ℓ+1-T_ℓ C_ℓ. For a<b, write C_a,b=C_aC_a+1⋯ C_b-1, with C_a,a=I.

    Exact mathematical passage
    C_{a,a}=I
C_{a,b}Use in source · 1 passage

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  • Use in source · Read passage · 05_defects.tex, line 221

    Let C_ℓ:X_ℓ+1⟶ X_ℓ be linear maps for 0≤ℓ<L, and let T_ℓ∈End(X_ℓ). Put Δ_ℓ=C_ℓ T_ℓ+1-T_ℓ C_ℓ. For a<b, write C_a,b=C_aC_a+1⋯ C_b-1, with C_a,a=I.

    Exact mathematical passage
    
    C_{a,b}=C_aC_{a+1}\cdots C_{b-1},
    
C_{b-1}Use in source · 1 passage

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  • Use in source · Read passage · 05_defects.tex, line 221

    Let C_ℓ:X_ℓ+1⟶ X_ℓ be linear maps for 0≤ℓ<L, and let T_ℓ∈End(X_ℓ). Put Δ_ℓ=C_ℓ T_ℓ+1-T_ℓ C_ℓ. For a<b, write C_a,b=C_aC_a+1⋯ C_b-1, with C_a,a=I.

    Exact mathematical passage
    
    C_{a,b}=C_aC_{a+1}\cdots C_{b-1},
    
C_{\Pcal\leftarrow\Rcal}Use in source · 1 passage

Search aliases: C_Pcal←Rcal C_ P← R Pcal leftarrow Rcal mathcal leftarrow mathcal

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  • Use in source · Read passage · 02_coordinates.tex, line 115

    herence] For any two packet systems on X, C_ P← QJ_ Q← P=I_X^ P, J_ Q← PC_ P← Q=I_X^ Q. For three packet systems P, Q, and R on X, J_ R← QJ_ Q← P = J_ R← P, C_ P← QC_ Q← R = C_ P← R. If Q refines P through ρ, then (J_ Q← Px)_β = Q_β x_ρ(β), (C_ P← Qy)_α = ∑_ρ(β)=αy_β.

    Exact mathematical passage
    
    C_{\Pcal\leftarrow\Qcal}C_{\Qcal\leftarrow\Rcal}
    =
    C_{\Pcal\leftarrow\Rcal}.
    
C_{\Qcal\leftarrow\Rcal}Use in source · 1 passage

Search aliases: C_Qcal←Rcal C_ Q← R Qcal leftarrow Rcal mathcal leftarrow mathcal

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  • Use in source · Read passage · 02_coordinates.tex, line 115

    herence] For any two packet systems on X, C_ P← QJ_ Q← P=I_X^ P, J_ Q← PC_ P← Q=I_X^ Q. For three packet systems P, Q, and R on X, J_ R← QJ_ Q← P = J_ R← P, C_ P← QC_ Q← R = C_ P← R. If Q refines P through ρ, then (J_ Q← Px)_β = Q_β x_ρ(β), (C_ P← Qy)_α = ∑_ρ(β)=αy_β.

    Exact mathematical passage
    
    C_{\Pcal\leftarrow\Qcal}C_{\Qcal\leftarrow\Rcal}
    =
    C_{\Pcal\leftarrow\Rcal}.
    
C_\ellUse in source · 3 passages

Search aliases: C_ℓ ell

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  • Use in source · Read passage · 05_defects.tex, line 213

    Let C_ℓ:X_ℓ+1⟶ X_ℓ be linear maps for 0≤ℓ<L, and let T_ℓ∈End(X_ℓ). Put Δ_ℓ=C_ℓ T_ℓ+1-T_ℓ C_ℓ. For a<b, write C_a,b=C_aC_a+1⋯ C_b-1, with C_a,a=I.

    Exact mathematical passage
    
    C_\ell:X_{\ell+1}\longrightarrow X_\ell
    
C_{\ell+1,L}Use in source · 3 passages

Search aliases: C_ℓ+1,L ell

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  • Use in source · Read passage · 05_defects.tex, line 228

    [Multilevel defect decomposition] The total defect from level L to level zero is C_0,LT_L-T_0C_0,L = ∑_ℓ=0^L-1 C_0,ℓΔ_ℓ C_ℓ+1,L. For bounded maps, C_0,LT_L-T_0C_0,L ≤ ∑_ℓ=0^L-1 C_0,ℓ Δ_ℓ C_ℓ+1,L .

    Exact mathematical passage
    
    C_{0,L}T_L-T_0C_{0,L}
    =
    \sum_{\ell=0}^{L-1}
    C_{0,\ell}\Delta_\ell C_{\ell+1,L}.
    
C_{\ell,L}Use in source · 1 passage

Search aliases: C_ℓ,L ell

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  • Use in source · Read passage · 05_defects.tex, line 247

    Insert the intermediate terms C_0,ℓT_ℓ C_ℓ,L for 0≤ℓ≤ L. Consecutive differences telescope. The difference between the terms indexed by ℓ+1 and ℓ is C_0,ℓ(C_ℓ T_ℓ+1-T_ℓ C_ℓ)C_ℓ+1,L. Summing gives the identity. The norm estimate follows from the triangle inequality.

    Exact mathematical passage
    
    C_{0,\ell}T_\ell C_{\ell,L}
    
\cA_QUse in source · 1 passage

Search aliases: cA_Q A_Q cA mathcal

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  • Use in source · Read passage · 02_coordinates.tex, line 189

    The same coherence applies to operators. Let P_a,P_b be packet systems on X, let Q_a,Q_b be packet systems on Y, where X and Y are modules over the same scalar ring, and let T:X→ Y be a linear map over that ring. Its exact coordinate representation widehat T_Q,P= A_QT S_P preserves identities and typed composition, and the naturality square is J^Y_Q_b,Q_a widehat T_Q_a,P_a = widehat T_Q_b,P_b J^X_P_b,P_a. The identity, cocycle, composition, inverse, and naturality laws are all proved in Lean. Th…

    Exact mathematical passage
    
    \widehat T_{Q,P}=\cA_QT\cS_P
    
\cBUse in source · 4 passages

Search aliases: cB B mathcal

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  • Use in source · Read passage · 03_weighted.tex, line 237

    Let O be a complete discrete valuation ring with uniformizer π, fraction field K, and filtration F^m B=π^m B on an O-algebra B. The finite quotient statements below do not require B itself to be complete. Suppose T=D+H, where D is invertible and the perturbation H raises filtration. The symbol K is reserved for the fraction field.

    Exact mathematical passage
    
    F^m\cB=\pi^m\cB
    
\cS_PUse in source · 1 passage

Search aliases: cS_P S_P cS mathcal

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  • Use in source · Read passage · 02_coordinates.tex, line 189

    The same coherence applies to operators. Let P_a,P_b be packet systems on X, let Q_a,Q_b be packet systems on Y, where X and Y are modules over the same scalar ring, and let T:X→ Y be a linear map over that ring. Its exact coordinate representation widehat T_Q,P= A_QT S_P preserves identities and typed composition, and the naturality square is J^Y_Q_b,Q_a widehat T_Q_a,P_a = widehat T_Q_b,P_b J^X_P_b,P_a. The identity, cocycle, composition, inverse, and naturality laws are all proved in Lean. Th…

    Exact mathematical passage
    
    \widehat T_{Q,P}=\cA_QT\cS_P
    
DUse in source · 59 passages

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  • Use in source · Read passage · 01_orientation.tex, line 8

    The second part studies inversion in a complete filtered algebra. Suppose an operator has the form T=D+N, where D is invertible and every packet transfer in N raises the filtration by a positive amount. The ordinary Neumann series can then be expanded into weighted paths. The weight is not the number of edges. It is the total filtration gain along the path. At precision L, every path of weight at least L vanishes. A finite transfer graph also gives a rational generating function for the number o…

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    T=D+N,
    
D^{-1}Use in source · 32 passages

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  • Use in source · Read passage · 03_weighted.tex, line 36

    [Weighted inverse] Let B be a complete filtered algebra. Let D∈ B be invertible with D,D^-1∈ F^0 B. Let E be a finite set and suppose T=D+∑_e∈ EN_e, N_e∈ F^w(e) B, w(e)≥1. Set A_e=D^-1N_e. For a word γ=(e_1,…,e_r), write A_γ=A_e_r⋯ A_e_1, W(γ)=∑_j=1^rw(e_j). The empty word has weight zero and contributes the identity. Then T is invertible and T^-1 = ∑_γ(-1)^|γ|A_γ D^-1. The series converges in the filtration, and the term indexed by γ belongs to F^W(γ) B.

    Exact mathematical passage
    
    D,D^{-1}\in F^0\Bcal.
    
D_0Use in source · 1 passage

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  • Use in source · Read passage · 01_orientation.tex, line 56

    A simple two packet model already contains all four notions. Let X=X_0⊕ X_1, D=D_0 · 0 0 · D_1, N=0 · N_01{ N_10 · 0. A finer family may split X_0 and X_1 into smaller summands. The blocks N_01 and N_10 may enter at different filtration weights. Over a fraction field, the rational packet spaces may fail to split the chosen lattice. A coarse operator on one selected summand may also fail to intertwine with the full matrix. The later sections isolate these four effects one at a time.

    Exact mathematical passage
    
    X=X_0\oplus X_1,
    \qquad
    D=\begin{pmatrix}D_0&0\\0&D_1\end{pmatrix},
    \qquad
    N=\begin{pmatrix}0&N_{01}\\N_{10}&0\end{pmatrix}.
    
D_1Use in source · 1 passage

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  • Use in source · Read passage · 01_orientation.tex, line 56

    A simple two packet model already contains all four notions. Let X=X_0⊕ X_1, D=D_0 · 0 0 · D_1, N=0 · N_01{ N_10 · 0. A finer family may split X_0 and X_1 into smaller summands. The blocks N_01 and N_10 may enter at different filtration weights. Over a fraction field, the rational packet spaces may fail to split the chosen lattice. A coarse operator on one selected summand may also fail to intertwine with the full matrix. The later sections isolate these four effects one at a time.

    Exact mathematical passage
    
    X=X_0\oplus X_1,
    \qquad
    D=\begin{pmatrix}D_0&0\\0&D_1\end{pmatrix},
    \qquad
    N=\begin{pmatrix}0&N_{01}\\N_{10}&0\end{pmatrix}.
    
D_\alphaUse in source · 2 passages

Search aliases: D_α alpha

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  • Use in source · Read passage · 03_weighted.tex, line 94

    [Block path formula] Let P=(P_α)_α∈ I be a finite packet system in a complete filtered algebra of operators. Suppose D=∑_α P_α D P_α belongs to B and is invertible on every packet. Assume that the assembled inverse D^-1=∑_α D_α^-1P_α∈ B=F^0 B, D_α=P_α DP_α, where each packet inverse is extended by zero to the other packets. Let the edge set be finite, assume w(e)≥1 for every edge, and write N=∑_e:α→βN_e, N_e=P_β N_eP_α, N_e∈ F^w(e) B. For an edge e:α→β, put A_e=(P_β DP_β)^-1N_e. Then the block f…

    Exact mathematical passage
    
    D^{-1}=\sum_\alpha D_\alpha^{-1}P_\alpha\in\Bcal=F^0\Bcal,
    \qquad D_\alpha=P_\alpha DP_\alpha,
    
D_\alpha^{-1}Use in source · 3 passages

Search aliases: D_α^-1 alpha

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  • Use in source · Read passage · 03_weighted.tex, line 94

    [Block path formula] Let P=(P_α)_α∈ I be a finite packet system in a complete filtered algebra of operators. Suppose D=∑_α P_α D P_α belongs to B and is invertible on every packet. Assume that the assembled inverse D^-1=∑_α D_α^-1P_α∈ B=F^0 B, D_α=P_α DP_α, where each packet inverse is extended by zero to the other packets. Let the edge set be finite, assume w(e)≥1 for every edge, and write N=∑_e:α→βN_e, N_e=P_β N_eP_α, N_e∈ F^w(e) B. For an edge e:α→β, put A_e=(P_β DP_β)^-1N_e. Then the block f…

    Exact mathematical passage
    
    D^{-1}=\sum_\alpha D_\alpha^{-1}P_\alpha\in\Bcal=F^0\Bcal,
    \qquad D_\alpha=P_\alpha DP_\alpha,
    
\degUse in source · 4 passages

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  • Use in source · Read passage · 03_weighted.tex, line 427

    [Recurrence for path counts] Write Z_u,v(t)=fracP(t)Q(t), Q(t)=1+q_1t+⋯+q_dt^d. Use the convention deg 0=-∞. Then, for every nonnegative integer n>deg P, a_n+q_1a_n-1+⋯+q_da_n-d=0.

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    \deg 0=-\infty
\detUse in source · 7 passages

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  • Use in source · Read passage · 03_weighted.tex, line 401

    [Rationality of the transfer series] The weighted transfer series satisfies Z_u,v(t) = u^ T(I-A(t))^-1v. It is a rational function whose denominator divides det(I-A(t)).

    Exact mathematical passage
    
    \det(I-A(t)).
    
\diagUse in source · 9 passages

Search aliases: diag operatorname

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  • Use in source · Read passage · 04_arithmetic.tex, line 100

    [A resultant bound that is not exact] Let A=diag(0,π^s) on the standard lattice Λ= O^2. The factors x and x-π^s have resultant -π^s, up to the harmless choice of resultant order, but the two spectral projectors are the integral coordinate projectors. Their exact separation weight is zero. The resultant sees the closeness of the two eigenvalues. It does not see that the chosen lattice already splits along their eigenspaces.

    Exact mathematical passage
    
    A=\diag(0,\pi^s)
    
e^{(t-s)T_c}Use in source · 4 passages

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  • Use in source · Read passage · 05_defects.tex, line 182

    [Exponential defect identity] Let C:X_f→ X_c, T_f, and T_c be bounded linear maps between Banach spaces over a common field. For real t, use real or complex spaces. For complex t, use complex spaces and complex-linear maps. Then Ce^tT_f-e^tT_cC = ∫_0^t e^(t-s)T_cΔ e^sT_f ds, where the integral is taken along the straight segment from 0 to t when t is complex. For real t≥0, Ce^tT_f-e^tT_cC ≤ Δ ∫_0^t e^(t-s)T_c e^sT_f ds.

    Exact mathematical passage
    
    Ce^{tT_f}-e^{tT_c}C
    =
    \int_0^t e^{(t-s)T_c}\Delta e^{sT_f}\,ds,
    
E^2Use in source · 1 passage

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  • Use in source · Read passage · 04_arithmetic.tex, line 156

    The B ezout identity gives N=rI-UF. The two stated commutation relations and FG=0 give N(UF)=VGUF=VUGF=VUFG=0. Therefore N^2=N(rI-UF)=rN. Since r≠0, E^2=r^-2N^2=E. If Fx=0, the evaluated B ezout identity gives VGx=rx, hence Ex=x. If Gx=0, then Ex=0. The lattice assertion follows directly from rE=VG.

    Exact mathematical passage
    E^2=r^{-2}N^2=E
e^{ik\pi/4}Use in source · 2 passages

Search aliases: e^ikπ/4 pi

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  • Use in source · visual_atlas.tex, line 510

    AR PHASE ORBITTraditional paper: Section 12.3 (p. 42), Section 12.3, Smith-phase identity (p. 43) Smith normal form concerns linear congruences. The Smith impedance chart uses the nonlinear coordinate change Γ=fracz-1z+1, z=frac1+Γ1-Γ. They share a name, not a mathematical definition. Sample the reflection circle at the exact algebraic points Γ_k=tfrac12 e^ikπ/4.

    Exact mathematical passage
    \Gamma_k=\tfrac12 e^{ik\pi/4}
E^nUse in source · 1 passage

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  • Use in source · Read passage · 03_weighted.tex, line 321

    et q_L:R→ R_L be a ring homomorphism that kills F^L R. Suppose H=∑_e∈ EH_e, D^-1H_e∈ F^w(e)R, w(e)≥1, with E finite. Then q_L(D^-1H)^L=0, the finite sum in [source reference](a) is a two-sided inverse after applying q_L, and its word expansion may discard every word of weight at least L. More explicitly, for a length cutoff N, define S^pr_L,N = ∑_n=0^N-1(-1)^n ∑_substackγ∈ E^n W(γ)<LA_γ. Lean proves directly that q_L(S^pr_L,N) equals the mapped geometric inverse whenever q_L(A^N)=0, and hence is…

    Exact mathematical passage
    
    S^{\mathrm{pr}}_{L,N}
    =
    \sum_{n=0}^{N-1}(-1)^n
    \sum_{\substack{\gamma\in E^n\\W(\gamma)<L}}A_\gamma.
    
e^{sT_f}Use in source · 4 passages

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  • Use in source · Read passage · 05_defects.tex, line 182

    [Exponential defect identity] Let C:X_f→ X_c, T_f, and T_c be bounded linear maps between Banach spaces over a common field. For real t, use real or complex spaces. For complex t, use complex spaces and complex-linear maps. Then Ce^tT_f-e^tT_cC = ∫_0^t e^(t-s)T_cΔ e^sT_f ds, where the integral is taken along the straight segment from 0 to t when t is complex. For real t≥0, Ce^tT_f-e^tT_cC ≤ Δ ∫_0^t e^(t-s)T_c e^sT_f ds.

    Exact mathematical passage
    
    Ce^{tT_f}-e^{tT_c}C
    =
    \int_0^t e^{(t-s)T_c}\Delta e^{sT_f}\,ds,
    
e^{tT_c}Use in source · 2 passages

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  • Use in source · Read passage · 05_defects.tex, line 182

    [Exponential defect identity] Let C:X_f→ X_c, T_f, and T_c be bounded linear maps between Banach spaces over a common field. For real t, use real or complex spaces. For complex t, use complex spaces and complex-linear maps. Then Ce^tT_f-e^tT_cC = ∫_0^t e^(t-s)T_cΔ e^sT_f ds, where the integral is taken along the straight segment from 0 to t when t is complex. For real t≥0, Ce^tT_f-e^tT_cC ≤ Δ ∫_0^t e^(t-s)T_c e^sT_f ds.

    Exact mathematical passage
    
    Ce^{tT_f}-e^{tT_c}C
    =
    \int_0^t e^{(t-s)T_c}\Delta e^{sT_f}\,ds,
    
e^{tT_f}Use in source · 2 passages

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  • Use in source · Read passage · 05_defects.tex, line 182

    [Exponential defect identity] Let C:X_f→ X_c, T_f, and T_c be bounded linear maps between Banach spaces over a common field. For real t, use real or complex spaces. For complex t, use complex spaces and complex-linear maps. Then Ce^tT_f-e^tT_cC = ∫_0^t e^(t-s)T_cΔ e^sT_f ds, where the integral is taken along the straight segment from 0 to t when t is complex. For real t≥0, Ce^tT_f-e^tT_cC ≤ Δ ∫_0^t e^(t-s)T_c e^sT_f ds.

    Exact mathematical passage
    
    Ce^{tT_f}-e^{tT_c}C
    =
    \int_0^t e^{(t-s)T_c}\Delta e^{sT_f}\,ds,
    
E_+Use in source · 22 passages

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  • Use in source · Read passage · 04_arithmetic.tex, line 563

    0 · -1 act on Z_p^2. Over Q_p, the sign projectors are E_+=fracI+A2 = 1 · 1/2 0 · 0 , E_-=fracI-A2 = 0 · -1/2

    Exact mathematical passage
    
    E_+=\frac{I+A}{2}
    =
    \begin{pmatrix}
    1&1/2\\
    0&0
    \end{pmatrix},
    
E_+^2Use in source · 1 passage

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  • Use in source · bezout_normalization.tex, line 30

    000); node[] at (8.25000,2.15000) frac12; draw[fill=black!0,draw=black!45,line width=.35pt,] (7.20000,1.10000) rectangle ++(0.70000,0.70000); node[] at (7.55000,1.45000) 0; draw[fill=black!0,draw=black!45,line width=.35pt,] (7.90000,1.10000) rectangle ++(0.70000,0.70000); node[] at (8.25000,1.45000) 0; node[] at (11.00000,2.10000) N^2=2N; node[] at (11.00000,1.20000) E_+^2=E_+; node[] at (6.00000,-0.05000) E_+(1,0)=(1,0), E_+(-1,2)=(0,0);

    Exact mathematical passage
    E_+^2=E_+
E_-Use in source · 7 passages

Search aliases: E_-

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  • Use in source · Read passage · 04_arithmetic.tex, line 571

    0 · 0 , E_-=fracI-A2 = 0 · -1/2 0 · 1 . For every odd prime p, both projectors preserve Z_p^2. At p=2, s_2(E_+)=s_2(E_-)=1. The factors x-1 and x+1 have resultant 2.

    Exact mathematical passage
    
    E_-=\frac{I-A}{2}
    =
    \begin{pmatrix}
    0&-1/2\\
    0&1
    \end{pmatrix}.
    
E_{00}Use in source · 2 passages

Search aliases: E_00

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  • Use in source · visual_atlas.tex, line 210

    The words are written matrix products: in ab, the map b acts first. Therefore ab=8E_00, ba=8E_11, aba=16E_01. The two products ab and ba cannot be identified merely because they have equal weight. Both their order and their source/target information matter.

    Exact mathematical passage
    
    ab=8E_{00},\qquad ba=8E_{11},\qquad aba=16E_{01}.
    
E_{01}Use in source · 7 passages

Search aliases: E_01

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  • Use in source · visual_atlas.tex, line 201

    vpage9Which words can survive precision five?MODEL B / ORDERED TRANSFERS IN A FILTERED RINGTraditional paper: Theorem 5.10 (p. 17), Corollary 5.11 (p. 18) Let E_ij send the jth basis vector to the ith. In integral 2×2 matrices set a=2E_01, b=4E_10, A=a+b. Their certified dyadic weights are 1 and 2. At precision L=5, every word of weight at least five vanishes modulo 32.

    Exact mathematical passage
    
    a=2E_{01},\qquad b=4E_{10},\qquad A=a+b.
    
E_{10}Use in source · 3 passages

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  • Use in source · visual_atlas.tex, line 201

    vpage9Which words can survive precision five?MODEL B / ORDERED TRANSFERS IN A FILTERED RINGTraditional paper: Theorem 5.10 (p. 17), Corollary 5.11 (p. 18) Let E_ij send the jth basis vector to the ith. In integral 2×2 matrices set a=2E_01, b=4E_10, A=a+b. Their certified dyadic weights are 1 and 2. At precision L=5, every word of weight at least five vanishes modulo 32.

    Exact mathematical passage
    
    a=2E_{01},\qquad b=4E_{10},\qquad A=a+b.
    
E_{11}Use in source · 2 passages

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  • Use in source · visual_atlas.tex, line 210

    The words are written matrix products: in ab, the map b acts first. Therefore ab=8E_00, ba=8E_11, aba=16E_01. The two products ab and ba cannot be identified merely because they have equal weight. Both their order and their source/target information matter.

    Exact mathematical passage
    
    ab=8E_{00},\qquad ba=8E_{11},\qquad aba=16E_{01}.
    
e_2Use in source · 6 passages

Search aliases: e_2

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  • Use in source · Read passage · 04_arithmetic.tex, line 501

    [The same rational split with two lattices] Let V=Ke_1⊕ Ke_2 and let E project onto Ke_1. On the split lattice Λ_0= O e_1⊕ O e_2, the weight is zero. Fix s≥1 and consider Λ_s = O e_1+ O(π^-se_1+e_2). Then Λ_s∩ Ke_1= O e_1, Λ_s∩ Ke_2=π^s O e_2. The gluing module is isomorphic to O/π^s O, so s_Λ_s(E)=s. The rational decomposition has not changed. Only the lattice has changed.

    Exact mathematical passage
    
    V=Ke_1\oplus Ke_2
    
E_fUse in source · 7 passages

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  • Use in source · Read passage · 04_arithmetic.tex, line 19

    [Bézout spectral projector] Assume that χ_A(x)=f(x)g(x) with monic polynomials f,g∈ O[x] that are coprime in K[x]. Choose u,v∈ O[x] and a nonzero r∈ O such that u(x)f(x)+v(x)g(x)=r. Then E_f=r^-1v(A)g(A) is the projector of V onto Ker f(A) along Ker g(A). In particular, E_f^2=E_f, rE_f∈End_ O(Λ).

    Exact mathematical passage
    
    E_f=r^{-1}v(A)g(A)
    
E_f^2Use in source · 1 passage

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  • Use in source · Read passage · 04_arithmetic.tex, line 23

    [Bézout spectral projector] Assume that χ_A(x)=f(x)g(x) with monic polynomials f,g∈ O[x] that are coprime in K[x]. Choose u,v∈ O[x] and a nonzero r∈ O such that u(x)f(x)+v(x)g(x)=r. Then E_f=r^-1v(A)g(A) is the projector of V onto Ker f(A) along Ker g(A). In particular, E_f^2=E_f, rE_f∈End_ O(Λ).

    Exact mathematical passage
    
    E_f^2=E_f,
    \qquad
    rE_f\in\End_{\OO}(\Lambda).
    
E_iUse in source · 4 passages

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  • Use in source · Read passage · 04_arithmetic.tex, line 63

    [Several coprime spectral packets] Assume χ_A(x)=∏_i=1^rf_i(x), where the monic factors f_i∈ O[x] are pairwise coprime in K[x]. Put g_i=∏_j≠ if_j. There are complementary projectors E_i with im E_i=Ker f_i(A), ∑_iE_i=I, E_iE_j=0 (i≠ j). One may choose E_i so that Res(f_i,g_i)E_i∈End_ O(Λ) up to multiplication of the resultant by a unit.

    Exact mathematical passage
    E_i
E_{ij}Use in source · 1 passage

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  • Use in source · visual_atlas.tex, line 200

    vpage9Which words can survive precision five?MODEL B / ORDERED TRANSFERS IN A FILTERED RINGTraditional paper: Theorem 5.10 (p. 17), Corollary 5.11 (p. 18) Let E_ij send the jth basis vector to the ith. In integral 2×2 matrices set a=2E_01, b=4E_10, A=a+b. Their certified dyadic weights are 1 and 2. At precision L=5, every word of weight at least five vanishes modulo 32.

    Exact mathematical passage
    E_{ij}
E_jUse in source · 2 passages

Search aliases: E_j

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  • Use in source · Read passage · 04_arithmetic.tex, line 64

    [Several coprime spectral packets] Assume χ_A(x)=∏_i=1^rf_i(x), where the monic factors f_i∈ O[x] are pairwise coprime in K[x]. Put g_i=∏_j≠ if_j. There are complementary projectors E_i with im E_i=Ker f_i(A), ∑_iE_i=I, E_iE_j=0 (i≠ j). One may choose E_i so that Res(f_i,g_i)E_i∈End_ O(Λ) up to multiplication of the resultant by a unit.

    Exact mathematical passage
    
    \im E_i=\Ker f_i(A),
    \qquad
    \sum_iE_i=I,
    \qquad
    E_iE_j=0
    \quad(i\ne j).
    
e_mUse in source · 1 passage

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  • Use in source · visual_atlas.tex, line 481

    vpage20Filter first or split first: same outputMODEL F / A FINITE POLYPHASE REALIZATIONTraditional paper: Section B.1 (p. 47) Use the finitely supported signal x=(1,2,3,4,5,6) and the filter h=(1,2,1). Outside the displayed support, the input is zero. Let e_m=x_2m and o_m=x_2m+1.

    Exact mathematical passage
    e_m=x_{2m}
e_rUse in source · 5 passages

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  • Use in source · Read passage · 03_weighted.tex, line 51

    [Weighted inverse] Let B be a complete filtered algebra. Let D∈ B be invertible with D,D^-1∈ F^0 B. Let E be a finite set and suppose T=D+∑_e∈ EN_e, N_e∈ F^w(e) B, w(e)≥1. Set A_e=D^-1N_e. For a word γ=(e_1,…,e_r), write A_γ=A_e_r⋯ A_e_1, W(γ)=∑_j=1^rw(e_j). The empty word has weight zero and contributes the identity. Then T is invertible and T^-1 = ∑_γ(-1)^|γ|A_γ D^-1. The series converges in the filtration, and the term indexed by γ belongs to F^W(γ) B.

    Exact mathematical passage
    \gamma=(e_1,\ldots,e_r)
E_\pmUse in source · 1 passage

Search aliases: E_± pm

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  • Use in source · visual_atlas.tex, line 366

    headThe special fiber does not retain the rational splitting Modulo two, x-1=x+1 and A becomes a nontrivial unipotent matrix. The entries 1/2 in E_± cannot be reduced modulo two. By contrast, the coefficient selectors on V6 use only zero and one and remain available.

    Exact mathematical passage
    E_\pm
\End_KUse in source · 1 passage

Search aliases: End_K End operatorname

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  • Use in source · Read passage · 04_arithmetic.tex, line 121

    [Evaluated B ezout spectral projector] Let F,G,U,V∈End_K(Λ⊗_ O K) and let r∈ K^×. Suppose UF+VG=rI, FG=0, FG=GF, GU=UG. Put N=VG. Then N^2=rN. Consequently the operator E=r^-1VG is idempotent, acts as the identity on ker F, and acts as zero on ker G. If V and G preserve Λ, then rE=VG∈End_ O(Λ).

    Exact mathematical passage
    F,G,U,V\in\End_K(\Lambda\otimes_\OO K)
\End_\OOUse in source · 2 passages

Search aliases: End_OO End_ O End OO operatorname mathcal

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  • Use in source · Read passage · 04_arithmetic.tex, line 114

    Let O be a DVR, K=Frac( O), and A∈End_ O(Λ) for a finite free lattice Λ. Suppose the characteristic polynomial factors over O as χ_A(x)=f(x)g(x), where f and g are coprime over K[x].

    Exact mathematical passage
    A\in\End_\OO(\Lambda)
\End_{\OO}Use in source · 3 passages

Search aliases: End_OO End_ O End OO operatorname mathcal

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  • Use in source · Read passage · 04_arithmetic.tex, line 7

    Let O be a discrete valuation ring with fraction field K and uniformizer π. Let Λ be a finite free O module and put V=K⊗_ OΛ. Suppose A∈End_ O(Λ).

    Exact mathematical passage
    A\in\End_{\OO}(\Lambda)
\FUse in source · 1 passage

Search aliases: F mathbb

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  • Use in source · Read passage · 04_arithmetic.tex, line 668

    The two characteristic factors x-1 and x+1 have the same reduction in F_2[x]. The rational matrices E_+ and E_- themselves cannot be reduced modulo 2, because their entries contain 1/2. Consequently the integral special fibre does not inherit their separate idempotent splitting, even though the two projectors remain distinct over Q_2. This is the simplest model of delayed dyadic separation.

    Exact mathematical passage
    \F_2[x]
\mathbb FUse in source · 7 passages

Search aliases: F mathbb

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  • Use in source · Read passage · 02_coordinates.tex, line 443

    The field or orthogonality condition is essential. A primitive element of order N in a ring with zero divisors does not by itself force the geometric sums away from the diagonal to vanish. For example, in F_3× F_3 the element (-1,1) has order two, but the second component of its nontrivial character sum is nonzero. The coefficient selector uses no division and remains valid without any Fourier certificate. This distinction becomes decisive at the dyadic prime.

    Exact mathematical passage
    \mathbb F_3\times\mathbb F_3
F'Use in source · 1 passage

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  • Use in source · Read passage · 05_defects.tex, line 204

    For real t, differentiate F(s)=e^(t-s)T_cCe^sT_f. We obtain F'(s)=e^(t-s)T_cΔ e^sT_f. Integration from 0 to t gives the identity. The complex statement follows by the same calculation along the straight segment. The norm bound follows from the integral formula.

    Exact mathematical passage
    
    F'(s)=e^{(t-s)T_c}\Delta e^{sT_f}.
    
F^\bulletUse in source · 1 passage

Search aliases: F^bullet bullet

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  • Use in source · Read passage · 03_weighted.tex, line 310

    [Finite precision] Let F^bullet R be a multiplicative decreasing filtration and let q_L:R→ R_L be a ring homomorphism that kills F^L R. Suppose H=∑_e∈ EH_e, D^-1H_e∈ F^w(e)R, w(e)≥1, with E finite. Then q_L(D^-1H)^L=0, the finite sum in [source reference](a) is a two-sided inverse after applying q_L, and its word expansion may discard every word of weight at least L. More explicitly, for a length cutoff N, define S^pr_L,N = ∑_n=0^N-1(-1)^n ∑_substackγ∈ E^n

    Exact mathematical passage
    F^\bullet R
F^{d(\alpha,\beta)}Use in source · 1 passage

Search aliases: F^d(α,β) alpha beta

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  • Use in source · Read passage · 03_weighted.tex, line 130

    [Minimum path weight] For packets α and β, let d(α,β) be the least total weight of a directed path from α to β, with d=∞ when no path exists. Use the convention F^∞ B=⋂_L≥0F^L B=0. If α≠β, then P_β(D+N)^-1P_α ∈ F^d(α,β) B. If there is no path from α to β, the block is zero.

    Exact mathematical passage
    
    P_\beta(D+N)^{-1}P_\alpha
    \in
    F^{d(\alpha,\beta)}\Bcal.
    
F^mUse in source · 1 passage

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  • Use in source · Read passage · 03_weighted.tex, line 237

    Let O be a complete discrete valuation ring with uniformizer π, fraction field K, and filtration F^m B=π^m B on an O-algebra B. The finite quotient statements below do not require B itself to be complete. Suppose T=D+H, where D is invertible and the perturbation H raises filtration. The symbol K is reserved for the fraction field.

    Exact mathematical passage
    
    F^m\cB=\pi^m\cB
    
F^{W(\gamma)}Use in source · 3 passages

Search aliases: F^W(γ) gamma

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  • Use in source · Read passage · 03_weighted.tex, line 63

    l, w(e)≥1. Set A_e=D^-1N_e. For a word γ=(e_1,…,e_r), write A_γ=A_e_r⋯ A_e_1, W(γ)=∑_j=1^rw(e_j). The empty word has weight zero and contributes the identity. Then T is invertible and T^-1 = ∑_γ(-1)^|γ|A_γ D^-1. The series converges in the filtration, and the term indexed by γ belongs to F^W(γ) B.

    Exact mathematical passage
    F^{W(\gamma)}\Bcal
F^\inftyUse in source · 1 passage

Search aliases: F^∞ infty

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  • Use in source · Read passage · 03_weighted.tex, line 129

    [Minimum path weight] For packets α and β, let d(α,β) be the least total weight of a directed path from α to β, with d=∞ when no path exists. Use the convention F^∞ B=⋂_L≥0F^L B=0. If α≠β, then P_β(D+N)^-1P_α ∈ F^d(α,β) B. If there is no path from α to β, the block is zero.

    Exact mathematical passage
    F^\infty\Bcal=\bigcap_{L\geq0}F^L\Bcal=0
\F_2Use in source · 1 passage

Search aliases: F_2 F mathbb

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  • Use in source · Read passage · 04_arithmetic.tex, line 668

    The two characteristic factors x-1 and x+1 have the same reduction in F_2[x]. The rational matrices E_+ and E_- themselves cannot be reduced modulo 2, because their entries contain 1/2. Consequently the integral special fibre does not inherit their separate idempotent splitting, even though the two projectors remain distinct over Q_2. This is the simplest model of delayed dyadic separation.

    Exact mathematical passage
    \F_2[x]
\mathbb F_2Use in source · 3 passages

Search aliases: F_2 mathbb

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  • Use in source · visual_atlas.tex, line 133

    vpage6Selectors survive without divisionMODEL A / RESIDUE MASKS IN CHARACTERISTIC TWOTraditional paper: Proposition 4.2 (p. 9) Work first in F_2, where 1+1=0. The eight coefficients below are just a finite display of a coefficient sequence. The even and odd projectors are diagonal masks with entries zero and one.

    Exact mathematical passage
    \mathbb F_2
\mathbb F_3Use in source · 3 passages

Search aliases: F_3 mathbb

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  • Use in source · Read passage · 02_coordinates.tex, line 443

    The field or orthogonality condition is essential. A primitive element of order N in a ring with zero divisors does not by itself force the geometric sums away from the diagonal to vanish. For example, in F_3× F_3 the element (-1,1) has order two, but the second component of its nontrivial character sum is nonzero. The coefficient selector uses no division and remains valid without any Fourier certificate. This distinction becomes decisive at the dyadic prime.

    Exact mathematical passage
    \mathbb F_3\times\mathbb F_3
\mathbb F_7Use in source · 1 passage

Search aliases: F_7 mathbb

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  • Use in source · visual_atlas.tex, line 156

    vpage7A Fourier certificate you can inspectMODEL A / AN EXACT NINE-ENTRY TABLETraditional paper: Theorem 4.3 (p. 10) Take N=3 and work in F_7. Set ω=2, ω^-1=4, η=3^-1=5. Here 2^3=1 and neither 2 nor 2^2 is one. The unnormalized geometric sums are the entries in the first matrix.

    Exact mathematical passage
    \mathbb F_7
f_iUse in source · 7 passages

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  • Use in source · Read passage · 04_arithmetic.tex, line 56

    [Several coprime spectral packets] Assume χ_A(x)=∏_i=1^rf_i(x), where the monic factors f_i∈ O[x] are pairwise coprime in K[x]. Put g_i=∏_j≠ if_j. There are complementary projectors E_i with im E_i=Ker f_i(A), ∑_iE_i=I, E_iE_j=0 (i≠ j). One may choose E_i so that Res(f_i,g_i)E_i∈End_ O(Λ) up to multiplication of the resultant by a unit.

