shear_holonomy.tex
Paper III: Typed Transfer, Nonlinear Packets, and Obstruction Theory
shear_holonomy.tex
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1 \begin{tikzpicture}[x=1cm,y=1cm,>=Latex,font=\sffamily\small,line cap=round,line join=round]
2 \draw[->,black!55] (0.40000,0.40000) -- (3.70000,0.40000);
3 \draw[->,black!55] (0.60000,0.25000) -- (0.60000,2.25000);
4 \draw[dashed,black!55] (0.60000,0.40000) -- (2.00000,0.40000) -- (2.00000,1.80000) -- (0.60000,1.80000) -- cycle;
5 \draw[fill=black!10,line width=1pt] (0.60000,0.40000) -- (2.00000,0.40000) -- (3.40000,1.80000) -- (2.00000,1.80000) -- cycle;
6 \draw[->,line width=1.4pt] (0.60000,0.40000) -- (2.00000,1.80000);
7 \node[font=\sffamily\bfseries] at (2.00000,2.75000) {The unit square under H};
8 \node[anchor=west] at (2.12000,2.02000) {$(1,1)$};
9 \node[] at (6.95000,3.55000) {$H$};
10 \draw[fill=black!12,draw=black!40,line width=.35pt,] (6.20000,2.25000) rectangle ++(0.75000,0.75000);
11 \node[] at (6.57500,2.62500) {$1$};
12 \draw[fill=black!12,draw=black!40,line width=.35pt,] (6.95000,2.25000) rectangle ++(0.75000,0.75000);
13 \node[] at (7.32500,2.62500) {$1$};
14 \draw[fill=black!0,draw=black!40,line width=.35pt,] (6.20000,1.50000) rectangle ++(0.75000,0.75000);
15 \node[] at (6.57500,1.87500) {$0$};
16 \draw[fill=black!12,draw=black!40,line width=.35pt,] (6.95000,1.50000) rectangle ++(0.75000,0.75000);
17 \node[] at (7.32500,1.87500) {$1$};
18 \node[] at (10.45000,3.55000) {$H-I$};
19 \draw[fill=black!0,draw=black!40,line width=.35pt,] (9.70000,2.25000) rectangle ++(0.75000,0.75000);
20 \node[] at (10.07500,2.62500) {$0$};
21 \draw[fill=black!12,draw=black!40,line width=.35pt,] (10.45000,2.25000) rectangle ++(0.75000,0.75000);
22 \node[] at (10.82500,2.62500) {$1$};
23 \draw[fill=black!0,draw=black!40,line width=.35pt,] (9.70000,1.50000) rectangle ++(0.75000,0.75000);
24 \node[] at (10.07500,1.87500) {$0$};
25 \draw[fill=black!0,draw=black!40,line width=.35pt,] (10.45000,1.50000) rectangle ++(0.75000,0.75000);
26 \node[] at (10.82500,1.87500) {$0$};
27 \node[] at (8.70000,0.20000) {$\operatorname{tr}H=2,\quad\det H=1,\quad(H-I)e_1=e_0$};
28 \end{tikzpicture}
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