    Exact mathematical passage
    
    \chi_A(x)=\prod_{i=1}^rf_i(x),
    
f_jUse in source · 2 passages

Search aliases: f_j

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  • Use in source · Read passage · 04_arithmetic.tex, line 60

    [Several coprime spectral packets] Assume χ_A(x)=∏_i=1^rf_i(x), where the monic factors f_i∈ O[x] are pairwise coprime in K[x]. Put g_i=∏_j≠ if_j. There are complementary projectors E_i with im E_i=Ker f_i(A), ∑_iE_i=I, E_iE_j=0 (i≠ j). One may choose E_i so that Res(f_i,g_i)E_i∈End_ O(Λ) up to multiplication of the resultant by a unit.

    Exact mathematical passage
    
    g_i=\prod_{j\ne i}f_j.
    
\FracUse in source · 1 passage

Search aliases: Frac operatorname

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  • Use in source · Read passage · 04_arithmetic.tex, line 114

    Let O be a DVR, K=Frac( O), and A∈End_ O(Λ) for a finite free lattice Λ. Suppose the characteristic polynomial factors over O as χ_A(x)=f(x)g(x), where f and g are coprime over K[x].

    Exact mathematical passage
    K=\Frac(\OO)
g_iUse in source · 4 passages

Search aliases: g_i

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  • Use in source · Read passage · 04_arithmetic.tex, line 60

    [Several coprime spectral packets] Assume χ_A(x)=∏_i=1^rf_i(x), where the monic factors f_i∈ O[x] are pairwise coprime in K[x]. Put g_i=∏_j≠ if_j. There are complementary projectors E_i with im E_i=Ker f_i(A), ∑_iE_i=I, E_iE_j=0 (i≠ j). One may choose E_i so that Res(f_i,g_i)E_i∈End_ O(Λ) up to multiplication of the resultant by a unit.

    Exact mathematical passage
    
    g_i=\prod_{j\ne i}f_j.
    
\operatorname{GL}Use in source · 1 passage

Search aliases: GL operatorname

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  • Use in source · Read passage · 04_arithmetic.tex, line 705

    [Smith normal form over a discrete valuation ring] Let M∈ M_m,n( O). There are invertible matrices U∈GL_m( O), V∈GL_n( O) such that UMV = diag(π^s_1,…,π^s_r,0,…,0), where 0≤ s_1≤⋯≤ s_r and r is the rank over K. The exponents are uniquely determined. See [source reference].

    Exact mathematical passage
    
    U\in\operatorname{GL}_m(\OO),
    \qquad
    V\in\operatorname{GL}_n(\OO)
    
\operatorname{GL}_mUse in source · 1 passage

Search aliases: GL_m operatorname

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  • Use in source · Read passage · 04_arithmetic.tex, line 705

    [Smith normal form over a discrete valuation ring] Let M∈ M_m,n( O). There are invertible matrices U∈GL_m( O), V∈GL_n( O) such that UMV = diag(π^s_1,…,π^s_r,0,…,0), where 0≤ s_1≤⋯≤ s_r and r is the rank over K. The exponents are uniquely determined. See [source reference].

    Exact mathematical passage
    
    U\in\operatorname{GL}_m(\OO),
    \qquad
    V\in\operatorname{GL}_n(\OO)
    
\operatorname{GL}_nUse in source · 1 passage

Search aliases: GL_n operatorname

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  • Use in source · Read passage · 04_arithmetic.tex, line 705

    [Smith normal form over a discrete valuation ring] Let M∈ M_m,n( O). There are invertible matrices U∈GL_m( O), V∈GL_n( O) such that UMV = diag(π^s_1,…,π^s_r,0,…,0), where 0≤ s_1≤⋯≤ s_r and r is the rank over K. The exponents are uniquely determined. See [source reference].

    Exact mathematical passage
    
    U\in\operatorname{GL}_m(\OO),
    \qquad
    V\in\operatorname{GL}_n(\OO)
    
H_eUse in source · 4 passages

Search aliases: H_e

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  • Use in source · Read passage · 03_weighted.tex, line 247

    A packet decomposition resolves H=∑_e∈ EH_e and assigns a certified filtration gain D^-1H_e∈ F^w(e) B, w(e)∈ Z_>0. Each e is a directed transfer edge. For an ordered transfer word γ=(e_1,…,e_r), define W(γ)=∑_j=1^rw(e_j), A_γ=A_e_1⋯ A_e_r, A_e=D^-1H_e.

    Exact mathematical passage
    H=\sum_{e\in E}H_e
H_{e_1}Use in source · 1 passage

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  • Use in source · Read passage · 03_weighted.tex, line 349

    Here A_γ=(D^-1H_e_1)⋯(D^-1H_e_r) in the written order. Multiplicativity places it in F^W(γ)R, so the quotient kills it when W(γ)≥ L. Positive weights also imply |γ|≤ W(γ), making the retained search finite.

    Exact mathematical passage
    A_\gamma=(D^{-1}H_{e_1})\cdots(D^{-1}H_{e_r})
H_{e_r}Use in source · 1 passage

Search aliases: H_e_r

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  • Use in source · Read passage · 03_weighted.tex, line 349

    Here A_γ=(D^-1H_e_1)⋯(D^-1H_e_r) in the written order. Multiplicativity places it in F^W(γ)R, so the quotient kills it when W(γ)≥ L. Positive weights also imply |γ|≤ W(γ), making the retained search finite.

    Exact mathematical passage
    A_\gamma=(D^{-1}H_{e_1})\cdots(D^{-1}H_{e_r})
\hlineUse in source · 1 passage

Search aliases: hline

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  • Use in source · visual_atlas.tex, line 464

    The values are c|rrrrrr L · 1 · 2 · 3 · 4 · 5 · 6 W(L) · 2 · 3 · 4 · 4 · 4 · 4 # solutions · 4 · 8 · 16 · 16 · 16 · 16. Once L≥3, the nonzero weights have been fully exposed and the admissible fiber cardinality stabilizes at sixteen. The input space still grows as 2^3L. The number of attainable targets grows accordingly.

    Exact mathematical passage
    
    \begin{array}{c|rrrrrr}
    L&1&2&3&4&5&6\\\hline
    W(L)&2&3&4&4&4&4\\
    \#\text{ solutions}&4&8&16&16&16&16.
    \end{array}
    
I_mUse in source · 1 passage

Search aliases: I_m

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  • Use in source · Read passage · 02_coordinates.tex, line 69

    A refinement tower is a sequence ( P_ℓ)_ℓ≥0 with parent maps ρ_m,ℓ:I_m⟶ I_ℓ (m≥ℓ) such that P_m refines P_ℓ through ρ_m,ℓ for every m≥ℓ, and ρ_ℓ,ℓ=id_I_ℓ, ρ_n,ℓ=ρ_m,ℓ∘ρ_n,m (n≥ m≥ℓ). Thus every parent map witnesses the stated refinement and the maps compose coherently. The next result shows that the coordinate changes form a coherent system.

    Exact mathematical passage
    
    \rho_{m,\ell}:I_m\longrightarrow I_\ell
    \qquad(m\geq\ell)
    
I_{X^{\Pcal}}Use in source · 1 passage

Search aliases: I_X^Pcal I_X^ P Pcal mathcal

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  • Use in source · Read passage · 02_coordinates.tex, line 104

    [Exact coordinate change and coherence] For any two packet systems on X, C_ P← QJ_ Q← P=I_X^ P, J_ Q← PC_ P← Q=I_X^ Q. For three packet systems P, Q, and R on X, J_ R← QJ_ Q← P = J_ R← P, C_ P← QC_ Q← R = C_ P← R. If Q refines P through ρ, then (J_ Q← Px)_β = Q_β x_ρ(β), (C_ P← Qy)_α = ∑_ρ(β)=αy_β.

    Exact mathematical passage
    
    C_{\Pcal\leftarrow\Qcal}J_{\Qcal\leftarrow\Pcal}=I_{X^{\Pcal}},
    \qquad
    J_{\Qcal\leftarrow\Pcal}C_{\Pcal\leftarrow\Qcal}=I_{X^{\Qcal}}.
    
I_{X^{\Qcal}}Use in source · 1 passage

Search aliases: I_X^Qcal I_X^ Q Qcal mathcal

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  • Use in source · Read passage · 02_coordinates.tex, line 104

    [Exact coordinate change and coherence] For any two packet systems on X, C_ P← QJ_ Q← P=I_X^ P, J_ Q← PC_ P← Q=I_X^ Q. For three packet systems P, Q, and R on X, J_ R← QJ_ Q← P = J_ R← P, C_ P← QC_ Q← R = C_ P← R. If Q refines P through ρ, then (J_ Q← Px)_β = Q_β x_ρ(β), (C_ P← Qy)_α = ∑_ρ(β)=αy_β.

    Exact mathematical passage
    
    C_{\Pcal\leftarrow\Qcal}J_{\Qcal\leftarrow\Pcal}=I_{X^{\Pcal}},
    \qquad
    J_{\Qcal\leftarrow\Pcal}C_{\Pcal\leftarrow\Qcal}=I_{X^{\Qcal}}.
    
\idUse in source · 1 passage

Search aliases: id mathrm

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  • Use in source · Read passage · 02_coordinates.tex, line 74

    A refinement tower is a sequence ( P_ℓ)_ℓ≥0 with parent maps ρ_m,ℓ:I_m⟶ I_ℓ (m≥ℓ) such that P_m refines P_ℓ through ρ_m,ℓ for every m≥ℓ, and ρ_ℓ,ℓ=id_I_ℓ, ρ_n,ℓ=ρ_m,ℓ∘ρ_n,m (n≥ m≥ℓ). Thus every parent map witnesses the stated refinement and the maps compose coherently. The next result shows that the coordinate changes form a coherent system.

    Exact mathematical passage
    
    \rho_{\ell,\ell}=\id_{I_\ell},
    \qquad
    \rho_{n,\ell}=\rho_{m,\ell}\circ\rho_{n,m}
    \qquad(n\geq m\geq\ell).
    
\id_{I_\ell}Use in source · 1 passage

Search aliases: id_I_ℓ id ell mathrm ell

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  • Use in source · Read passage · 02_coordinates.tex, line 74

    A refinement tower is a sequence ( P_ℓ)_ℓ≥0 with parent maps ρ_m,ℓ:I_m⟶ I_ℓ (m≥ℓ) such that P_m refines P_ℓ through ρ_m,ℓ for every m≥ℓ, and ρ_ℓ,ℓ=id_I_ℓ, ρ_n,ℓ=ρ_m,ℓ∘ρ_n,m (n≥ m≥ℓ). Thus every parent map witnesses the stated refinement and the maps compose coherently. The next result shows that the coordinate changes form a coherent system.

    Exact mathematical passage
    
    \rho_{\ell,\ell}=\id_{I_\ell},
    \qquad
    \rho_{n,\ell}=\rho_{m,\ell}\circ\rho_{n,m}
    \qquad(n\geq m\geq\ell).
    
\iffUse in source · 1 passage

Search aliases: iff

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  • Use in source · visual_atlas.tex, line 412

    For a specific attainable target (2,4), 2x≡2pmod8iff x∈{1,5}, 4y≡4pmod8iff y∈{1,3,5,7}. The coordinate choices are independent, giving 2·4=8 solutions. The entire carrier is partitioned consistently: 8 attainable targets × 8 inputs per target=64. For an inadmissible target, such as (1,4) or (2,2), the fiber is empty. The same nonzero cardinality formula must not be applied to it.

    Exact mathematical passage
    
    2x\equiv2\pmod8\iff x\in\{1,5\},\qquad
    4y\equiv4\pmod8\iff y\in\{1,3,5,7\}.
    
\imUse in source · 1 passage

Search aliases: im operatorname

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  • Use in source · Read passage · 04_arithmetic.tex, line 64

    [Several coprime spectral packets] Assume χ_A(x)=∏_i=1^rf_i(x), where the monic factors f_i∈ O[x] are pairwise coprime in K[x]. Put g_i=∏_j≠ if_j. There are complementary projectors E_i with im E_i=Ker f_i(A), ∑_iE_i=I, E_iE_j=0 (i≠ j). One may choose E_i so that Res(f_i,g_i)E_i∈End_ O(Λ) up to multiplication of the resultant by a unit.

    Exact mathematical passage
    
    \im E_i=\Ker f_i(A),
    \qquad
    \sum_iE_i=I,
    \qquad
    E_iE_j=0
    \quad(i\ne j).
    
J^X_{P_b,P_a}Use in source · 1 passage

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  • Use in source · Read passage · 02_coordinates.tex, line 193

    The same coherence applies to operators. Let P_a,P_b be packet systems on X, let Q_a,Q_b be packet systems on Y, where X and Y are modules over the same scalar ring, and let T:X→ Y be a linear map over that ring. Its exact coordinate representation widehat T_Q,P= A_QT S_P preserves identities and typed composition, and the naturality square is J^Y_Q_b,Q_a widehat T_Q_a,P_a = widehat T_Q_b,P_b J^X_P_b,P_a. The identity, cocycle, composition, inverse, and naturality laws are all proved in Lean. Th…

    Exact mathematical passage
    
    \boxed{
    J^Y_{Q_b,Q_a}\,\widehat T_{Q_a,P_a}
    =
    \widehat T_{Q_b,P_b}\,J^X_{P_b,P_a}.
    }
    
J^Y_{Q_b,Q_a}Use in source · 1 passage

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  • Use in source · Read passage · 02_coordinates.tex, line 193

    The same coherence applies to operators. Let P_a,P_b be packet systems on X, let Q_a,Q_b be packet systems on Y, where X and Y are modules over the same scalar ring, and let T:X→ Y be a linear map over that ring. Its exact coordinate representation widehat T_Q,P= A_QT S_P preserves identities and typed composition, and the naturality square is J^Y_Q_b,Q_a widehat T_Q_a,P_a = widehat T_Q_b,P_b J^X_P_b,P_a. The identity, cocycle, composition, inverse, and naturality laws are all proved in Lean. Th…

    Exact mathematical passage
    
    \boxed{
    J^Y_{Q_b,Q_a}\,\widehat T_{Q_a,P_a}
    =
    \widehat T_{Q_b,P_b}\,J^X_{P_b,P_a}.
    }
    
J_{4,2}Use in source · 4 passages

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  • Use in source · visual_atlas.tex, line 113

    The reordered operators and change of coordinates are widehat T_N=R_NTR_N^-1, J_4,2=R_4R_2^-1. Multiplication cancels the intermediate coordinate maps: J_4,2widehat T_2=widehat T_4J_4,2, J_8,4J_4,2=J_8,2. Thus it makes no difference whether the operator is applied before or after a consistent coordinate change. One must transport the operator, not merely reuse the same numerical matrix under a new ordering.

    Exact mathematical passage
    
    \widehat T_N=R_NTR_N^{-1},\qquad J_{4,2}=R_4R_2^{-1}.
    
J_{8,2}Use in source · 1 passage

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  • Use in source · visual_atlas.tex, line 117

    The reordered operators and change of coordinates are widehat T_N=R_NTR_N^-1, J_4,2=R_4R_2^-1. Multiplication cancels the intermediate coordinate maps: J_4,2widehat T_2=widehat T_4J_4,2, J_8,4J_4,2=J_8,2. Thus it makes no difference whether the operator is applied before or after a consistent coordinate change. One must transport the operator, not merely reuse the same numerical matrix under a new ordering.

    Exact mathematical passage
    
    J_{4,2}\widehat T_2=\widehat T_4J_{4,2},\qquad
    J_{8,4}J_{4,2}=J_{8,2}.
    
J_{8,4}Use in source · 1 passage

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  • Use in source · visual_atlas.tex, line 117

    The reordered operators and change of coordinates are widehat T_N=R_NTR_N^-1, J_4,2=R_4R_2^-1. Multiplication cancels the intermediate coordinate maps: J_4,2widehat T_2=widehat T_4J_4,2, J_8,4J_4,2=J_8,2. Thus it makes no difference whether the operator is applied before or after a consistent coordinate change. One must transport the operator, not merely reuse the same numerical matrix under a new ordering.

    Exact mathematical passage
    
    J_{4,2}\widehat T_2=\widehat T_4J_{4,2},\qquad
    J_{8,4}J_{4,2}=J_{8,2}.
    
j_AUse in source · 3 passages

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  • Use in source · Read passage · 02_coordinates.tex, line 500

    [Coprime factorization] Let A and B be coprime positive integers. For each j modulo AB, write j_A=jpmod A, j_B=jpmod B. Then P_AB,j=P_A,j_AP_B,j_B. Every pair (j_A,j_B) occurs for one residue j modulo AB.

    Exact mathematical passage
    
    j_A=j\pmod A,
    \qquad
    j_B=j\pmod B.
    
J_{a,a}Use in source · 1 passage

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  • Use in source · Read passage · 02_coordinates.tex, line 177

    Typed coordinate naturality. These coordinate changes are coherent through every finite tower. If three complete packet systems are denoted by a,b,c, then J_c,bJ_b,a=J_c,a, J_a,a=I, J_b,a^-1=J_a,b. These laws hold for arbitrary exact packet systems representing the same ambient module. The parent maps supply the component formulas linking children to their parents. Coordinate coherence itself does not require them.

    Exact mathematical passage
    
    J_{c,b}J_{b,a}=J_{c,a},
    \qquad J_{a,a}=I,
    \qquad J_{b,a}^{-1}=J_{a,b}.
    
J_{a,b}Use in source · 1 passage

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  • Use in source · Read passage · 02_coordinates.tex, line 177

    Typed coordinate naturality. These coordinate changes are coherent through every finite tower. If three complete packet systems are denoted by a,b,c, then J_c,bJ_b,a=J_c,a, J_a,a=I, J_b,a^-1=J_a,b. These laws hold for arbitrary exact packet systems representing the same ambient module. The parent maps supply the component formulas linking children to their parents. Coordinate coherence itself does not require them.

    Exact mathematical passage
    
    J_{c,b}J_{b,a}=J_{c,a},
    \qquad J_{a,a}=I,
    \qquad J_{b,a}^{-1}=J_{a,b}.
    
j_BUse in source · 3 passages

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  • Use in source · Read passage · 02_coordinates.tex, line 500

    [Coprime factorization] Let A and B be coprime positive integers. For each j modulo AB, write j_A=jpmod A, j_B=jpmod B. Then P_AB,j=P_A,j_AP_B,j_B. Every pair (j_A,j_B) occurs for one residue j modulo AB.

    Exact mathematical passage
    
    j_A=j\pmod A,
    \qquad
    j_B=j\pmod B.
    
J_{b,a}Use in source · 1 passage

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  • Use in source · Read passage · 02_coordinates.tex, line 177

    Typed coordinate naturality. These coordinate changes are coherent through every finite tower. If three complete packet systems are denoted by a,b,c, then J_c,bJ_b,a=J_c,a, J_a,a=I, J_b,a^-1=J_a,b. These laws hold for arbitrary exact packet systems representing the same ambient module. The parent maps supply the component formulas linking children to their parents. Coordinate coherence itself does not require them.

    Exact mathematical passage
    
    J_{c,b}J_{b,a}=J_{c,a},
    \qquad J_{a,a}=I,
    \qquad J_{b,a}^{-1}=J_{a,b}.
    
J_{b,a}^{-1}Use in source · 1 passage

Search aliases: J_b,a^-1

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  • Use in source · Read passage · 02_coordinates.tex, line 177

    Typed coordinate naturality. These coordinate changes are coherent through every finite tower. If three complete packet systems are denoted by a,b,c, then J_c,bJ_b,a=J_c,a, J_a,a=I, J_b,a^-1=J_a,b. These laws hold for arbitrary exact packet systems representing the same ambient module. The parent maps supply the component formulas linking children to their parents. Coordinate coherence itself does not require them.

    Exact mathematical passage
    
    J_{c,b}J_{b,a}=J_{c,a},
    \qquad J_{a,a}=I,
    \qquad J_{b,a}^{-1}=J_{a,b}.
    
J_{c,a}Use in source · 1 passage

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  • Use in source · Read passage · 02_coordinates.tex, line 177

    Typed coordinate naturality. These coordinate changes are coherent through every finite tower. If three complete packet systems are denoted by a,b,c, then J_c,bJ_b,a=J_c,a, J_a,a=I, J_b,a^-1=J_a,b. These laws hold for arbitrary exact packet systems representing the same ambient module. The parent maps supply the component formulas linking children to their parents. Coordinate coherence itself does not require them.

    Exact mathematical passage
    
    J_{c,b}J_{b,a}=J_{c,a},
    \qquad J_{a,a}=I,
    \qquad J_{b,a}^{-1}=J_{a,b}.
    
J_{c,b}Use in source · 1 passage

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  • Use in source · Read passage · 02_coordinates.tex, line 177

    Typed coordinate naturality. These coordinate changes are coherent through every finite tower. If three complete packet systems are denoted by a,b,c, then J_c,bJ_b,a=J_c,a, J_a,a=I, J_b,a^-1=J_a,b. These laws hold for arbitrary exact packet systems representing the same ambient module. The parent maps supply the component formulas linking children to their parents. Coordinate coherence itself does not require them.

    Exact mathematical passage
    
    J_{c,b}J_{b,a}=J_{c,a},
    \qquad J_{a,a}=I,
    \qquad J_{b,a}^{-1}=J_{a,b}.
    
J_{\Rcal\leftarrow\Pcal}Use in source · 1 passage

Search aliases: J_Rcal←Pcal J_ R← P Rcal leftarrow Pcal mathcal leftarrow mathcal

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  • Use in source · Read passage · 02_coordinates.tex, line 110

    [Exact coordinate change and coherence] For any two packet systems on X, C_ P← QJ_ Q← P=I_X^ P, J_ Q← PC_ P← Q=I_X^ Q. For three packet systems P, Q, and R on X, J_ R← QJ_ Q← P = J_ R← P, C_ P← QC_ Q← R = C_ P← R. If Q refines P through ρ, then (J_ Q← Px)_β = Q_β x_ρ(β), (C_ P← Qy)_α = ∑_ρ(β)=αy_β.

    Exact mathematical passage
    
    J_{\Rcal\leftarrow\Qcal}J_{\Qcal\leftarrow\Pcal}
    =
    J_{\Rcal\leftarrow\Pcal},
    
J_{\Rcal\leftarrow\Qcal}Use in source · 1 passage

Search aliases: J_Rcal←Qcal J_ R← Q Rcal leftarrow Qcal mathcal leftarrow mathcal

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  • Use in source · Read passage · 02_coordinates.tex, line 110

    [Exact coordinate change and coherence] For any two packet systems on X, C_ P← QJ_ Q← P=I_X^ P, J_ Q← PC_ P← Q=I_X^ Q. For three packet systems P, Q, and R on X, J_ R← QJ_ Q← P = J_ R← P, C_ P← QC_ Q← R = C_ P← R. If Q refines P through ρ, then (J_ Q← Px)_β = Q_β x_ρ(β), (C_ P← Qy)_α = ∑_ρ(β)=αy_β.

    Exact mathematical passage
    
    J_{\Rcal\leftarrow\Qcal}J_{\Qcal\leftarrow\Pcal}
    =
    J_{\Rcal\leftarrow\Pcal},
    
kUse in source · 32 passages

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  • Use in source · Read passage · 02_coordinates.tex, line 408

    [Root-of-unity realization] Let R be a commutative semiring, let N>0, and suppose ω,ω^vee,η∈ R satisfy ω^N=1 and the finite N× N Fourier orthogonality table η∑_k=0^N-1(ω^vee)^jkω^rk = 1, · r=j, 0, · r≠ j, 0≤ j,r<N. Then P_N,j = η∑_k=0^N-1(ω^vee)^jkU^k. In particular, if R is a field, N>0, and ω is a primitive Nth root of unity, the certificate holds with ω^vee=ω^-1 and η=N^-1.

    Exact mathematical passage
    
    \eta\sum_{k=0}^{N-1}(\omega^\vee)^{jk}\omega^{rk}
    =
    \begin{cases}
    1,&r=j,\\
    0,&r\ne j,
    \end{cases}
    \qquad 0\le j,r<N.
    
K^\timesUse in source · 1 passage

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  • Use in source · Read passage · 04_arithmetic.tex, line 121

    [Evaluated B ezout spectral projector] Let F,G,U,V∈End_K(Λ⊗_ O K) and let r∈ K^×. Suppose UF+VG=rI, FG=0, FG=GF, GU=UG. Put N=VG. Then N^2=rN. Consequently the operator E=r^-1VG is idempotent, acts as the identity on ker F, and acts as zero on ker G. If V and G preserve Λ, then rE=VG∈End_ O(Λ).

    Exact mathematical passage
    r\in K^\times
\KerUse in source · 10 passages

Search aliases: Ker operatorname

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  • Use in source · Read passage · 04_arithmetic.tex, line 22

    [Bézout spectral projector] Assume that χ_A(x)=f(x)g(x) with monic polynomials f,g∈ O[x] that are coprime in K[x]. Choose u,v∈ O[x] and a nonzero r∈ O such that u(x)f(x)+v(x)g(x)=r. Then E_f=r^-1v(A)g(A) is the projector of V onto Ker f(A) along Ker g(A). In particular, E_f^2=E_f, rE_f∈End_ O(Λ).

    Exact mathematical passage
    \Ker f(A)
\kerUse in source · 6 passages

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  • Use in source · Read passage · 04_arithmetic.tex, line 139

    [Evaluated B ezout spectral projector] Let F,G,U,V∈End_K(Λ⊗_ O K) and let r∈ K^×. Suppose UF+VG=rI, FG=0, FG=GF, GU=UG. Put N=VG. Then N^2=rN. Consequently the operator E=r^-1VG is idempotent, acts as the identity on ker F, and acts as zero on ker G. If V and G preserve Λ, then rE=VG∈End_ O(Λ).

    Exact mathematical passage
    \ker F
lUse in source · 1 passage

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  • Use in source · regrouping_not_averaging.tex, line 52

    =.35pt,] (4.57000,2.26000) rectangle ++(0.57000,0.57000); node[] at (4.85500,2.54500) 2; draw[fill=black!0,draw=black!45,line width=.35pt,] (5.14000,2.26000) rectangle ++(0.57000,0.57000); node[] at (5.42500,2.54500) 0; draw[fill=black!12,draw=black!45,line width=.35pt,] (5.71000,2.26000) rectangle ++(0.57000,0.57000); node[] at (5.99500,2.54500) 4; node[] at (3.15000,2.20000) ∑_rm children; node[] at (1.14000,0.10000) 4×1=4 free coordinates; node[] at (5.14000,0.10000) 2×2=4 free coordinates; d…

    Exact mathematical passage
    \sum_{\rm children}
\lceilUse in source · 3 passages

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  • Use in source · Read passage · 03_weighted.tex, line 338

    , where A=∑_eA_e=D^-1H. With the supplied two-sided inverse D^-1 of D, this gives the explicit two-sided inverse q_L (S^pr_L,ND^-1) of q_L(D+H). If every edge weight is at least m and L≤ mN, then the nilpotence condition follows from the filtration data because m|γ|≤ W(γ). For m>0, the executable choice N=lceil L/mrceil satisfies L≤ mN. This elementary ceiling inequality is also proved in Lean. The choice m=1,N=L gives the standard cutoff. In the DVR example q_L:R→ R/π^L R, this reads q_L(T)^-1 …

    Exact mathematical passage
    N=\lceil L/m\rceil
\lengthUse in source · 1 passage

Search aliases: length operatorname

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  • Use in source · Read passage · 04_arithmetic.tex, line 329

    [Total gluing and worst precision] If G_Λ, P ≅ ⊕_j=1^r O/π^a_j O, then length_ O(G_Λ, P) = ∑_j=1^ra_j, s_Λ( P)=max({0}∪{a_j:1≤ j≤ r}). Thus the lattice index measures the total amount of gluing, while the separation weight measures the worst precision loss in one direction.

    Exact mathematical passage
    
    \length_{\OO}(G_{\Lambda,\Pcal})
    =
    \sum_{j=1}^ra_j,
    \qquad
    s_\Lambda(\Pcal)=\max\bigl(\{0\}\cup\{a_j:1\leq j\leq r\}\bigr).
    
\operatorname{length}Use in source · 1 passage

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  • Use in source · Read passage · 05_defects.tex, line 158

    olomorphic on an open set U containing both spectra. Let Γ be an admissible finite rectifiable Cauchy cycle in U and in both resolvent sets, with winding number one on the union of the spectra and zero outside U. The length of a cycle counts multiplicities. Then Ch(T_f)-h(T_c)C = frac12π i ∫_Γ h(z)(z-T_c)^-1Δ(z-T_f)^-1 dz. Consequently, Ch(T_f)-h(T_c)C · ≤ fraclength(Γ)2π sup_z∈Γ|h(z)| Δ · × sup_z∈Γ (z-T_c)^-1 sup_z∈Γ (z-T_f)^-1 .

    Exact mathematical passage
    
    \|Ch(T_f)-h(T_c)C\|
    &\leq
    \frac{\operatorname{length}(\Gamma)}{2\pi}
    \sup_{z\in\Gamma}|h(z)|\,\|\Delta\|\\
    &\quad\times
    \sup_{z\in\Gamma}\|(z-T_c)^{-1}\|
    \sup_{z\in\Gamma}\|(z-T_f)^{-1}\|.
    
\length_{\OO}Use in source · 1 passage

Search aliases: length_OO length_ O length OO operatorname mathcal

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  • Use in source · Read passage · 04_arithmetic.tex, line 329

    [Total gluing and worst precision] If G_Λ, P ≅ ⊕_j=1^r O/π^a_j O, then length_ O(G_Λ, P) = ∑_j=1^ra_j, s_Λ( P)=max({0}∪{a_j:1≤ j≤ r}). Thus the lattice index measures the total amount of gluing, while the separation weight measures the worst precision loss in one direction.

    Exact mathematical passage
    
    \length_{\OO}(G_{\Lambda,\Pcal})
    =
    \sum_{j=1}^ra_j,
    \qquad
    s_\Lambda(\Pcal)=\max\bigl(\{0\}\cup\{a_j:1\leq j\leq r\}\bigr).
    
\LongleftrightarrowUse in source · 3 passages

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  • Use in source · Read passage · 04_arithmetic.tex, line 378

    [Integral splitting criterion] Every packet projector preserves Λ if and only if Λ=⊕_α(Λ∩ V_α). Equivalently, s_Λ( P)=0 Longleftrightarrow G_Λ, P=0.

    Exact mathematical passage
    
    s_\Lambda(\Pcal)=0
    \quad\Longleftrightarrow\quad
    G_{\Lambda,\Pcal}=0.
    
\lVertUse in source · 1 passage

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  • Use in source · Read passage · 03_weighted.tex, line 281

    lineskip [Certified weighted inverse] Let R be a possibly noncommutative ring, let D^-1 be a supplied two-sided inverse of D, and put A=D^-1H. [label=(alph*)] item If A^r=0, then D+H has the two-sided inverse (D+H)^-1=(∑_k=0^r-1(-A)^k)D^-1. item If R is a complete normed ring and lVert ArVert<1, then ∑_k≥0(-A)^k converges and (D+H)^-1=(∑_k≥0(-A)^k)D^-1.

    Exact mathematical passage
    \lVert A\rVert<1
MUse in source · 22 passages

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  • Use in source · Read passage · 02_coordinates.tex, line 279

    [htbp] centering includegraphics[width=0.96textwidth]03_refinement_incidence.pdf captionThe incidence matrix M_r,s=1 when the fine residue s belongs to the coarse residue r. Its rows implement exact aggregation from fine packets to coarse packets. Common refinements.

    Exact mathematical passage
    M_{r,s}=1
M_{m,n}Use in source · 2 passages

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  • Use in source · Read passage · 04_arithmetic.tex, line 704

    [Smith normal form over a discrete valuation ring] Let M∈ M_m,n( O). There are invertible matrices U∈GL_m( O), V∈GL_n( O) such that UMV = diag(π^s_1,…,π^s_r,0,…,0), where 0≤ s_1≤⋯≤ s_r and r is the rank over K. The exponents are uniquely determined. See [source reference].

    Exact mathematical passage
    M\in M_{m,n}(\OO)
M_{r,s}Use in source · 1 passage

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  • Use in source · Read passage · 02_coordinates.tex, line 279

    [htbp] centering includegraphics[width=0.96textwidth]03_refinement_incidence.pdf captionThe incidence matrix M_r,s=1 when the fine residue s belongs to the coarse residue r. Its rows implement exact aggregation from fine packets to coarse packets. Common refinements.

    Exact mathematical passage
    M_{r,s}=1
\midUse in source · 3 passages

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  • Use in source · Read passage · 04_arithmetic.tex, line 838

    [Concrete Smith-weighted congruence solve] Let p>1 and consider the diagonal system over ( Z/(p^L) Z)^d diag(p^s_1,…,p^s_d)x=b pmodp^L. The system is solvable if and only if p^min(s_i,L)mid (b_i)_val for every i, where (b_i)_val is the canonical natural representative. Conditional on this admissibility condition, the number of solutions is p^∑_i=1^dmin(s_i,L). If any coordinate is inadmissible, the solution set is empty and its cardinality is zero.

    Exact mathematical passage
    
    p^{\min(s_i,L)}\mid (b_i)_{\mathrm{val}}
    
\mathbb NUse in source · 1 passage

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  • Use in source · Read passage · 03_weighted.tex, line 445

    [Several independent weights] Suppose every edge has a weight vector w(e)=(w_1(e),…,w_r(e))∈ N^r∖{0}. Replace t^w(e) by t_1^w_1(e)⋯ t_r^w_r(e). The resulting multigraded transfer series is rational in t_1,…,t_r.

    Exact mathematical passage
    
    w(e)=(w_1(e),\ldots,w_r(e))\in\mathbb N^r\setminus\{0\}.
    
N^{-1}Use in source · 1 passage

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  • Use in source · Read passage · 02_coordinates.tex, line 427

    0, · r≠ j, 0≤ j,r<N. Then P_N,j = η∑_k=0^N-1(ω^vee)^jkU^k. In particular, if R is a field, N>0, and ω is a primitive Nth root of unity, the certificate holds with ω^vee=ω^-1 and η=N^-1.

    Exact mathematical passage
    \eta=N^{-1}
N^2Use in source · 6 passages

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  • Use in source · Read passage · 04_arithmetic.tex, line 130

    [Evaluated B ezout spectral projector] Let F,G,U,V∈End_K(Λ⊗_ O K) and let r∈ K^×. Suppose UF+VG=rI, FG=0, FG=GF, GU=UG. Put N=VG. Then N^2=rN. Consequently the operator E=r^-1VG is idempotent, acts as the identity on ker F, and acts as zero on ker G. If V and G preserve Λ, then rE=VG∈End_ O(Λ).

    Exact mathematical passage
    
    \boxed{N^2=rN.}
    
\mathbb N^rUse in source · 1 passage

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  • Use in source · Read passage · 03_weighted.tex, line 445

    [Several independent weights] Suppose every edge has a weight vector w(e)=(w_1(e),…,w_r(e))∈ N^r∖{0}. Replace t^w(e) by t_1^w_1(e)⋯ t_r^w_r(e). The resulting multigraded transfer series is rational in t_1,…,t_r.

    Exact mathematical passage
    
    w(e)=(w_1(e),\ldots,w_r(e))\in\mathbb N^r\setminus\{0\}.
    
N_{01}Use in source · 2 passages

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  • Use in source · Read passage · 01_orientation.tex, line 56

    A simple two packet model already contains all four notions. Let X=X_0⊕ X_1, D=D_0 · 0 0 · D_1, N=0 · N_01{ N_10 · 0. A finer family may split X_0 and X_1 into smaller summands. The blocks N_01 and N_10 may enter at different filtration weights. Over a fraction field, the rational packet spaces may fail to split the chosen lattice. A coarse operator on one selected summand may also fail to intertwine with the full matrix. The later sections isolate these four effects one at a time.

    Exact mathematical passage
    
    X=X_0\oplus X_1,
    \qquad
    D=\begin{pmatrix}D_0&0\\0&D_1\end{pmatrix},
    \qquad
    N=\begin{pmatrix}0&N_{01}\\N_{10}&0\end{pmatrix}.
    
N_{10}Use in source · 2 passages

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  • Use in source · Read passage · 01_orientation.tex, line 56

    A simple two packet model already contains all four notions. Let X=X_0⊕ X_1, D=D_0 · 0 0 · D_1, N=0 · N_01{ N_10 · 0. A finer family may split X_0 and X_1 into smaller summands. The blocks N_01 and N_10 may enter at different filtration weights. Over a fraction field, the rational packet spaces may fail to split the chosen lattice. A coarse operator on one selected summand may also fail to intertwine with the full matrix. The later sections isolate these four effects one at a time.

    Exact mathematical passage
    
    X=X_0\oplus X_1,
    \qquad
    D=\begin{pmatrix}D_0&0\\0&D_1\end{pmatrix},
    \qquad
    N=\begin{pmatrix}0&N_{01}\\N_{10}&0\end{pmatrix}.
    
\notUse in source · 1 passage

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  • Use in source · Read passage · 04_arithmetic.tex, line 464

    be a rational projector on V, let Λ be a lattice, and let s=s_Λ(E). For every m≥0, the rule [x]_m+s⟼[Ex]_m from Λ/π^m+sΛ to V/π^mΛ is well defined. Here m is an integer. If d is an integer with 0≤ d<s, then for every integer m≥0 there are x,y∈Λ such that x≡ ypmodπ^m+dΛ but Exnot≡ Eypmodπ^mΛ. Thus s extra digits are both sufficient and necessary for a uniform precision guarantee.

    Exact mathematical passage
    
    Ex\not\equiv Ey\pmod{\pi^m\Lambda}.
    
o_mUse in source · 1 passage

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  • Use in source · visual_atlas.tex, line 481

    vpage20Filter first or split first: same outputMODEL F / A FINITE POLYPHASE REALIZATIONTraditional paper: Section B.1 (p. 47) Use the finitely supported signal x=(1,2,3,4,5,6) and the filter h=(1,2,1). Outside the displayed support, the input is zero. Let e_m=x_2m and o_m=x_2m+1.

    Exact mathematical passage
    o_m=x_{2m+1}
\OO^2Use in source · 1 passage

Search aliases: OO^2 O^2 OO mathcal

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  • Use in source · Read passage · 04_arithmetic.tex, line 103

    [A resultant bound that is not exact] Let A=diag(0,π^s) on the standard lattice Λ= O^2. The factors x and x-π^s have resultant -π^s, up to the harmless choice of resultant order, but the two spectral projectors are the integral coordinate projectors. Their exact separation weight is zero. The resultant sees the closeness of the two eigenvalues. It does not see that the chosen lattice already splits along their eigenspaces.

    Exact mathematical passage
    \Lambda=\OO^2
p^LUse in source · 10 passages

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  • Use in source · Read passage · 04_arithmetic.tex, line 832

    [Concrete Smith-weighted congruence solve] Let p>1 and consider the diagonal system over ( Z/(p^L) Z)^d diag(p^s_1,…,p^s_d)x=b pmodp^L. The system is solvable if and only if p^min(s_i,L)mid (b_i)_val for every i, where (b_i)_val is the canonical natural representative. Conditional on this admissibility condition, the number of solutions is p^∑_i=1^dmin(s_i,L). If any coordinate is inadmissible, the solution set is empty and its cardinality is zero.

    Exact mathematical passage
    (\Z/(p^L)\Z)^d
p^{\min(s,L)}Use in source · 3 passages

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  • Use in source · Read passage · 04_arithmetic.tex, line 856

    Lean proves the one-coordinate arithmetic directly over Z/p^L Z for every p>1: (∃ x∈ Z/p^L Z: p^s x=bpmodp^L) Longleftrightarrow p^min(s,L)mid b_val, where b_val is the canonical natural representative, and every admissible fibre has exactly p^min(s,L) elements. The coordinates are independent, so the product equivalence gives the displayed global count. If one coordinate fibre is empty, the global fibre is empty. Lean proves both the global solvability equivalence and the conditional count, inc…

    Exact mathematical passage
    
    \bigl(\exists x\in\mathbb Z/p^L\mathbb Z:\quad p^s x=b\pmod{p^L}\bigr)
    \quad\Longleftrightarrow\quad
    p^{\min(s,L)}\mid b_{\mathrm{val}},
    
p^{\min(s_i,L)}Use in source · 1 passage

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  • Use in source · Read passage · 04_arithmetic.tex, line 838

    [Concrete Smith-weighted congruence solve] Let p>1 and consider the diagonal system over ( Z/(p^L) Z)^d diag(p^s_1,…,p^s_d)x=b pmodp^L. The system is solvable if and only if p^min(s_i,L)mid (b_i)_val for every i, where (b_i)_val is the canonical natural representative. Conditional on this admissibility condition, the number of solutions is p^∑_i=1^dmin(s_i,L). If any coordinate is inadmissible, the solution set is empty and its cardinality is zero.

    Exact mathematical passage
    
    p^{\min(s_i,L)}\mid (b_i)_{\mathrm{val}}
    
p^sUse in source · 2 passages

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  • Use in source · Read passage · 04_arithmetic.tex, line 856

    Lean proves the one-coordinate arithmetic directly over Z/p^L Z for every p>1: (∃ x∈ Z/p^L Z: p^s x=bpmodp^L) Longleftrightarrow p^min(s,L)mid b_val, where b_val is the canonical natural representative, and every admissible fibre has exactly p^min(s,L) elements. The coordinates are independent, so the product equivalence gives the displayed global count. If one coordinate fibre is empty, the global fibre is empty. Lean proves both the global solvability equivalence and the conditional count, inc…

    Exact mathematical passage
    
    \bigl(\exists x\in\mathbb Z/p^L\mathbb Z:\quad p^s x=b\pmod{p^L}\bigr)
    \quad\Longleftrightarrow\quad
    p^{\min(s,L)}\mid b_{\mathrm{val}},
    
p^{s_1}Use in source · 1 passage

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  • Use in source · Read passage · 04_arithmetic.tex, line 833

    [Concrete Smith-weighted congruence solve] Let p>1 and consider the diagonal system over ( Z/(p^L) Z)^d diag(p^s_1,…,p^s_d)x=b pmodp^L. The system is solvable if and only if p^min(s_i,L)mid (b_i)_val for every i, where (b_i)_val is the canonical natural representative. Conditional on this admissibility condition, the number of solutions is p^∑_i=1^dmin(s_i,L). If any coordinate is inadmissible, the solution set is empty and its cardinality is zero.

    Exact mathematical passage
    
    \diag(p^{s_1},\ldots,p^{s_d})x=b
    \pmod{p^L}.
    
p^{s_d}Use in source · 1 passage

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  • Use in source · Read passage · 04_arithmetic.tex, line 833

    [Concrete Smith-weighted congruence solve] Let p>1 and consider the diagonal system over ( Z/(p^L) Z)^d diag(p^s_1,…,p^s_d)x=b pmodp^L. The system is solvable if and only if p^min(s_i,L)mid (b_i)_val for every i, where (b_i)_val is the canonical natural representative. Conditional on this admissibility condition, the number of solutions is p^∑_i=1^dmin(s_i,L). If any coordinate is inadmissible, the solution set is empty and its cardinality is zero.

    Exact mathematical passage
    
    \diag(p^{s_1},\ldots,p^{s_d})x=b
    \pmod{p^L}.
    
p^{s_i}Use in source · 1 passage

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  • Use in source · Read passage · 04_arithmetic.tex, line 886

    If a Smith form is rank deficient, a literal zero diagonal factor requires the corresponding target coordinate to vanish modulo p^L and then contributes all p^L possible coordinate values. In the concrete quotient it can equivalently be represented by any weight s_i≥ L, since p^s_i=0 in Z/(p^L) Z. The theorem then gives exactly that condition and factor. The numbered theorem takes the diagonal data as its input.

    Exact mathematical passage
    p^{s_i}=0
p^{\sum_{i=1}^d\min(s_i,L)}Use in source · 1 passage

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  • Use in source · Read passage · 04_arithmetic.tex, line 844

    ongruence solve] Let p>1 and consider the diagonal system over ( Z/(p^L) Z)^d diag(p^s_1,…,p^s_d)x=b pmodp^L. The system is solvable if and only if p^min(s_i,L)mid (b_i)_val for every i, where (b_i)_val is the canonical natural representative. Conditional on this admissibility condition, the number of solutions is p^∑_i=1^dmin(s_i,L). If any coordinate is inadmissible, the solution set is empty and its cardinality is zero.

    Exact mathematical passage
    
    \boxed{
    p^{\sum_{i=1}^d\min(s_i,L)}.
    }
    
P_0Use in source · 1 passage

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  • Use in source · Read passage · 02_coordinates.tex, line 352

    [A two level split] Let X=X_00⊕ X_01⊕ X_10⊕ X_11. Assume that all four summands are nonzero. The four coordinate projections form a fine packet system. The two sums P_0=Q_00+Q_01, P_1=Q_10+Q_11 form a coarse packet system. If x=(x_00,x_01,x_10,x_11), the coarse coordinates are (x_00+x_01,x_10+x_11) when the sums are interpreted inside the two coarse direct summands. Fine analysis recovers the four entries exactly. Nothing has been approximated.

    Exact mathematical passage
    
    P_0=Q_{00}+Q_{01},
    \qquad
    P_1=Q_{10}+Q_{11}
    
P_1Use in source · 1 passage

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  • Use in source · Read passage · 02_coordinates.tex, line 352

    [A two level split] Let X=X_00⊕ X_01⊕ X_10⊕ X_11. Assume that all four summands are nonzero. The four coordinate projections form a fine packet system. The two sums P_0=Q_00+Q_01, P_1=Q_10+Q_11 form a coarse packet system. If x=(x_00,x_01,x_10,x_11), the coarse coordinates are (x_00+x_01,x_10+x_11) when the sums are interpreted inside the two coarse direct summands. Fine analysis recovers the four entries exactly. Nothing has been approximated.

    Exact mathematical passage
    
    P_0=Q_{00}+Q_{01},
    \qquad
    P_1=Q_{10}+Q_{11}
    
P_{12,7}Use in source · 3 passages

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  • Use in source · Read passage · 02_coordinates.tex, line 530

    [Residues modulo twelve] The pair (jpmod4,jpmod3)=(3,1) corresponds to j=7 modulo 12. Hence P_12,7=P_4,3P_3,1. This factorization concerns addresses. It does not say that the two factors have the same integral spectral behavior.

    Exact mathematical passage
    
    P_{12,7}=P_{4,3}P_{3,1}.
    
P_{2,0}Use in source · 5 passages

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  • Use in source · visual_atlas.tex, line 46

    vpage3Follow one coefficient through the towerMODEL A / LOSSLESS ADDRESS REFINEMENTTraditional paper: Theorem 3.3 (p. 3), Theorem 4.6 (p. 11) Take a vector x=(x_0,…,x_15). A packet is not a single summary number: it retains every coefficient at its selected addresses. For example, P_2,0x=(x_0,0,x_2,0,…,x_14,0). The rail below lists the addresses in each packet. Its display order groups descendants under their parents. The matrix example on V5 instead uses increasing residue order.

    Exact mathematical passage
    
    P_{2,0}x=(x_0,0,x_2,0,\ldots,x_{14},0).
    
P_{2,1}Use in source · 2 passages

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  • Use in source · division_free_masks.tex, line 36

    75000,2.55000) rectangle ++(0.75000,0.60000); node[] at (4.12500,2.85000) 0; draw[fill=black!22,draw=black!45,line width=.35pt,] (4.50000,2.55000) rectangle ++(0.75000,0.60000); node[] at (4.87500,2.85000) 1; draw[fill=black!0,draw=black!45,line width=.35pt,] (5.25000,2.55000) rectangle ++(0.75000,0.60000); node[] at (5.62500,2.85000) 0; node[anchor=east] at (-0.20000,2.00000) P_2,1x; draw[fill=black!0,draw=black!45,line width=.35pt,] (0.00000,1.70000) rectangle ++(0.75000,0.60000); node[] at (0…

    Exact mathematical passage
    P_{2,1}x
P_{3,1}Use in source · 3 passages

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  • Use in source · Read passage · 02_coordinates.tex, line 530

    [Residues modulo twelve] The pair (jpmod4,jpmod3)=(3,1) corresponds to j=7 modulo 12. Hence P_12,7=P_4,3P_3,1. This factorization concerns addresses. It does not say that the two factors have the same integral spectral behavior.

    Exact mathematical passage
    
    P_{12,7}=P_{4,3}P_{3,1}.
    
P_{4,0}Use in source · 1 passage

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  • Use in source · visual_atlas.tex, line 59

    The address 6 is even, is 2 modulo 4, and is 6 modulo 8. Its coefficient therefore lies in the successive ranges P_8,6X⊆ P_4,2X⊆ P_2,0X. The corresponding identities hold as operators: P_2,0=P_4,0+P_4,2, P_4,2=P_8,2+P_8,6. Applying either composite parent selector to P_8,6x leaves it unchanged. Applying the odd selector kills it. This is absorption between a parent and a child, rather than an approximate resemblance between nearby scales.

    Exact mathematical passage
    
    P_{2,0}=P_{4,0}+P_{4,2},\qquad
    P_{4,2}=P_{8,2}+P_{8,6}.
    
P_{4,2}Use in source · 2 passages

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  • Use in source · visual_atlas.tex, line 55

    The address 6 is even, is 2 modulo 4, and is 6 modulo 8. Its coefficient therefore lies in the successive ranges P_8,6X⊆ P_4,2X⊆ P_2,0X. The corresponding identities hold as operators: P_2,0=P_4,0+P_4,2, P_4,2=P_8,2+P_8,6. Applying either composite parent selector to P_8,6x leaves it unchanged. Applying the odd selector kills it. This is absorption between a parent and a child, rather than an approximate resemblance between nearby scales.

    Exact mathematical passage
    
    P_{8,6}X\subseteq P_{4,2}X\subseteq P_{2,0}X.
    
P_{4,3}Use in source · 3 passages

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  • Use in source · Read passage · 02_coordinates.tex, line 530

    [Residues modulo twelve] The pair (jpmod4,jpmod3)=(3,1) corresponds to j=7 modulo 12. Hence P_12,7=P_4,3P_3,1. This factorization concerns addresses. It does not say that the two factors have the same integral spectral behavior.

    Exact mathematical passage
    
    P_{12,7}=P_{4,3}P_{3,1}.
    
P_{8,2}Use in source · 1 passage

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  • Use in source · visual_atlas.tex, line 59

    The address 6 is even, is 2 modulo 4, and is 6 modulo 8. Its coefficient therefore lies in the successive ranges P_8,6X⊆ P_4,2X⊆ P_2,0X. The corresponding identities hold as operators: P_2,0=P_4,0+P_4,2, P_4,2=P_8,2+P_8,6. Applying either composite parent selector to P_8,6x leaves it unchanged. Applying the odd selector kills it. This is absorption between a parent and a child, rather than an approximate resemblance between nearby scales.

    Exact mathematical passage
    
    P_{2,0}=P_{4,0}+P_{4,2},\qquad
    P_{4,2}=P_{8,2}+P_{8,6}.
    
P_{8,6}Use in source · 3 passages

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  • Use in source · visual_atlas.tex, line 55

    The address 6 is even, is 2 modulo 4, and is 6 modulo 8. Its coefficient therefore lies in the successive ranges P_8,6X⊆ P_4,2X⊆ P_2,0X. The corresponding identities hold as operators: P_2,0=P_4,0+P_4,2, P_4,2=P_8,2+P_8,6. Applying either composite parent selector to P_8,6x leaves it unchanged. Applying the odd selector kills it. This is absorption between a parent and a child, rather than an approximate resemblance between nearby scales.

    Exact mathematical passage
    
    P_{8,6}X\subseteq P_{4,2}X\subseteq P_{2,0}X.
    
P_aUse in source · 6 passages

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  • Use in source · Read passage · 02_coordinates.tex, line 186

    The same coherence applies to operators. Let P_a,P_b be packet systems on X, let Q_a,Q_b be packet systems on Y, where X and Y are modules over the same scalar ring, and let T:X→ Y be a linear map over that ring. Its exact coordinate representation widehat T_Q,P= A_QT S_P preserves identities and typed composition, and the naturality square is J^Y_Q_b,Q_a widehat T_Q_a,P_a = widehat T_Q_b,P_b J^X_P_b,P_a. The identity, cocycle, composition, inverse, and naturality laws are all proved in Lean. Th…

    Exact mathematical passage
    P_a,P_b
P_{A,j_A}Use in source · 1 passage

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  • Use in source · Read passage · 02_coordinates.tex, line 506

    [Coprime factorization] Let A and B be coprime positive integers. For each j modulo AB, write j_A=jpmod A, j_B=jpmod B. Then P_AB,j=P_A,j_AP_B,j_B. Every pair (j_A,j_B) occurs for one residue j modulo AB.

    Exact mathematical passage
    
    P_{AB,j}=P_{A,j_A}P_{B,j_B}.
    
P_{AB,j}Use in source · 1 passage

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  • Use in source · Read passage · 02_coordinates.tex, line 506

    [Coprime factorization] Let A and B be coprime positive integers. For each j modulo AB, write j_A=jpmod A, j_B=jpmod B. Then P_AB,j=P_A,j_AP_B,j_B. Every pair (j_A,j_B) occurs for one residue j modulo AB.

    Exact mathematical passage
    
    P_{AB,j}=P_{A,j_A}P_{B,j_B}.
    
P_bUse in source · 6 passages

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  • Use in source · Read passage · 02_coordinates.tex, line 186

    The same coherence applies to operators. Let P_a,P_b be packet systems on X, let Q_a,Q_b be packet systems on Y, where X and Y are modules over the same scalar ring, and let T:X→ Y be a linear map over that ring. Its exact coordinate representation widehat T_Q,P= A_QT S_P preserves identities and typed composition, and the naturality square is J^Y_Q_b,Q_a widehat T_Q_a,P_a = widehat T_Q_b,P_b J^X_P_b,P_a. The identity, cocycle, composition, inverse, and naturality laws are all proved in Lean. Th…

    Exact mathematical passage
    P_a,P_b
P_{B,j_B}Use in source · 1 passage

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  • Use in source · Read passage · 02_coordinates.tex, line 506

    [Coprime factorization] Let A and B be coprime positive integers. For each j modulo AB, write j_A=jpmod A, j_B=jpmod B. Then P_AB,j=P_A,j_AP_B,j_B. Every pair (j_A,j_B) occurs for one residue j modulo AB.

    Exact mathematical passage
    
    P_{AB,j}=P_{A,j_A}P_{B,j_B}.
    
P_jUse in source · 1 passage

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  • Use in source · finite_fourier_table.tex, line 22

    000,0.70000); node[] at (0.35000,1.45000) 0; draw[fill=black!0,draw=black!45,line width=.35pt,] (0.70000,1.10000) rectangle ++(0.70000,0.70000); node[] at (1.05000,1.45000) 0; draw[fill=black!12,draw=black!45,line width=.35pt,] (1.40000,1.10000) rectangle ++(0.70000,0.70000); node[] at (1.75000,1.45000) 3; node[] at (3.70000,2.05000) × 5; node[] at (6.05000,3.75000) P_j(z^r): 5=3^-1pmod7; draw[fill=black!12,draw=black!45,line width=.35pt,] (5.00000,2.50000) rectangle ++(0.70000,0.70000); node[] …

    Exact mathematical passage
    P_j(z^r):\ 5=3^{-1}\pmod7
P_{M,s}Use in source · 1 passage

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  • Use in source · Read passage · 02_coordinates.tex, line 478

    [Nested residue refinement] Let N,M be positive integers with N dividing M, and let 0≤ j<N. Then P_N,j = ∑_substack0≤ s<M s≡ jpmod NP_M,s. When R is nonzero, the packet system modulo M refines the packet system modulo N.

    Exact mathematical passage
    
    P_{N,j}
    =
    \sum_{\substack{0\leq s<M\\s\equiv j\pmod N}}P_{M,s}.
    
P_{N,i}Use in source · 3 passages

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  • Use in source · Read passage · 02_coordinates.tex, line 383

    [Residue packet algebra] For every commutative ring R, the operators (P_N,j)_0≤ j<N satisfy the identities below. If R is nonzero, they form a packet system on R[[z]]: P_N,iP_N,j=δ_ijP_N,j, ∑_j=0^N-1P_N,j=I.

    Exact mathematical passage
    
    P_{N,i}P_{N,j}=\delta_{ij}P_{N,j},
    \qquad
    \sum_{j=0}^{N-1}P_{N,j}=I.
    
P_{N,j+1}Use in source · 1 passage

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  • Use in source · Read passage · 02_coordinates.tex, line 491

    [The shift graph of residue packets] Assume that R is nonzero and N>0. Multiplication by z sends the residue packet P_N,jR[[z]] into P_N,j+1R[[z]], where the index is read modulo N. Its packet graph is the directed cycle 0⟶1⟶⋯⟶ N-1⟶0. Multiplication by a polynomial supported on a set of residues gives the corresponding finite set of phase shifts. This is the simplest transfer graph behind a polyphase representation.

    Exact mathematical passage
    P_{N,j+1}R[[z]]
P_{N,j+r}Use in source · 1 passage

Search aliases: P_N,j+r

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  • Use in source · Read passage · 06_models.tex, line 24

    A banded operator need not remain banded after residue reordering, but its nonzero couplings become a structured packet graph. With the convention (S_rx)_n=x_n-r, the only active transfer is P_N,j+rS_rP_N,j, with indices taken modulo N. More general finite stencils produce a finite set of active phase differences.

    Exact mathematical passage
    
    P_{N,j+r}S_rP_{N,j},
    
P_{s,t}Use in source · 4 passages

Search aliases: P_s,t

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  • Use in source · Read passage · 03_weighted.tex, line 507

    w(e)≤ n a_n-w(e)(target(e),t). Let T(t)=I-A(t), Q(t)=det T(t), P_s,t(t)=adj(T(t))_s,t. Then Q(0)=1, hence Q≠0 and Q is a unit in Z[[t]], and the independently enumerated walk series satisfies Z_s,t(t)=Q(t)^-1P_s,t(t), Q(t)Z_s,t(t)=P_s,t(t) in Z[[t]].

    Exact mathematical passage
    
    T(t)=I-A(t),\qquad
    Q(t)=\det T(t),\qquad
    P_{s,t}(t)=\operatorname{adj}(T(t))_{s,t}.
    
P_{\alpha'}Use in source · 1 passage

Search aliases: P_α' alpha

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  • Use in source · Read passage · 02_coordinates.tex, line 303

    Commutativity gives R_αβ^2=P_α^2Q_β^2=R_αβ. If (α,β)≠(α',β'), then either P_α P_α'=0 or Q_β Q_β'=0, so the corresponding products annihilate one another. Finally, ∑_α,βR_αβ = (∑_α P_α) (∑_β Q_β) =I_X. For a fixed α, P_α =P_α∑_β Q_β = ∑_β R_αβ, and the same argument works for a fixed β. Since each P_α and Q_β is nonzero, these identities ensure that every parent has a nonzero product child. The two parent maps on the supported product family are therefore surjective. Iteration proves the finite f…

    Exact mathematical passage
    P_\alpha P_{\alpha'}=0
P_\alpha^2Use in source · 1 passage

Search aliases: P_α^2 alpha

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  • Use in source · Read passage · 02_coordinates.tex, line 300

    Commutativity gives R_αβ^2=P_α^2Q_β^2=R_αβ. If (α,β)≠(α',β'), then either P_α P_α'=0 or Q_β Q_β'=0, so the corresponding products annihilate one another. Finally, ∑_α,βR_αβ = (∑_α P_α) (∑_β Q_β) =I_X. For a fixed α, P_α =P_α∑_β Q_β = ∑_β R_αβ, and the same argument works for a fixed β. Since each P_α and Q_β is nonzero, these identities ensure that every parent has a nonzero product child. The two parent maps on the supported product family are therefore surjective. Iteration proves the finite f…

    Exact mathematical passage
    
    R_{\alpha\beta}^2=P_\alpha^2Q_\beta^2=R_{\alpha\beta}.
    
P_{\rho(\beta)}Use in source · 1 passage

Search aliases: P_ρ(β) rho beta

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  • Use in source · Read passage · 02_coordinates.tex, line 57

    0 · ρ(β)≠α. Hence Q_β X⊆ P_ρ(β)X. If a third packet system R refines Q, then R refines P through the composite parent map.

    Exact mathematical passage
    Q_\beta X\subseteq P_{\rho(\beta)}X
\Pcal_mUse in source · 1 passage

Search aliases: Pcal_m P_m Pcal mathcal

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  • Use in source · Read passage · 02_coordinates.tex, line 73

    A refinement tower is a sequence ( P_ℓ)_ℓ≥0 with parent maps ρ_m,ℓ:I_m⟶ I_ℓ (m≥ℓ) such that P_m refines P_ℓ through ρ_m,ℓ for every m≥ℓ, and ρ_ℓ,ℓ=id_I_ℓ, ρ_n,ℓ=ρ_m,ℓ∘ρ_n,m (n≥ m≥ℓ). Thus every parent map witnesses the stated refinement and the maps compose coherently. The next result shows that the coordinate changes form a coherent system.

    Exact mathematical passage
    \Pcal_m
\Pcal_\ellUse in source · 2 passages

Search aliases: Pcal_ℓ P_ℓ Pcal ell mathcal ell

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  • Use in source · Read passage · 02_coordinates.tex, line 68

    A refinement tower is a sequence ( P_ℓ)_ℓ≥0 with parent maps ρ_m,ℓ:I_m⟶ I_ℓ (m≥ℓ) such that P_m refines P_ℓ through ρ_m,ℓ for every m≥ℓ, and ρ_ℓ,ℓ=id_I_ℓ, ρ_n,ℓ=ρ_m,ℓ∘ρ_n,m (n≥ m≥ℓ). Thus every parent map witnesses the stated refinement and the maps compose coherently. The next result shows that the coordinate changes form a coherent system.

    Exact mathematical passage
    (\Pcal_\ell)_{\ell\geq0}
\mathrm{pr}Use in source · 3 passages

Search aliases: pr mathrm

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  • Use in source · Read passage · 03_weighted.tex, line 321

    et q_L:R→ R_L be a ring homomorphism that kills F^L R. Suppose H=∑_e∈ EH_e, D^-1H_e∈ F^w(e)R, w(e)≥1, with E finite. Then q_L(D^-1H)^L=0, the finite sum in [source reference](a) is a two-sided inverse after applying q_L, and its word expansion may discard every word of weight at least L. More explicitly, for a length cutoff N, define S^pr_L,N = ∑_n=0^N-1(-1)^n ∑_substackγ∈ E^n W(γ)<LA_γ. Lean proves directly that q_L(S^pr_L,N) equals the mapped geometric inverse whenever q_L(A^N)=0, and hence is…

    Exact mathematical passage
    
    S^{\mathrm{pr}}_{L,N}
    =
    \sum_{n=0}^{N-1}(-1)^n
    \sum_{\substack{\gamma\in E^n\\W(\gamma)<L}}A_\gamma.
    
\QUse in source · 1 passage

Search aliases: Q mathbb

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  • Use in source · Read passage · 04_arithmetic.tex, line 671

    The two characteristic factors x-1 and x+1 have the same reduction in F_2[x]. The rational matrices E_+ and E_- themselves cannot be reduced modulo 2, because their entries contain 1/2. Consequently the integral special fibre does not inherit their separate idempotent splitting, even though the two projectors remain distinct over Q_2. This is the simplest model of delayed dyadic separation.

    Exact mathematical passage
    \Q_2
\mathbb QUse in source · 2 passages

Search aliases: Q mathbb

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qUse in source · 21 passages

Search aliases: q

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  • Use in source · Read passage · 03_weighted.tex, line 311

    [Finite precision] Let F^bullet R be a multiplicative decreasing filtration and let q_L:R→ R_L be a ring homomorphism that kills F^L R. Suppose H=∑_e∈ EH_e, D^-1H_e∈ F^w(e)R, w(e)≥1, with E finite. Then q_L(D^-1H)^L=0, the finite sum in [source reference](a) is a two-sided inverse after applying q_L, and its word expansion may discard every word of weight at least L. More explicitly, for a length cutoff N, define S^pr_L,N = ∑_n=0^N-1(-1)^n ∑_substackγ∈ E^n

    Exact mathematical passage
    q_L:R\to R_L
q^{(n-r)L+\sum_{i=1}^r\min(s_i,L)}Use in source · 1 passage

Search aliases: q^(n-r)L+∑_i=1^rmin(s_i,L) sum min

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  • Use in source · Read passage · 04_arithmetic.tex, line 770

    rdinality q, fix L≥1, and consider Mx≡ bpmodπ^L. Put widetilde b=Ub for a Smith matrix U as in [source reference]. The congruence is solvable if and only if widetilde b_i≡0 pmodπ^min(s_i,L) (1≤ i≤ r) and widetilde b_i≡0 pmodπ^L (r<i≤ m). When it is solvable, the number of solutions in ( O/π^L O)^n is q^(n-r)L+∑_i=1^rmin(s_i,L).

    Exact mathematical passage
    
    \boxed{
    q^{(n-r)L+\sum_{i=1}^r\min(s_i,L)}.
    }
    
q^LUse in source · 1 passage

Search aliases: q^L

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  • Use in source · Read passage · 04_arithmetic.tex, line 787

    ultiplying the congruence by U reduces it to independent equations π^s_iy_i≡widetilde b_ipmodπ^L (1≤ i≤ r) and zero equations in the remaining rows. Multiplication by π^s_i on O/π^L O has image equal to the elements divisible by π^min(s_i,L) and kernel of size q^min(s_i,L). Each of the n-r unused variables is free and contributes q^L choices. Multiplying the independent counts gives the formula.

    Exact mathematical passage
    q^L
q^{\min(s_i,L)}Use in source · 1 passage

Search aliases: q^min(s_i,L) min

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  • Use in source · Read passage · 04_arithmetic.tex, line 784

    Set x=Vy. Multiplying the congruence by U reduces it to independent equations π^s_iy_i≡widetilde b_ipmodπ^L (1≤ i≤ r) and zero equations in the remaining rows. Multiplication by π^s_i on O/π^L O has image equal to the elements divisible by π^min(s_i,L) and kernel of size q^min(s_i,L). Each of the n-r unused variables is free and contributes q^L choices. Multiplying the independent counts gives the formula.

    Exact mathematical passage
    
    q^{\min(s_i,L)}.
    
q^{\sum_i\min(s_i,L)}Use in source · 1 passage

Search aliases: q^∑_imin(s_i,L) sum min

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  • Use in source · Read passage · 04_arithmetic.tex, line 871

    For an arbitrary DVR O with residue field cardinality q, the analogous formula q^∑_imin(s_i,L) follows from the solvability and fibre count for each coordinate. The current revision adds direct proofs of this DVR coordinate arithmetic; the current correspondence records those targets and the rectangular transport separately. The inherited abstract product interface remains available when the coordinate facts are supplied as certificates. A Smith form and its changes of basis are inputs to the tr…

    Exact mathematical passage
    
    q^{\sum_i\min(s_i,L)}
    
Q_{00}Use in source · 1 passage

Search aliases: Q_00

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  • Use in source · Read passage · 02_coordinates.tex, line 352

    [A two level split] Let X=X_00⊕ X_01⊕ X_10⊕ X_11. Assume that all four summands are nonzero. The four coordinate projections form a fine packet system. The two sums P_0=Q_00+Q_01, P_1=Q_10+Q_11 form a coarse packet system. If x=(x_00,x_01,x_10,x_11), the coarse coordinates are (x_00+x_01,x_10+x_11) when the sums are interpreted inside the two coarse direct summands. Fine analysis recovers the four entries exactly. Nothing has been approximated.

    Exact mathematical passage
    
    P_0=Q_{00}+Q_{01},
    \qquad
    P_1=Q_{10}+Q_{11}
    
Q_{01}Use in source · 1 passage

Search aliases: Q_01

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  • Use in source · Read passage · 02_coordinates.tex, line 352

    [A two level split] Let X=X_00⊕ X_01⊕ X_10⊕ X_11. Assume that all four summands are nonzero. The four coordinate projections form a fine packet system. The two sums P_0=Q_00+Q_01, P_1=Q_10+Q_11 form a coarse packet system. If x=(x_00,x_01,x_10,x_11), the coarse coordinates are (x_00+x_01,x_10+x_11) when the sums are interpreted inside the two coarse direct summands. Fine analysis recovers the four entries exactly. Nothing has been approximated.

    Exact mathematical passage
    
    P_0=Q_{00}+Q_{01},
    \qquad
    P_1=Q_{10}+Q_{11}
    
q_1Use in source · 2 passages

Search aliases: q_1

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  • Use in source · Read passage · 03_weighted.tex, line 422

    [Recurrence for path counts] Write Z_u,v(t)=fracP(t)Q(t), Q(t)=1+q_1t+⋯+q_dt^d. Use the convention deg 0=-∞. Then, for every nonnegative integer n>deg P, a_n+q_1a_n-1+⋯+q_da_n-d=0.

    Exact mathematical passage
    
    Z_{u,v}(t)=\frac{P(t)}{Q(t)},
    \qquad
    Q(t)=1+q_1t+\cdots+q_dt^d.
    
Q_{10}Use in source · 1 passage

Search aliases: Q_10

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  • Use in source · Read passage · 02_coordinates.tex, line 352

    [A two level split] Let X=X_00⊕ X_01⊕ X_10⊕ X_11. Assume that all four summands are nonzero. The four coordinate projections form a fine packet system. The two sums P_0=Q_00+Q_01, P_1=Q_10+Q_11 form a coarse packet system. If x=(x_00,x_01,x_10,x_11), the coarse coordinates are (x_00+x_01,x_10+x_11) when the sums are interpreted inside the two coarse direct summands. Fine analysis recovers the four entries exactly. Nothing has been approximated.

    Exact mathematical passage
    
    P_0=Q_{00}+Q_{01},
    \qquad
    P_1=Q_{10}+Q_{11}
    
Q_{11}Use in source · 1 passage

Search aliases: Q_11

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  • Use in source · Read passage · 02_coordinates.tex, line 352

    [A two level split] Let X=X_00⊕ X_01⊕ X_10⊕ X_11. Assume that all four summands are nonzero. The four coordinate projections form a fine packet system. The two sums P_0=Q_00+Q_01, P_1=Q_10+Q_11 form a coarse packet system. If x=(x_00,x_01,x_10,x_11), the coarse coordinates are (x_00+x_01,x_10+x_11) when the sums are interpreted inside the two coarse direct summands. Fine analysis recovers the four entries exactly. Nothing has been approximated.

    Exact mathematical passage
    
    P_0=Q_{00}+Q_{01},
    \qquad
    P_1=Q_{10}+Q_{11}
    
\Q_2Use in source · 1 passage

Search aliases: Q_2 Q mathbb

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  • Use in source · Read passage · 04_arithmetic.tex, line 671

    The two characteristic factors x-1 and x+1 have the same reduction in F_2[x]. The rational matrices E_+ and E_- themselves cannot be reduced modulo 2, because their entries contain 1/2. Consequently the integral special fibre does not inherit their separate idempotent splitting, even though the two projectors remain distinct over Q_2. This is the simplest model of delayed dyadic separation.

    Exact mathematical passage
    \Q_2
\mathbb Q_2Use in source · 1 passage

Search aliases: Q_2 mathbb

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  • Use in source · Read passage · 04_arithmetic.tex, line 590

    Modulo 2, the two eigenvalues become equal. The rational sign packets remain distinct over Q_2, but the standard lattice does not split into their intersections until one more dyadic digit is retained.

    Exact mathematical passage
    \mathbb Q_2
Q_aUse in source · 2 passages

Search aliases: Q_a

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  • Use in source · Read passage · 02_coordinates.tex, line 186

    The same coherence applies to operators. Let P_a,P_b be packet systems on X, let Q_a,Q_b be packet systems on Y, where X and Y are modules over the same scalar ring, and let T:X→ Y be a linear map over that ring. Its exact coordinate representation widehat T_Q,P= A_QT S_P preserves identities and typed composition, and the naturality square is J^Y_Q_b,Q_a widehat T_Q_a,P_a = widehat T_Q_b,P_b J^X_P_b,P_a. The identity, cocycle, composition, inverse, and naturality laws are all proved in Lean. Th…

    Exact mathematical passage
    Q_a,Q_b
Q_bUse in source · 2 passages

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  • Use in source · Read passage · 02_coordinates.tex, line 186

    The same coherence applies to operators. Let P_a,P_b be packet systems on X, let Q_a,Q_b be packet systems on Y, where X and Y are modules over the same scalar ring, and let T:X→ Y be a linear map over that ring. Its exact coordinate representation widehat T_Q,P= A_QT S_P preserves identities and typed composition, and the naturality square is J^Y_Q_b,Q_a widehat T_Q_a,P_a = widehat T_Q_b,P_b J^X_P_b,P_a. The identity, cocycle, composition, inverse, and naturality laws are all proved in Lean. Th…

    Exact mathematical passage
    Q_a,Q_b
q_dUse in source · 2 passages

Search aliases: q_d

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  • Use in source · Read passage · 03_weighted.tex, line 422

    [Recurrence for path counts] Write Z_u,v(t)=fracP(t)Q(t), Q(t)=1+q_1t+⋯+q_dt^d. Use the convention deg 0=-∞. Then, for every nonnegative integer n>deg P, a_n+q_1a_n-1+⋯+q_da_n-d=0.

    Exact mathematical passage
    
    Z_{u,v}(t)=\frac{P(t)}{Q(t)},
    \qquad
    Q(t)=1+q_1t+\cdots+q_dt^d.
    
q_kUse in source · 2 passages

Search aliases: q_k

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  • Use in source · Read passage · 03_weighted.tex, line 557

    [Linear recurrence] With the canonical polynomials from [source reference], write Q(t)=∑_kq_kt^k, Z_s,t(t)=∑_n≥0a_n(s,t)t^n. Then the walk counts satisfy the recurrence with constant coefficients determined by Q after the finite initial range contributed by P_s,t, with deg 0=-∞: ∑_k=0^nq_k a_n-k(s,t)=0 (n>deg P_s,t).

    Exact mathematical passage
    
    Q(t)=\sum_kq_kt^k,
    \qquad
    Z_{s,t}(t)=\sum_{n\ge0}a_n(s,t)t^n.
    
q_LUse in source · 11 passages

Search aliases: q_L

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  • Use in source · Read passage · 03_weighted.tex, line 311

    [Finite precision] Let F^bullet R be a multiplicative decreasing filtration and let q_L:R→ R_L be a ring homomorphism that kills F^L R. Suppose H=∑_e∈ EH_e, D^-1H_e∈ F^w(e)R, w(e)≥1, with E finite. Then q_L(D^-1H)^L=0, the finite sum in [source reference](a) is a two-sided inverse after applying q_L, and its word expansion may discard every word of weight at least L. More explicitly, for a length cutoff N, define S^pr_L,N = ∑_n=0^N-1(-1)^n ∑_substackγ∈ E^n

    Exact mathematical passage
    q_L:R\to R_L
\mathbb Q_pUse in source · 1 passage

Search aliases: Q_p mathbb

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Q_\alphaUse in source · 3 passages

Search aliases: Q_α alpha

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  • Use in source · Read passage · 02_coordinates.tex, line 240

    Expand the two coarse projectors into their children: P_bTP_a = (∑_ρ(β)=bQ_β) T (∑_ρ(α)=aQ_α). Distributing the finite sums gives the first identity. For the coordinate identity, use [T]_ P= A_ PT S_ P and insert I_X= S_ Q A_ Q.

    Exact mathematical passage
    
    P_bTP_a
    =
    \left(\sum_{\rho(\beta)=b}Q_\beta\right)
    T
    \left(\sum_{\rho(\alpha)=a}Q_\alpha\right).
    
Q_{\beta'}Use in source · 1 passage

Search aliases: Q_β' beta

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  • Use in source · Read passage · 02_coordinates.tex, line 303

    Commutativity gives R_αβ^2=P_α^2Q_β^2=R_αβ. If (α,β)≠(α',β'), then either P_α P_α'=0 or Q_β Q_β'=0, so the corresponding products annihilate one another. Finally, ∑_α,βR_αβ = (∑_α P_α) (∑_β Q_β) =I_X. For a fixed α, P_α =P_α∑_β Q_β = ∑_β R_αβ, and the same argument works for a fixed β. Since each P_α and Q_β is nonzero, these identities ensure that every parent has a nonzero product child. The two parent maps on the supported product family are therefore surjective. Iteration proves the finite f…

    Exact mathematical passage
    Q_\beta Q_{\beta'}=0
Q_\beta^2Use in source · 1 passage

Search aliases: Q_β^2 beta

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  • Use in source · Read passage · 02_coordinates.tex, line 300

    Commutativity gives R_αβ^2=P_α^2Q_β^2=R_αβ. If (α,β)≠(α',β'), then either P_α P_α'=0 or Q_β Q_β'=0, so the corresponding products annihilate one another. Finally, ∑_α,βR_αβ = (∑_α P_α) (∑_β Q_β) =I_X. For a fixed α, P_α =P_α∑_β Q_β = ∑_β R_αβ, and the same argument works for a fixed β. Since each P_α and Q_β is nonzero, these identities ensure that every parent has a nonzero product child. The two parent maps on the supported product family are therefore surjective. Iteration proves the finite f…

    Exact mathematical passage
    
    R_{\alpha\beta}^2=P_\alpha^2Q_\beta^2=R_{\alpha\beta}.
    
Q_\gammaUse in source · 3 passages

Search aliases: Q_γ gamma

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  • Use in source · Read passage · 02_coordinates.tex, line 62

    Multiply the identity P_α=∑_ρ(γ)=αQ_γ by Q_β on either side. Pairwise annihilation in the fine family leaves Q_β when ρ(β)=α and leaves zero otherwise. For transitivity, substitute the child expansion of each Q_β into the expansion of P_α and group the resulting terms by the composite parent.

    Exact mathematical passage
    
    P_\alpha=\sum_{\rho(\gamma)=\alpha}Q_\gamma
    
\QQ_2Use in source · 1 passage

Search aliases: QQ_2 QQ

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  • Use in source · visual_atlas.tex, line 353

    vfig[.94]dyadic_eigenlattice platecaptionAn ordinary integer-lattice picture, not a drawing of the topology of QQ_2. Filled dots have even second coordinate. Unfilled dots lie in the other coset. The hollow point at (1/2,0) records the image of an integral vector under E_+.

    Exact mathematical passage
    \QQ_2
r^{-1}Use in source · 4 passages

Search aliases: r^-1

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  • Use in source · Read passage · 04_arithmetic.tex, line 19

    [Bézout spectral projector] Assume that χ_A(x)=f(x)g(x) with monic polynomials f,g∈ O[x] that are coprime in K[x]. Choose u,v∈ O[x] and a nonzero r∈ O such that u(x)f(x)+v(x)g(x)=r. Then E_f=r^-1v(A)g(A) is the projector of V onto Ker f(A) along Ker g(A). In particular, E_f^2=E_f, rE_f∈End_ O(Λ).

    Exact mathematical passage
    
    E_f=r^{-1}v(A)g(A)
    
r^{-2}Use in source · 1 passage

Search aliases: r^-2

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  • Use in source · Read passage · 04_arithmetic.tex, line 156

    The B ezout identity gives N=rI-UF. The two stated commutation relations and FG=0 give N(UF)=VGUF=VUGF=VUFG=0. Therefore N^2=N(rI-UF)=rN. Since r≠0, E^2=r^-2N^2=E. If Fx=0, the evaluated B ezout identity gives VGx=rx, hence Ex=x. If Gx=0, then Ex=0. The lattice assertion follows directly from rE=VG.

    Exact mathematical passage
    E^2=r^{-2}N^2=E
R_2^{-1}Use in source · 1 passage

Search aliases: R_2^-1

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  • Use in source · visual_atlas.tex, line 113

    The reordered operators and change of coordinates are widehat T_N=R_NTR_N^-1, J_4,2=R_4R_2^-1. Multiplication cancels the intermediate coordinate maps: J_4,2widehat T_2=widehat T_4J_4,2, J_8,4J_4,2=J_8,2. Thus it makes no difference whether the operator is applied before or after a consistent coordinate change. One must transport the operator, not merely reuse the same numerical matrix under a new ordering.

    Exact mathematical passage
    
    \widehat T_N=R_NTR_N^{-1},\qquad J_{4,2}=R_4R_2^{-1}.
    
R_4Use in source · 1 passage

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  • Use in source · visual_atlas.tex, line 113

    The reordered operators and change of coordinates are widehat T_N=R_NTR_N^-1, J_4,2=R_4R_2^-1. Multiplication cancels the intermediate coordinate maps: J_4,2widehat T_2=widehat T_4J_4,2, J_8,4J_4,2=J_8,2. Thus it makes no difference whether the operator is applied before or after a consistent coordinate change. One must transport the operator, not merely reuse the same numerical matrix under a new ordering.

    Exact mathematical passage
    
    \widehat T_N=R_NTR_N^{-1},\qquad J_{4,2}=R_4R_2^{-1}.
    
R_cUse in source · 5 passages

Search aliases: R_c

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  • Use in source · Read passage · 05_defects.tex, line 119

    Inverse witnesses from one side and norm control. For continuous linear maps, the same identity gives the certified norm bound C R_f-R_c C ≤ R_c Δ R_f , from a left inverse witness for the coarse scalar shift and a right inverse witness for the fine scalar shift. These witnesses suffice for the displayed identity. On their own, they need not define inverses on both sides and hence need not define resolvents. If Δ=0, Lean also proves, for every finite polynomial p, the exact compatibility C p(T_f…

    Exact mathematical passage
    
    \boxed{
    \|C R_f-R_c C\|
    \le \|R_c\|\,\|\Delta\|\,\|R_f\|,
    }
    
R_fUse in source · 5 passages

Search aliases: R_f

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  • Use in source · Read passage · 05_defects.tex, line 119

    Inverse witnesses from one side and norm control. For continuous linear maps, the same identity gives the certified norm bound C R_f-R_c C ≤ R_c Δ R_f , from a left inverse witness for the coarse scalar shift and a right inverse witness for the fine scalar shift. These witnesses suffice for the displayed identity. On their own, they need not define inverses on both sides and hence need not define resolvents. If Δ=0, Lean also proves, for every finite polynomial p, the exact compatibility C p(T_f…

    Exact mathematical passage
    
    \boxed{
    \|C R_f-R_c C\|
    \le \|R_c\|\,\|\Delta\|\,\|R_f\|,
    }
    
R_LUse in source · 5 passages

Search aliases: R_L

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  • Use in source · Read passage · 03_weighted.tex, line 187

    [Exact finite precision truncation] Under the hypotheses of [source reference], define R_L = ∑_W(γ)<L(-1)^|γ|A_γ D^-1. Then T^-1-R_L∈ F^L B, TR_L-I∈ F^L B, R_LT-I∈ F^L B. Thus R_L is the exact inverse in B/F^L B.

    Exact mathematical passage
    
    R_L
    =
    \sum_{W(\gamma)<L}(-1)^{|\gamma|}A_\gamma D^{-1}.
    
R_N^{-1}Use in source · 1 passage

Search aliases: R_N^-1

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  • Use in source · visual_atlas.tex, line 113

    The reordered operators and change of coordinates are widehat T_N=R_NTR_N^-1, J_4,2=R_4R_2^-1. Multiplication cancels the intermediate coordinate maps: J_4,2widehat T_2=widehat T_4J_4,2, J_8,4J_4,2=J_8,2. Thus it makes no difference whether the operator is applied before or after a consistent coordinate change. One must transport the operator, not merely reuse the same numerical matrix under a new ordering.

    Exact mathematical passage
    
    \widehat T_N=R_NTR_N^{-1},\qquad J_{4,2}=R_4R_2^{-1}.
    
R_{\alpha\beta}Use in source · 4 passages

Search aliases: R_αβ alpha beta

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  • Use in source · Read passage · 02_coordinates.tex, line 292

    [Common refinement of commuting packet systems] Let P=(P_α)_α∈ I and Q=(Q_β)_β∈ J be packet systems on X. Assume P_α Q_β=Q_β P_α for all α and β. Remove the zero operators from the family R_αβ=P_α Q_β. The remaining operators form a packet system that refines both P and Q. The same statement holds for any finite collection of pairwise commuting packet systems.

    Exact mathematical passage
    
    R_{\alpha\beta}=P_\alpha Q_\beta.
    
R_{\alpha\beta}^2Use in source · 1 passage

Search aliases: R_αβ^2 alpha beta

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  • Use in source · Read passage · 02_coordinates.tex, line 300

    Commutativity gives R_αβ^2=P_α^2Q_β^2=R_αβ. If (α,β)≠(α',β'), then either P_α P_α'=0 or Q_β Q_β'=0, so the corresponding products annihilate one another. Finally, ∑_α,βR_αβ = (∑_α P_α) (∑_β Q_β) =I_X. For a fixed α, P_α =P_α∑_β Q_β = ∑_β R_αβ, and the same argument works for a fixed β. Since each P_α and Q_β is nonzero, these identities ensure that every parent has a nonzero product child. The two parent maps on the supported product family are therefore surjective. Iteration proves the finite f…

    Exact mathematical passage
    
    R_{\alpha\beta}^2=P_\alpha^2Q_\beta^2=R_{\alpha\beta}.
    
R_\gammaUse in source · 6 passages

Search aliases: R_γ gamma

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  • Use in source · Read passage · 02_coordinates.tex, line 326

    Let R_γ be a packet in R. Because R refines P, there is a unique α with P_α R_γ=R_γ. Likewise there is a unique β with Q_β R_γ=R_γ. Therefore P_α Q_β R_γ=R_γ. Every packet of R lies in one product packet. Multiplying ∑_γ R_γ=I_X by P_α Q_β and using the parent identities gives P_α Q_β =∑_substackγ: P_α R_γ=R_γ

    Exact mathematical passage
    R_\gamma
\RcalUse in source · 10 passages

Search aliases: Rcal R mathcal

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  • Use in source · Read passage · 02_coordinates.tex, line 57

    0 · ρ(β)≠α. Hence Q_β X⊆ P_ρ(β)X. If a third packet system R refines Q, then R refines P through the composite parent map.

    Exact mathematical passage
    \Rcal
\rceilUse in source · 3 passages

Search aliases: rceil

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  • Use in source · Read passage · 03_weighted.tex, line 338

    , where A=∑_eA_e=D^-1H. With the supplied two-sided inverse D^-1 of D, this gives the explicit two-sided inverse q_L (S^pr_L,ND^-1) of q_L(D+H). If every edge weight is at least m and L≤ mN, then the nilpotence condition follows from the filtration data because m|γ|≤ W(γ). For m>0, the executable choice N=lceil L/mrceil satisfies L≤ mN. This elementary ceiling inequality is also proved in Lean. The choice m=1,N=L gives the standard cutoff. In the DVR example q_L:R→ R/π^L R, this reads q_L(T)^-1 …

    Exact mathematical passage
    N=\lceil L/m\rceil
\ResUse in source · 4 passages

Search aliases: Res operatorname

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  • Use in source · Read passage · 04_arithmetic.tex, line 73

    [Several coprime spectral packets] Assume χ_A(x)=∏_i=1^rf_i(x), where the monic factors f_i∈ O[x] are pairwise coprime in K[x]. Put g_i=∏_j≠ if_j. There are complementary projectors E_i with im E_i=Ker f_i(A), ∑_iE_i=I, E_iE_j=0 (i≠ j). One may choose E_i so that Res(f_i,g_i)E_i∈End_ O(Λ) up to multiplication of the resultant by a unit.

    Exact mathematical passage
    
    \Res(f_i,g_i)E_i\in\End_{\OO}(\Lambda)
    
\operatorname{Res}Use in source · 1 passage

Search aliases: Res operatorname

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  • Use in source · visual_atlas.tex, line 345

    For the original sign factors the concrete resultant is Res(x-1,x+1)=2 and the bound is sharp. That equality is special to this displayed calculation, not a universal minimality theorem for every resultant certificate.

    Exact mathematical passage
    \operatorname{Res}(x-1,x+1)=2
\rVertUse in source · 1 passage

Search aliases: rVert

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  • Use in source · Read passage · 03_weighted.tex, line 281

    lineskip [Certified weighted inverse] Let R be a possibly noncommutative ring, let D^-1 be a supplied two-sided inverse of D, and put A=D^-1H. [label=(alph*)] item If A^r=0, then D+H has the two-sided inverse (D+H)^-1=(∑_k=0^r-1(-A)^k)D^-1. item If R is a complete normed ring and lVert ArVert<1, then ∑_k≥0(-A)^k converges and (D+H)^-1=(∑_k≥0(-A)^k)D^-1.

    Exact mathematical passage
    \lVert A\rVert<1
\mathcal SUse in source · 3 passages

Search aliases: S mathcal

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  • Use in source · visual_atlas.tex, line 27

    A_N, S_N · Split into range-restricted packet vectors, then sum them. · A permutation/interleaving of eight coordinates.

    Exact mathematical passage
    \mathcal A_N,\mathcal S_N
S^{\mathrm{pr}}_{L,N}Use in source · 3 passages

Search aliases: S^pr_L,N mathrm

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  • Use in source · Read passage · 03_weighted.tex, line 321

    et q_L:R→ R_L be a ring homomorphism that kills F^L R. Suppose H=∑_e∈ EH_e, D^-1H_e∈ F^w(e)R, w(e)≥1, with E finite. Then q_L(D^-1H)^L=0, the finite sum in [source reference](a) is a two-sided inverse after applying q_L, and its word expansion may discard every word of weight at least L. More explicitly, for a length cutoff N, define S^pr_L,N = ∑_n=0^N-1(-1)^n ∑_substackγ∈ E^n W(γ)<LA_γ. Lean proves directly that q_L(S^pr_L,N) equals the mapped geometric inverse whenever q_L(A^N)=0, and hence is…

    Exact mathematical passage
    
    S^{\mathrm{pr}}_{L,N}
    =
    \sum_{n=0}^{N-1}(-1)^n
    \sum_{\substack{\gamma\in E^n\\W(\gamma)<L}}A_\gamma.
    
S^rUse in source · 1 passage

Search aliases: S^r

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  • Use in source · Read passage · 06_models.tex, line 6

    Let x=(x_n)_n∈ Z∈ c_00( Z;R) and let the seed be δ_0 under the bilateral shifts (S^rδ_0)_n=δ_n,r. This makes the algebraic span and every displayed sum finite. The N packets are x_j[m]=x[Nm+j]. Synthesis interleaves these sequences. A linear filter with a finite impulse response that is invariant under shifts becomes an N× N matrix of transfer blocks. Refining from N to M with Nmid M splits each coarse phase into its descendants without changing the reconstructed signal. The same formulas extend…

    Exact mathematical passage
    (S^r\delta_0)_n=\delta_{n,r}
s_0Use in source · 2 passages

Search aliases: s_0

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  • Use in source · visual_atlas.tex, line 453

    vpage19Precision exposes directional freedomMODEL E / A DEPTH-BY-DEPTH FIBER BUDGETTraditional paper: Theorem 10.6 (p. 36) Take p=2 and the supplied diagonal weights (s_0,s_1,s_2)=(0,1,3). At depth L, an admissible target has 2^W(L) solutions, W(L)=min(0,L)+min(1,L)+min(3,L). Each direction contributes only the amount visible at the current depth.

    Exact mathematical passage
    (s_0,s_1,s_2)=(0,1,3)
s_1Use in source · 8 passages

Search aliases: s_1

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  • Use in source · Read passage · 04_arithmetic.tex, line 711

    [Smith normal form over a discrete valuation ring] Let M∈ M_m,n( O). There are invertible matrices U∈GL_m( O), V∈GL_n( O) such that UMV = diag(π^s_1,…,π^s_r,0,…,0), where 0≤ s_1≤⋯≤ s_r and r is the rank over K. The exponents are uniquely determined. See [source reference].

    Exact mathematical passage
    
    UMV
    =
    \diag(\pi^{s_1},\ldots,\pi^{s_r},0,\ldots,0),
    
\mathcal S_2Use in source · 1 passage

Search aliases: S_2 mathcal

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  • Use in source · visual_atlas.tex, line 87

    Define X_N^rm pkt=⊕_j P_N,jX, A_Nx=(P_N,jx)_j, S_N(x_j)_j=∑_jx_j. Completeness and mutual annihilation give both inverse laws. Consequently, J= A_4 S_2, C= A_2 S_4, CJ=I, JC=I. The apparently larger list of fine packets simply has smaller individual packet spaces.

    Exact mathematical passage
    
    J=\mathcal A_4\mathcal S_2,\qquad C=\mathcal A_2\mathcal S_4,
    \qquad CJ=I,\quad JC=I.
    
s_2Use in source · 3 passages

Search aliases: s_2

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  • Use in source · Read passage · 04_arithmetic.tex, line 580

    0 · 1 . For every odd prime p, both projectors preserve Z_p^2. At p=2, s_2(E_+)=s_2(E_-)=1. The factors x-1 and x+1 have resultant 2.

    Exact mathematical passage
    
    s_2(E_+)=s_2(E_-)=1.
    
s_{2,\Z_2^2}Use in source · 1 passage

Search aliases: s_2,Z_2^2 s_2, Z_2^2 Z mathbb

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  • Use in source · Read passage · 04_arithmetic.tex, line 650

    [Odd-adic versus dyadic behavior] For every prime p≠2, every entry of E_+ and E_- is p-integral, and each projector has exact local denominator weight zero. At p=2, each projector has exact local denominator weight one. Multiplication by 2 makes it integral, while the unscaled matrix is not integral: s_2, Z_2^2(E_+)=s_2, Z_2^2(E_-)=1. The characteristic factors x-1 and x+1 have resultant 2. Its 2-adic valuation is one, exactly the two local projector weights above, and its p-adic valuation is ze…

    Exact mathematical passage
    
    s_{2,\Z_2^2}(E_+)=s_{2,\Z_2^2}(E_-)=1.
    
\mathcal S_4Use in source · 1 passage

Search aliases: S_4 mathcal

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  • Use in source · visual_atlas.tex, line 87

    Define X_N^rm pkt=⊕_j P_N,jX, A_Nx=(P_N,jx)_j, S_N(x_j)_j=∑_jx_j. Completeness and mutual annihilation give both inverse laws. Consequently, J= A_4 S_2, C= A_2 S_4, CJ=I, JC=I. The apparently larger list of fine packets simply has smaller individual packet spaces.

    Exact mathematical passage
    
    J=\mathcal A_4\mathcal S_2,\qquad C=\mathcal A_2\mathcal S_4,
    \qquad CJ=I,\quad JC=I.
    
s_dUse in source · 1 passage

Search aliases: s_d

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  • Use in source · Read passage · 04_arithmetic.tex, line 833

    [Concrete Smith-weighted congruence solve] Let p>1 and consider the diagonal system over ( Z/(p^L) Z)^d diag(p^s_1,…,p^s_d)x=b pmodp^L. The system is solvable if and only if p^min(s_i,L)mid (b_i)_val for every i, where (b_i)_val is the canonical natural representative. Conditional on this admissibility condition, the number of solutions is p^∑_i=1^dmin(s_i,L). If any coordinate is inadmissible, the solution set is empty and its cardinality is zero.

    Exact mathematical passage
    
    \diag(p^{s_1},\ldots,p^{s_d})x=b
    \pmod{p^L}.
    
s_iUse in source · 15 passages

Search aliases: s_i

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  • Use in source · Read passage · 04_arithmetic.tex, line 758

    [Smith weighted congruence solve] Let M∈ M_m,n( O) have Smith exponents s_1,…,s_r. Assume the residue field is finite of cardinality q, fix L≥1, and consider Mx≡ bpmodπ^L. Put widetilde b=Ub for a Smith matrix U as in [source reference]. The congruence is solvable if and only if widetilde b_i≡0 pmodπ^min(s_i,L) (1≤ i≤ r) and widetilde b_i≡0 pmodπ^L (r<i≤ m). When it is solvable, the number of solutions in ( O/π^L O)^n is q^(n-r)L+∑_i=1^rmin(s_i,L).

    Exact mathematical passage
    
    \widetilde b_i\equiv0
    \pmod{\pi^{\min(s_i,L)}}
    \qquad(1\leq i\leq r)
    
S_NUse in source · 2 passages

Search aliases: S_N

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  • Use in source · visual_atlas.tex, line 250

    vpage11The residual tells you when to stopMODEL B / A CERTIFIED CUTOFF, NOT A HEURISTICTraditional paper: Theorem 5.10 (p. 17), Corollary 5.11 (p. 18), Section B.2 (p. 47) For S_N=∑_k=0^N-1(-A)^k, telescoping gives (I+A)S_N=S_N(I+A)=I-(-A)^N. Thus the exact residual is known. To certify precision L, it is enough to show that every residual entry is divisible by 2^L.

    Exact mathematical passage
    S_N=\sum_{k=0}^{N-1}(-A)^k
\mathcal S_NUse in source · 2 passages

Search aliases: S_N mathcal

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  • Use in source · visual_atlas.tex, line 27

    A_N, S_N · Split into range-restricted packet vectors, then sum them. · A permutation/interleaving of eight coordinates.

    Exact mathematical passage
    \mathcal A_N,\mathcal S_N
S_rUse in source · 2 passages

Search aliases: S_r

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  • Use in source · Read passage · 06_models.tex, line 23

    A banded operator need not remain banded after residue reordering, but its nonzero couplings become a structured packet graph. With the convention (S_rx)_n=x_n-r, the only active transfer is P_N,j+rS_rP_N,j, with indices taken modulo N. More general finite stencils produce a finite set of active phase differences.

    Exact mathematical passage
    (S_rx)_n=x_{n-r}
s_rUse in source · 5 passages

Search aliases: s_r

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  • Use in source · Read passage · 04_arithmetic.tex, line 711

    [Smith normal form over a discrete valuation ring] Let M∈ M_m,n( O). There are invertible matrices U∈GL_m( O), V∈GL_n( O) such that UMV = diag(π^s_1,…,π^s_r,0,…,0), where 0≤ s_1≤⋯≤ s_r and r is the rank over K. The exponents are uniquely determined. See [source reference].

    Exact mathematical passage
    
    UMV
    =
    \diag(\pi^{s_1},\ldots,\pi^{s_r},0,\ldots,0),
    
s_{\Lambda_s}Use in source · 1 passage

Search aliases: s_Λ_s Lambda

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  • Use in source · Read passage · 04_arithmetic.tex, line 522

    with two lattices] Let V=Ke_1⊕ Ke_2 and let E project onto Ke_1. On the split lattice Λ_0= O e_1⊕ O e_2, the weight is zero. Fix s≥1 and consider Λ_s = O e_1+ O(π^-se_1+e_2). Then Λ_s∩ Ke_1= O e_1, Λ_s∩ Ke_2=π^s O e_2. The gluing module is isomorphic to O/π^s O, so s_Λ_s(E)=s. The rational decomposition has not changed. Only the lattice has changed.

    Exact mathematical passage
    
    s_{\Lambda_s}(E)=s.
    
\mathrm{Smith}Use in source · 1 passage

Search aliases: Smith mathrm

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  • Use in source · Read passage · 06_models.tex, line 79

    The symmetric weight w_Smith(Γ) = frac1|1-Γ|^2 + frac1|1+Γ|^2 indicates where small errors in reflection coordinates produce large impedance or admittance errors.

    Exact mathematical passage
    
    w_{\mathrm{Smith}}(\Gamma)
    =
    \frac1{|1-\Gamma|^2}
    +
    \frac1{|1+\Gamma|^2}
    
\mathrm{source}Use in source · 1 passage

Search aliases: source mathrm

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  • Use in source · visual_atlas.tex, line 289

    headThe first-edge decomposition Let a_n(s,t) count walks of total weight n from s to t. Removing the first edge gives a_n(s,t)=1_s=t, n=0 +∑_substacke: source(e)=s w(e)≤ n a_n-w(e)(target(e),t). The empty walk is allowed precisely on the diagonal at weight zero. Positive weights ensure that every contributing walk has length at most n, so enumeration at each fixed weight is finite.

    Exact mathematical passage
    
    a_n(s,t)=\mathbf1_{s=t,\,n=0}
     +\sum_{\substack{e:\,\mathrm{source}(e)=s\\w(e)\le n}}
     a_{n-w(e)}(\mathrm{target}(e),t).
    
\operatorname{source}Use in source · 1 passage

Search aliases: source operatorname

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  • Use in source · Read passage · 03_weighted.tex, line 499

    [Automatic finite-graph transfer-zeta rationality] Assume the vertex and edge sets are finite and every edge has positive integer weight. For every n, exact enumeration of edge tuples of lengths at most n, followed by endpoint and total-weight filtering, returns a_n(s,t). These coefficients obey the recurrence obtained by removing the first edge a_n(s,t) = 1_s=t, n=0 +∑_substacke: source(e)=s w(e)≤ n a_n-w(e)(target(e),t). Let T(t)=I-A(t), Q(t)=det T(t), P_s,t(t)=adj(T(t))_s,t. Then Q(0)=1, henc…

    Exact mathematical passage
    
    a_n(s,t)
    =
    \mathbf 1_{s=t,\,n=0}
    +\sum_{\substack{e:\,\operatorname{source}(e)=s\\w(e)\le n}}
    a_{n-w(e)}(\operatorname{target}(e),t).
    
\supUse in source · 1 passage

Search aliases: sup

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  • Use in source · Read passage · 05_defects.tex, line 158

    olomorphic on an open set U containing both spectra. Let Γ be an admissible finite rectifiable Cauchy cycle in U and in both resolvent sets, with winding number one on the union of the spectra and zero outside U. The length of a cycle counts multiplicities. Then Ch(T_f)-h(T_c)C = frac12π i ∫_Γ h(z)(z-T_c)^-1Δ(z-T_f)^-1 dz. Consequently, Ch(T_f)-h(T_c)C · ≤ fraclength(Γ)2π sup_z∈Γ|h(z)| Δ · × sup_z∈Γ (z-T_c)^-1 sup_z∈Γ (z-T_f)^-1 .

    Exact mathematical passage
    
    \|Ch(T_f)-h(T_c)C\|
    &\leq
    \frac{\operatorname{length}(\Gamma)}{2\pi}
    \sup_{z\in\Gamma}|h(z)|\,\|\Delta\|\\
    &\quad\times
    \sup_{z\in\Gamma}\|(z-T_c)^{-1}\|
    \sup_{z\in\Gamma}\|(z-T_f)^{-1}\|.
    
\sup_{z\in\Gamma}Use in source · 1 passage

Search aliases: sup_z∈Γ sup in Gamma

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  • Use in source · Read passage · 05_defects.tex, line 158

    olomorphic on an open set U containing both spectra. Let Γ be an admissible finite rectifiable Cauchy cycle in U and in both resolvent sets, with winding number one on the union of the spectra and zero outside U. The length of a cycle counts multiplicities. Then Ch(T_f)-h(T_c)C = frac12π i ∫_Γ h(z)(z-T_c)^-1Δ(z-T_f)^-1 dz. Consequently, Ch(T_f)-h(T_c)C · ≤ fraclength(Γ)2π sup_z∈Γ|h(z)| Δ · × sup_z∈Γ (z-T_c)^-1 sup_z∈Γ (z-T_f)^-1 .

    Exact mathematical passage
    
    \|Ch(T_f)-h(T_c)C\|
    &\leq
    \frac{\operatorname{length}(\Gamma)}{2\pi}
    \sup_{z\in\Gamma}|h(z)|\,\|\Delta\|\\
    &\quad\times
    \sup_{z\in\Gamma}\|(z-T_c)^{-1}\|
    \sup_{z\in\Gamma}\|(z-T_f)^{-1}\|.
    
\operatorname{synthesize}Use in source · 1 passage

Search aliases: synthesize operatorname

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  • Use in source · Read passage · 06_models.tex, line 214

    The verified contract is synthesize(analyze(x,N))=x. The Lean counterpart uses packet coordinates restricted to projector ranges and proves both inverse laws. The finite Python routine checks the concrete array realization.

    Exact mathematical passage
    \operatorname{synthesize}(\operatorname{analyze}(x,N))=x
\mathsf TUse in source · 3 passages

Search aliases: T mathsf

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  • Use in source · Read passage · 03_weighted.tex, line 395

    [Rationality of the transfer series] The weighted transfer series satisfies Z_u,v(t) = u^ T(I-A(t))^-1v. It is a rational function whose denominator divides det(I-A(t)).

    Exact mathematical passage
    
    Z_{u,v}(t)
    =
    u^{\mathsf T}(I-A(t))^{-1}v.
    
T^{-1}Use in source · 6 passages

Search aliases: T^-1

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  • Use in source · Read passage · 03_weighted.tex, line 58

    B be invertible with D,D^-1∈ F^0 B. Let E be a finite set and suppose T=D+∑_e∈ EN_e, N_e∈ F^w(e) B, w(e)≥1. Set A_e=D^-1N_e. For a word γ=(e_1,…,e_r), write A_γ=A_e_r⋯ A_e_1, W(γ)=∑_j=1^rw(e_j). The empty word has weight zero and contributes the identity. Then T is invertible and T^-1 = ∑_γ(-1)^|γ|A_γ D^-1. The series converges in the filtration, and the term indexed by γ belongs to F^W(γ) B.

    Exact mathematical passage
    
    T^{-1}
    =
    \sum_\gamma(-1)^{|\gamma|}A_\gamma D^{-1}.
    
t^2Use in source · 7 passages

Search aliases: t^2

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  • Use in source · Read passage · 03_weighted.tex, line 463

    [A transfer series with one loop] Take vertices 0, 1, and 2. Give the edge 0→1 weight one, the loop 1→1 weight two, and the edge 1→2 weight one. Every path from 0 to 2 uses the first and last edges and may traverse the loop any number of times. Hence Z_0,2(t) = t^2(1+t^2+t^4+⋯) = fract^21-t^2. There is one path at every positive even weight and no path at an odd weight. The denominator records the increase of two units produced by the loop.

    Exact mathematical passage
    
    Z_{0,2}(t)
    =
    t^2(1+t^2+t^4+\cdots)
    =
    \frac{t^2}{1-t^2}.
    
t^3Use in source · 4 passages

Search aliases: t^3

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  • Use in source · Read passage · 03_weighted.tex, line 581

    [A computed transfer zeta] For the graph used in the numerical companion, the walk series from packet 0 to packet 2 is Z_0,2(t) = fract^31-t^2-t^3-2t^4+t^5+t^6+t^7-t^9. The first nonzero coefficients are 1,1,1,3,1,5,4,10,7,19,17,37,… at their corresponding weights. Direct enumeration through weight 30 agrees coefficient by coefficient with the rational expansion.

    Exact mathematical passage
    
    Z_{0,2}(t)
    =
    \frac{t^3}{1-t^2-t^3-2t^4+t^5+t^6+t^7-t^9}.
    
t^4Use in source · 3 passages

Search aliases: t^4

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  • Use in source · Read passage · 03_weighted.tex, line 463

    [A transfer series with one loop] Take vertices 0, 1, and 2. Give the edge 0→1 weight one, the loop 1→1 weight two, and the edge 1→2 weight one. Every path from 0 to 2 uses the first and last edges and may traverse the loop any number of times. Hence Z_0,2(t) = t^2(1+t^2+t^4+⋯) = fract^21-t^2. There is one path at every positive even weight and no path at an odd weight. The denominator records the increase of two units produced by the loop.

    Exact mathematical passage
    
    Z_{0,2}(t)
    =
    t^2(1+t^2+t^4+\cdots)
    =
    \frac{t^2}{1-t^2}.
    
t^5Use in source · 2 passages

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  • Use in source · Read passage · 03_weighted.tex, line 581

    [A computed transfer zeta] For the graph used in the numerical companion, the walk series from packet 0 to packet 2 is Z_0,2(t) = fract^31-t^2-t^3-2t^4+t^5+t^6+t^7-t^9. The first nonzero coefficients are 1,1,1,3,1,5,4,10,7,19,17,37,… at their corresponding weights. Direct enumeration through weight 30 agrees coefficient by coefficient with the rational expansion.

    Exact mathematical passage
    
    Z_{0,2}(t)
    =
    \frac{t^3}{1-t^2-t^3-2t^4+t^5+t^6+t^7-t^9}.
    
t^6Use in source · 2 passages

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  • Use in source · Read passage · 03_weighted.tex, line 581

    [A computed transfer zeta] For the graph used in the numerical companion, the walk series from packet 0 to packet 2 is Z_0,2(t) = fract^31-t^2-t^3-2t^4+t^5+t^6+t^7-t^9. The first nonzero coefficients are 1,1,1,3,1,5,4,10,7,19,17,37,… at their corresponding weights. Direct enumeration through weight 30 agrees coefficient by coefficient with the rational expansion.

    Exact mathematical passage
    
    Z_{0,2}(t)
    =
    \frac{t^3}{1-t^2-t^3-2t^4+t^5+t^6+t^7-t^9}.
    
t^7Use in source · 2 passages

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  • Use in source · Read passage · 03_weighted.tex, line 581

    [A computed transfer zeta] For the graph used in the numerical companion, the walk series from packet 0 to packet 2 is Z_0,2(t) = fract^31-t^2-t^3-2t^4+t^5+t^6+t^7-t^9. The first nonzero coefficients are 1,1,1,3,1,5,4,10,7,19,17,37,… at their corresponding weights. Direct enumeration through weight 30 agrees coefficient by coefficient with the rational expansion.

    Exact mathematical passage
    
    Z_{0,2}(t)
    =
    \frac{t^3}{1-t^2-t^3-2t^4+t^5+t^6+t^7-t^9}.
    
t^9Use in source · 2 passages

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  • Use in source · Read passage · 03_weighted.tex, line 581

    [A computed transfer zeta] For the graph used in the numerical companion, the walk series from packet 0 to packet 2 is Z_0,2(t) = fract^31-t^2-t^3-2t^4+t^5+t^6+t^7-t^9. The first nonzero coefficients are 1,1,1,3,1,5,4,10,7,19,17,37,… at their corresponding weights. Direct enumeration through weight 30 agrees coefficient by coefficient with the rational expansion.

    Exact mathematical passage
    
    Z_{0,2}(t)
    =
    \frac{t^3}{1-t^2-t^3-2t^4+t^5+t^6+t^7-t^9}.
    
t^dUse in source · 1 passage

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  • Use in source · Read passage · 03_weighted.tex, line 422

    [Recurrence for path counts] Write Z_u,v(t)=fracP(t)Q(t), Q(t)=1+q_1t+⋯+q_dt^d. Use the convention deg 0=-∞. Then, for every nonnegative integer n>deg P, a_n+q_1a_n-1+⋯+q_da_n-d=0.

    Exact mathematical passage
    
    Z_{u,v}(t)=\frac{P(t)}{Q(t)},
    \qquad
    Q(t)=1+q_1t+\cdots+q_dt^d.
    
t^kUse in source · 1 passage

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  • Use in source · Read passage · 03_weighted.tex, line 557

    [Linear recurrence] With the canonical polynomials from [source reference], write Q(t)=∑_kq_kt^k, Z_s,t(t)=∑_n≥0a_n(s,t)t^n. Then the walk counts satisfy the recurrence with constant coefficients determined by Q after the finite initial range contributed by P_s,t, with deg 0=-∞: ∑_k=0^nq_k a_n-k(s,t)=0 (n>deg P_s,t).

    Exact mathematical passage
    
    Q(t)=\sum_kq_kt^k,
    \qquad
    Z_{s,t}(t)=\sum_{n\ge0}a_n(s,t)t^n.
    
T^{\Pcal}_{ba}Use in source · 2 passages

Search aliases: T^Pcal_ba T^ P_ba Pcal mathcal

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  • Use in source · Read passage · 02_coordinates.tex, line 224

    [Refinement of operator blocks] Suppose that Q refines P through ρ. Then T^ P_ba = ∑_substackρ(β)=b ρ(α)=a T^ Q_βα. The matrix of T in fine coordinates is related to the matrix in coarse coordinates by [T]_ P = C_ P← Q[T]_ QJ_ Q← P.

    Exact mathematical passage
    
    T^{\Pcal}_{ba}
    =
    \sum_{\substack{\rho(\beta)=b\\\rho(\alpha)=a}}
    T^{\Qcal}_{\beta\alpha}.
    
T^{\Pcal}_{\beta\alpha}Use in source · 1 passage

Search aliases: T^Pcal_βα T^ P_βα Pcal beta alpha mathcal beta alpha

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T^{\Qcal}_{\beta\alpha}Use in source · 2 passages

Search aliases: T^Qcal_βα T^ Q_βα Qcal beta alpha mathcal beta alpha

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  • Use in source · Read passage · 02_coordinates.tex, line 224

    [Refinement of operator blocks] Suppose that Q refines P through ρ. Then T^ P_ba = ∑_substackρ(β)=b ρ(α)=a T^ Q_βα. The matrix of T in fine coordinates is related to the matrix in coarse coordinates by [T]_ P = C_ P← Q[T]_ QJ_ Q← P.

    Exact mathematical passage
    
    T^{\Pcal}_{ba}
    =
    \sum_{\substack{\rho(\beta)=b\\\rho(\alpha)=a}}
    T^{\Qcal}_{\beta\alpha}.
    
T_0Use in source · 3 passages

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  • Use in source · Read passage · 05_defects.tex, line 228

    [Multilevel defect decomposition] The total defect from level L to level zero is C_0,LT_L-T_0C_0,L = ∑_ℓ=0^L-1 C_0,ℓΔ_ℓ C_ℓ+1,L. For bounded maps, C_0,LT_L-T_0C_0,L ≤ ∑_ℓ=0^L-1 C_0,ℓ Δ_ℓ C_ℓ+1,L .

    Exact mathematical passage
    
    C_{0,L}T_L-T_0C_{0,L}
    =
    \sum_{\ell=0}^{L-1}
    C_{0,\ell}\Delta_\ell C_{\ell+1,L}.
    
t_1Use in source · 1 passage

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  • Use in source · Read passage · 03_weighted.tex, line 452

    [Several independent weights] Suppose every edge has a weight vector w(e)=(w_1(e),…,w_r(e))∈ N^r∖{0}. Replace t^w(e) by t_1^w_1(e)⋯ t_r^w_r(e). The resulting multigraded transfer series is rational in t_1,…,t_r.

    Exact mathematical passage
    t_1,\ldots,t_r
t_1^{w_1(e)}Use in source · 1 passage

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  • Use in source · Read passage · 03_weighted.tex, line 449

    [Several independent weights] Suppose every edge has a weight vector w(e)=(w_1(e),…,w_r(e))∈ N^r∖{0}. Replace t^w(e) by t_1^w_1(e)⋯ t_r^w_r(e). The resulting multigraded transfer series is rational in t_1,…,t_r.

    Exact mathematical passage
    
    t_1^{w_1(e)}\cdots t_r^{w_r(e)}.
    
T_{2,1}Use in source · 1 passage

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  • Use in source · Read passage · 06_models.tex, line 59

    y any phase ω_N^k stays in the disk and has a finite inverse-chart image. The phase action is Γ↦ω_N^kΓ. Outside the open disk, the same chart formula requires 1-ω_N^kΓ≠0. Pulling the phase action back on this domain gives T_N,k(z) = frac(1+ω_N^k)z+(1-ω_N^k) (1-ω_N^k)z+(1+ω_N^k). For N=2 and k=1, T_2,1(z)=frac1z, z≠0,-1. Thus the nontrivial action at the first phase level exchanges normalized impedance and admittance. Calling these values ``packets'' is geometric terminology for the sampled orbit…

    Exact mathematical passage
    
    T_{2,1}(z)=\frac1z,
    \qquad z\ne0,-1.
    \label{eq:smith-inversion}
    
T_{ba}Use in source · 1 passage

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  • Use in source · visual_atlas.tex, line 29

    T_ba · Input packet a, output packet b: P_bTP_a. · Blocks of a finite cyclic filter.

    Exact mathematical passage
    T_{ba}
T_c'Use in source · 1 passage

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  • Use in source · visual_atlas.tex, line 547

    Had we chosen the transported operator T_c'=CT_fC^-1, the defect would be zero and every polynomial action would intertwine exactly. That is a different choice of coarse operator, not a stronger conclusion from the faulty one.

    Exact mathematical passage
    T_c'=CT_fC^{-1}
T_c^nUse in source · 7 passages

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  • Use in source · Read passage · 05_defects.tex, line 27

    [Power defect identity] For every integer n≥1, CT_f^n-T_c^nC = ∑_k=0^n-1T_c^n-1-kΔ T_f^k.

    Exact mathematical passage
    
    CT_f^n-T_c^nC
    =
    \sum_{k=0}^{n-1}T_c^{n-1-k}\Delta T_f^k.
    
T_c^{n+1}Use in source · 1 passage

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  • Use in source · Read passage · 05_defects.tex, line 36

    The statement is clear for n=1. For the induction step, write CT_f^n+1-T_c^n+1C = (CT_f^n-T_c^nC)T_f+T_c^n(CT_f-T_cC) and apply the induction hypothesis.

    Exact mathematical passage
    
    CT_f^{n+1}-T_c^{n+1}C
    =
    (CT_f^n-T_c^nC)T_f+T_c^n(CT_f-T_cC)
    
T_c^{n-1-k}Use in source · 3 passages

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  • Use in source · Read passage · 05_defects.tex, line 27

    [Power defect identity] For every integer n≥1, CT_f^n-T_c^nC = ∑_k=0^n-1T_c^n-1-kΔ T_f^k.

    Exact mathematical passage
    
    CT_f^n-T_c^nC
    =
    \sum_{k=0}^{n-1}T_c^{n-1-k}\Delta T_f^k.
    
T_f^kUse in source · 3 passages

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  • Use in source · Read passage · 05_defects.tex, line 27

    [Power defect identity] For every integer n≥1, CT_f^n-T_c^nC = ∑_k=0^n-1T_c^n-1-kΔ T_f^k.

    Exact mathematical passage
    
    CT_f^n-T_c^nC
    =
    \sum_{k=0}^{n-1}T_c^{n-1-k}\Delta T_f^k.
    
T_f^nUse in source · 7 passages

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  • Use in source · Read passage · 05_defects.tex, line 27

    [Power defect identity] For every integer n≥1, CT_f^n-T_c^nC = ∑_k=0^n-1T_c^n-1-kΔ T_f^k.

    Exact mathematical passage
    
    CT_f^n-T_c^nC
    =
    \sum_{k=0}^{n-1}T_c^{n-1-k}\Delta T_f^k.
    
T_f^{n+1}Use in source · 1 passage

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  • Use in source · Read passage · 05_defects.tex, line 36

    The statement is clear for n=1. For the induction step, write CT_f^n+1-T_c^n+1C = (CT_f^n-T_c^nC)T_f+T_c^n(CT_f-T_cC) and apply the induction hypothesis.

    Exact mathematical passage
    
    CT_f^{n+1}-T_c^{n+1}C
    =
    (CT_f^n-T_c^nC)T_f+T_c^n(CT_f-T_cC)
    
T_LUse in source · 3 passages

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  • Use in source · Read passage · 05_defects.tex, line 228

    [Multilevel defect decomposition] The total defect from level L to level zero is C_0,LT_L-T_0C_0,L = ∑_ℓ=0^L-1 C_0,ℓΔ_ℓ C_ℓ+1,L. For bounded maps, C_0,LT_L-T_0C_0,L ≤ ∑_ℓ=0^L-1 C_0,ℓ Δ_ℓ C_ℓ+1,L .

    Exact mathematical passage
    
    C_{0,L}T_L-T_0C_{0,L}
    =
    \sum_{\ell=0}^{L-1}
    C_{0,\ell}\Delta_\ell C_{\ell+1,L}.
    
T_{N,k}Use in source · 1 passage

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  • Use in source · Read passage · 06_models.tex, line 51

    t z=Z/Z_0, and assume z≠-1. Write Γ=fracz-1z+1. On the open reflection disk |Γ|<1, multiplication by any phase ω_N^k stays in the disk and has a finite inverse-chart image. The phase action is Γ↦ω_N^kΓ. Outside the open disk, the same chart formula requires 1-ω_N^kΓ≠0. Pulling the phase action back on this domain gives T_N,k(z) = frac(1+ω_N^k)z+(1-ω_N^k) (1-ω_N^k)z+(1+ω_N^k). For N=2 and k=1, T_2,1(z)=frac1z, z≠0,-1. Thus the nontrivial action at the first phase level exchanges normalized impeda…

    Exact mathematical passage
    
    T_{N,k}(z)
    =
    \frac{(1+\omega_N^k)z+(1-\omega_N^k)}
    {(1-\omega_N^k)z+(1+\omega_N^k)}.
    
t_rUse in source · 1 passage

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  • Use in source · Read passage · 03_weighted.tex, line 452

    [Several independent weights] Suppose every edge has a weight vector w(e)=(w_1(e),…,w_r(e))∈ N^r∖{0}. Replace t^w(e) by t_1^w_1(e)⋯ t_r^w_r(e). The resulting multigraded transfer series is rational in t_1,…,t_r.

    Exact mathematical passage
    t_1,\ldots,t_r
t_r^{w_r(e)}Use in source · 1 passage

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  • Use in source · Read passage · 03_weighted.tex, line 449

    [Several independent weights] Suppose every edge has a weight vector w(e)=(w_1(e),…,w_r(e))∈ N^r∖{0}. Replace t^w(e) by t_1^w_1(e)⋯ t_r^w_r(e). The resulting multigraded transfer series is rational in t_1,…,t_r.

    Exact mathematical passage
    
    t_1^{w_1(e)}\cdots t_r^{w_r(e)}.
    
T_\ellUse in source · 4 passages

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  • Use in source · Read passage · 05_defects.tex, line 216

    Let C_ℓ:X_ℓ+1⟶ X_ℓ be linear maps for 0≤ℓ<L, and let T_ℓ∈End(X_ℓ). Put Δ_ℓ=C_ℓ T_ℓ+1-T_ℓ C_ℓ. For a<b, write C_a,b=C_aC_a+1⋯ C_b-1, with C_a,a=I.

    Exact mathematical passage
    T_\ell\in\End(X_\ell)
T_{\ell+1}Use in source · 2 passages

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  • Use in source · Read passage · 05_defects.tex, line 217

    Let C_ℓ:X_ℓ+1⟶ X_ℓ be linear maps for 0≤ℓ<L, and let T_ℓ∈End(X_ℓ). Put Δ_ℓ=C_ℓ T_ℓ+1-T_ℓ C_ℓ. For a<b, write C_a,b=C_aC_a+1⋯ C_b-1, with C_a,a=I.

    Exact mathematical passage
    
    \Delta_\ell=C_\ell T_{\ell+1}-T_\ell C_\ell.
    
\mathrm{target}Use in source · 1 passage

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  • Use in source · visual_atlas.tex, line 289

    headThe first-edge decomposition Let a_n(s,t) count walks of total weight n from s to t. Removing the first edge gives a_n(s,t)=1_s=t, n=0 +∑_substacke: source(e)=s w(e)≤ n a_n-w(e)(target(e),t). The empty walk is allowed precisely on the diagonal at weight zero. Positive weights ensure that every contributing walk has length at most n, so enumeration at each fixed weight is finite.

    Exact mathematical passage
    
    a_n(s,t)=\mathbf1_{s=t,\,n=0}
     +\sum_{\substack{e:\,\mathrm{source}(e)=s\\w(e)\le n}}
     a_{n-w(e)}(\mathrm{target}(e),t).
    
\operatorname{target}Use in source · 1 passage

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  • Use in source · Read passage · 03_weighted.tex, line 499

    [Automatic finite-graph transfer-zeta rationality] Assume the vertex and edge sets are finite and every edge has positive integer weight. For every n, exact enumeration of edge tuples of lengths at most n, followed by endpoint and total-weight filtering, returns a_n(s,t). These coefficients obey the recurrence obtained by removing the first edge a_n(s,t) = 1_s=t, n=0 +∑_substacke: source(e)=s w(e)≤ n a_n-w(e)(target(e),t). Let T(t)=I-A(t), Q(t)=det T(t), P_s,t(t)=adj(T(t))_s,t. Then Q(0)=1, henc…

    Exact mathematical passage
    
    a_n(s,t)
    =
    \mathbf 1_{s=t,\,n=0}
    +\sum_{\substack{e:\,\operatorname{source}(e)=s\\w(e)\le n}}
    a_{n-w(e)}(\operatorname{target}(e),t).
    
UUse in source · 29 passages

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u^{\mathsf T}Use in source · 1 passage

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  • Use in source · Read passage · 03_weighted.tex, line 395

    [Rationality of the transfer series] The weighted transfer series satisfies Z_u,v(t) = u^ T(I-A(t))^-1v. It is a rational function whose denominator divides det(I-A(t)).

    Exact mathematical passage
    
    Z_{u,v}(t)
    =
    u^{\mathsf T}(I-A(t))^{-1}v.
    
U^kUse in source · 3 passages

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  • Use in source · Read passage · 02_coordinates.tex, line 418

    0, · r≠ j, 0≤ j,r<N. Then P_N,j = η∑_k=0^N-1(ω^vee)^jkU^k. In particular, if R is a field, N>0, and ω is a primitive Nth root of unity, the certificate holds with ω^vee=ω^-1 and η=N^-1.

    Exact mathematical passage
    
    \boxed{
    P_{N,j}
    =
    \eta\sum_{k=0}^{N-1}(\omega^\vee)^{jk}U^k.
    }
    
U^NUse in source · 2 passages

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u_1Use in source · 1 passage

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  • Use in source · Read passage · 04_arithmetic.tex, line 819

    Let M be a matrix over a DVR. Smith normal form gives invertible matrices U,V such that UMV = diag(π^s_1u_1,…,π^s_ru_r,0,…,0), where each u_i is a unit and 0≤ s_1≤⋯≤ s_r. The exponents s_i are directional lifting weights.

    Exact mathematical passage
    
    UMV
    =
    \diag(\pi^{s_1}u_1,\ldots,\pi^{s_r}u_r,0,\ldots,0),
    
u_rUse in source · 1 passage

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  • Use in source · Read passage · 04_arithmetic.tex, line 819

    Let M be a matrix over a DVR. Smith normal form gives invertible matrices U,V such that UMV = diag(π^s_1u_1,…,π^s_ru_r,0,…,0), where each u_i is a unit and 0≤ s_1≤⋯≤ s_r. The exponents s_i are directional lifting weights.

    Exact mathematical passage
    
    UMV
    =
    \diag(\pi^{s_1}u_1,\ldots,\pi^{s_r}u_r,0,\ldots,0),
    
V_1Use in source · 2 passages

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  • Use in source · Read passage · 04_arithmetic.tex, line 345

    [Two complementary packets] Suppose V=V_1⊕ V_2 with projector E onto V_1 and complementary projector I-E. Then Λ/(Λ_1⊕Λ_2) ≅ EΛ/Λ_1 ≅ (I-E)Λ/Λ_2. Consequently s_Λ(E)=s_Λ(I-E) = exp_π(Λ/(Λ_1⊕Λ_2)).

    Exact mathematical passage
    
    V=V_1\oplus V_2
    
V_2Use in source · 2 passages

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  • Use in source · Read passage · 04_arithmetic.tex, line 345

    [Two complementary packets] Suppose V=V_1⊕ V_2 with projector E onto V_1 and complementary projector I-E. Then Λ/(Λ_1⊕Λ_2) ≅ EΛ/Λ_1 ≅ (I-E)Λ/Λ_2. Consequently s_Λ(E)=s_Λ(I-E) = exp_π(Λ/(Λ_1⊕Λ_2)).

    Exact mathematical passage
    
    V=V_1\oplus V_2
    
v_2Use in source · 3 passages

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  • Use in source · Read passage · 04_arithmetic.tex, line 664

    The reduced denominators of the displayed entries are 1 or 2, which proves the local integrality and minimality statements directly. The resultant is Res(x-1,x+1)=2. Thus v_2(2)=1 and v_p(2)=0 for primes p≠2.

    Exact mathematical passage
    v_2(2)=1
v_3Use in source · 1 passage

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v_pUse in source · 1 passage

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  • Use in source · Read passage · 04_arithmetic.tex, line 664

    The reduced denominators of the displayed entries are 1 or 2, which proves the local integrality and minimality statements directly. The resultant is Res(x-1,x+1)=2. Thus v_2(2)=1 and v_p(2)=0 for primes p≠2.

    Exact mathematical passage
    v_p(2)=0
\mathrm{val}Use in source · 4 passages

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  • Use in source · Read passage · 04_arithmetic.tex, line 838

    [Concrete Smith-weighted congruence solve] Let p>1 and consider the diagonal system over ( Z/(p^L) Z)^d diag(p^s_1,…,p^s_d)x=b pmodp^L. The system is solvable if and only if p^min(s_i,L)mid (b_i)_val for every i, where (b_i)_val is the canonical natural representative. Conditional on this admissibility condition, the number of solutions is p^∑_i=1^dmin(s_i,L). If any coordinate is inadmissible, the solution set is empty and its cardinality is zero.

    Exact mathematical passage
    
    p^{\min(s_i,L)}\mid (b_i)_{\mathrm{val}}
    
\veeUse in source · 5 passages

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  • Use in source · Read passage · 02_coordinates.tex, line 406

    [Root-of-unity realization] Let R be a commutative semiring, let N>0, and suppose ω,ω^vee,η∈ R satisfy ω^N=1 and the finite N× N Fourier orthogonality table η∑_k=0^N-1(ω^vee)^jkω^rk = 1, · r=j,

    Exact mathematical passage
    \omega,\omega^\vee,\eta\in R
w^2Use in source · 3 passages

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  • Use in source · visual_atlas.tex, line 495

    Here e=1+3w+5w^2 and o=2+4w+6w^2, so direct polynomial multiplication gives y_rm even=1+8w+16w^2+17w^3, y_rm odd=4+12w+20w^2+6w^3. This is the same result as ordinary convolution followed by residue extraction. No numerical transform or limiting argument is needed because every sequence is finitely supported.

    Exact mathematical passage
    e=1+3w+5w^2
w^3Use in source · 1 passage

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  • Use in source · visual_atlas.tex, line 496

    Here e=1+3w+5w^2 and o=2+4w+6w^2, so direct polynomial multiplication gives y_rm even=1+8w+16w^2+17w^3, y_rm odd=4+12w+20w^2+6w^3. This is the same result as ordinary convolution followed by residue extraction. No numerical transform or limiting argument is needed because every sequence is finitely supported.

    Exact mathematical passage
    
    y_{\rm even}=1+8w+16w^2+17w^3,
    \qquad
    y_{\rm odd}=4+12w+20w^2+6w^3.
    
w_1Use in source · 2 passages

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  • Use in source · Read passage · 03_weighted.tex, line 445

    [Several independent weights] Suppose every edge has a weight vector w(e)=(w_1(e),…,w_r(e))∈ N^r∖{0}. Replace t^w(e) by t_1^w_1(e)⋯ t_r^w_r(e). The resulting multigraded transfer series is rational in t_1,…,t_r.

    Exact mathematical passage
    
    w(e)=(w_1(e),\ldots,w_r(e))\in\mathbb N^r\setminus\{0\}.
    
w_rUse in source · 2 passages

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  • Use in source · Read passage · 03_weighted.tex, line 445

    [Several independent weights] Suppose every edge has a weight vector w(e)=(w_1(e),…,w_r(e))∈ N^r∖{0}. Replace t^w(e) by t_1^w_1(e)⋯ t_r^w_r(e). The resulting multigraded transfer series is rational in t_1,…,t_r.

    Exact mathematical passage
    
    w(e)=(w_1(e),\ldots,w_r(e))\in\mathbb N^r\setminus\{0\}.
    
w_{\mathrm{Smith}}Use in source · 1 passage

Search aliases: w_Smith mathrm

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  • Use in source · Read passage · 06_models.tex, line 79

    The symmetric weight w_Smith(Γ) = frac1|1-Γ|^2 + frac1|1+Γ|^2 indicates where small errors in reflection coordinates produce large impedance or admittance errors.

    Exact mathematical passage
    
    w_{\mathrm{Smith}}(\Gamma)
    =
    \frac1{|1-\Gamma|^2}
    +
    \frac1{|1+\Gamma|^2}
    
\widehat TUse in source · 7 passages

Search aliases: widehat T widehat

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  • Use in source · Read passage · 02_coordinates.tex, line 189

    The same coherence applies to operators. Let P_a,P_b be packet systems on X, let Q_a,Q_b be packet systems on Y, where X and Y are modules over the same scalar ring, and let T:X→ Y be a linear map over that ring. Its exact coordinate representation widehat T_Q,P= A_QT S_P preserves identities and typed composition, and the naturality square is J^Y_Q_b,Q_a widehat T_Q_a,P_a = widehat T_Q_b,P_b J^X_P_b,P_a. The identity, cocycle, composition, inverse, and naturality laws are all proved in Lean. Th…

    Exact mathematical passage
    
    \widehat T_{Q,P}=\cA_QT\cS_P
    
\widehat T_2Use in source · 3 passages

Search aliases: widehat T_2 widehat

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  • Use in source · visual_atlas.tex, line 117

    The reordered operators and change of coordinates are widehat T_N=R_NTR_N^-1, J_4,2=R_4R_2^-1. Multiplication cancels the intermediate coordinate maps: J_4,2widehat T_2=widehat T_4J_4,2, J_8,4J_4,2=J_8,2. Thus it makes no difference whether the operator is applied before or after a consistent coordinate change. One must transport the operator, not merely reuse the same numerical matrix under a new ordering.

    Exact mathematical passage
    
    J_{4,2}\widehat T_2=\widehat T_4J_{4,2},\qquad
    J_{8,4}J_{4,2}=J_{8,2}.
    
\widehat T_4Use in source · 3 passages

Search aliases: widehat T_4 widehat

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  • Use in source · visual_atlas.tex, line 117

    The reordered operators and change of coordinates are widehat T_N=R_NTR_N^-1, J_4,2=R_4R_2^-1. Multiplication cancels the intermediate coordinate maps: J_4,2widehat T_2=widehat T_4J_4,2, J_8,4J_4,2=J_8,2. Thus it makes no difference whether the operator is applied before or after a consistent coordinate change. One must transport the operator, not merely reuse the same numerical matrix under a new ordering.

    Exact mathematical passage
    
    J_{4,2}\widehat T_2=\widehat T_4J_{4,2},\qquad
    J_{8,4}J_{4,2}=J_{8,2}.
    
\widehat T_NUse in source · 1 passage

Search aliases: widehat T_N widehat

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  • Use in source · visual_atlas.tex, line 113

    The reordered operators and change of coordinates are widehat T_N=R_NTR_N^-1, J_4,2=R_4R_2^-1. Multiplication cancels the intermediate coordinate maps: J_4,2widehat T_2=widehat T_4J_4,2, J_8,4J_4,2=J_8,2. Thus it makes no difference whether the operator is applied before or after a consistent coordinate change. One must transport the operator, not merely reuse the same numerical matrix under a new ordering.

    Exact mathematical passage
    
    \widehat T_N=R_NTR_N^{-1},\qquad J_{4,2}=R_4R_2^{-1}.
    
\widehat T_{Q,P}Use in source · 1 passage

Search aliases: widehat T_Q,P widehat

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  • Use in source · Read passage · 02_coordinates.tex, line 189

    The same coherence applies to operators. Let P_a,P_b be packet systems on X, let Q_a,Q_b be packet systems on Y, where X and Y are modules over the same scalar ring, and let T:X→ Y be a linear map over that ring. Its exact coordinate representation widehat T_Q,P= A_QT S_P preserves identities and typed composition, and the naturality square is J^Y_Q_b,Q_a widehat T_Q_a,P_a = widehat T_Q_b,P_b J^X_P_b,P_a. The identity, cocycle, composition, inverse, and naturality laws are all proved in Lean. Th…

    Exact mathematical passage
    
    \widehat T_{Q,P}=\cA_QT\cS_P
    
\widehat T_{Q_a,P_a}Use in source · 1 passage

Search aliases: widehat T_Q_a,P_a widehat

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  • Use in source · Read passage · 02_coordinates.tex, line 193

    The same coherence applies to operators. Let P_a,P_b be packet systems on X, let Q_a,Q_b be packet systems on Y, where X and Y are modules over the same scalar ring, and let T:X→ Y be a linear map over that ring. Its exact coordinate representation widehat T_Q,P= A_QT S_P preserves identities and typed composition, and the naturality square is J^Y_Q_b,Q_a widehat T_Q_a,P_a = widehat T_Q_b,P_b J^X_P_b,P_a. The identity, cocycle, composition, inverse, and naturality laws are all proved in Lean. Th…

    Exact mathematical passage
    
    \boxed{
    J^Y_{Q_b,Q_a}\,\widehat T_{Q_a,P_a}
    =
    \widehat T_{Q_b,P_b}\,J^X_{P_b,P_a}.
    }
    
\widehat T_{Q_b,P_b}Use in source · 1 passage

Search aliases: widehat T_Q_b,P_b widehat

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  • Use in source · Read passage · 02_coordinates.tex, line 193

    The same coherence applies to operators. Let P_a,P_b be packet systems on X, let Q_a,Q_b be packet systems on Y, where X and Y are modules over the same scalar ring, and let T:X→ Y be a linear map over that ring. Its exact coordinate representation widehat T_Q,P= A_QT S_P preserves identities and typed composition, and the naturality square is J^Y_Q_b,Q_a widehat T_Q_a,P_a = widehat T_Q_b,P_b J^X_P_b,P_a. The identity, cocycle, composition, inverse, and naturality laws are all proved in Lean. Th…

    Exact mathematical passage
    
    \boxed{
    J^Y_{Q_b,Q_a}\,\widehat T_{Q_a,P_a}
    =
    \widehat T_{Q_b,P_b}\,J^X_{P_b,P_a}.
    }
    
\widetilde bUse in source · 5 passages

Search aliases: widetilde b widetilde

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  • Use in source · Read passage · 04_arithmetic.tex, line 754

    [Smith weighted congruence solve] Let M∈ M_m,n( O) have Smith exponents s_1,…,s_r. Assume the residue field is finite of cardinality q, fix L≥1, and consider Mx≡ bpmodπ^L. Put widetilde b=Ub for a Smith matrix U as in [source reference]. The congruence is solvable if and only if widetilde b_i≡0 pmodπ^min(s_i,L) (1≤ i≤ r) and widetilde b_i≡0 pmodπ^L (r<i≤ m). When it is solvable, the number of solutions in ( O/π^L O)^n is q^(n-r)L+∑_i=1^rmin(s_i,L).

    Exact mathematical passage
    
    \widetilde b=Ub
    
\widetilde b_iUse in source · 3 passages

Search aliases: widetilde b_i widetilde

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  • Use in source · Read passage · 04_arithmetic.tex, line 758

    [Smith weighted congruence solve] Let M∈ M_m,n( O) have Smith exponents s_1,…,s_r. Assume the residue field is finite of cardinality q, fix L≥1, and consider Mx≡ bpmodπ^L. Put widetilde b=Ub for a Smith matrix U as in [source reference]. The congruence is solvable if and only if widetilde b_i≡0 pmodπ^min(s_i,L) (1≤ i≤ r) and widetilde b_i≡0 pmodπ^L (r<i≤ m). When it is solvable, the number of solutions in ( O/π^L O)^n is q^(n-r)L+∑_i=1^rmin(s_i,L).

    Exact mathematical passage
    
    \widetilde b_i\equiv0
    \pmod{\pi^{\min(s_i,L)}}
    \qquad(1\leq i\leq r)
    
\widetilde TUse in source · 4 passages

Search aliases: widetilde T widetilde

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  • Use in source · Read passage · 03_weighted.tex, line 165

    [Stability of inversion at finite precision] Let T and widetilde T be invertible elements of F^0 B. If T-widetilde T∈ F^L B, then T^-1-widetilde T^-1∈ F^L B.

    Exact mathematical passage
    \widetilde T
\widetilde T^{-1}Use in source · 2 passages

Search aliases: widetilde T^-1 widetilde

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  • Use in source · Read passage · 03_weighted.tex, line 170

    [Stability of inversion at finite precision] Let T and widetilde T be invertible elements of F^0 B. If T-widetilde T∈ F^L B, then T^-1-widetilde T^-1∈ F^L B.

    Exact mathematical passage
    
    T^{-1}-\widetilde T^{-1}\in F^L\Bcal.
    
X_0Use in source · 2 passages

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  • Use in source · Read passage · 01_orientation.tex, line 56

    A simple two packet model already contains all four notions. Let X=X_0⊕ X_1, D=D_0 · 0 0 · D_1, N=0 · N_01{ N_10 · 0. A finer family may split X_0 and X_1 into smaller summands. The blocks N_01 and N_10 may enter at different filtration weights. Over a fraction field, the rational packet spaces may fail to split the chosen lattice. A coarse operator on one selected summand may also fail to intertwine with the full matrix. The later sections isolate these four effects one at a time.

    Exact mathematical passage
    
    X=X_0\oplus X_1,
    \qquad
    D=\begin{pmatrix}D_0&0\\0&D_1\end{pmatrix},
    \qquad
    N=\begin{pmatrix}0&N_{01}\\N_{10}&0\end{pmatrix}.
    
x_0Use in source · 4 passages

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  • Use in source · visual_atlas.tex, line 45

    vpage3Follow one coefficient through the towerMODEL A / LOSSLESS ADDRESS REFINEMENTTraditional paper: Theorem 3.3 (p. 3), Theorem 4.6 (p. 11) Take a vector x=(x_0,…,x_15). A packet is not a single summary number: it retains every coefficient at its selected addresses. For example, P_2,0x=(x_0,0,x_2,0,…,x_14,0). The rail below lists the addresses in each packet. Its display order groups descendants under their parents. The matrix example on V5 instead uses increasing residue order.

    Exact mathematical passage
    x=(x_0,\ldots,x_{15})
X_{00}Use in source · 1 passage

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  • Use in source · Read passage · 02_coordinates.tex, line 348

    [A two level split] Let X=X_00⊕ X_01⊕ X_10⊕ X_11. Assume that all four summands are nonzero. The four coordinate projections form a fine packet system. The two sums P_0=Q_00+Q_01, P_1=Q_10+Q_11 form a coarse packet system. If x=(x_00,x_01,x_10,x_11), the coarse coordinates are (x_00+x_01,x_10+x_11) when the sums are interpreted inside the two coarse direct summands. Fine analysis recovers the four entries exactly. Nothing has been approximated.

    Exact mathematical passage
    
    X=X_{00}\oplus X_{01}\oplus X_{10}\oplus X_{11}.
    
x_{00}Use in source · 2 passages

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  • Use in source · Read passage · 02_coordinates.tex, line 357

    [A two level split] Let X=X_00⊕ X_01⊕ X_10⊕ X_11. Assume that all four summands are nonzero. The four coordinate projections form a fine packet system. The two sums P_0=Q_00+Q_01, P_1=Q_10+Q_11 form a coarse packet system. If x=(x_00,x_01,x_10,x_11), the coarse coordinates are (x_00+x_01,x_10+x_11) when the sums are interpreted inside the two coarse direct summands. Fine analysis recovers the four entries exactly. Nothing has been approximated.

    Exact mathematical passage
    x=(x_{00},x_{01},x_{10},x_{11})
X_{01}Use in source · 1 passage

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  • Use in source · Read passage · 02_coordinates.tex, line 348

    [A two level split] Let X=X_00⊕ X_01⊕ X_10⊕ X_11. Assume that all four summands are nonzero. The four coordinate projections form a fine packet system. The two sums P_0=Q_00+Q_01, P_1=Q_10+Q_11 form a coarse packet system. If x=(x_00,x_01,x_10,x_11), the coarse coordinates are (x_00+x_01,x_10+x_11) when the sums are interpreted inside the two coarse direct summands. Fine analysis recovers the four entries exactly. Nothing has been approximated.

    Exact mathematical passage
    
    X=X_{00}\oplus X_{01}\oplus X_{10}\oplus X_{11}.
    
x_{01}Use in source · 2 passages

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  • Use in source · Read passage · 02_coordinates.tex, line 357

    [A two level split] Let X=X_00⊕ X_01⊕ X_10⊕ X_11. Assume that all four summands are nonzero. The four coordinate projections form a fine packet system. The two sums P_0=Q_00+Q_01, P_1=Q_10+Q_11 form a coarse packet system. If x=(x_00,x_01,x_10,x_11), the coarse coordinates are (x_00+x_01,x_10+x_11) when the sums are interpreted inside the two coarse direct summands. Fine analysis recovers the four entries exactly. Nothing has been approximated.

    Exact mathematical passage
    x=(x_{00},x_{01},x_{10},x_{11})
X_1Use in source · 2 passages

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  • Use in source · Read passage · 01_orientation.tex, line 56

    A simple two packet model already contains all four notions. Let X=X_0⊕ X_1, D=D_0 · 0 0 · D_1, N=0 · N_01{ N_10 · 0. A finer family may split X_0 and X_1 into smaller summands. The blocks N_01 and N_10 may enter at different filtration weights. Over a fraction field, the rational packet spaces may fail to split the chosen lattice. A coarse operator on one selected summand may also fail to intertwine with the full matrix. The later sections isolate these four effects one at a time.

    Exact mathematical passage
    
    X=X_0\oplus X_1,
    \qquad
    D=\begin{pmatrix}D_0&0\\0&D_1\end{pmatrix},
    \qquad
    N=\begin{pmatrix}0&N_{01}\\N_{10}&0\end{pmatrix}.
    
x_1Use in source · 3 passages

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  • Use in source · Read passage · 05_defects.tex, line 263

    [A visible one step defect] Let X_f=bbk^2, let X_c=bbk, and let C(x_1,x_2)=x_1. Take T_f= a · b

    Exact mathematical passage
    
    C(x_1,x_2)=x_1.
    
X_{10}Use in source · 1 passage

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  • Use in source · Read passage · 02_coordinates.tex, line 348

    [A two level split] Let X=X_00⊕ X_01⊕ X_10⊕ X_11. Assume that all four summands are nonzero. The four coordinate projections form a fine packet system. The two sums P_0=Q_00+Q_01, P_1=Q_10+Q_11 form a coarse packet system. If x=(x_00,x_01,x_10,x_11), the coarse coordinates are (x_00+x_01,x_10+x_11) when the sums are interpreted inside the two coarse direct summands. Fine analysis recovers the four entries exactly. Nothing has been approximated.

    Exact mathematical passage
    
    X=X_{00}\oplus X_{01}\oplus X_{10}\oplus X_{11}.
    
x_{10}Use in source · 2 passages

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  • Use in source · Read passage · 02_coordinates.tex, line 357

    [A two level split] Let X=X_00⊕ X_01⊕ X_10⊕ X_11. Assume that all four summands are nonzero. The four coordinate projections form a fine packet system. The two sums P_0=Q_00+Q_01, P_1=Q_10+Q_11 form a coarse packet system. If x=(x_00,x_01,x_10,x_11), the coarse coordinates are (x_00+x_01,x_10+x_11) when the sums are interpreted inside the two coarse direct summands. Fine analysis recovers the four entries exactly. Nothing has been approximated.

    Exact mathematical passage
    x=(x_{00},x_{01},x_{10},x_{11})
X_{11}Use in source · 1 passage

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  • Use in source · Read passage · 02_coordinates.tex, line 348

    [A two level split] Let X=X_00⊕ X_01⊕ X_10⊕ X_11. Assume that all four summands are nonzero. The four coordinate projections form a fine packet system. The two sums P_0=Q_00+Q_01, P_1=Q_10+Q_11 form a coarse packet system. If x=(x_00,x_01,x_10,x_11), the coarse coordinates are (x_00+x_01,x_10+x_11) when the sums are interpreted inside the two coarse direct summands. Fine analysis recovers the four entries exactly. Nothing has been approximated.

    Exact mathematical passage
    
    X=X_{00}\oplus X_{01}\oplus X_{10}\oplus X_{11}.
    
x_{11}Use in source · 2 passages

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  • Use in source · Read passage · 02_coordinates.tex, line 357

    [A two level split] Let X=X_00⊕ X_01⊕ X_10⊕ X_11. Assume that all four summands are nonzero. The four coordinate projections form a fine packet system. The two sums P_0=Q_00+Q_01, P_1=Q_10+Q_11 form a coarse packet system. If x=(x_00,x_01,x_10,x_11), the coarse coordinates are (x_00+x_01,x_10+x_11) when the sums are interpreted inside the two coarse direct summands. Fine analysis recovers the four entries exactly. Nothing has been approximated.

    Exact mathematical passage
    x=(x_{00},x_{01},x_{10},x_{11})
x_{14}Use in source · 1 passage

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  • Use in source · visual_atlas.tex, line 46

    vpage3Follow one coefficient through the towerMODEL A / LOSSLESS ADDRESS REFINEMENTTraditional paper: Theorem 3.3 (p. 3), Theorem 4.6 (p. 11) Take a vector x=(x_0,…,x_15). A packet is not a single summary number: it retains every coefficient at its selected addresses. For example, P_2,0x=(x_0,0,x_2,0,…,x_14,0). The rail below lists the addresses in each packet. Its display order groups descendants under their parents. The matrix example on V5 instead uses increasing residue order.

    Exact mathematical passage
    
    P_{2,0}x=(x_0,0,x_2,0,\ldots,x_{14},0).
    
x_{15}Use in source · 1 passage

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  • Use in source · visual_atlas.tex, line 45

    vpage3Follow one coefficient through the towerMODEL A / LOSSLESS ADDRESS REFINEMENTTraditional paper: Theorem 3.3 (p. 3), Theorem 4.6 (p. 11) Take a vector x=(x_0,…,x_15). A packet is not a single summary number: it retains every coefficient at its selected addresses. For example, P_2,0x=(x_0,0,x_2,0,…,x_14,0). The rail below lists the addresses in each packet. Its display order groups descendants under their parents. The matrix example on V5 instead uses increasing residue order.

    Exact mathematical passage
    x=(x_0,\ldots,x_{15})
x_2Use in source · 3 passages

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  • Use in source · Read passage · 05_defects.tex, line 263

    [A visible one step defect] Let X_f=bbk^2, let X_c=bbk, and let C(x_1,x_2)=x_1. Take T_f= a · b

    Exact mathematical passage
    
    C(x_1,x_2)=x_1.
    
x_{2m}Use in source · 1 passage

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  • Use in source · visual_atlas.tex, line 481

    vpage20Filter first or split first: same outputMODEL F / A FINITE POLYPHASE REALIZATIONTraditional paper: Section B.1 (p. 47) Use the finitely supported signal x=(1,2,3,4,5,6) and the filter h=(1,2,1). Outside the displayed support, the input is zero. Let e_m=x_2m and o_m=x_2m+1.

    Exact mathematical passage
    e_m=x_{2m}
x_{2m+1}Use in source · 1 passage

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  • Use in source · visual_atlas.tex, line 481

    vpage20Filter first or split first: same outputMODEL F / A FINITE POLYPHASE REALIZATIONTraditional paper: Section B.1 (p. 47) Use the finitely supported signal x=(1,2,3,4,5,6) and the filter h=(1,2,1). Outside the displayed support, the input is zero. Let e_m=x_2m and o_m=x_2m+1.

    Exact mathematical passage
    o_m=x_{2m+1}
x_3Use in source · 1 passage

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  • Use in source · regrouping_not_averaging.tex, line 73

    5pt,] (9.17000,2.26000) rectangle ++(0.57000,0.57000); node[] at (9.45500,2.54500) 1; draw[fill=black!0,draw=black!45,line width=.35pt,] (9.74000,2.26000) rectangle ++(0.57000,0.57000); node[] at (10.02500,2.54500) 0; draw[fill=black!12,draw=black!45,line width=.35pt,] (10.31000,2.26000) rectangle ++(0.57000,0.57000); node[] at (10.59500,2.54500) 1; node[] at (9.74000,1.55000) (x_0+x_2, x_1+x_3); node[] at (9.74000,0.10000) 4⟶2 scalars: loss;

    Exact mathematical passage
    (x_0+x_2,\ x_1+x_3)
x_6Use in source · 1 passage

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  • Use in source · visual_atlas.tex, line 10

    headAddress resolution A coefficient such as x_6 can sit in the even packet, then the residue-2 packet modulo 4, then the residue-6 packet modulo 8. Its value does not become more accurate. Its address becomes more specific, while the full object remains exactly reconstructible.

    Exact mathematical passage
    x_6
X_cUse in source · 7 passages

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  • Use in source · Read passage · 05_defects.tex, line 5

    Let X_f and X_c be vector spaces or Banach spaces over a common field, and let C:X_f⟶ X_c be a linear map, and let T_f∈End(X_f), T_c∈End(X_c). Define Δ=CT_f-T_cC.

    Exact mathematical passage
    X_c
X_fUse in source · 7 passages

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  • Use in source · Read passage · 05_defects.tex, line 5

    Let X_f and X_c be vector spaces or Banach spaces over a common field, and let C:X_f⟶ X_c be a linear map, and let T_f∈End(X_f), T_c∈End(X_c). Define Δ=CT_f-T_cC.

    Exact mathematical passage
    X_f
x_jUse in source · 2 passages

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  • Use in source · Read passage · 06_models.tex, line 8

    Let x=(x_n)_n∈ Z∈ c_00( Z;R) and let the seed be δ_0 under the bilateral shifts (S^rδ_0)_n=δ_n,r. This makes the algebraic span and every displayed sum finite. The N packets are x_j[m]=x[Nm+j]. Synthesis interleaves these sequences. A linear filter with a finite impulse response that is invariant under shifts becomes an N× N matrix of transfer blocks. Refining from N to M with Nmid M splits each coarse phase into its descendants without changing the reconstructed signal. The same formulas extend…

    Exact mathematical passage
    
    x_j[m]=x[Nm+j].
    
x_nUse in source · 2 passages

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  • Use in source · Read passage · 06_models.tex, line 5

    Let x=(x_n)_n∈ Z∈ c_00( Z;R) and let the seed be δ_0 under the bilateral shifts (S^rδ_0)_n=δ_n,r. This makes the algebraic span and every displayed sum finite. The N packets are x_j[m]=x[Nm+j]. Synthesis interleaves these sequences. A linear filter with a finite impulse response that is invariant under shifts becomes an N× N matrix of transfer blocks. Refining from N to M with Nmid M splits each coarse phase into its descendants without changing the reconstructed signal. The same formulas extend…

    Exact mathematical passage
    x=(x_n)_{n\in\Z}\in c_{00}(\Z;R)
x_{n-r}Use in source · 1 passage

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  • Use in source · Read passage · 06_models.tex, line 23

    A banded operator need not remain banded after residue reordering, but its nonzero couplings become a structured packet graph. With the convention (S_rx)_n=x_n-r, the only active transfer is P_N,j+rS_rP_N,j, with indices taken modulo N. More general finite stencils produce a finite set of active phase differences.

    Exact mathematical passage
    (S_rx)_n=x_{n-r}
X_N^{\rm pkt}Use in source · 1 passage

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  • Use in source · visual_atlas.tex, line 79

    Define X_N^rm pkt=⊕_j P_N,jX, A_Nx=(P_N,jx)_j, S_N(x_j)_j=∑_jx_j. Completeness and mutual annihilation give both inverse laws. Consequently, J= A_4 S_2, C= A_2 S_4, CJ=I, JC=I. The apparently larger list of fine packets simply has smaller individual packet spaces.

    Exact mathematical passage
    
    X_N^{\rm pkt}=\bigoplus_j P_{N,j}X,
    \qquad
    \mathcal A_Nx=(P_{N,j}x)_j,
    \qquad
    \mathcal S_N(x_j)_j=\sum_jx_j.
    
x_\betaUse in source · 1 passage

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  • Use in source · Read passage · 02_coordinates.tex, line 172

    Every coarse packet is also uniquely reconstructed from its fine children. If vectors x_β∈ Q_β X sum to a coarse packet x, applying Q_γ recovers x_γ=Q_γ x. This is the uniqueness clause of the canonical nested-refinement statement.

    Exact mathematical passage
    x_\beta\in Q_\beta X
x_\gammaUse in source · 1 passage

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  • Use in source · Read passage · 02_coordinates.tex, line 172

    Every coarse packet is also uniquely reconstructed from its fine children. If vectors x_β∈ Q_β X sum to a coarse packet x, applying Q_γ recovers x_γ=Q_γ x. This is the uniqueness clause of the canonical nested-refinement statement.

    Exact mathematical passage
    x_\gamma=Q_\gamma x
x_{\rho(\beta)}Use in source · 2 passages

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  • Use in source · Read passage · 02_coordinates.tex, line 121

    w QJ_ Q← P=I_X^ P, J_ Q← PC_ P← Q=I_X^ Q. For three packet systems P, Q, and R on X, J_ R← QJ_ Q← P = J_ R← P, C_ P← QC_ Q← R = C_ P← R. If Q refines P through ρ, then (J_ Q← Px)_β = Q_β x_ρ(β), (C_ P← Qy)_α = ∑_ρ(β)=αy_β.

    Exact mathematical passage
    
    \bigl(J_{\Qcal\leftarrow\Pcal}x\bigr)_\beta
    =
    Q_\beta x_{\rho(\beta)},
    \qquad
    \bigl(C_{\Pcal\leftarrow\Qcal}y\bigr)_\alpha
    =
    \sum_{\rho(\beta)=\alpha}y_\beta.
    
X_\ellUse in source · 2 passages

Search aliases: X_ℓ ell

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  • Use in source · Read passage · 05_defects.tex, line 213

    Let C_ℓ:X_ℓ+1⟶ X_ℓ be linear maps for 0≤ℓ<L, and let T_ℓ∈End(X_ℓ). Put Δ_ℓ=C_ℓ T_ℓ+1-T_ℓ C_ℓ. For a<b, write C_a,b=C_aC_a+1⋯ C_b-1, with C_a,a=I.

    Exact mathematical passage
    
    C_\ell:X_{\ell+1}\longrightarrow X_\ell
    
X_{\ell+1}Use in source · 1 passage

Search aliases: X_ℓ+1 ell

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  • Use in source · Read passage · 05_defects.tex, line 213

    Let C_ℓ:X_ℓ+1⟶ X_ℓ be linear maps for 0≤ℓ<L, and let T_ℓ∈End(X_ℓ). Put Δ_ℓ=C_ℓ T_ℓ+1-T_ℓ C_ℓ. For a<b, write C_a,b=C_aC_a+1⋯ C_b-1, with C_a,a=I.

    Exact mathematical passage
    
    C_\ell:X_{\ell+1}\longrightarrow X_\ell
    
YUse in source · 4 passages

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  • Use in source · Read passage · 02_coordinates.tex, line 187

    The same coherence applies to operators. Let P_a,P_b be packet systems on X, let Q_a,Q_b be packet systems on Y, where X and Y are modules over the same scalar ring, and let T:X→ Y be a linear map over that ring. Its exact coordinate representation widehat T_Q,P= A_QT S_P preserves identities and typed composition, and the naturality square is J^Y_Q_b,Q_a widehat T_Q_a,P_a = widehat T_Q_b,P_b J^X_P_b,P_a. The identity, cocycle, composition, inverse, and naturality laws are all proved in Lean. Th…

    Exact mathematical passage
    Y
y_0Use in source · 1 passage

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  • Use in source · smith_coordinate_transport.tex, line 165

    (6.70000,0.88000) 2; node[font=sffamilyscriptsize] at (6.70000,1.32000) 3; node[font=sffamilyscriptsize] at (6.70000,1.76000) 4; node[font=sffamilyscriptsize] at (6.70000,2.20000) 5; node[font=sffamilyscriptsize] at (6.70000,2.64000) 6; node[font=sffamilyscriptsize] at (6.70000,3.08000) 7; node[] at (5.10000,2.30000) x=Vy; node[] at (5.10000,1.30000) x_0=y_0-y_1; node[] at (5.10000,0.50000) x_1=y_1; node[] at (5.40000,-1.00000) The eight solutions are permuted, not created or discarded.;

    Exact mathematical passage
    x_0=y_0-y_1
y_1Use in source · 2 passages

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  • Use in source · smith_coordinate_transport.tex, line 165

    (6.70000,0.88000) 2; node[font=sffamilyscriptsize] at (6.70000,1.32000) 3; node[font=sffamilyscriptsize] at (6.70000,1.76000) 4; node[font=sffamilyscriptsize] at (6.70000,2.20000) 5; node[font=sffamilyscriptsize] at (6.70000,2.64000) 6; node[font=sffamilyscriptsize] at (6.70000,3.08000) 7; node[] at (5.10000,2.30000) x=Vy; node[] at (5.10000,1.30000) x_0=y_0-y_1; node[] at (5.10000,0.50000) x_1=y_1; node[] at (5.40000,-1.00000) The eight solutions are permuted, not created or discarded.;

    Exact mathematical passage
    x_0=y_0-y_1
y_iUse in source · 1 passage

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  • Use in source · Read passage · 04_arithmetic.tex, line 779

    Set x=Vy. Multiplying the congruence by U reduces it to independent equations π^s_iy_i≡widetilde b_ipmodπ^L (1≤ i≤ r) and zero equations in the remaining rows. Multiplication by π^s_i on O/π^L O has image equal to the elements divisible by π^min(s_i,L) and kernel of size q^min(s_i,L). Each of the n-r unused variables is free and contributes q^L choices. Multiplying the independent counts gives the formula.

    Exact mathematical passage
    
    \pi^{s_i}y_i\equiv\widetilde b_i\pmod{\pi^L}
    \qquad(1\leq i\leq r)
    
y_\alphaUse in source · 1 passage

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  • Use in source · Read passage · 02_coordinates.tex, line 161

    [Orthogonal Hilbert packets] If X is a real or complex Hilbert space and every packet system in the tower consists of orthogonal projections, equip each finite packet direct sum with the Hilbert inner product ⟨(x_α),(y_α)⟩=∑_α⟨ x_α,y_α⟩. Then analysis and synthesis are unitary. Every coordinate change in [source reference] is unitary.

    Exact mathematical passage
    \langle(x_\alpha),(y_\alpha)\rangle=\sum_\alpha\langle x_\alpha,y_\alpha\rangle
y_\betaUse in source · 1 passage

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  • Use in source · Read passage · 02_coordinates.tex, line 121

    w QJ_ Q← P=I_X^ P, J_ Q← PC_ P← Q=I_X^ Q. For three packet systems P, Q, and R on X, J_ R← QJ_ Q← P = J_ R← P, C_ P← QC_ Q← R = C_ P← R. If Q refines P through ρ, then (J_ Q← Px)_β = Q_β x_ρ(β), (C_ P← Qy)_α = ∑_ρ(β)=αy_β.

    Exact mathematical passage
    
    \bigl(J_{\Qcal\leftarrow\Pcal}x\bigr)_\beta
    =
    Q_\beta x_{\rho(\beta)},
    \qquad
    \bigl(C_{\Pcal\leftarrow\Qcal}y\bigr)_\alpha
    =
    \sum_{\rho(\beta)=\alpha}y_\beta.
    
\ZUse in source · 9 passages

Search aliases: Z mathbb

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  • Use in source · Read passage · 03_weighted.tex, line 249

    A packet decomposition resolves H=∑_e∈ EH_e and assigns a certified filtration gain D^-1H_e∈ F^w(e) B, w(e)∈ Z_>0. Each e is a directed transfer edge. For an ordered transfer word γ=(e_1,…,e_r), define W(γ)=∑_j=1^rw(e_j), A_γ=A_e_1⋯ A_e_r, A_e=D^-1H_e.

    Exact mathematical passage
    
    D^{-1}H_e\in F^{w(e)}\cB,
    \qquad w(e)\in\Z_{>0}.
    
\mathbb Z^2Use in source · 1 passage

Search aliases: Z^2 mathbb

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  • Use in source · dyadic_eigenlattice.tex, line 53

    0 · 2, det B=2; node[] at (6.45000,0.60000) Filled: B Z^2={(x,y):y is even}; node[] at (6.45000,-0.35000) Unfilled: the other lattice coset.; node[] at (6.45000,-1.25000) B^-1 is integral at odd primes, not at 2.;

    Exact mathematical passage
    B\mathbb Z^2=\{(x,y):y\text{ is even}\}
z^rUse in source · 1 passage

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  • Use in source · finite_fourier_table.tex, line 22

    000,0.70000); node[] at (0.35000,1.45000) 0; draw[fill=black!0,draw=black!45,line width=.35pt,] (0.70000,1.10000) rectangle ++(0.70000,0.70000); node[] at (1.05000,1.45000) 0; draw[fill=black!12,draw=black!45,line width=.35pt,] (1.40000,1.10000) rectangle ++(0.70000,0.70000); node[] at (1.75000,1.45000) 3; node[] at (3.70000,2.05000) × 5; node[] at (6.05000,3.75000) P_j(z^r): 5=3^-1pmod7; draw[fill=black!12,draw=black!45,line width=.35pt,] (5.00000,2.50000) rectangle ++(0.70000,0.70000); node[] …

    Exact mathematical passage
    P_j(z^r):\ 5=3^{-1}\pmod7
Z_0Use in source · 2 passages

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  • Use in source · Read passage · 06_models.tex, line 42

    Let Z and Z_0≠0 be complex impedances, put z=Z/Z_0, and assume z≠-1. Write Γ=fracz-1z+1. On the open reflection disk |Γ|<1, multiplication by any phase ω_N^k stays in the disk and has a finite inverse-chart image. The phase action is Γ↦ω_N^kΓ. Outside the open disk, the same chart formula requires 1-ω_N^kΓ≠0. Pulling the phase action back on this domain gives T_N,k(z) = frac(1+ω_N^k)z+(1-ω_N^k) (1-ω_N^k)z+(1+ω_N^k). For N=2 and k=1, T_2,1(z)=frac1z, z≠0,-1. Thus the nontrivial action at the firs…

    Exact mathematical passage
    Z_0\ne0
Z_{0,1}Use in source · 2 passages

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  • Use in source · visual_atlas.tex, line 310

    From QZ_0,1=2t^2 one obtains a_0=a_1=0, a_2=2, a_n=a_n-1+2a_n-3 (n≥3). The numerator is responsible for the initial exception. Omitting it would incorrectly force the entire series to vanish.

    Exact mathematical passage
    QZ_{0,1}=2t^2
Z_{0,2}Use in source · 2 passages

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  • Use in source · Read passage · 03_weighted.tex, line 463

    [A transfer series with one loop] Take vertices 0, 1, and 2. Give the edge 0→1 weight one, the loop 1→1 weight two, and the edge 1→2 weight one. Every path from 0 to 2 uses the first and last edges and may traverse the loop any number of times. Hence Z_0,2(t) = t^2(1+t^2+t^4+⋯) = fract^21-t^2. There is one path at every positive even weight and no path at an odd weight. The denominator records the increase of two units produced by the loop.

    Exact mathematical passage
    
    Z_{0,2}(t)
    =
    t^2(1+t^2+t^4+\cdots)
    =
    \frac{t^2}{1-t^2}.
    
\Z_2Use in source · 1 passage

Search aliases: Z_2 Z mathbb

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  • Use in source · Read passage · 04_arithmetic.tex, line 696

    The failure of the character formula frac12(I± A) to be integral does not invalidate coefficient selectors such as even and odd residue extraction. It shows that two distinct constructions must be distinguished: integral address selector ≠ character-average spectral projector when the group order is not a unit. The first can remain exact over Z_2. The second can acquire a denominator weight.

    Exact mathematical passage
    \Z_2
\mathbb Z_2Use in source · 1 passage

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  • Use in source · Read passage · 04_arithmetic.tex, line 587

    The displayed matrices are complementary idempotents. The scalar 2 is a unit in Z_p for odd p, so both matrices are integral there. Over Z_2, multiplying by 2 clears the denominators, while neither projector preserves the standard lattice. Thus both weights are one. The resultant of the two linear factors is their root difference, which is 2.

    Exact mathematical passage
    \mathbb Z_2
\Z_2^2Use in source · 1 passage

Search aliases: Z_2^2 Z mathbb

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  • Use in source · Read passage · 04_arithmetic.tex, line 650

    [Odd-adic versus dyadic behavior] For every prime p≠2, every entry of E_+ and E_- is p-integral, and each projector has exact local denominator weight zero. At p=2, each projector has exact local denominator weight one. Multiplication by 2 makes it integral, while the unscaled matrix is not integral: s_2, Z_2^2(E_+)=s_2, Z_2^2(E_-)=1. The characteristic factors x-1 and x+1 have resultant 2. Its 2-adic valuation is one, exactly the two local projector weights above, and its p-adic valuation is ze…

    Exact mathematical passage
    
    s_{2,\Z_2^2}(E_+)=s_{2,\Z_2^2}(E_-)=1.
    
\mathbb Z_2^2Use in source · 1 passage

Search aliases: Z_2^2 mathbb

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  • Use in source · Read passage · 04_arithmetic.tex, line 436

    [Strict growth under refinement] Take the standard lattice Z_2^2 and the involution from [source reference]. The one packet system (I) has weight zero. Refining it into the two rational sign packets produces weight one. The coarse lattice is already split because there is only one summand. The fine eigenspaces are glued together by one dyadic digit.

    Exact mathematical passage
    \mathbb Z_2^2
\Z_{>0}Use in source · 1 passage

Search aliases: Z_>0 Z mathbb

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  • Use in source · Read passage · 03_weighted.tex, line 249

    A packet decomposition resolves H=∑_e∈ EH_e and assigns a certified filtration gain D^-1H_e∈ F^w(e) B, w(e)∈ Z_>0. Each e is a directed transfer edge. For an ordered transfer word γ=(e_1,…,e_r), define W(γ)=∑_j=1^rw(e_j), A_γ=A_e_1⋯ A_e_r, A_e=D^-1H_e.

    Exact mathematical passage
    
    D^{-1}H_e\in F^{w(e)}\cB,
    \qquad w(e)\in\Z_{>0}.
    
z_kUse in source · 1 passage

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  • Use in source · smith_chart_orbit.tex, line 25

    ) circle (.075); node[] at (-1.38027,-1.38027) 5; fill (0.00000,-1.60000) circle (.075); node[] at (0.00000,-1.95200) 6; fill (1.13137,-1.13137) circle (.075); node[] at (1.38027,-1.38027) 7; draw[dashed] (11.28333,0) circle (2.46667); draw[black!45] (7.90000,0.00000) -- (14.21250,0.00000); draw[black!45] (8.20000,-2.85000) -- (8.20000,2.85000); node[] at (11.28333,3.90000) z_k=(1+Γ_k)/(1-Γ_k); fill (13.75000,0.00000) circle (.075); node[] at (13.98433,0.00000) 0; fill (10.75575,2.40959) circle …

    Exact mathematical passage
    z_k=(1+\Gamma_k)/(1-\Gamma_k)
\mathbb Z_pUse in source · 1 passage

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  • Use in source · Read passage · 04_arithmetic.tex, line 587

    The displayed matrices are complementary idempotents. The scalar 2 is a unit in Z_p for odd p, so both matrices are integral there. Over Z_2, multiplying by 2 clears the denominators, while neither projector preserves the standard lattice. Thus both weights are one. The resultant of the two linear factors is their root difference, which is 2.

    Exact mathematical passage
    \mathbb Z_p
\mathbb Z_p^2Use in source · 2 passages

Search aliases: Z_p^2 mathbb

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\ZZUse in source · 4 passages

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  • Use in source · visual_atlas.tex, line 32

    L · Precision depth in a quotient such as ZZ/2^LZZ. · L=5 gives arithmetic modulo 32.

    Exact mathematical passage
    \ZZ/2^L\ZZ
\ZZ^2Use in source · 1 passage

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  • Use in source · visual_atlas.tex, line 350

    vpage15Where the dyadic digit is lostMODEL D / THE EIGENLATTICE HAS INDEX TWOTraditional paper: Proposition 9.3 (p. 32) The eigenspaces are spanned by (1,0) and (-1,2). Their integral eigenvectors do not form an integral basis of ZZ^2. The change-of-basis determinant is two.

    Exact mathematical passage
    \ZZ^2
\ZZ_{(p)}^2Use in source · 1 passage

Search aliases: ZZ_(p)^2 ZZ

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  • Use in source · visual_atlas.tex, line 361

    0 · 2, AB=Bdiag(1,-1), E_+=Bdiag(1,0)B^-1. The index-two eigenlattice explains the denominator in B^-1 and in the projector. Over the localized lattice Λ_p=ZZ_(p)^2, the number 2 is a unit for every odd prime p. Hence the local denominator weight is zero there and one at p=2.

    Exact mathematical passage
    \Lambda_p=\ZZ_{(p)}^2
|^2Use in source · 1 passage

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  • Use in source · Read passage · 06_models.tex, line 79

    The symmetric weight w_Smith(Γ) = frac1|1-Γ|^2 + frac1|1+Γ|^2 indicates where small errors in reflection coordinates produce large impedance or admittance errors.

    Exact mathematical passage
    
    w_{\mathrm{Smith}}(\Gamma)
    =
    \frac1{|1-\Gamma|^2}
    +
    \frac1{|1+\Gamma|^2}
    
\pmUse in source · 3 passages

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  • Use in source · Read passage · 04_arithmetic.tex, line 685

    The failure of the character formula frac12(I± A) to be integral does not invalidate coefficient selectors such as even and odd residue extraction. It shows that two distinct constructions must be distinguished: integral address selector ≠ character-average spectral projector when the group order is not a unit. The first can remain exact over Z_2. The second can acquire a denominator weight.

    Exact mathematical passage
    
    \frac12(I\pm A)
    
\cdotUse in source · 139 passages

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  • Use in source · visual_atlas.tex, line 416

    For a specific attainable target (2,4), 2x≡2pmod8iff x∈{1,5}, 4y≡4pmod8iff y∈{1,3,5,7}. The coordinate choices are independent, giving 2·4=8 solutions. The entire carrier is partitioned consistently: 8 attainable targets × 8 inputs per target=64. For an inadmissible target, such as (1,4) or (2,2), the fiber is empty. The same nonzero cardinality formula must not be applied to it.

    Exact mathematical passage
    2\cdot4=8
\timesUse in source · 23 passages

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  • Use in source · Read passage · 02_coordinates.tex, line 407

    [Root-of-unity realization] Let R be a commutative semiring, let N>0, and suppose ω,ω^vee,η∈ R satisfy ω^N=1 and the finite N× N Fourier orthogonality table η∑_k=0^N-1(ω^vee)^jkω^rk = 1, · r=j,

    Exact mathematical passage
    N\times N
\alpha'Use in source · 2 passages

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  • Use in source · Read passage · 02_coordinates.tex, line 303

    Commutativity gives R_αβ^2=P_α^2Q_β^2=R_αβ. If (α,β)≠(α',β'), then either P_α P_α'=0 or Q_β Q_β'=0, so the corresponding products annihilate one another. Finally, ∑_α,βR_αβ = (∑_α P_α) (∑_β Q_β) =I_X. For a fixed α, P_α =P_α∑_β Q_β = ∑_β R_αβ, and the same argument works for a fixed β. Since each P_α and Q_β is nonzero, these identities ensure that every parent has a nonzero product child. The two parent maps on the supported product family are therefore surjective. Iteration proves the finite f…

    Exact mathematical passage
    (\alpha,\beta)\ne(\alpha',\beta')
\beta'Use in source · 2 passages

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  • Use in source · Read passage · 02_coordinates.tex, line 303

    Commutativity gives R_αβ^2=P_α^2Q_β^2=R_αβ. If (α,β)≠(α',β'), then either P_α P_α'=0 or Q_β Q_β'=0, so the corresponding products annihilate one another. Finally, ∑_α,βR_αβ = (∑_α P_α) (∑_β Q_β) =I_X. For a fixed α, P_α =P_α∑_β Q_β = ∑_β R_αβ, and the same argument works for a fixed β. Since each P_α and Q_β is nonzero, these identities ensure that every parent has a nonzero product child. The two parent maps on the supported product family are therefore surjective. Iteration proves the finite f…

    Exact mathematical passage
    (\alpha,\beta)\ne(\alpha',\beta')
\GammaUse in source · 17 passages

Search aliases: Γ Gamma

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  • Use in source · Read passage · 05_defects.tex, line 149

    Analytic functional calculus. [Holomorphic functional calculus defect] Let X_f and X_c be complex Banach spaces, and let C:X_f→ X_c, T_f, and T_c be bounded complex-linear maps. Let h be holomorphic on an open set U containing both spectra. Let Γ be an admissible finite rectifiable Cauchy cycle in U and in both resolvent sets, with winding number one on the union of the spectra and zero outside U. The length of a cycle counts multiplicities. Then Ch(T_f)-h(T_c)C = frac12π i ∫_Γ h(z)(z-T_c)^-1Δ(z…

    Exact mathematical passage
    \Gamma
\Gamma_kUse in source · 3 passages

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  • Use in source · visual_atlas.tex, line 510

    AR PHASE ORBITTraditional paper: Section 12.3 (p. 42), Section 12.3, Smith-phase identity (p. 43) Smith normal form concerns linear congruences. The Smith impedance chart uses the nonlinear coordinate change Γ=fracz-1z+1, z=frac1+Γ1-Γ. They share a name, not a mathematical definition. Sample the reflection circle at the exact algebraic points Γ_k=tfrac12 e^ikπ/4.

    Exact mathematical passage
    \Gamma_k=\tfrac12 e^{ik\pi/4}
\deltaUse in source · 4 passages

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  • Use in source · Read passage · 02_coordinates.tex, line 383

    [Residue packet algebra] For every commutative ring R, the operators (P_N,j)_0≤ j<N satisfy the identities below. If R is nonzero, they form a packet system on R[[z]]: P_N,iP_N,j=δ_ijP_N,j, ∑_j=0^N-1P_N,j=I.

    Exact mathematical passage
    
    P_{N,i}P_{N,j}=\delta_{ij}P_{N,j},
    \qquad
    \sum_{j=0}^{N-1}P_{N,j}=I.
    
\delta_0Use in source · 2 passages

Search aliases: δ_0 delta

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  • Use in source · Read passage · 06_models.tex, line 5

    Let x=(x_n)_n∈ Z∈ c_00( Z;R) and let the seed be δ_0 under the bilateral shifts (S^rδ_0)_n=δ_n,r. This makes the algebraic span and every displayed sum finite. The N packets are x_j[m]=x[Nm+j]. Synthesis interleaves these sequences. A linear filter with a finite impulse response that is invariant under shifts becomes an N× N matrix of transfer blocks. Refining from N to M with Nmid M splits each coarse phase into its descendants without changing the reconstructed signal. The same formulas extend…

    Exact mathematical passage
    \delta_0
\delta_{ij}Use in source · 2 passages

Search aliases: δ_ij delta

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  • Use in source · Read passage · 02_coordinates.tex, line 383

    [Residue packet algebra] For every commutative ring R, the operators (P_N,j)_0≤ j<N satisfy the identities below. If R is nonzero, they form a packet system on R[[z]]: P_N,iP_N,j=δ_ijP_N,j, ∑_j=0^N-1P_N,j=I.

    Exact mathematical passage
    
    P_{N,i}P_{N,j}=\delta_{ij}P_{N,j},
    \qquad
    \sum_{j=0}^{N-1}P_{N,j}=I.
    
\delta_{n,r}Use in source · 1 passage

Search aliases: δ_n,r delta

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  • Use in source · Read passage · 06_models.tex, line 6

    Let x=(x_n)_n∈ Z∈ c_00( Z;R) and let the seed be δ_0 under the bilateral shifts (S^rδ_0)_n=δ_n,r. This makes the algebraic span and every displayed sum finite. The N packets are x_j[m]=x[Nm+j]. Synthesis interleaves these sequences. A linear filter with a finite impulse response that is invariant under shifts becomes an N× N matrix of transfer blocks. Refining from N to M with Nmid M splits each coarse phase into its descendants without changing the reconstructed signal. The same formulas extend…

    Exact mathematical passage
    (S^r\delta_0)_n=\delta_{n,r}
\Delta_\ellUse in source · 4 passages

Search aliases: Δ_ℓ Delta ell

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  • Use in source · Read passage · 05_defects.tex, line 217

    Let C_ℓ:X_ℓ+1⟶ X_ℓ be linear maps for 0≤ℓ<L, and let T_ℓ∈End(X_ℓ). Put Δ_ℓ=C_ℓ T_ℓ+1-T_ℓ C_ℓ. For a<b, write C_a,b=C_aC_a+1⋯ C_b-1, with C_a,a=I.

    Exact mathematical passage
    
    \Delta_\ell=C_\ell T_{\ell+1}-T_\ell C_\ell.
    
\varepsilonUse in source · 9 passages

Search aliases: ε varepsilon

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  • Use in source · visual_atlas.tex, line 527

    vpage22A small defect can grow under powersMODEL H / EXACT TELESCOPING, EXPLICIT GROWTHTraditional paper: Theorem 11.1 (p. 37), Corollary 11.3 (p. 38) Choose an invertible coordinate shear but independently keep the same numerical operator at both levels: C=1 · ε 0 · 1, T_f=T_c=diag(1,2), ε=frac116. Then Δ=CT_f-T_cC=ε E_01. Exact coordinate invertibility has not forced these independently selected operators to intertwine.

    Exact mathematical passage
    
    C=\begin{pmatrix}1&\varepsilon\\0&1\end{pmatrix},\quad
    T_f=T_c=\diag(1,2),\quad \varepsilon=\frac1{16}.
    
\etaUse in source · 8 passages

Search aliases: η eta

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  • Use in source · Read passage · 02_coordinates.tex, line 406

    [Root-of-unity realization] Let R be a commutative semiring, let N>0, and suppose ω,ω^vee,η∈ R satisfy ω^N=1 and the finite N× N Fourier orthogonality table η∑_k=0^N-1(ω^vee)^jkω^rk = 1, · r=j,

    Exact mathematical passage
    \omega,\omega^\vee,\eta\in R
\Lambda_0Use in source · 1 passage

Search aliases: Λ_0 Lambda

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  • Use in source · Read passage · 04_arithmetic.tex, line 505

    [The same rational split with two lattices] Let V=Ke_1⊕ Ke_2 and let E project onto Ke_1. On the split lattice Λ_0= O e_1⊕ O e_2, the weight is zero. Fix s≥1 and consider Λ_s = O e_1+ O(π^-se_1+e_2). Then Λ_s∩ Ke_1= O e_1, Λ_s∩ Ke_2=π^s O e_2. The gluing module is isomorphic to O/π^s O, so s_Λ_s(E)=s. The rational decomposition has not changed. Only the lattice has changed.

    Exact mathematical passage
    
    \Lambda_0=\OO e_1\oplus\OO e_2,
    
\Lambda_1Use in source · 5 passages

Search aliases: Λ_1 Lambda

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  • Use in source · Read passage · 04_arithmetic.tex, line 349

    [Two complementary packets] Suppose V=V_1⊕ V_2 with projector E onto V_1 and complementary projector I-E. Then Λ/(Λ_1⊕Λ_2) ≅ EΛ/Λ_1 ≅ (I-E)Λ/Λ_2. Consequently s_Λ(E)=s_Λ(I-E) = exp_π(Λ/(Λ_1⊕Λ_2)).

    Exact mathematical passage
    
    \Lambda/(\Lambda_1\oplus\Lambda_2)
    \cong
    E\Lambda/\Lambda_1
    \cong
    (I-E)\Lambda/\Lambda_2.
    
\Lambda_2Use in source · 4 passages

Search aliases: Λ_2 Lambda

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  • Use in source · Read passage · 04_arithmetic.tex, line 349

    [Two complementary packets] Suppose V=V_1⊕ V_2 with projector E onto V_1 and complementary projector I-E. Then Λ/(Λ_1⊕Λ_2) ≅ EΛ/Λ_1 ≅ (I-E)Λ/Λ_2. Consequently s_Λ(E)=s_Λ(I-E) = exp_π(Λ/(Λ_1⊕Λ_2)).

    Exact mathematical passage
    
    \Lambda/(\Lambda_1\oplus\Lambda_2)
    \cong
    E\Lambda/\Lambda_1
    \cong
    (I-E)\Lambda/\Lambda_2.
    
\Lambda_pUse in source · 1 passage

Search aliases: Λ_p Lambda

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  • Use in source · visual_atlas.tex, line 361

    0 · 2, AB=Bdiag(1,-1), E_+=Bdiag(1,0)B^-1. The index-two eigenlattice explains the denominator in B^-1 and in the projector. Over the localized lattice Λ_p=ZZ_(p)^2, the number 2 is a unit for every odd prime p. Hence the local denominator weight is zero there and one at p=2.

    Exact mathematical passage
    \Lambda_p=\ZZ_{(p)}^2
\Lambda_{\Pcal}Use in source · 4 passages

Search aliases: Λ_Pcal Λ_ P Lambda Pcal Lambda mathcal

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  • Use in source · Read passage · 04_arithmetic.tex, line 399

    [Gluing exact sequence under refinement] Let Q=(Q_β) refine P=(P_α) on V, and let Λ be a lattice. Define Λ_ P = ⊕_α(Λ∩ P_α V), Λ_ Q = ⊕_β(Λ∩ Q_β V). Then Λ_ Q⊆Λ_ P⊆Λ and there is a short exact sequence 0 ⟶ Λ_ P/Λ_ Q ⟶ Λ/Λ_ Q ⟶ Λ/Λ_ P ⟶0. In particular, s_Λ( P)≤ s_Λ( Q).

    Exact mathematical passage
    
    \Lambda_{\Pcal}
    =
    \bigoplus_\alpha(\Lambda\cap P_\alpha V),
    \qquad
    \Lambda_{\Qcal}
    =
    \bigoplus_\beta(\Lambda\cap Q_\beta V).
    
\Lambda_{\Qcal}Use in source · 4 passages

Search aliases: Λ_Qcal Λ_ Q Lambda Qcal Lambda mathcal

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  • Use in source · Read passage · 04_arithmetic.tex, line 399

    [Gluing exact sequence under refinement] Let Q=(Q_β) refine P=(P_α) on V, and let Λ be a lattice. Define Λ_ P = ⊕_α(Λ∩ P_α V), Λ_ Q = ⊕_β(Λ∩ Q_β V). Then Λ_ Q⊆Λ_ P⊆Λ and there is a short exact sequence 0 ⟶ Λ_ P/Λ_ Q ⟶ Λ/Λ_ Q ⟶ Λ/Λ_ P ⟶0. In particular, s_Λ( P)≤ s_Λ( Q).

    Exact mathematical passage
    
    \Lambda_{\Pcal}
    =
    \bigoplus_\alpha(\Lambda\cap P_\alpha V),
    \qquad
    \Lambda_{\Qcal}
    =
    \bigoplus_\beta(\Lambda\cap Q_\beta V).
    
\Lambda_sUse in source · 4 passages

Search aliases: Λ_s Lambda

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  • Use in source · Read passage · 04_arithmetic.tex, line 509

    [The same rational split with two lattices] Let V=Ke_1⊕ Ke_2 and let E project onto Ke_1. On the split lattice Λ_0= O e_1⊕ O e_2, the weight is zero. Fix s≥1 and consider Λ_s = O e_1+ O(π^-se_1+e_2). Then Λ_s∩ Ke_1= O e_1, Λ_s∩ Ke_2=π^s O e_2. The gluing module is isomorphic to O/π^s O, so s_Λ_s(E)=s. The rational decomposition has not changed. Only the lattice has changed.

    Exact mathematical passage
    
    \Lambda_s
    =
    \OO e_1+
    \OO(\pi^{-s}e_1+e_2).
    
\pi^{-s}Use in source · 2 passages

Search aliases: π^-s pi

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  • Use in source · Read passage · 04_arithmetic.tex, line 509

    [The same rational split with two lattices] Let V=Ke_1⊕ Ke_2 and let E project onto Ke_1. On the split lattice Λ_0= O e_1⊕ O e_2, the weight is zero. Fix s≥1 and consider Λ_s = O e_1+ O(π^-se_1+e_2). Then Λ_s∩ Ke_1= O e_1, Λ_s∩ Ke_2=π^s O e_2. The gluing module is isomorphic to O/π^s O, so s_Λ_s(E)=s. The rational decomposition has not changed. Only the lattice has changed.

    Exact mathematical passage
    
    \Lambda_s
    =
    \OO e_1+
    \OO(\pi^{-s}e_1+e_2).
    
\pi^aUse in source · 2 passages

Search aliases: π^a pi

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  • Use in source · Read passage · 03_weighted.tex, line 211

    [A triangular transfer] Let O be complete with uniformizer π, and consider T= 1 · π^a 0 · 1 with a≥1. The only nontrivial transfer has weight a, and its square is zero. Hence T^-1 = 1 · -π^a

    Exact mathematical passage
    
    T=
    \begin{pmatrix}
    1&\pi^a\\
    0&1
    \end{pmatrix}
    
\pi^{a_1}Use in source · 1 passage

Search aliases: π^a_1 pi

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  • Use in source · Read passage · 04_arithmetic.tex, line 729

    [Computing a packet weight from an inclusion matrix] Choose an O basis of Λ and an O basis of Λ_split. Let B be the matrix of the inclusion Λ_split↪Λ. If the Smith form of B is diag(π^a_1,…,π^a_n), 0≤ a_1≤⋯≤ a_n, then G_Λ, P ≅ ⊕_j=1^n O/π^a_j O, s_Λ( P)=max({0}∪{a_j:1≤ j≤ n}).

    Exact mathematical passage
    
    \diag(\pi^{a_1},\ldots,\pi^{a_n}),
    \qquad
    0\leq a_1\leq\cdots\leq a_n,
    
\pi^{a_j}Use in source · 3 passages

Search aliases: π^a_j pi

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  • Use in source · Read passage · 04_arithmetic.tex, line 284

    ght] With the notation of [source reference], the map Φ:G_Λ, P ⟶ ⊕_α∈ IE_αΛ/Λ_α, [x]⟼(E_α x+Λ_α)_α is injective, and every coordinate projection of its image is surjective. We also have exp_π(G_Λ, P) = s_Λ( P). If G_Λ, P ≅ ⊕_j=1^r O/π^a_j O with a_1≤⋯≤ a_r, then s_Λ( P)=max({0}∪{a_j:1≤ j≤ r}).

    Exact mathematical passage
    
    G_{\Lambda,\Pcal}
    \cong
    \bigoplus_{j=1}^r\OO/\pi^{a_j}\OO
    
\pi^{a_n}Use in source · 1 passage

Search aliases: π^a_n pi

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  • Use in source · Read passage · 04_arithmetic.tex, line 729

    [Computing a packet weight from an inclusion matrix] Choose an O basis of Λ and an O basis of Λ_split. Let B be the matrix of the inclusion Λ_split↪Λ. If the Smith form of B is diag(π^a_1,…,π^a_n), 0≤ a_1≤⋯≤ a_n, then G_Λ, P ≅ ⊕_j=1^n O/π^a_j O, s_Λ( P)=max({0}∪{a_j:1≤ j≤ n}).

    Exact mathematical passage
    
    \diag(\pi^{a_1},\ldots,\pi^{a_n}),
    \qquad
    0\leq a_1\leq\cdots\leq a_n,
    
\pi^dUse in source · 5 passages

Search aliases: π^d pi

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  • Use in source · Read passage · 04_arithmetic.tex, line 315

    Let s=s_Λ( P). For every x∈Λ and every α, π^sE_α x∈Λ_α. Hence π^sx=∑_απ^sE_α x∈Λ_split, so π^sG_Λ, P=0. This proves exp_π(G_Λ, P)≤ s. If d<s, then for some α there is an x∈Λ with π^dE_α x∉Λ_α. The class π^d[x] is therefore nonzero in the gluing module. Thus π^d does not annihilate the gluing module, and equality follows. The final formula is the usual description of the exponent through Smith normal form.

    Exact mathematical passage
    
    \pi^dE_\alpha x\notin\Lambda_\alpha.
    
\pi^LUse in source · 8 passages

Search aliases: π^L pi

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  • Use in source · Read passage · 03_weighted.tex, line 29

    If O is a complete discrete valuation ring with uniformizer π and B is a separated and complete O algebra for the filtration F^L B=π^L B, then this is a standard example. Finite matrix algebras over O satisfy these conditions. Completeness of O alone does not imply completeness of every O algebra. Basic facts about completeness in this setting are reviewed in [source reference].

    Exact mathematical passage
    
    F^L\Bcal=\pi^L\Bcal,
    
\pi^mUse in source · 8 passages

Search aliases: π^m pi

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  • Use in source · Read passage · 03_weighted.tex, line 237

    Let O be a complete discrete valuation ring with uniformizer π, fraction field K, and filtration F^m B=π^m B on an O-algebra B. The finite quotient statements below do not require B itself to be complete. Suppose T=D+H, where D is invertible and the perturbation H raises filtration. The symbol K is reserved for the fraction field.

    Exact mathematical passage
    
    F^m\cB=\pi^m\cB
    
\pi^{m+d}Use in source · 3 passages

Search aliases: π^m+d pi

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  • Use in source · Read passage · 04_arithmetic.tex, line 460

    n delay] Let E be a rational projector on V, let Λ be a lattice, and let s=s_Λ(E). For every m≥0, the rule [x]_m+s⟼[Ex]_m from Λ/π^m+sΛ to V/π^mΛ is well defined. Here m is an integer. If d is an integer with 0≤ d<s, then for every integer m≥0 there are x,y∈Λ such that x≡ ypmodπ^m+dΛ but Exnot≡ Eypmodπ^mΛ. Thus s extra digits are both sufficient and necessary for a uniform precision guarantee.

    Exact mathematical passage
    
    x\equiv y\pmod{\pi^{m+d}\Lambda}
    
\pi^{m+s}Use in source · 5 passages

Search aliases: π^m+s pi

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  • Use in source · Read passage · 04_arithmetic.tex, line 209

    [Projector precision delay] Let E be a rational projector with π^sE(Λ)⊆Λ. If x≡ ypmodπ^m+sΛ, then Ex≡ Eypmodπ^mΛ. Thus m+s input digits suffice to determine m output digits of the projected packet.

    Exact mathematical passage
    
    x\equiv y\pmod{\pi^{m+s}\Lambda},
    
\pi^{\min(s_i,L)}Use in source · 2 passages

Search aliases: π^min(s_i,L) pi min

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  • Use in source · Read passage · 04_arithmetic.tex, line 758

    [Smith weighted congruence solve] Let M∈ M_m,n( O) have Smith exponents s_1,…,s_r. Assume the residue field is finite of cardinality q, fix L≥1, and consider Mx≡ bpmodπ^L. Put widetilde b=Ub for a Smith matrix U as in [source reference]. The congruence is solvable if and only if widetilde b_i≡0 pmodπ^min(s_i,L) (1≤ i≤ r) and widetilde b_i≡0 pmodπ^L (r<i≤ m). When it is solvable, the number of solutions in ( O/π^L O)^n is q^(n-r)L+∑_i=1^rmin(s_i,L).

    Exact mathematical passage
    
    \widetilde b_i\equiv0
    \pmod{\pi^{\min(s_i,L)}}
    \qquad(1\leq i\leq r)
    
\pi^{s_1}Use in source · 2 passages

Search aliases: π^s_1 pi

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  • Use in source · Read passage · 04_arithmetic.tex, line 711

    [Smith normal form over a discrete valuation ring] Let M∈ M_m,n( O). There are invertible matrices U∈GL_m( O), V∈GL_n( O) such that UMV = diag(π^s_1,…,π^s_r,0,…,0), where 0≤ s_1≤⋯≤ s_r and r is the rank over K. The exponents are uniquely determined. See [source reference].

    Exact mathematical passage
    
    UMV
    =
    \diag(\pi^{s_1},\ldots,\pi^{s_r},0,\ldots,0),
    
\pi^{s_i}Use in source · 2 passages

Search aliases: π^s_i pi

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  • Use in source · Read passage · 04_arithmetic.tex, line 779

    Set x=Vy. Multiplying the congruence by U reduces it to independent equations π^s_iy_i≡widetilde b_ipmodπ^L (1≤ i≤ r) and zero equations in the remaining rows. Multiplication by π^s_i on O/π^L O has image equal to the elements divisible by π^min(s_i,L) and kernel of size q^min(s_i,L). Each of the n-r unused variables is free and contributes q^L choices. Multiplying the independent counts gives the formula.

    Exact mathematical passage
    
    \pi^{s_i}y_i\equiv\widetilde b_i\pmod{\pi^L}
    \qquad(1\leq i\leq r)
    
\pi^{s_r}Use in source · 2 passages

Search aliases: π^s_r pi

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  • Use in source · Read passage · 04_arithmetic.tex, line 711

    [Smith normal form over a discrete valuation ring] Let M∈ M_m,n( O). There are invertible matrices U∈GL_m( O), V∈GL_n( O) such that UMV = diag(π^s_1,…,π^s_r,0,…,0), where 0≤ s_1≤⋯≤ s_r and r is the rank over K. The exponents are uniquely determined. See [source reference].

    Exact mathematical passage
    
    UMV
    =
    \diag(\pi^{s_1},\ldots,\pi^{s_r},0,\ldots,0),
    
\pi^{\val_\pi(\Res(f,g))}Use in source · 1 passage

Search aliases: π^val_π(Res(f,g)) pi val pi Res pi operatorname pi operatorname

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  • Use in source · Read passage · 04_arithmetic.tex, line 89

    [Resultant denominator bound] Under the hypotheses of [source reference], one may take r=Res(f,g) up to multiplication by a unit. Therefore π^val_π(Res(f,g))E_fΛ⊆Λ.

    Exact mathematical passage
    
    \pi^{\val_\pi(\Res(f,g))}E_f\Lambda\subseteq\Lambda.
    
\rho^{n-1}Use in source · 1 passage

Search aliases: ρ^n-1 rho

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  • Use in source · Read passage · 05_defects.tex, line 70

    [Norm bound] For a submultiplicative operator norm, CT_f^n-T_c^nC ≤ Δ ∑_k=0^n-1 T_c ^n-1-k T_f ^k. If T_f , T_c ≤ρ, then CT_f^n-T_c^nC ≤ nρ^n-1 Δ .

    Exact mathematical passage
    
    \boxed{
    \|CT_f^n-T_c^nC\|
    \le n\rho^{n-1}\|\Delta\|.
    }
    
\rho_{m,\ell}Use in source · 3 passages

Search aliases: ρ_m,ℓ rho ell

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  • Use in source · Read passage · 02_coordinates.tex, line 69

    A refinement tower is a sequence ( P_ℓ)_ℓ≥0 with parent maps ρ_m,ℓ:I_m⟶ I_ℓ (m≥ℓ) such that P_m refines P_ℓ through ρ_m,ℓ for every m≥ℓ, and ρ_ℓ,ℓ=id_I_ℓ, ρ_n,ℓ=ρ_m,ℓ∘ρ_n,m (n≥ m≥ℓ). Thus every parent map witnesses the stated refinement and the maps compose coherently. The next result shows that the coordinate changes form a coherent system.

    Exact mathematical passage
    
    \rho_{m,\ell}:I_m\longrightarrow I_\ell
    \qquad(m\geq\ell)
    
\rho_{n,m}Use in source · 1 passage

Search aliases: ρ_n,m rho

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  • Use in source · Read passage · 02_coordinates.tex, line 74

    A refinement tower is a sequence ( P_ℓ)_ℓ≥0 with parent maps ρ_m,ℓ:I_m⟶ I_ℓ (m≥ℓ) such that P_m refines P_ℓ through ρ_m,ℓ for every m≥ℓ, and ρ_ℓ,ℓ=id_I_ℓ, ρ_n,ℓ=ρ_m,ℓ∘ρ_n,m (n≥ m≥ℓ). Thus every parent map witnesses the stated refinement and the maps compose coherently. The next result shows that the coordinate changes form a coherent system.

    Exact mathematical passage
    
    \rho_{\ell,\ell}=\id_{I_\ell},
    \qquad
    \rho_{n,\ell}=\rho_{m,\ell}\circ\rho_{n,m}
    \qquad(n\geq m\geq\ell).
    
\rho_{n,\ell}Use in source · 1 passage

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  • Use in source · Read passage · 02_coordinates.tex, line 74

    A refinement tower is a sequence ( P_ℓ)_ℓ≥0 with parent maps ρ_m,ℓ:I_m⟶ I_ℓ (m≥ℓ) such that P_m refines P_ℓ through ρ_m,ℓ for every m≥ℓ, and ρ_ℓ,ℓ=id_I_ℓ, ρ_n,ℓ=ρ_m,ℓ∘ρ_n,m (n≥ m≥ℓ). Thus every parent map witnesses the stated refinement and the maps compose coherently. The next result shows that the coordinate changes form a coherent system.

    Exact mathematical passage
    
    \rho_{\ell,\ell}=\id_{I_\ell},
    \qquad
    \rho_{n,\ell}=\rho_{m,\ell}\circ\rho_{n,m}
    \qquad(n\geq m\geq\ell).
    
\rho_{\ell,\ell}Use in source · 1 passage

Search aliases: ρ_ℓ,ℓ rho ell ell

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  • Use in source · Read passage · 02_coordinates.tex, line 74

    A refinement tower is a sequence ( P_ℓ)_ℓ≥0 with parent maps ρ_m,ℓ:I_m⟶ I_ℓ (m≥ℓ) such that P_m refines P_ℓ through ρ_m,ℓ for every m≥ℓ, and ρ_ℓ,ℓ=id_I_ℓ, ρ_n,ℓ=ρ_m,ℓ∘ρ_n,m (n≥ m≥ℓ). Thus every parent map witnesses the stated refinement and the maps compose coherently. The next result shows that the coordinate changes form a coherent system.

    Exact mathematical passage
    
    \rho_{\ell,\ell}=\id_{I_\ell},
    \qquad
    \rho_{n,\ell}=\rho_{m,\ell}\circ\rho_{n,m}
    \qquad(n\geq m\geq\ell).
    
\sigmaUse in source · 1 passage

Search aliases: σ sigma

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  • Use in source · Read passage · 05_defects.tex, line 170

    The assertion is immediate if either space is zero. Otherwise, use the rectifiable-cycle form of the holomorphic functional calculus in [source reference]. For each operator T, compare Γ with a positive simple system around its spectrum. Their difference has zero winding outside U∖σ(T), so Theorem~4.1 applied to the resolvent-valued integrand identifies the two integrals. Consequently, h(T) = frac12π i ∫_Γ h(z)(z-T)^-1 dz. Subtract the two formulas after composing with C, then use [source refere…

    Exact mathematical passage
    U\setminus\sigma(T)
\PhiUse in source · 2 passages

Search aliases: Φ Phi

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  • Use in source · Read passage · 04_arithmetic.tex, line 268

    [Gluing module and exact separation weight] With the notation of [source reference], the map Φ:G_Λ, P ⟶ ⊕_α∈ IE_αΛ/Λ_α, [x]⟼(E_α x+Λ_α)_α is injective, and every coordinate projection of its image is surjective. We also have exp_π(G_Λ, P) = s_Λ( P). If G_Λ, P ≅ ⊕_j=1^r O/π^a_j O with a_1≤⋯≤ a_r, then s_Λ( P)=max({0}∪{a_j:1≤ j≤ r}).

    Exact mathematical passage
    
    \Phi:G_{\Lambda,\Pcal}
    \longrightarrow
    \bigoplus_{\alpha\in I}E_\alpha\Lambda/\Lambda_\alpha,
    \qquad
    [x]\longmapsto(E_\alpha x+\Lambda_\alpha)_\alpha
    
\chiUse in source · 6 passages

Search aliases: χ chi

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  • Use in source · Read passage · 04_arithmetic.tex, line 11

    [Bézout spectral projector] Assume that χ_A(x)=f(x)g(x) with monic polynomials f,g∈ O[x] that are coprime in K[x]. Choose u,v∈ O[x] and a nonzero r∈ O such that u(x)f(x)+v(x)g(x)=r. Then E_f=r^-1v(A)g(A) is the projector of V onto Ker f(A) along Ker g(A). In particular, E_f^2=E_f, rE_f∈End_ O(Λ).

    Exact mathematical passage
    
    \chi_A(x)=f(x)g(x)
    
\chi_AUse in source · 6 passages

Search aliases: χ_A chi

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  • Use in source · Read passage · 04_arithmetic.tex, line 11

    [Bézout spectral projector] Assume that χ_A(x)=f(x)g(x) with monic polynomials f,g∈ O[x] that are coprime in K[x]. Choose u,v∈ O[x] and a nonzero r∈ O such that u(x)f(x)+v(x)g(x)=r. Then E_f=r^-1v(A)g(A) is the projector of V onto Ker f(A) along Ker g(A). In particular, E_f^2=E_f, rE_f∈End_ O(Λ).

    Exact mathematical passage
    
    \chi_A(x)=f(x)g(x)
    
\omegaUse in source · 25 passages

Search aliases: ω omega

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\omega^{-1}Use in source · 3 passages

Search aliases: ω^-1 omega

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  • Use in source · Read passage · 02_coordinates.tex, line 427

    0, · r≠ j, 0≤ j,r<N. Then P_N,j = η∑_k=0^N-1(ω^vee)^jkU^k. In particular, if R is a field, N>0, and ω is a primitive Nth root of unity, the certificate holds with ω^vee=ω^-1 and η=N^-1.

    Exact mathematical passage
    \omega^\vee=\omega^{-1}
\omega^{-jk}Use in source · 2 passages

Search aliases: ω^-jk omega

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  • Use in source · Read passage · 02_coordinates.tex, line 457

    The field specialization. [Character realization] Let bbk be a field, assume that N is nonzero in bbk, and suppose that bbk contains a primitive Nth root of unity ω. Define (UF)(z)=F(ω z). Then P_N,j = frac1N∑_k=0^N-1ω^-jkU^k.

    Exact mathematical passage
    
    P_{N,j}
    =
    \frac1N\sum_{k=0}^{N-1}\omega^{-jk}U^k.
    
\omega^3Use in source · 1 passage

Search aliases: ω^3 omega

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  • Use in source · finite_fourier_table.tex, line 41

    .35pt,] (5.00000,1.10000) rectangle ++(0.70000,0.70000); node[] at (5.35000,1.45000) 0; draw[fill=black!0,draw=black!45,line width=.35pt,] (5.70000,1.10000) rectangle ++(0.70000,0.70000); node[] at (6.05000,1.45000) 0; draw[fill=black!12,draw=black!45,line width=.35pt,] (6.40000,1.10000) rectangle ++(0.70000,0.70000); node[] at (6.75000,1.45000) 1; node[] at (10.15000,3.05000) ω=2, ω^3=1; node[] at (10.15000,2.15000) ω^-1=4, η=5; node[] at (10.15000,1.25000) j,r∈{0,1,2}; draw[black!35] (0.00000,…

    Exact mathematical passage
    \omega=2,\quad\omega^3=1
\omega^{k(n-j)}Use in source · 1 passage

Search aliases: ω^k(n-j) omega

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  • Use in source · Read passage · 02_coordinates.tex, line 466

    On z^n, the right side acts by the scalar frac1N∑_k=0^N-1ω^k(n-j). This is one when n≡ jpmod N and zero otherwise by the geometric sum identity in the field bbk.

    Exact mathematical passage
    
    \frac1N\sum_{k=0}^{N-1}\omega^{k(n-j)}.
    
\omega^NUse in source · 3 passages

Search aliases: ω^N omega

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\omega^{nk}Use in source · 1 passage

Search aliases: ω^nk omega

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  • Use in source · Read passage · 02_coordinates.tex, line 432

    On the monomial z^n, the right-hand side acts by η∑_k=0^N-1(ω^vee)^jkω^nk. The identity ω^N=1 reduces this expression to the table entry indexed by r=nbmod N. The finite certificate therefore gives exactly the coefficient mask defining P_N,j. Over a field, the primitive-root geometric sum supplies the certificate.

    Exact mathematical passage
    
    \eta\sum_{k=0}^{N-1}(\omega^\vee)^{jk}\omega^{nk}.
    
\omega^{rk}Use in source · 1 passage

Search aliases: ω^rk omega

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  • Use in source · Read passage · 02_coordinates.tex, line 408

    [Root-of-unity realization] Let R be a commutative semiring, let N>0, and suppose ω,ω^vee,η∈ R satisfy ω^N=1 and the finite N× N Fourier orthogonality table η∑_k=0^N-1(ω^vee)^jkω^rk = 1, · r=j, 0, · r≠ j, 0≤ j,r<N. Then P_N,j = η∑_k=0^N-1(ω^vee)^jkU^k. In particular, if R is a field, N>0, and ω is a primitive Nth root of unity, the certificate holds with ω^vee=ω^-1 and η=N^-1.

    Exact mathematical passage
    
    \eta\sum_{k=0}^{N-1}(\omega^\vee)^{jk}\omega^{rk}
    =
    \begin{cases}
    1,&r=j,\\
    0,&r\ne j,
    \end{cases}
    \qquad 0\le j,r<N.
    
\omega^\veeUse in source · 5 passages

Search aliases: ω^vee omega vee

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  • Use in source · Read passage · 02_coordinates.tex, line 406

    [Root-of-unity realization] Let R be a commutative semiring, let N>0, and suppose ω,ω^vee,η∈ R satisfy ω^N=1 and the finite N× N Fourier orthogonality table η∑_k=0^N-1(ω^vee)^jkω^rk = 1, · r=j,

    Exact mathematical passage
    \omega,\omega^\vee,\eta\in R
\omega_N^kUse in source · 4 passages

Search aliases: ω_N^k omega

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  • Use in source · Read passage · 06_models.tex, line 46

    Let Z and Z_0≠0 be complex impedances, put z=Z/Z_0, and assume z≠-1. Write Γ=fracz-1z+1. On the open reflection disk |Γ|<1, multiplication by any phase ω_N^k stays in the disk and has a finite inverse-chart image. The phase action is Γ↦ω_N^kΓ. Outside the open disk, the same chart formula requires 1-ω_N^kΓ≠0. Pulling the phase action back on this domain gives T_N,k(z) = frac(1+ω_N^k)z+(1-ω_N^k) (1-ω_N^k)z+(1+ω_N^k). For N=2 and k=1, T_2,1(z)=frac1z, z≠0,-1. Thus the nontrivial action at the firs…

    Exact mathematical passage
    \omega_N^k
\ell^2Use in source · 1 passage

Search aliases: ℓ^2 ell

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  • Use in source · visual_atlas.tex, line 317

    headThree boundaries of this calculation This is a formal series identity. No analytic convergence at a chosen real or complex value of t is needed. The canonical determinant need not be the minimal denominator after cancellation. Finally, positive weights prevent infinitely many walks at a fixed weight: a single weight-zero loop would already give the infinitely many distinct walks 1,ℓ,ℓ^2,… at weight zero.

    Exact mathematical passage
    1,\ell,\ell^2,\ldots
\mapstoUse in source · 3 passages

Search aliases: ↦ mapsto

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  • Use in source · Read passage · 06_models.tex, line 47

    Let Z and Z_0≠0 be complex impedances, put z=Z/Z_0, and assume z≠-1. Write Γ=fracz-1z+1. On the open reflection disk |Γ|<1, multiplication by any phase ω_N^k stays in the disk and has a finite inverse-chart image. The phase action is Γ↦ω_N^kΓ. Outside the open disk, the same chart formula requires 1-ω_N^kΓ≠0. Pulling the phase action back on this domain gives T_N,k(z) = frac(1+ω_N^k)z+(1-ω_N^k) (1-ω_N^k)z+(1+ω_N^k). For N=2 and k=1, T_2,1(z)=frac1z, z≠0,-1. Thus the nontrivial action at the firs…

    Exact mathematical passage
    
    \Gamma\mapsto\omega_N^k\Gamma.
    
\hookrightarrowUse in source · 1 passage

Search aliases: ↪ hookrightarrow

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  • Use in source · Read passage · 04_arithmetic.tex, line 725

    [Computing a packet weight from an inclusion matrix] Choose an O basis of Λ and an O basis of Λ_split. Let B be the matrix of the inclusion Λ_split↪Λ. If the Smith form of B is diag(π^a_1,…,π^a_n), 0≤ a_1≤⋯≤ a_n, then G_Λ, P ≅ ⊕_j=1^n O/π^a_j O, s_Λ( P)=max({0}∪{a_j:1≤ j≤ n}).

    Exact mathematical passage
    
    \Lambda_{\mathrm{split}}\hookrightarrow\Lambda.
    
\RightarrowUse in source · 1 passage

Search aliases: ⇒ Rightarrow

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  • Use in source · Read passage · 06_models.tex, line 285

    The proof order is: · complete packet axioms ⇒finite-packet uniqueness and coordinate coherence · ⇒coordinate naturality and refined transfer blocks, · residue selectors and a finite Fourier table ⇒Fourier formulas, · coprime moduli⇒dyadic--odd formulas, · quotient, filtration, and edge-weight certificates ⇒explicit pruned inverse, · finite positive-weight graph ⇒semantic enumeration and first-edge recurrence · ⇒det/adj rationality and recurrence, · minimal evaluated B ezout data and inverse-uni…

    Exact mathematical passage
    
    \begin{aligned}
    &\text{complete packet axioms}
      \Rightarrow\text{finite-packet uniqueness and coordinate coherence}\\
    &\qquad\Rightarrow\text{coordinate naturality and refined transfer blocks},\\
    &\text{residue selectors and a finite Fourier table}
      \Rightarrow\text{Fourier formulas},\\
    &\text{coprime moduli}\Rightarrow\text{dyadic--odd formulas},\\
    &\text{quotient, filtration, and edge-weight certificates}
      \Rightarrow\text{explicit pruned inverse},\\
    &\text{finite positive-weight graph}
      \Rightarrow\text{semantic enumeration and first-edge recurrence}\\
    &\qquad\Rightarrow\det/\operatorname{adj}\text{ rationality and recurrence},\\
    &\text{minimal evaluated B\'ezout data and inverse-unit lattice action}\\
    &\qquad\Rightarrow\text{separation bound, upward closure, and precision delay},\\
    &\text{concrete }\mathbb Z/p^L\mathbb Z\text{ coordinate fibres}
      \Rightarrow\text{finite Smith product count},\\
    &\text{one-step typed defect}
      \Rightarrow\text{powers, polynomial actions, and witnessed resolvents}.
    \end{aligned}
    
\existsUse in source · 1 passage

Search aliases: ∃ exists

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  • Use in source · Read passage · 04_arithmetic.tex, line 856

    Lean proves the one-coordinate arithmetic directly over Z/p^L Z for every p>1: (∃ x∈ Z/p^L Z: p^s x=bpmodp^L) Longleftrightarrow p^min(s,L)mid b_val, where b_val is the canonical natural representative, and every admissible fibre has exactly p^min(s,L) elements. The coordinates are independent, so the product equivalence gives the displayed global count. If one coordinate fibre is empty, the global fibre is empty. Lean proves both the global solvability equivalence and the conditional count, inc…

    Exact mathematical passage
    
    \bigl(\exists x\in\mathbb Z/p^L\mathbb Z:\quad p^s x=b\pmod{p^L}\bigr)
    \quad\Longleftrightarrow\quad
    p^{\min(s,L)}\mid b_{\mathrm{val}},
    
\notinUse in source · 5 passages

Search aliases: ∉ notin

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  • Use in source · Read passage · 04_arithmetic.tex, line 315

    Let s=s_Λ( P). For every x∈Λ and every α, π^sE_α x∈Λ_α. Hence π^sx=∑_απ^sE_α x∈Λ_split, so π^sG_Λ, P=0. This proves exp_π(G_Λ, P)≤ s. If d<s, then for some α there is an x∈Λ with π^dE_α x∉Λ_α. The class π^d[x] is therefore nonzero in the gluing module. Thus π^d does not annihilate the gluing module, and equality follows. The final formula is the usual description of the exponent through Smith normal form.

    Exact mathematical passage
    
    \pi^dE_\alpha x\notin\Lambda_\alpha.
    
\prod_{i=1}^rUse in source · 1 passage

Search aliases: ∏_i=1^r prod

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  • Use in source · Read passage · 04_arithmetic.tex, line 56

    [Several coprime spectral packets] Assume χ_A(x)=∏_i=1^rf_i(x), where the monic factors f_i∈ O[x] are pairwise coprime in K[x]. Put g_i=∏_j≠ if_j. There are complementary projectors E_i with im E_i=Ker f_i(A), ∑_iE_i=I, E_iE_j=0 (i≠ j). One may choose E_i so that Res(f_i,g_i)E_i∈End_ O(Λ) up to multiplication of the resultant by a unit.

    Exact mathematical passage
    
    \chi_A(x)=\prod_{i=1}^rf_i(x),
    
\prod_{j\ne i}Use in source · 1 passage

Search aliases: ∏_j≠ i prod ne

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  • Use in source · Read passage · 04_arithmetic.tex, line 60

    [Several coprime spectral packets] Assume χ_A(x)=∏_i=1^rf_i(x), where the monic factors f_i∈ O[x] are pairwise coprime in K[x]. Put g_i=∏_j≠ if_j. There are complementary projectors E_i with im E_i=Ker f_i(A), ∑_iE_i=I, E_iE_j=0 (i≠ j). One may choose E_i so that Res(f_i,g_i)E_i∈End_ O(Λ) up to multiplication of the resultant by a unit.

    Exact mathematical passage
    
    g_i=\prod_{j\ne i}f_j.
    
\sum_eUse in source · 1 passage

Search aliases: ∑_e sum

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  • Use in source · Read passage · 03_weighted.tex, line 329

    W(γ)<LA_γ. Lean proves directly that q_L(S^pr_L,N) equals the mapped geometric inverse whenever q_L(A^N)=0, and hence is a two-sided inverse of q_L(I+A), where A=∑_eA_e=D^-1H. With the supplied two-sided inverse D^-1 of D, this gives the explicit two-sided inverse q_L (S^pr_L,ND^-1) of q_L(D+H). If every edge weight is at least m and L≤ mN, then the nilpotence condition follows from the filtration data because m|γ|≤ W(γ). For m>0, the executable choice N=lceil L/mrceil satisfies L≤ mN. This elem…

    Exact mathematical passage
    A=\sum_eA_e=D^{-1}H
\sum_{e:\alpha\to\beta}Use in source · 1 passage

Search aliases: ∑_e:α→β sum alpha to beta

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  • Use in source · Read passage · 03_weighted.tex, line 99

    ra of operators. Suppose D=∑_α P_α D P_α belongs to B and is invertible on every packet. Assume that the assembled inverse D^-1=∑_α D_α^-1P_α∈ B=F^0 B, D_α=P_α DP_α, where each packet inverse is extended by zero to the other packets. Let the edge set be finite, assume w(e)≥1 for every edge, and write N=∑_e:α→βN_e, N_e=P_β N_eP_α, N_e∈ F^w(e) B. For an edge e:α→β, put A_e=(P_β DP_β)^-1N_e. Then the block from P_α X to P_β X of (D+N)^-1 is P_β(D+N)^-1P_α = ∑_γ:αleadstoβ (-1)^|γ|A_γ D_α^-1, where D…

    Exact mathematical passage
    
    N=\sum_{e:\alpha\to\beta}N_e,
    \qquad
    N_e=P_\beta N_eP_\alpha,
    \qquad
    N_e\in F^{w(e)}\Bcal.
    
\sum_{e\in E}Use in source · 4 passages

Search aliases: ∑_e∈ E sum in

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  • Use in source · Read passage · 03_weighted.tex, line 40

    [Weighted inverse] Let B be a complete filtered algebra. Let D∈ B be invertible with D,D^-1∈ F^0 B. Let E be a finite set and suppose T=D+∑_e∈ EN_e, N_e∈ F^w(e) B, w(e)≥1. Set A_e=D^-1N_e. For a word γ=(e_1,…,e_r), write A_γ=A_e_r⋯ A_e_1, W(γ)=∑_j=1^rw(e_j). The empty word has weight zero and contributes the identity. Then T is invertible and T^-1 = ∑_γ(-1)^|γ|A_γ D^-1. The series converges in the filtration, and the term indexed by γ belongs to F^W(γ) B.

    Exact mathematical passage
    
    T=D+\sum_{e\in E}N_e,
    \qquad
    N_e\in F^{w(e)}\Bcal,
    \qquad
    w(e)\geq1.
    
\sum_iUse in source · 2 passages

Search aliases: ∑_i sum

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  • Use in source · Read passage · 04_arithmetic.tex, line 64

    [Several coprime spectral packets] Assume χ_A(x)=∏_i=1^rf_i(x), where the monic factors f_i∈ O[x] are pairwise coprime in K[x]. Put g_i=∏_j≠ if_j. There are complementary projectors E_i with im E_i=Ker f_i(A), ∑_iE_i=I, E_iE_j=0 (i≠ j). One may choose E_i so that Res(f_i,g_i)E_i∈End_ O(Λ) up to multiplication of the resultant by a unit.

    Exact mathematical passage
    
    \im E_i=\Ker f_i(A),
    \qquad
    \sum_iE_i=I,
    \qquad
    E_iE_j=0
    \quad(i\ne j).
    
\sum_{i=1}^dUse in source · 1 passage

Search aliases: ∑_i=1^d sum

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  • Use in source · Read passage · 04_arithmetic.tex, line 844

    ongruence solve] Let p>1 and consider the diagonal system over ( Z/(p^L) Z)^d diag(p^s_1,…,p^s_d)x=b pmodp^L. The system is solvable if and only if p^min(s_i,L)mid (b_i)_val for every i, where (b_i)_val is the canonical natural representative. Conditional on this admissibility condition, the number of solutions is p^∑_i=1^dmin(s_i,L). If any coordinate is inadmissible, the solution set is empty and its cardinality is zero.

    Exact mathematical passage
    
    \boxed{
    p^{\sum_{i=1}^d\min(s_i,L)}.
    }
    
\sum_{i=1}^rUse in source · 1 passage

Search aliases: ∑_i=1^r sum

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  • Use in source · Read passage · 04_arithmetic.tex, line 770

    rdinality q, fix L≥1, and consider Mx≡ bpmodπ^L. Put widetilde b=Ub for a Smith matrix U as in [source reference]. The congruence is solvable if and only if widetilde b_i≡0 pmodπ^min(s_i,L) (1≤ i≤ r) and widetilde b_i≡0 pmodπ^L (r<i≤ m). When it is solvable, the number of solutions in ( O/π^L O)^n is q^(n-r)L+∑_i=1^rmin(s_i,L).

    Exact mathematical passage
    
    \boxed{
    q^{(n-r)L+\sum_{i=1}^r\min(s_i,L)}.
    }
    
\sum_jUse in source · 2 passages

Search aliases: ∑_j sum

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  • Use in source · visual_atlas.tex, line 79

    Define X_N^rm pkt=⊕_j P_N,jX, A_Nx=(P_N,jx)_j, S_N(x_j)_j=∑_jx_j. Completeness and mutual annihilation give both inverse laws. Consequently, J= A_4 S_2, C= A_2 S_4, CJ=I, JC=I. The apparently larger list of fine packets simply has smaller individual packet spaces.

    Exact mathematical passage
    
    X_N^{\rm pkt}=\bigoplus_j P_{N,j}X,
    \qquad
    \mathcal A_Nx=(P_{N,j}x)_j,
    \qquad
    \mathcal S_N(x_j)_j=\sum_jx_j.
    
\sum_{j=0}^{N-1}Use in source · 1 passage

Search aliases: ∑_j=0^N-1 sum

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  • Use in source · Read passage · 02_coordinates.tex, line 383

    [Residue packet algebra] For every commutative ring R, the operators (P_N,j)_0≤ j<N satisfy the identities below. If R is nonzero, they form a packet system on R[[z]]: P_N,iP_N,j=δ_ijP_N,j, ∑_j=0^N-1P_N,j=I.

    Exact mathematical passage
    
    P_{N,i}P_{N,j}=\delta_{ij}P_{N,j},
    \qquad
    \sum_{j=0}^{N-1}P_{N,j}=I.
    
\sum_{j=1}^rUse in source · 3 passages

Search aliases: ∑_j=1^r sum

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  • Use in source · Read passage · 03_weighted.tex, line 52

    [Weighted inverse] Let B be a complete filtered algebra. Let D∈ B be invertible with D,D^-1∈ F^0 B. Let E be a finite set and suppose T=D+∑_e∈ EN_e, N_e∈ F^w(e) B, w(e)≥1. Set A_e=D^-1N_e. For a word γ=(e_1,…,e_r), write A_γ=A_e_r⋯ A_e_1, W(γ)=∑_j=1^rw(e_j). The empty word has weight zero and contributes the identity. Then T is invertible and T^-1 = ∑_γ(-1)^|γ|A_γ D^-1. The series converges in the filtration, and the term indexed by γ belongs to F^W(γ) B.

    Exact mathematical passage
    
    A_\gamma=A_{e_r}\cdots A_{e_1},
    \qquad
    W(\gamma)=\sum_{j=1}^rw(e_j).
    
\sum_kUse in source · 2 passages

Search aliases: ∑_k sum

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  • Use in source · Read passage · 03_weighted.tex, line 557

    [Linear recurrence] With the canonical polynomials from [source reference], write Q(t)=∑_kq_kt^k, Z_s,t(t)=∑_n≥0a_n(s,t)t^n. Then the walk counts satisfy the recurrence with constant coefficients determined by Q after the finite initial range contributed by P_s,t, with deg 0=-∞: ∑_k=0^nq_k a_n-k(s,t)=0 (n>deg P_s,t).

    Exact mathematical passage
    
    Q(t)=\sum_kq_kt^k,
    \qquad
    Z_{s,t}(t)=\sum_{n\ge0}a_n(s,t)t^n.
    
\sum_{k=0}^2Use in source · 1 passage

Search aliases: ∑_k=0^2 sum

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  • Use in source · visual_atlas.tex, line 166

    On the monomial z^n, define UF(z)=F(2z). The proposed projector acts by 5∑_k=0^2 4^jk2^nk. The identity 2^3=1 makes this depend only on nbmod3. The nine-entry table therefore establishes the formula for every exponent once periodicity is used, rather than requiring a separate test at every coefficient.

    Exact mathematical passage
    
    5\sum_{k=0}^2 4^{jk}2^{nk}.
    
\sum_{k=0}^{n}Use in source · 1 passage

Search aliases: ∑_k=0^n sum

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  • Use in source · Read passage · 03_weighted.tex, line 564

    [Linear recurrence] With the canonical polynomials from [source reference], write Q(t)=∑_kq_kt^k, Z_s,t(t)=∑_n≥0a_n(s,t)t^n. Then the walk counts satisfy the recurrence with constant coefficients determined by Q after the finite initial range contributed by P_s,t, with deg 0=-∞: ∑_k=0^nq_k a_n-k(s,t)=0 (n>deg P_s,t).

    Exact mathematical passage
    
    \boxed{
    \sum_{k=0}^{n}q_k a_{n-k}(s,t)=0
    \qquad\bigl(n>\deg P_{s,t}\bigr).
    }
    
\sum_{k=0}^{N-1}Use in source · 7 passages

Search aliases: ∑_k=0^N-1 sum

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  • Use in source · Read passage · 02_coordinates.tex, line 408

    [Root-of-unity realization] Let R be a commutative semiring, let N>0, and suppose ω,ω^vee,η∈ R satisfy ω^N=1 and the finite N× N Fourier orthogonality table η∑_k=0^N-1(ω^vee)^jkω^rk = 1, · r=j, 0, · r≠ j, 0≤ j,r<N. Then P_N,j = η∑_k=0^N-1(ω^vee)^jkU^k. In particular, if R is a field, N>0, and ω is a primitive Nth root of unity, the certificate holds with ω^vee=ω^-1 and η=N^-1.

    Exact mathematical passage
    
    \eta\sum_{k=0}^{N-1}(\omega^\vee)^{jk}\omega^{rk}
    =
    \begin{cases}
    1,&r=j,\\
    0,&r\ne j,
    \end{cases}
    \qquad 0\le j,r<N.
    
\sum_{k=0}^{n-1}Use in source · 5 passages

Search aliases: ∑_k=0^n-1 sum

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  • Use in source · Read passage · 05_defects.tex, line 27

    [Power defect identity] For every integer n≥1, CT_f^n-T_c^nC = ∑_k=0^n-1T_c^n-1-kΔ T_f^k.

    Exact mathematical passage
    
    CT_f^n-T_c^nC
    =
    \sum_{k=0}^{n-1}T_c^{n-1-k}\Delta T_f^k.
    
\sum_{k=0}^{r-1}Use in source · 2 passages

Search aliases: ∑_k=0^r-1 sum

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  • Use in source · Read passage · 03_weighted.tex, line 278

    [Certified weighted inverse] Let R be a possibly noncommutative ring, let D^-1 be a supplied two-sided inverse of D, and put A=D^-1H. [label=(alph*)] item If A^r=0, then D+H has the two-sided inverse (D+H)^-1=(∑_k=0^r-1(-A)^k)D^-1. item If R is a complete normed ring and lVert ArVert<1, then ∑_k≥0(-A)^k converges and (D+H)^-1=(∑_k≥0(-A)^k)D^-1.

    Exact mathematical passage
    
    \boxed{(D+H)^{-1}=\left(\sum_{k=0}^{r-1}(-A)^k\right)D^{-1}.}
    
\sum_{k\ge0}Use in source · 2 passages

Search aliases: ∑_k≥0 sum ge

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  • Use in source · Read passage · 03_weighted.tex, line 282

    [Certified weighted inverse] Let R be a possibly noncommutative ring, let D^-1 be a supplied two-sided inverse of D, and put A=D^-1H. [label=(alph*)] item If A^r=0, then D+H has the two-sided inverse (D+H)^-1=(∑_k=0^r-1(-A)^k)D^-1. item If R is a complete normed ring and lVert ArVert<1, then ∑_k≥0(-A)^k converges and (D+H)^-1=(∑_k≥0(-A)^k)D^-1.

    Exact mathematical passage
    \sum_{k\ge0}(-A)^k
\sum_{n=0}^NUse in source · 1 passage

Search aliases: ∑_n=0^N sum

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  • Use in source · Read passage · 05_defects.tex, line 80

    [Polynomial defect] For p(z)=∑_n=0^Na_nz^n, we have Cp(T_f)-p(T_c)C = ∑_n=1^Na_n ∑_k=0^n-1T_c^n-1-kΔ T_f^k.

    Exact mathematical passage
    
    p(z)=\sum_{n=0}^Na_nz^n,
    
\sum_{n=0}^{N-1}Use in source · 1 passage

Search aliases: ∑_n=0^N-1 sum

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  • Use in source · Read passage · 03_weighted.tex, line 321

    et q_L:R→ R_L be a ring homomorphism that kills F^L R. Suppose H=∑_e∈ EH_e, D^-1H_e∈ F^w(e)R, w(e)≥1, with E finite. Then q_L(D^-1H)^L=0, the finite sum in [source reference](a) is a two-sided inverse after applying q_L, and its word expansion may discard every word of weight at least L. More explicitly, for a length cutoff N, define S^pr_L,N = ∑_n=0^N-1(-1)^n ∑_substackγ∈ E^n W(γ)<LA_γ. Lean proves directly that q_L(S^pr_L,N) equals the mapped geometric inverse whenever q_L(A^N)=0, and hence is…

    Exact mathematical passage
    
    S^{\mathrm{pr}}_{L,N}
    =
    \sum_{n=0}^{N-1}(-1)^n
    \sum_{\substack{\gamma\in E^n\\W(\gamma)<L}}A_\gamma.
    
\sum_{n=1}^NUse in source · 1 passage

Search aliases: ∑_n=1^N sum

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  • Use in source · Read passage · 05_defects.tex, line 84

    [Polynomial defect] For p(z)=∑_n=0^Na_nz^n, we have Cp(T_f)-p(T_c)C = ∑_n=1^Na_n ∑_k=0^n-1T_c^n-1-kΔ T_f^k.

    Exact mathematical passage
    
    Cp(T_f)-p(T_c)C
    =
    \sum_{n=1}^Na_n
    \sum_{k=0}^{n-1}T_c^{n-1-k}\Delta T_f^k.
    
\sum_{n\ge0}Use in source · 2 passages

Search aliases: ∑_n≥0 sum ge

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  • Use in source · Read passage · 03_weighted.tex, line 485

    For fixed start and target vertices s,t, define Z_s,t(t) = ∑_n≥0a_n(s,t)t^n, where a_n(s,t) counts directed walks from s to t with total weight n. Vertices and edges may repeat. Thus ``path zeta'' is retained as the name of the series and Lean API, but the walks are not required to visit each vertex only once.

    Exact mathematical passage
    
    Z_{s,t}(t)
    =
    \sum_{n\ge0}a_n(s,t)t^n,
    
\sum_{\rm children}Use in source · 1 passage

Search aliases: ∑_rm children sum rm

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  • Use in source · regrouping_not_averaging.tex, line 52

    =.35pt,] (4.57000,2.26000) rectangle ++(0.57000,0.57000); node[] at (4.85500,2.54500) 2; draw[fill=black!0,draw=black!45,line width=.35pt,] (5.14000,2.26000) rectangle ++(0.57000,0.57000); node[] at (5.42500,2.54500) 0; draw[fill=black!12,draw=black!45,line width=.35pt,] (5.71000,2.26000) rectangle ++(0.57000,0.57000); node[] at (5.99500,2.54500) 4; node[] at (3.15000,2.20000) ∑_rm children; node[] at (1.14000,0.10000) 4×1=4 free coordinates; node[] at (5.14000,0.10000) 2×2=4 free coordinates; d…

    Exact mathematical passage
    \sum_{\rm children}
\sum_{r\geq0}Use in source · 2 passages

Search aliases: ∑_r≥0 sum geq

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  • Use in source · Read passage · 03_weighted.tex, line 72

    Put A=∑_e∈ EA_e. Since left multiplication by D^-1 preserves the filtration, A∈ F^1 B. Completeness gives the convergent Neumann series (I+A)^-1=∑_r≥0(-A)^r. Because T=D(I+A), T^-1=(I+A)^-1D^-1. Expanding each power of A gives the sum over words, with the rightmost edge acting first. Multiplicativity of the filtration gives A_γ∈ F^W(γ) B. For each L, only finitely many words have weight below L because E is finite and every edge has positive weight. Thus the word expansion converges to the same …

    Exact mathematical passage
    
    (I+A)^{-1}=\sum_{r\geq0}(-A)^r.
    
\sum_{\substack{0\leq s<M\\s\equiv j\pmod N}}Use in source · 1 passage

Search aliases: ∑_substack0≤ s<M s≡ jpmod N sum substack leq s equiv pmod

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  • Use in source · Read passage · 02_coordinates.tex, line 478

    [Nested residue refinement] Let N,M be positive integers with N dividing M, and let 0≤ j<N. Then P_N,j = ∑_substack0≤ s<M s≡ jpmod NP_M,s. When R is nonzero, the packet system modulo M refines the packet system modulo N.

    Exact mathematical passage
    
    P_{N,j}
    =
    \sum_{\substack{0\leq s<M\\s\equiv j\pmod N}}P_{M,s}.
    
\sum_{\substack{e:\,\mathrm{source}(e)=s\\w(e)\le n}}Use in source · 1 passage

Search aliases: ∑_substacke: source(e)=s w(e)≤ n sum substack mathrm w le

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  • Use in source · visual_atlas.tex, line 289

    headThe first-edge decomposition Let a_n(s,t) count walks of total weight n from s to t. Removing the first edge gives a_n(s,t)=1_s=t, n=0 +∑_substacke: source(e)=s w(e)≤ n a_n-w(e)(target(e),t). The empty walk is allowed precisely on the diagonal at weight zero. Positive weights ensure that every contributing walk has length at most n, so enumeration at each fixed weight is finite.

    Exact mathematical passage
    
    a_n(s,t)=\mathbf1_{s=t,\,n=0}
     +\sum_{\substack{e:\,\mathrm{source}(e)=s\\w(e)\le n}}
     a_{n-w(e)}(\mathrm{target}(e),t).
    
\sum_{\substack{e:\,\operatorname{source}(e)=s\\w(e)\le n}}Use in source · 1 passage

Search aliases: ∑_substacke: source(e)=s w(e)≤ n sum substack operatorname w le

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  • Use in source · Read passage · 03_weighted.tex, line 499

    [Automatic finite-graph transfer-zeta rationality] Assume the vertex and edge sets are finite and every edge has positive integer weight. For every n, exact enumeration of edge tuples of lengths at most n, followed by endpoint and total-weight filtering, returns a_n(s,t). These coefficients obey the recurrence obtained by removing the first edge a_n(s,t) = 1_s=t, n=0 +∑_substacke: source(e)=s w(e)≤ n a_n-w(e)(target(e),t). Let T(t)=I-A(t), Q(t)=det T(t), P_s,t(t)=adj(T(t))_s,t. Then Q(0)=1, henc…

    Exact mathematical passage
    
    a_n(s,t)
    =
    \mathbf 1_{s=t,\,n=0}
    +\sum_{\substack{e:\,\operatorname{source}(e)=s\\w(e)\le n}}
    a_{n-w(e)}(\operatorname{target}(e),t).
    
\sum_{\substack{\gamma:\ P_\alpha R_\gamma=R_\gamma\\Q_\beta R_\gamma=R_\gamma}}Use in source · 1 passage

Search aliases: ∑_substackγ: P_α R_γ=R_γ Q_β R_γ=R_γ ∑_substackγ: P_α R_γ=R_γ{ Q_β R_γ=R_γ sum substack gamma alpha gamma gamma Q beta gamma gamma sum substack gamma alpha gamma gamma mathbb beta gamma gamma

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  • Use in source · Read passage · 02_coordinates.tex, line 339

    a packet in R. Because R refines P, there is a unique α with P_α R_γ=R_γ. Likewise there is a unique β with Q_β R_γ=R_γ. Therefore P_α Q_β R_γ=R_γ. Every packet of R lies in one product packet. Multiplying ∑_γ R_γ=I_X by P_α Q_β and using the parent identities gives P_α Q_β =∑_substackγ: P_α R_γ=R_γ{ Q_β R_γ=R_γR_γ. Thus the packets with the same pair of parents reconstruct the product packet. If that product packet is nonzero, the sum has a child, so the parent map onto the supported product fa…

    Exact mathematical passage
    
    P_\alpha Q_\beta
    =\sum_{\substack{\gamma:\ P_\alpha R_\gamma=R_\gamma\\Q_\beta R_\gamma=R_\gamma}}R_\gamma.
    
\sum_{\substack{\gamma\in E^n\\W(\gamma)<L}}Use in source · 1 passage

Search aliases: ∑_substackγ∈ E^n W(γ)<L sum substack gamma in W gamma

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  • Use in source · Read passage · 03_weighted.tex, line 321

    et q_L:R→ R_L be a ring homomorphism that kills F^L R. Suppose H=∑_e∈ EH_e, D^-1H_e∈ F^w(e)R, w(e)≥1, with E finite. Then q_L(D^-1H)^L=0, the finite sum in [source reference](a) is a two-sided inverse after applying q_L, and its word expansion may discard every word of weight at least L. More explicitly, for a length cutoff N, define S^pr_L,N = ∑_n=0^N-1(-1)^n ∑_substackγ∈ E^n W(γ)<LA_γ. Lean proves directly that q_L(S^pr_L,N) equals the mapped geometric inverse whenever q_L(A^N)=0, and hence is…

    Exact mathematical passage
    
    S^{\mathrm{pr}}_{L,N}
    =
    \sum_{n=0}^{N-1}(-1)^n
    \sum_{\substack{\gamma\in E^n\\W(\gamma)<L}}A_\gamma.
    
\sum_{\substack{\rho(\beta)=b\\\rho(\alpha)=a}}Use in source · 1 passage

Search aliases: ∑_substackρ(β)=b ρ(α)=a sum substack rho beta rho alpha

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  • Use in source · Read passage · 02_coordinates.tex, line 224

    [Refinement of operator blocks] Suppose that Q refines P through ρ. Then T^ P_ba = ∑_substackρ(β)=b ρ(α)=a T^ Q_βα. The matrix of T in fine coordinates is related to the matrix in coarse coordinates by [T]_ P = C_ P← Q[T]_ QJ_ Q← P.

    Exact mathematical passage
    
    T^{\Pcal}_{ba}
    =
    \sum_{\substack{\rho(\beta)=b\\\rho(\alpha)=a}}
    T^{\Qcal}_{\beta\alpha}.
    
\sum_{W(\gamma)<L}Use in source · 2 passages

Search aliases: ∑_W(γ)<L sum gamma

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  • Use in source · Read passage · 03_weighted.tex, line 187

    [Exact finite precision truncation] Under the hypotheses of [source reference], define R_L = ∑_W(γ)<L(-1)^|γ|A_γ D^-1. Then T^-1-R_L∈ F^L B, TR_L-I∈ F^L B, R_LT-I∈ F^L B. Thus R_L is the exact inverse in B/F^L B.

    Exact mathematical passage
    
    R_L
    =
    \sum_{W(\gamma)<L}(-1)^{|\gamma|}A_\gamma D^{-1}.
    
\sum_{\alpha,\beta}Use in source · 1 passage

Search aliases: ∑_α,β sum alpha beta

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  • Use in source · Read passage · 02_coordinates.tex, line 304

    Commutativity gives R_αβ^2=P_α^2Q_β^2=R_αβ. If (α,β)≠(α',β'), then either P_α P_α'=0 or Q_β Q_β'=0, so the corresponding products annihilate one another. Finally, ∑_α,βR_αβ = (∑_α P_α) (∑_β Q_β) =I_X. For a fixed α, P_α =P_α∑_β Q_β = ∑_β R_αβ, and the same argument works for a fixed β. Since each P_α and Q_β is nonzero, these identities ensure that every parent has a nonzero product child. The two parent maps on the supported product family are therefore surjective. Iteration proves the finite f…

    Exact mathematical passage
    
    \sum_{\alpha,\beta}R_{\alpha\beta}
    =
    \left(\sum_\alpha P_\alpha\right)
    \left(\sum_\beta Q_\beta\right)
    =I_X.
    
\sum_\betaUse in source · 2 passages

Search aliases: ∑_β sum beta

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  • Use in source · Read passage · 02_coordinates.tex, line 304

    Commutativity gives R_αβ^2=P_α^2Q_β^2=R_αβ. If (α,β)≠(α',β'), then either P_α P_α'=0 or Q_β Q_β'=0, so the corresponding products annihilate one another. Finally, ∑_α,βR_αβ = (∑_α P_α) (∑_β Q_β) =I_X. For a fixed α, P_α =P_α∑_β Q_β = ∑_β R_αβ, and the same argument works for a fixed β. Since each P_α and Q_β is nonzero, these identities ensure that every parent has a nonzero product child. The two parent maps on the supported product family are therefore surjective. Iteration proves the finite f…

    Exact mathematical passage
    
    \sum_{\alpha,\beta}R_{\alpha\beta}
    =
    \left(\sum_\alpha P_\alpha\right)
    \left(\sum_\beta Q_\beta\right)
    =I_X.
    
\sum_{\beta\succ b,\,\alpha\succ a}Use in source · 1 passage

Search aliases: ∑_βsucc b, αsucc a sum beta succ alpha succ

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  • Use in source · visual_atlas.tex, line 125

    headRefined blocks still reconstruct the same map A coarse block expands as P_bTP_a=∑_βsucc b, αsucc aP_β TP_α. The terms are maps embedded in the original source and target spaces. Adding their norms, or adding their matrix entries after forgetting the embeddings, is not this operator identity.

    Exact mathematical passage
    
    P_bTP_a=\sum_{\beta\succ b,\,\alpha\succ a}P_\beta TP_\alpha.
    
\sum_\gammaUse in source · 2 passages

Search aliases: ∑_γ sum gamma

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  • Use in source · Read passage · 02_coordinates.tex, line 338

    Let R_γ be a packet in R. Because R refines P, there is a unique α with P_α R_γ=R_γ. Likewise there is a unique β with Q_β R_γ=R_γ. Therefore P_α Q_β R_γ=R_γ. Every packet of R lies in one product packet. Multiplying ∑_γ R_γ=I_X by P_α Q_β and using the parent identities gives P_α Q_β =∑_substackγ: P_α R_γ=R_γ

    Exact mathematical passage
    \sum_\gamma R_\gamma=I_X
\sum_{\gamma:\alpha\leadsto\beta}Use in source · 1 passage

Search aliases: ∑_γ:αleadstoβ sum gamma alpha leadsto beta

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  • Use in source · Read passage · 03_weighted.tex, line 111

    pha DP_α, where each packet inverse is extended by zero to the other packets. Let the edge set be finite, assume w(e)≥1 for every edge, and write N=∑_e:α→βN_e, N_e=P_β N_eP_α, N_e∈ F^w(e) B. For an edge e:α→β, put A_e=(P_β DP_β)^-1N_e. Then the block from P_α X to P_β X of (D+N)^-1 is P_β(D+N)^-1P_α = ∑_γ:αleadstoβ (-1)^|γ|A_γ D_α^-1, where D_α=P_α DP_α and the sum runs over directed paths from α to β, including the empty path when α=β.

    Exact mathematical passage
    
    P_\beta(D+N)^{-1}P_\alpha
    =
    \sum_{\gamma:\alpha\leadsto\beta}
    (-1)^{|\gamma|}A_\gamma D_\alpha^{-1},
    
\sum_{\rho(\alpha)=a}Use in source · 1 passage

Search aliases: ∑_ρ(α)=a sum rho alpha

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  • Use in source · Read passage · 02_coordinates.tex, line 240

    Expand the two coarse projectors into their children: P_bTP_a = (∑_ρ(β)=bQ_β) T (∑_ρ(α)=aQ_α). Distributing the finite sums gives the first identity. For the coordinate identity, use [T]_ P= A_ PT S_ P and insert I_X= S_ Q A_ Q.

    Exact mathematical passage
    
    P_bTP_a
    =
    \left(\sum_{\rho(\beta)=b}Q_\beta\right)
    T
    \left(\sum_{\rho(\alpha)=a}Q_\alpha\right).
    
\sum_{\rho(\beta)=b}Use in source · 1 passage

Search aliases: ∑_ρ(β)=b sum rho beta

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  • Use in source · Read passage · 02_coordinates.tex, line 240

    Expand the two coarse projectors into their children: P_bTP_a = (∑_ρ(β)=bQ_β) T (∑_ρ(α)=aQ_α). Distributing the finite sums gives the first identity. For the coordinate identity, use [T]_ P= A_ PT S_ P and insert I_X= S_ Q A_ Q.

    Exact mathematical passage
    
    P_bTP_a
    =
    \left(\sum_{\rho(\beta)=b}Q_\beta\right)
    T
    \left(\sum_{\rho(\alpha)=a}Q_\alpha\right).
    
\sum_{\rho(\gamma)=\alpha}Use in source · 1 passage

Search aliases: ∑_ρ(γ)=α sum rho gamma alpha

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  • Use in source · Read passage · 02_coordinates.tex, line 62

    Multiply the identity P_α=∑_ρ(γ)=αQ_γ by Q_β on either side. Pairwise annihilation in the fine family leaves Q_β when ρ(β)=α and leaves zero otherwise. For transitivity, substitute the child expansion of each Q_β into the expansion of P_α and group the resulting terms by the composite parent.

    Exact mathematical passage
    
    P_\alpha=\sum_{\rho(\gamma)=\alpha}Q_\gamma
    
\sum_{\ell=0}^{L-1}Use in source · 2 passages

Search aliases: ∑_ℓ=0^L-1 sum ell

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  • Use in source · Read passage · 05_defects.tex, line 228

    [Multilevel defect decomposition] The total defect from level L to level zero is C_0,LT_L-T_0C_0,L = ∑_ℓ=0^L-1 C_0,ℓΔ_ℓ C_ℓ+1,L. For bounded maps, C_0,LT_L-T_0C_0,L ≤ ∑_ℓ=0^L-1 C_0,ℓ Δ_ℓ C_ℓ+1,L .

    Exact mathematical passage
    
    C_{0,L}T_L-T_0C_{0,L}
    =
    \sum_{\ell=0}^{L-1}
    C_{0,\ell}\Delta_\ell C_{\ell+1,L}.
    
\setminusUse in source · 2 passages

Search aliases: ∖ setminus

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  • Use in source · Read passage · 03_weighted.tex, line 445

    [Several independent weights] Suppose every edge has a weight vector w(e)=(w_1(e),…,w_r(e))∈ N^r∖{0}. Replace t^w(e) by t_1^w_1(e)⋯ t_r^w_r(e). The resulting multigraded transfer series is rational in t_1,…,t_r.

    Exact mathematical passage
    
    w(e)=(w_1(e),\ldots,w_r(e))\in\mathbb N^r\setminus\{0\}.
    
\circUse in source · 1 passage

Search aliases: ∘ circ

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  • Use in source · Read passage · 02_coordinates.tex, line 74

    A refinement tower is a sequence ( P_ℓ)_ℓ≥0 with parent maps ρ_m,ℓ:I_m⟶ I_ℓ (m≥ℓ) such that P_m refines P_ℓ through ρ_m,ℓ for every m≥ℓ, and ρ_ℓ,ℓ=id_I_ℓ, ρ_n,ℓ=ρ_m,ℓ∘ρ_n,m (n≥ m≥ℓ). Thus every parent map witnesses the stated refinement and the maps compose coherently. The next result shows that the coordinate changes form a coherent system.

    Exact mathematical passage
    
    \rho_{\ell,\ell}=\id_{I_\ell},
    \qquad
    \rho_{n,\ell}=\rho_{m,\ell}\circ\rho_{n,m}
    \qquad(n\geq m\geq\ell).
    
\inftyUse in source · 6 passages

Search aliases: ∞ infty

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  • Use in source · Read passage · 03_weighted.tex, line 129

    [Minimum path weight] For packets α and β, let d(α,β) be the least total weight of a directed path from α to β, with d=∞ when no path exists. Use the convention F^∞ B=⋂_L≥0F^L B=0. If α≠β, then P_β(D+N)^-1P_α ∈ F^d(α,β) B. If there is no path from α to β, the block is zero.

    Exact mathematical passage
    d=\infty
\intUse in source · 4 passages

Search aliases: ∫ int

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  • Use in source · Read passage · 05_defects.tex, line 150

    X_c be complex Banach spaces, and let C:X_f→ X_c, T_f, and T_c be bounded complex-linear maps. Let h be holomorphic on an open set U containing both spectra. Let Γ be an admissible finite rectifiable Cauchy cycle in U and in both resolvent sets, with winding number one on the union of the spectra and zero outside U. The length of a cycle counts multiplicities. Then Ch(T_f)-h(T_c)C = frac12π i ∫_Γ h(z)(z-T_c)^-1Δ(z-T_f)^-1 dz. Consequently, Ch(T_f)-h(T_c)C · ≤ fraclength(Γ)2π sup_z∈Γ|h(z)| Δ

    Exact mathematical passage
    
    Ch(T_f)-h(T_c)C
    =
    \frac{1}{2\pi i}
    \int_\Gamma
    h(z)(z-T_c)^{-1}\Delta(z-T_f)^{-1}\,dz.
    
\int_0^tUse in source · 2 passages

Search aliases: ∫_0^t int

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  • Use in source · Read passage · 05_defects.tex, line 182

    [Exponential defect identity] Let C:X_f→ X_c, T_f, and T_c be bounded linear maps between Banach spaces over a common field. For real t, use real or complex spaces. For complex t, use complex spaces and complex-linear maps. Then Ce^tT_f-e^tT_cC = ∫_0^t e^(t-s)T_cΔ e^sT_f ds, where the integral is taken along the straight segment from 0 to t when t is complex. For real t≥0, Ce^tT_f-e^tT_cC ≤ Δ ∫_0^t e^(t-s)T_c e^sT_f ds.

    Exact mathematical passage
    
    Ce^{tT_f}-e^{tT_c}C
    =
    \int_0^t e^{(t-s)T_c}\Delta e^{sT_f}\,ds,
    
\int_\GammaUse in source · 2 passages

Search aliases: ∫_Γ int Gamma

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  • Use in source · Read passage · 05_defects.tex, line 150

    X_c be complex Banach spaces, and let C:X_f→ X_c, T_f, and T_c be bounded complex-linear maps. Let h be holomorphic on an open set U containing both spectra. Let Γ be an admissible finite rectifiable Cauchy cycle in U and in both resolvent sets, with winding number one on the union of the spectra and zero outside U. The length of a cycle counts multiplicities. Then Ch(T_f)-h(T_c)C = frac12π i ∫_Γ h(z)(z-T_c)^-1Δ(z-T_f)^-1 dz. Consequently, Ch(T_f)-h(T_c)C · ≤ fraclength(Γ)2π sup_z∈Γ|h(z)| Δ

    Exact mathematical passage
    
    Ch(T_f)-h(T_c)C
    =
    \frac{1}{2\pi i}
    \int_\Gamma
    h(z)(z-T_c)^{-1}\Delta(z-T_f)^{-1}\,dz.
    
\congUse in source · 4 passages

Search aliases: ≅ cong

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  • Use in source · Read passage · 04_arithmetic.tex, line 284

    ght] With the notation of [source reference], the map Φ:G_Λ, P ⟶ ⊕_α∈ IE_αΛ/Λ_α, [x]⟼(E_α x+Λ_α)_α is injective, and every coordinate projection of its image is surjective. We also have exp_π(G_Λ, P) = s_Λ( P). If G_Λ, P ≅ ⊕_j=1^r O/π^a_j O with a_1≤⋯≤ a_r, then s_Λ( P)=max({0}∪{a_j:1≤ j≤ r}).

    Exact mathematical passage
    
    G_{\Lambda,\Pcal}
    \cong
    \bigoplus_{j=1}^r\OO/\pi^{a_j}\OO
    
\neqUse in source · 1 passage

Search aliases: ≠ neq

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  • Use in source · Read passage · 04_arithmetic.tex, line 689

    The failure of the character formula frac12(I± A) to be integral does not invalidate coefficient selectors such as even and odd residue extraction. It shows that two distinct constructions must be distinguished: integral address selector ≠ character-average spectral projector when the group order is not a unit. The first can remain exact over Z_2. The second can acquire a denominator weight.

    Exact mathematical passage
    
    \boxed{
    \text{integral address selector}
    \quad\neq\quad
    \text{character-average spectral projector}
    }
    
\oplusUse in source · 9 passages

Search aliases: ⊕ oplus

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  • Use in source · Read passage · 01_orientation.tex, line 56

    A simple two packet model already contains all four notions. Let X=X_0⊕ X_1, D=D_0 · 0 0 · D_1, N=0 · N_01{ N_10 · 0. A finer family may split X_0 and X_1 into smaller summands. The blocks N_01 and N_10 may enter at different filtration weights. Over a fraction field, the rational packet spaces may fail to split the chosen lattice. A coarse operator on one selected summand may also fail to intertwine with the full matrix. The later sections isolate these four effects one at a time.

    Exact mathematical passage
    
    X=X_0\oplus X_1,
    \qquad
    D=\begin{pmatrix}D_0&0\\0&D_1\end{pmatrix},
    \qquad
    N=\begin{pmatrix}0&N_{01}\\N_{10}&0\end{pmatrix}.
    
\bigoplus_jUse in source · 1 passage

Search aliases: ⊕_j bigoplus

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  • Use in source · visual_atlas.tex, line 79

    Define X_N^rm pkt=⊕_j P_N,jX, A_Nx=(P_N,jx)_j, S_N(x_j)_j=∑_jx_j. Completeness and mutual annihilation give both inverse laws. Consequently, J= A_4 S_2, C= A_2 S_4, CJ=I, JC=I. The apparently larger list of fine packets simply has smaller individual packet spaces.

    Exact mathematical passage
    
    X_N^{\rm pkt}=\bigoplus_j P_{N,j}X,
    \qquad
    \mathcal A_Nx=(P_{N,j}x)_j,
    \qquad
    \mathcal S_N(x_j)_j=\sum_jx_j.
    
\bigoplus_{j=1}^nUse in source · 1 passage

Search aliases: ⊕_j=1^n bigoplus

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  • Use in source · Read passage · 04_arithmetic.tex, line 735

    [Computing a packet weight from an inclusion matrix] Choose an O basis of Λ and an O basis of Λ_split. Let B be the matrix of the inclusion Λ_split↪Λ. If the Smith form of B is diag(π^a_1,…,π^a_n), 0≤ a_1≤⋯≤ a_n, then G_Λ, P ≅ ⊕_j=1^n O/π^a_j O, s_Λ( P)=max({0}∪{a_j:1≤ j≤ n}).

    Exact mathematical passage
    
    G_{\Lambda,\Pcal}
    \cong
    \bigoplus_{j=1}^n\OO/\pi^{a_j}\OO,
    \qquad
    s_\Lambda(\Pcal)=\max\bigl(\{0\}\cup\{a_j:1\leq j\leq n\}\bigr).
    
\bigoplus_{j=1}^rUse in source · 2 passages

Search aliases: ⊕_j=1^r bigoplus

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  • Use in source · Read passage · 04_arithmetic.tex, line 284

    ght] With the notation of [source reference], the map Φ:G_Λ, P ⟶ ⊕_α∈ IE_αΛ/Λ_α, [x]⟼(E_α x+Λ_α)_α is injective, and every coordinate projection of its image is surjective. We also have exp_π(G_Λ, P) = s_Λ( P). If G_Λ, P ≅ ⊕_j=1^r O/π^a_j O with a_1≤⋯≤ a_r, then s_Λ( P)=max({0}∪{a_j:1≤ j≤ r}).

    Exact mathematical passage
    
    G_{\Lambda,\Pcal}
    \cong
    \bigoplus_{j=1}^r\OO/\pi^{a_j}\OO
    
\bigoplus_{\alpha}Use in source · 1 passage

Search aliases: ⊕_α bigoplus alpha

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  • Use in source · Read passage · 01_orientation.tex, line 18

    Λ be an O lattice in V. A rational projector E need not preserve Λ. Its separation weight is the least s such that π^sEΛ⊆Λ. A Bézout construction gives an upper bound through a polynomial resultant. That bound need not be exact because it does not see the position of the lattice. The exact answer is controlled by the finite length module G_Λ, P = Λ/⊕_α(Λ∩ V_α), where V=⊕_α V_α is the rational packet decomposition. The largest Smith exponent of this gluing module is exactly the common denominator…

    Exact mathematical passage
    
    G_{\Lambda,\Pcal}
    =
    \Lambda\Big/\bigoplus_{\alpha}(\Lambda\cap V_\alpha),
    
\bigoplus_\betaUse in source · 1 passage

Search aliases: ⊕_β bigoplus beta

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  • Use in source · Read passage · 04_arithmetic.tex, line 399

    [Gluing exact sequence under refinement] Let Q=(Q_β) refine P=(P_α) on V, and let Λ be a lattice. Define Λ_ P = ⊕_α(Λ∩ P_α V), Λ_ Q = ⊕_β(Λ∩ Q_β V). Then Λ_ Q⊆Λ_ P⊆Λ and there is a short exact sequence 0 ⟶ Λ_ P/Λ_ Q ⟶ Λ/Λ_ Q ⟶ Λ/Λ_ P ⟶0. In particular, s_Λ( P)≤ s_Λ( Q).

    Exact mathematical passage
    
    \Lambda_{\Pcal}
    =
    \bigoplus_\alpha(\Lambda\cap P_\alpha V),
    \qquad
    \Lambda_{\Qcal}
    =
    \bigoplus_\beta(\Lambda\cap Q_\beta V).
    
\otimesUse in source · 2 passages

Search aliases: ⊗ otimes

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  • Use in source · Read passage · 04_arithmetic.tex, line 4

    Let O be a discrete valuation ring with fraction field K and uniformizer π. Let Λ be a finite free O module and put V=K⊗_ OΛ. Suppose A∈End_ O(Λ).

    Exact mathematical passage
    
    V=K\otimes_{\OO}\Lambda.
    
\otimes_\OOUse in source · 1 passage

Search aliases: ⊗_OO ⊗_ O otimes OO otimes mathcal

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  • Use in source · Read passage · 04_arithmetic.tex, line 121

    [Evaluated B ezout spectral projector] Let F,G,U,V∈End_K(Λ⊗_ O K) and let r∈ K^×. Suppose UF+VG=rI, FG=0, FG=GF, GU=UG. Put N=VG. Then N^2=rN. Consequently the operator E=r^-1VG is idempotent, acts as the identity on ker F, and acts as zero on ker G. If V and G preserve Λ, then rE=VG∈End_ O(Λ).

    Exact mathematical passage
    F,G,U,V\in\End_K(\Lambda\otimes_\OO K)
\otimes_{\OO}Use in source · 1 passage

Search aliases: ⊗_OO ⊗_ O otimes OO otimes mathcal

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  • Use in source · Read passage · 04_arithmetic.tex, line 4

    Let O be a discrete valuation ring with fraction field K and uniformizer π. Let Λ be a finite free O module and put V=K⊗_ OΛ. Suppose A∈End_ O(Λ).

    Exact mathematical passage
    
    V=K\otimes_{\OO}\Lambda.
    
\langleUse in source · 1 passage

Search aliases: ⟨ langle

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  • Use in source · Read passage · 02_coordinates.tex, line 161

    [Orthogonal Hilbert packets] If X is a real or complex Hilbert space and every packet system in the tower consists of orthogonal projections, equip each finite packet direct sum with the Hilbert inner product ⟨(x_α),(y_α)⟩=∑_α⟨ x_α,y_α⟩. Then analysis and synthesis are unitary. Every coordinate change in [source reference] is unitary.

    Exact mathematical passage
    \langle(x_\alpha),(y_\alpha)\rangle=\sum_\alpha\langle x_\alpha,y_\alpha\rangle
\rangleUse in source · 1 passage

Search aliases: ⟩ rangle

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  • Use in source · Read passage · 02_coordinates.tex, line 161

    [Orthogonal Hilbert packets] If X is a real or complex Hilbert space and every packet system in the tower consists of orthogonal projections, equip each finite packet direct sum with the Hilbert inner product ⟨(x_α),(y_α)⟩=∑_α⟨ x_α,y_α⟩. Then analysis and synthesis are unitary. Every coordinate change in [source reference] is unitary.

    Exact mathematical passage
    \langle(x_\alpha),(y_\alpha)\rangle=\sum_\alpha\langle x_\alpha,y_\alpha\rangle
\longmapstoUse in source · 4 passages

Search aliases: ⟼ longmapsto

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  • Use in source · Read passage · 04_arithmetic.tex, line 268

    [Gluing module and exact separation weight] With the notation of [source reference], the map Φ:G_Λ, P ⟶ ⊕_α∈ IE_αΛ/Λ_α, [x]⟼(E_α x+Λ_α)_α is injective, and every coordinate projection of its image is surjective. We also have exp_π(G_Λ, P) = s_Λ( P). If G_Λ, P ≅ ⊕_j=1^r O/π^a_j O with a_1≤⋯≤ a_r, then s_Λ( P)=max({0}∪{a_j:1≤ j≤ r}).

    Exact mathematical passage
    
    \Phi:G_{\Lambda,\Pcal}
    \longrightarrow
    \bigoplus_{\alpha\in I}E_\alpha\Lambda/\Lambda_\alpha,
    \qquad
    [x]\longmapsto(E_\alpha x+\Lambda_\alpha)_\alpha
    

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